Prove that if matrix $C = I - 2M $ and $M = M^2, $ then $ C^3 = C.$Matrix properties after multiplication.If...

How is the partial sum of a geometric sequence calculated?

Light propagating through a sound wave

Is there a term for accumulated dirt on the outside of your hands and feet?

Worshiping one God at a time?

Should I use acronyms in dialogues before telling the readers what it stands for in fiction?

Is there a creature that is resistant or immune to non-magical damage other than bludgeoning, slashing, and piercing?

Is it possible to stack the damage done by the Absorb Elements spell?

Can a wizard cast a spell during their first turn of combat if they initiated combat by releasing a readied spell?

I got the following comment from a reputed math journal. What does it mean?

How can an organ that provides biological immortality be unable to regenerate?

What does Jesus mean regarding "Raca," and "you fool?" - is he contrasting them?

Synchronized implementation of a bank account in Java

Existence of a celestial body big enough for early civilization to be thought of as a second moon

Geography in 3D perspective

Recruiter wants very extensive technical details about all of my previous work

Why didn't Héctor fade away after this character died in the movie Coco?

Unfrosted light bulb

PTIJ: Do Irish Jews have "the luck of the Irish"?

Probably overheated black color SMD pads

What (if any) is the reason to buy in small local stores?

Deletion of copy-ctor & copy-assignment - public, private or protected?

Suggestions on how to spend Shaabath (constructively) alone

Print a physical multiplication table

Do I need to consider instance restrictions when showing a language is in P?



Prove that if matrix $C = I - 2M $ and $M = M^2, $ then $ C^3 = C.$


Matrix properties after multiplication.If AB is a projection then BA is a projectionProve that Det(A-E)=0 if and only if AC=CSum of identity and idempotent (projection) matrixThe Zero Matrixquestion about idempotent matrixAngle from rotation matrixMutual coherence for identity matrix and DFT matrixWhy if add a multiple of $I$ to a symmetric matrix then we have positive semidefinite matrixFinding the idempotent matrix













0












$begingroup$


I'm faced with a problem for which I haven't been given a correction, so I expected you could tell me if I am right or not, and in the later case give me the appropriate answer.



Let $M$ be an idempotent matrix such that $M=M^2$, and let $C = I - 2M$, with $I$ being the identity matrix.



Prove that $C^3 = C$



My answer:



$$C=I-2M$$
$$Rightarrow C^2=(I-2M)^2$$
$$=I^2-4IM+4M^2$$
$$=I^2-4M^2+4M^2$$
$$=I$$
$$Rightarrow C^3 = IC=C$$



Thank you.










share|cite|improve this question











$endgroup$








  • 6




    $begingroup$
    In my opinion the idea of your proof is correct. However, you can't use the symbol $iff$. Note that $C=I-2M$ is not equivalent to $C^2=I$. If you use $implies$ it is correct. The same happens in $C^2=Iiff C^3=C.$
    $endgroup$
    – mfl
    Mar 11 at 20:10












  • $begingroup$
    I agree with the above. Also, to be clear, it might be helpful to write $C^3=C^2C=IC=C$
    $endgroup$
    – J. W. Tanner
    Mar 11 at 20:14










  • $begingroup$
    I changed the implication according to your correction. Thank you.
    $endgroup$
    – torito verdejo
    Mar 11 at 20:17






  • 2




    $begingroup$
    Maybe it's worth noting that $(I-2M)^2 = I^2-2IM-2MI+4M^2$ and $IM=MI=M$.
    $endgroup$
    – Wolfgang Kais
    Mar 11 at 20:36
















0












$begingroup$


I'm faced with a problem for which I haven't been given a correction, so I expected you could tell me if I am right or not, and in the later case give me the appropriate answer.



Let $M$ be an idempotent matrix such that $M=M^2$, and let $C = I - 2M$, with $I$ being the identity matrix.



Prove that $C^3 = C$



My answer:



$$C=I-2M$$
$$Rightarrow C^2=(I-2M)^2$$
$$=I^2-4IM+4M^2$$
$$=I^2-4M^2+4M^2$$
$$=I$$
$$Rightarrow C^3 = IC=C$$



Thank you.










share|cite|improve this question











$endgroup$








  • 6




    $begingroup$
    In my opinion the idea of your proof is correct. However, you can't use the symbol $iff$. Note that $C=I-2M$ is not equivalent to $C^2=I$. If you use $implies$ it is correct. The same happens in $C^2=Iiff C^3=C.$
    $endgroup$
    – mfl
    Mar 11 at 20:10












  • $begingroup$
    I agree with the above. Also, to be clear, it might be helpful to write $C^3=C^2C=IC=C$
    $endgroup$
    – J. W. Tanner
    Mar 11 at 20:14










  • $begingroup$
    I changed the implication according to your correction. Thank you.
    $endgroup$
    – torito verdejo
    Mar 11 at 20:17






  • 2




    $begingroup$
    Maybe it's worth noting that $(I-2M)^2 = I^2-2IM-2MI+4M^2$ and $IM=MI=M$.
    $endgroup$
    – Wolfgang Kais
    Mar 11 at 20:36














0












0








0


1



$begingroup$


I'm faced with a problem for which I haven't been given a correction, so I expected you could tell me if I am right or not, and in the later case give me the appropriate answer.



Let $M$ be an idempotent matrix such that $M=M^2$, and let $C = I - 2M$, with $I$ being the identity matrix.



Prove that $C^3 = C$



My answer:



$$C=I-2M$$
$$Rightarrow C^2=(I-2M)^2$$
$$=I^2-4IM+4M^2$$
$$=I^2-4M^2+4M^2$$
$$=I$$
$$Rightarrow C^3 = IC=C$$



Thank you.










share|cite|improve this question











$endgroup$




I'm faced with a problem for which I haven't been given a correction, so I expected you could tell me if I am right or not, and in the later case give me the appropriate answer.



Let $M$ be an idempotent matrix such that $M=M^2$, and let $C = I - 2M$, with $I$ being the identity matrix.



Prove that $C^3 = C$



My answer:



$$C=I-2M$$
$$Rightarrow C^2=(I-2M)^2$$
$$=I^2-4IM+4M^2$$
$$=I^2-4M^2+4M^2$$
$$=I$$
$$Rightarrow C^3 = IC=C$$



Thank you.







linear-algebra matrices






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Mar 11 at 20:15









J. W. Tanner

3,3351320




3,3351320










asked Mar 11 at 20:05









torito verdejotorito verdejo

745




745








  • 6




    $begingroup$
    In my opinion the idea of your proof is correct. However, you can't use the symbol $iff$. Note that $C=I-2M$ is not equivalent to $C^2=I$. If you use $implies$ it is correct. The same happens in $C^2=Iiff C^3=C.$
    $endgroup$
    – mfl
    Mar 11 at 20:10












  • $begingroup$
    I agree with the above. Also, to be clear, it might be helpful to write $C^3=C^2C=IC=C$
    $endgroup$
    – J. W. Tanner
    Mar 11 at 20:14










  • $begingroup$
    I changed the implication according to your correction. Thank you.
    $endgroup$
    – torito verdejo
    Mar 11 at 20:17






  • 2




    $begingroup$
    Maybe it's worth noting that $(I-2M)^2 = I^2-2IM-2MI+4M^2$ and $IM=MI=M$.
    $endgroup$
    – Wolfgang Kais
    Mar 11 at 20:36














  • 6




    $begingroup$
    In my opinion the idea of your proof is correct. However, you can't use the symbol $iff$. Note that $C=I-2M$ is not equivalent to $C^2=I$. If you use $implies$ it is correct. The same happens in $C^2=Iiff C^3=C.$
    $endgroup$
    – mfl
    Mar 11 at 20:10












  • $begingroup$
    I agree with the above. Also, to be clear, it might be helpful to write $C^3=C^2C=IC=C$
    $endgroup$
    – J. W. Tanner
    Mar 11 at 20:14










  • $begingroup$
    I changed the implication according to your correction. Thank you.
    $endgroup$
    – torito verdejo
    Mar 11 at 20:17






  • 2




    $begingroup$
    Maybe it's worth noting that $(I-2M)^2 = I^2-2IM-2MI+4M^2$ and $IM=MI=M$.
    $endgroup$
    – Wolfgang Kais
    Mar 11 at 20:36








6




6




$begingroup$
In my opinion the idea of your proof is correct. However, you can't use the symbol $iff$. Note that $C=I-2M$ is not equivalent to $C^2=I$. If you use $implies$ it is correct. The same happens in $C^2=Iiff C^3=C.$
$endgroup$
– mfl
Mar 11 at 20:10






$begingroup$
In my opinion the idea of your proof is correct. However, you can't use the symbol $iff$. Note that $C=I-2M$ is not equivalent to $C^2=I$. If you use $implies$ it is correct. The same happens in $C^2=Iiff C^3=C.$
$endgroup$
– mfl
Mar 11 at 20:10














$begingroup$
I agree with the above. Also, to be clear, it might be helpful to write $C^3=C^2C=IC=C$
$endgroup$
– J. W. Tanner
Mar 11 at 20:14




$begingroup$
I agree with the above. Also, to be clear, it might be helpful to write $C^3=C^2C=IC=C$
$endgroup$
– J. W. Tanner
Mar 11 at 20:14












$begingroup$
I changed the implication according to your correction. Thank you.
$endgroup$
– torito verdejo
Mar 11 at 20:17




$begingroup$
I changed the implication according to your correction. Thank you.
$endgroup$
– torito verdejo
Mar 11 at 20:17




2




2




$begingroup$
Maybe it's worth noting that $(I-2M)^2 = I^2-2IM-2MI+4M^2$ and $IM=MI=M$.
$endgroup$
– Wolfgang Kais
Mar 11 at 20:36




$begingroup$
Maybe it's worth noting that $(I-2M)^2 = I^2-2IM-2MI+4M^2$ and $IM=MI=M$.
$endgroup$
– Wolfgang Kais
Mar 11 at 20:36










0






active

oldest

votes











Your Answer





StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3144169%2fprove-that-if-matrix-c-i-2m-and-m-m2-then-c3-c%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























0






active

oldest

votes








0






active

oldest

votes









active

oldest

votes






active

oldest

votes
















draft saved

draft discarded




















































Thanks for contributing an answer to Mathematics Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3144169%2fprove-that-if-matrix-c-i-2m-and-m-m2-then-c3-c%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Magento 2 - Add success message with knockout Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?Success / Error message on ajax request$.widget is not a function when loading a homepage after add custom jQuery on custom themeHow can bind jQuery to current document in Magento 2 When template load by ajaxRedirect page using plugin in Magento 2Magento 2 - Update quantity and totals of cart page without page reload?Magento 2: Quote data not loaded on knockout checkoutMagento 2 : I need to change add to cart success message after adding product into cart through pluginMagento 2.2.5 How to add additional products to cart from new checkout step?Magento 2 Add error/success message with knockoutCan't validate Post Code on checkout page

Fil:Tokke komm.svg

Where did Arya get these scars? Unicorn Meta Zoo #1: Why another podcast? Announcing the arrival of Valued Associate #679: Cesar Manara Favourite questions and answers from the 1st quarter of 2019Why did Arya refuse to end it?Has the pronunciation of Arya Stark's name changed?Has Arya forgiven people?Why did Arya Stark lose her vision?Why can Arya still use the faces?Has the Narrow Sea become narrower?Does Arya Stark know how to make poisons outside of the House of Black and White?Why did Nymeria leave Arya?Why did Arya not kill the Lannister soldiers she encountered in the Riverlands?What is the current canonical age of Sansa, Bran and Arya Stark?