Find the point on the plane $x+2y+3z = 1$, which is nearest to the point $(-1,0,1)$ by Lagrange’s...

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Find the point on the plane $x+2y+3z = 1$, which is nearest to the point $(-1,0,1)$ by Lagrange’s multiplier method.



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Find the point on the line of intersection of the two planes using Lagrange's method.Help with Lagrangian multiplier methodLagrange Multiplier Method On Linear Equation SetLagrange's multiplier method find the highest and the lowest pointoptimize distance from point to plane with Lagrange methodUse the Lagrange multiplier method to compute the maximum value of the function?Nearest point to origin of a hyperplane by Lagrange multiplierFind the desired point using Lagrange's Multiplier MethodUsing Lagrange's multiplier method, find the shortest distance between the line y=10-2x and the ellipse $frac{x^2}{4}+frac{y^2}{9}=1$Lagrange duality compared with Lagrange multiplier method












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Find the point on the plane $x+2y+3z = 1$, which is nearest to the point $(-1,0,1)$ by Lagrange’s multiplier method.










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Find the point on the plane $x+2y+3z = 1$, which is nearest to the point $(-1,0,1)$ by Lagrange’s multiplier method.










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    What did you try?
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    – Mark
    Mar 24 at 20:18














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Find the point on the plane $x+2y+3z = 1$, which is nearest to the point $(-1,0,1)$ by Lagrange’s multiplier method.










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Find the point on the plane $x+2y+3z = 1$, which is nearest to the point $(-1,0,1)$ by Lagrange’s multiplier method.







lagrange-multiplier






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edited Mar 24 at 20:19









Robert Z

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asked Mar 24 at 20:17









mohammed yahayamohammed yahaya

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    $begingroup$
    What did you try?
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    – Mark
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    $begingroup$
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    – Mark
    Mar 24 at 20:18








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$begingroup$
What did you try?
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– Mark
Mar 24 at 20:18




$begingroup$
What did you try?
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– Mark
Mar 24 at 20:18










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$${min (x+1)^2+y^2+(z-1)^2\text{s. t.}\x+2y+3z-1=0}$$






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    $${min (x+1)^2+y^2+(z-1)^2\text{s. t.}\x+2y+3z-1=0}$$






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      $${min (x+1)^2+y^2+(z-1)^2\text{s. t.}\x+2y+3z-1=0}$$






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        $${min (x+1)^2+y^2+(z-1)^2\text{s. t.}\x+2y+3z-1=0}$$






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        Hint



        $${min (x+1)^2+y^2+(z-1)^2\text{s. t.}\x+2y+3z-1=0}$$







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        answered Mar 24 at 20:22









        Mostafa AyazMostafa Ayaz

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