How to find p(Y|X), if Y=X+Z and I know the distribution of Z?Marginal DistributionChi Squared Distribution...
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How to find p(Y|X), if Y=X+Z and I know the distribution of Z?
Marginal DistributionChi Squared Distribution with $mu = 0$, $sigma^2 neq 1$Let $X_1$ and $X_2$ are independent $N(0, sigma^2)$ random variables. What is the distribution of $X_1^2 + X_2^2$?Find the distribution of $X_1^2 + X_2^2$?What is the magnitude of Complex random variable Gaussian Case?Find the Distribution of the following;Distribution name and PDFIf $X$ and $Y$ are two NON independent random normal variables, what is the distribution of $Z = frac{X}{Y^n}$Show that the random variables have the same distributionMean and variance of uniform distribution where maximum depends on product of RVs with uniform and Bernoulli
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Suppose I have three random variables $x,y,z$ and they have a relation as
$y=x+z$ now I have the distribution of $z sim p(z)$, how to find $p(y|x)$.
I know intuitively if I have $zsim N(0,sigma^2)$ then $x$ will just impact its mean and so $p(y|x)sim N(x,sigma^2)$.
But I want to know general mathematical procedures to find $p(y|x)$, specifically, if $zsim p(z)$ where $p(z)$ have an undefined MGF and mean and variance both are infinite. Further, I assume that $x$ and $z$ are independent of one another.
probability-theory statistics probability-distributions
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add a comment |
$begingroup$
Suppose I have three random variables $x,y,z$ and they have a relation as
$y=x+z$ now I have the distribution of $z sim p(z)$, how to find $p(y|x)$.
I know intuitively if I have $zsim N(0,sigma^2)$ then $x$ will just impact its mean and so $p(y|x)sim N(x,sigma^2)$.
But I want to know general mathematical procedures to find $p(y|x)$, specifically, if $zsim p(z)$ where $p(z)$ have an undefined MGF and mean and variance both are infinite. Further, I assume that $x$ and $z$ are independent of one another.
probability-theory statistics probability-distributions
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1
$begingroup$
@Kavi Rama Murthy I assume $x$ and $z$ are independent of one another.
$endgroup$
– Ankit
yesterday
add a comment |
$begingroup$
Suppose I have three random variables $x,y,z$ and they have a relation as
$y=x+z$ now I have the distribution of $z sim p(z)$, how to find $p(y|x)$.
I know intuitively if I have $zsim N(0,sigma^2)$ then $x$ will just impact its mean and so $p(y|x)sim N(x,sigma^2)$.
But I want to know general mathematical procedures to find $p(y|x)$, specifically, if $zsim p(z)$ where $p(z)$ have an undefined MGF and mean and variance both are infinite. Further, I assume that $x$ and $z$ are independent of one another.
probability-theory statistics probability-distributions
$endgroup$
Suppose I have three random variables $x,y,z$ and they have a relation as
$y=x+z$ now I have the distribution of $z sim p(z)$, how to find $p(y|x)$.
I know intuitively if I have $zsim N(0,sigma^2)$ then $x$ will just impact its mean and so $p(y|x)sim N(x,sigma^2)$.
But I want to know general mathematical procedures to find $p(y|x)$, specifically, if $zsim p(z)$ where $p(z)$ have an undefined MGF and mean and variance both are infinite. Further, I assume that $x$ and $z$ are independent of one another.
probability-theory statistics probability-distributions
probability-theory statistics probability-distributions
edited yesterday
Ankit
asked yesterday
AnkitAnkit
1829
1829
1
$begingroup$
@Kavi Rama Murthy I assume $x$ and $z$ are independent of one another.
$endgroup$
– Ankit
yesterday
add a comment |
1
$begingroup$
@Kavi Rama Murthy I assume $x$ and $z$ are independent of one another.
$endgroup$
– Ankit
yesterday
1
1
$begingroup$
@Kavi Rama Murthy I assume $x$ and $z$ are independent of one another.
$endgroup$
– Ankit
yesterday
$begingroup$
@Kavi Rama Murthy I assume $x$ and $z$ are independent of one another.
$endgroup$
– Ankit
yesterday
add a comment |
1 Answer
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The distribution function of $Y$ given $X$ is $F_Z(y-X)$ and the density function is $f_Z(y-X)$ where $F_Z$ and $f_Z$ are the disrtibution function and the density of $Z$ respectively.
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1 Answer
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$begingroup$
The distribution function of $Y$ given $X$ is $F_Z(y-X)$ and the density function is $f_Z(y-X)$ where $F_Z$ and $f_Z$ are the disrtibution function and the density of $Z$ respectively.
$endgroup$
add a comment |
$begingroup$
The distribution function of $Y$ given $X$ is $F_Z(y-X)$ and the density function is $f_Z(y-X)$ where $F_Z$ and $f_Z$ are the disrtibution function and the density of $Z$ respectively.
$endgroup$
add a comment |
$begingroup$
The distribution function of $Y$ given $X$ is $F_Z(y-X)$ and the density function is $f_Z(y-X)$ where $F_Z$ and $f_Z$ are the disrtibution function and the density of $Z$ respectively.
$endgroup$
The distribution function of $Y$ given $X$ is $F_Z(y-X)$ and the density function is $f_Z(y-X)$ where $F_Z$ and $f_Z$ are the disrtibution function and the density of $Z$ respectively.
answered yesterday
Kavi Rama MurthyKavi Rama Murthy
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@Kavi Rama Murthy I assume $x$ and $z$ are independent of one another.
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– Ankit
yesterday