If $(X,A)$ has homotopy extension property, then $(X times I, X times partial I cup A times I)$ also shares...
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If $(X,A)$ has homotopy extension property, then $(X times I, X times partial I cup A times I)$ also shares this property.
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)concerning the definition of homotopy extension propertyRetract and Homotopy extension propertyTwo deformation retractions (onto $A$) are homotopic (rel $A$).If $(X,A)$ has homotopy extension, then $X times I$ def. retracts to $X times {0} cup A times I$if $(X,A)$ has homotopy extension, so does $(X cup CA,CA)$Need help in understanding a proof from Hatcher's Algebraic Topology (proposition $0.19$)Prove HEP with YonedaHow to prove that if $(X,A)$ has the homotopy extension property, then so does $(Xcup CA,CA)$?Homotopy extension property and relative homotopyHomotopy Extension Property: necessary and sufficient condition
$begingroup$
The original problem is to prove:
If $(X,A)$ has HEP (homotopy extension property), then $(X times I, X times partial I cup A times I)$ also shares this property.
I found a proof in Page 35, Theorem 2.33 of this note, or see here in picture, but I want an explicit one.
My question:
Can we get an explicit expression of retraction $$phi: X times I times I to X times I times {0} cup (X times partial I cup A times I) times I$$
?
Thank you!
algebraic-topology homotopy-theory
$endgroup$
add a comment |
$begingroup$
The original problem is to prove:
If $(X,A)$ has HEP (homotopy extension property), then $(X times I, X times partial I cup A times I)$ also shares this property.
I found a proof in Page 35, Theorem 2.33 of this note, or see here in picture, but I want an explicit one.
My question:
Can we get an explicit expression of retraction $$phi: X times I times I to X times I times {0} cup (X times partial I cup A times I) times I$$
?
Thank you!
algebraic-topology homotopy-theory
$endgroup$
add a comment |
$begingroup$
The original problem is to prove:
If $(X,A)$ has HEP (homotopy extension property), then $(X times I, X times partial I cup A times I)$ also shares this property.
I found a proof in Page 35, Theorem 2.33 of this note, or see here in picture, but I want an explicit one.
My question:
Can we get an explicit expression of retraction $$phi: X times I times I to X times I times {0} cup (X times partial I cup A times I) times I$$
?
Thank you!
algebraic-topology homotopy-theory
$endgroup$
The original problem is to prove:
If $(X,A)$ has HEP (homotopy extension property), then $(X times I, X times partial I cup A times I)$ also shares this property.
I found a proof in Page 35, Theorem 2.33 of this note, or see here in picture, but I want an explicit one.
My question:
Can we get an explicit expression of retraction $$phi: X times I times I to X times I times {0} cup (X times partial I cup A times I) times I$$
?
Thank you!
algebraic-topology homotopy-theory
algebraic-topology homotopy-theory
edited Mar 24 at 20:26
Andrews
asked Oct 19 '18 at 4:59
AndrewsAndrews
1,3012423
1,3012423
add a comment |
add a comment |
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