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Scalars in tensor notation
How to visualize a rank-2 tensor?Question about cross product and tensor notationIntuitive transition from matrices to tensor-conceptFinding the Gradient of a Tensor FieldMultidimensional Tensor Inverse - Index NotationTensor rank as a first order formulaHow do you represent functionals in tensor-notation?What is a tensor?How do I tell the rank of the electric susceptibility tensor (and others)?What is a rank-1 tensor? What is the meaning of rank in this context?
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I know that usually the number of indices on a tensor indicates it’s rank, so how do you represent a scalar/rank zero tensor. I’ve had trouble making this work and it seems at times like there’s ambiguity between scalars and vectors.
tensors tensor-rank
asked Mar 11 at 19:46
Benjamin ThoburnBenjamin Thoburn
356313
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add a comment |
$begingroup$
I know that usually the number of indices on a tensor indicates it’s rank, so how do you represent a scalar/rank zero tensor. I’ve had trouble making this work and it seems at times like there’s ambiguity between scalars and vectors.
tensors tensor-rank
asked Mar 11 at 19:46
Benjamin ThoburnBenjamin Thoburn
356313
$endgroup$
add a comment |
$begingroup$
I know that usually the number of indices on a tensor indicates it’s rank, so how do you represent a scalar/rank zero tensor. I’ve had trouble making this work and it seems at times like there’s ambiguity between scalars and vectors.
tensors tensor-rank
asked Mar 11 at 19:46
Benjamin ThoburnBenjamin Thoburn
356313
$endgroup$
I know that usually the number of indices on a tensor indicates it’s rank, so how do you represent a scalar/rank zero tensor. I’ve had trouble making this work and it seems at times like there’s ambiguity between scalars and vectors.
tensors tensor-rank
tensors tensor-rank
asked Mar 11 at 19:46
Benjamin ThoburnBenjamin Thoburn
356313
asked Mar 11 at 19:46
Benjamin ThoburnBenjamin Thoburn
356313
asked Mar 11 at 19:46
Benjamin ThoburnBenjamin Thoburn
356313
asked Mar 11 at 19:46
Benjamin ThoburnBenjamin Thoburn
356313
asked Mar 11 at 19:46
Benjamin ThoburnBenjamin Thoburn
356313
356313
add a comment |
add a comment |
1 Answer
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You're right: the number of indices indicates the rank, so a scalar has no indices and hence a single component (cf. $n$ components of a vector).
answered Mar 11 at 19:55
colt_browningcolt_browning
768110
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add a comment |
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1 Answer
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1 Answer
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$begingroup$
You're right: the number of indices indicates the rank, so a scalar has no indices and hence a single component (cf. $n$ components of a vector).
answered Mar 11 at 19:55
colt_browningcolt_browning
768110
$endgroup$
add a comment |
$begingroup$
You're right: the number of indices indicates the rank, so a scalar has no indices and hence a single component (cf. $n$ components of a vector).
answered Mar 11 at 19:55
colt_browningcolt_browning
768110
$endgroup$
add a comment |
$begingroup$
You're right: the number of indices indicates the rank, so a scalar has no indices and hence a single component (cf. $n$ components of a vector).
answered Mar 11 at 19:55
colt_browningcolt_browning
768110
$endgroup$
You're right: the number of indices indicates the rank, so a scalar has no indices and hence a single component (cf. $n$ components of a vector).
answered Mar 11 at 19:55
colt_browningcolt_browning
768110
answered Mar 11 at 19:55
colt_browningcolt_browning
768110
answered Mar 11 at 19:55
colt_browningcolt_browning
768110
answered Mar 11 at 19:55
colt_browningcolt_browning
768110
768110
add a comment |
add a comment |
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