If $(X,A)$ has homotopy extension property, then $(X times I, X times partial I cup A times I)$ also shares...

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If $(X,A)$ has homotopy extension property, then $(X times I, X times partial I cup A times I)$ also shares this property.



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)concerning the definition of homotopy extension propertyRetract and Homotopy extension propertyTwo deformation retractions (onto $A$) are homotopic (rel $A$).If $(X,A)$ has homotopy extension, then $X times I$ def. retracts to $X times {0} cup A times I$if $(X,A)$ has homotopy extension, so does $(X cup CA,CA)$Need help in understanding a proof from Hatcher's Algebraic Topology (proposition $0.19$)Prove HEP with YonedaHow to prove that if $(X,A)$ has the homotopy extension property, then so does $(Xcup CA,CA)$?Homotopy extension property and relative homotopyHomotopy Extension Property: necessary and sufficient condition












4












$begingroup$


The original problem is to prove:



If $(X,A)$ has HEP (homotopy extension property), then $(X times I, X times partial I cup A times I)$ also shares this property.



I found a proof in Page 35, Theorem 2.33 of this note, or see here in picture, but I want an explicit one.



My question:



Can we get an explicit expression of retraction $$phi: X times I times I to X times I times {0} cup (X times partial I cup A times I) times I$$
?



Thank you!










share|cite|improve this question











$endgroup$

















    4












    $begingroup$


    The original problem is to prove:



    If $(X,A)$ has HEP (homotopy extension property), then $(X times I, X times partial I cup A times I)$ also shares this property.



    I found a proof in Page 35, Theorem 2.33 of this note, or see here in picture, but I want an explicit one.



    My question:



    Can we get an explicit expression of retraction $$phi: X times I times I to X times I times {0} cup (X times partial I cup A times I) times I$$
    ?



    Thank you!










    share|cite|improve this question











    $endgroup$















      4












      4








      4


      0



      $begingroup$


      The original problem is to prove:



      If $(X,A)$ has HEP (homotopy extension property), then $(X times I, X times partial I cup A times I)$ also shares this property.



      I found a proof in Page 35, Theorem 2.33 of this note, or see here in picture, but I want an explicit one.



      My question:



      Can we get an explicit expression of retraction $$phi: X times I times I to X times I times {0} cup (X times partial I cup A times I) times I$$
      ?



      Thank you!










      share|cite|improve this question











      $endgroup$




      The original problem is to prove:



      If $(X,A)$ has HEP (homotopy extension property), then $(X times I, X times partial I cup A times I)$ also shares this property.



      I found a proof in Page 35, Theorem 2.33 of this note, or see here in picture, but I want an explicit one.



      My question:



      Can we get an explicit expression of retraction $$phi: X times I times I to X times I times {0} cup (X times partial I cup A times I) times I$$
      ?



      Thank you!







      algebraic-topology homotopy-theory






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Mar 24 at 20:26







      Andrews

















      asked Oct 19 '18 at 4:59









      AndrewsAndrews

      1,3012423




      1,3012423






















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