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Characterizing potentially non-differentiable functions by their maximum


What is an example that a function is differentiable but derivative is not Riemann integrableDistinction between nowhere monotone and nowhere differentiableIs there only one continuous-everywhere non-differentiable function?Non differentiable solutions to $partial_x f + partial_y f =0$Common traits of functions which are non-trivial to integrate?Non-decreasing and everywhere differentiable on $[0,1]$ implies absolutelly continuous?Definition of Concavity for Twice Differentiable FunctionsDifference of increasing functions differentiable a.e.My proof uses derivatives. Can I extend it to non-differentiable functions?Determining, without recourse to complex analysis, which functions $f: mathbf{R} to mathbf{R}$ converge to their Taylor seriesIs $f:mathbb Rtomathbb R$ concave everywhere if, within each interval on the domain, $exists$ a sub-interval s.t. $f$ is concave locally?













1












$begingroup$


In short, my question – which has come up in a mechanism design setting I'm working on – is the following. Let $f,gcolon mathbb{R} rightarrow mathbb{R}$ be continuous functions and let $f$ be non-decreasing and non-negative. Then for each $yinmathbb{R}$ consider the function
$$
r_ycolon mathbb{R} rightarrow mathbb{R}colon x mapsto f(x)cdot y-g(x)
$$

over $mathbb{R}$. What do $f,g$ have to look like for $r_y$ to be globally optimal at $x=y$ for all $yin mathbb{R}$?



Of course, if $f,g$ are somewhat "well-behaved", we can go through the usual motions. For all $y$ it has to be $r_y'(y)=0$, i.e. $g'(y)=f'(y)y$ and via the fundamental theorem of calculus
$$
g(x)=C+int_0^x f'(zeta)zeta dzeta.
$$



But my calculus/real analysis knowledge is insufficient to understand whether the premises of the problem ensure that $f,g$ are sufficiently well-behaved or to understand what happens if they are not well-behaved.



Here are some more thoughts of mine. It's been a while since I took advanced calculus, so some of this might be confused.




  • Instead of talking about derivatives, we can talk about the (ratios of) differences. In particular, for all $d>0,yin mathbb{R}$, it must be $r_y(y+d)-r_y(y)leq 0$ and $r_y(y)-r_y(y-d)geq 0$. Rearranging stuff a little, this is equivalent to (for all $d>0,yin mathbb{R}$)
    $$
    y(f(y+d)-f(y))leq g(y+d)-g(y)leq (y+d)(f(y+d)-f(y)).
    $$

    This is nice because it's similar to the relationship between the derivatives. (Dividing by $d$ and letting it go to $0$ gives the relationship between the derivatives if they exist.) But it doesn't immediately answer questions about what kinds of $f$ are allowed or how to construct the corresponding $g$. (See below for problematic examples.)


  • Lebesgue's theorem for the differentiability of monotone functions seems to imply that $f$ and $g$ are differentiable almost everywhere. (The previous point implies that if $f$ is monotone, $g$ is monotone on $(-infty,0)$ and on $(0,infty)$.) So we can talk about the derivatives of $f$ and $g$ almost everywhere. But we might not be able to obtain (an "allowed") $g$ via integration of $g'(x)=f'(x)x$. For example, if $f$ is the Cantor function for $xin[0,1]$, then
    $$
    int_0^x f'(zeta)zeta dzeta = 0,
    $$

    right (see, e.g., sect. 2 here)? But if $f$ is the Cantor function and $g=0$, then $r_{frac{1}{2}}(frac{1}{2})<r_{frac{1}{2}}(1)$. That is, $r_{frac{1}{2}}$ does not have a maximum at $1/2$. So can $f$ be the Cantor function? That is, if $f$ is the Cantor function, is there a corresponding $g$ (s.t. $r_y$ has a maximum at $y$ for all $y$) and if so what is the corresponding $g$? More generally, can $f$ be a function that we can't find by integrating its derivative and if so, is there a way of finding the corresponding $g$?


  • The above point asks whether $g$ might not be an integral over $g'$. Another question is whether $g'$ (or $f'$) must be integrable at all. Of course, there are continuous functions whose derivatives are not integrable, but the examples I am aware of aren't even monotone (not to mention our other requirements for $f,g$).


  • One standard move that people use to replace derivatives is to use sub-/super-derivatives. But that seems to require the functions in question to be convex/concave. But neither $r_y$, nor $f$ or $g$ must be convex/concave everywhere.











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    $begingroup$


    In short, my question – which has come up in a mechanism design setting I'm working on – is the following. Let $f,gcolon mathbb{R} rightarrow mathbb{R}$ be continuous functions and let $f$ be non-decreasing and non-negative. Then for each $yinmathbb{R}$ consider the function
    $$
    r_ycolon mathbb{R} rightarrow mathbb{R}colon x mapsto f(x)cdot y-g(x)
    $$

    over $mathbb{R}$. What do $f,g$ have to look like for $r_y$ to be globally optimal at $x=y$ for all $yin mathbb{R}$?



    Of course, if $f,g$ are somewhat "well-behaved", we can go through the usual motions. For all $y$ it has to be $r_y'(y)=0$, i.e. $g'(y)=f'(y)y$ and via the fundamental theorem of calculus
    $$
    g(x)=C+int_0^x f'(zeta)zeta dzeta.
    $$



    But my calculus/real analysis knowledge is insufficient to understand whether the premises of the problem ensure that $f,g$ are sufficiently well-behaved or to understand what happens if they are not well-behaved.



    Here are some more thoughts of mine. It's been a while since I took advanced calculus, so some of this might be confused.




    • Instead of talking about derivatives, we can talk about the (ratios of) differences. In particular, for all $d>0,yin mathbb{R}$, it must be $r_y(y+d)-r_y(y)leq 0$ and $r_y(y)-r_y(y-d)geq 0$. Rearranging stuff a little, this is equivalent to (for all $d>0,yin mathbb{R}$)
      $$
      y(f(y+d)-f(y))leq g(y+d)-g(y)leq (y+d)(f(y+d)-f(y)).
      $$

      This is nice because it's similar to the relationship between the derivatives. (Dividing by $d$ and letting it go to $0$ gives the relationship between the derivatives if they exist.) But it doesn't immediately answer questions about what kinds of $f$ are allowed or how to construct the corresponding $g$. (See below for problematic examples.)


    • Lebesgue's theorem for the differentiability of monotone functions seems to imply that $f$ and $g$ are differentiable almost everywhere. (The previous point implies that if $f$ is monotone, $g$ is monotone on $(-infty,0)$ and on $(0,infty)$.) So we can talk about the derivatives of $f$ and $g$ almost everywhere. But we might not be able to obtain (an "allowed") $g$ via integration of $g'(x)=f'(x)x$. For example, if $f$ is the Cantor function for $xin[0,1]$, then
      $$
      int_0^x f'(zeta)zeta dzeta = 0,
      $$

      right (see, e.g., sect. 2 here)? But if $f$ is the Cantor function and $g=0$, then $r_{frac{1}{2}}(frac{1}{2})<r_{frac{1}{2}}(1)$. That is, $r_{frac{1}{2}}$ does not have a maximum at $1/2$. So can $f$ be the Cantor function? That is, if $f$ is the Cantor function, is there a corresponding $g$ (s.t. $r_y$ has a maximum at $y$ for all $y$) and if so what is the corresponding $g$? More generally, can $f$ be a function that we can't find by integrating its derivative and if so, is there a way of finding the corresponding $g$?


    • The above point asks whether $g$ might not be an integral over $g'$. Another question is whether $g'$ (or $f'$) must be integrable at all. Of course, there are continuous functions whose derivatives are not integrable, but the examples I am aware of aren't even monotone (not to mention our other requirements for $f,g$).


    • One standard move that people use to replace derivatives is to use sub-/super-derivatives. But that seems to require the functions in question to be convex/concave. But neither $r_y$, nor $f$ or $g$ must be convex/concave everywhere.











    share|cite|improve this question









    New contributor




    CPO is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$















      1












      1








      1





      $begingroup$


      In short, my question – which has come up in a mechanism design setting I'm working on – is the following. Let $f,gcolon mathbb{R} rightarrow mathbb{R}$ be continuous functions and let $f$ be non-decreasing and non-negative. Then for each $yinmathbb{R}$ consider the function
      $$
      r_ycolon mathbb{R} rightarrow mathbb{R}colon x mapsto f(x)cdot y-g(x)
      $$

      over $mathbb{R}$. What do $f,g$ have to look like for $r_y$ to be globally optimal at $x=y$ for all $yin mathbb{R}$?



      Of course, if $f,g$ are somewhat "well-behaved", we can go through the usual motions. For all $y$ it has to be $r_y'(y)=0$, i.e. $g'(y)=f'(y)y$ and via the fundamental theorem of calculus
      $$
      g(x)=C+int_0^x f'(zeta)zeta dzeta.
      $$



      But my calculus/real analysis knowledge is insufficient to understand whether the premises of the problem ensure that $f,g$ are sufficiently well-behaved or to understand what happens if they are not well-behaved.



      Here are some more thoughts of mine. It's been a while since I took advanced calculus, so some of this might be confused.




      • Instead of talking about derivatives, we can talk about the (ratios of) differences. In particular, for all $d>0,yin mathbb{R}$, it must be $r_y(y+d)-r_y(y)leq 0$ and $r_y(y)-r_y(y-d)geq 0$. Rearranging stuff a little, this is equivalent to (for all $d>0,yin mathbb{R}$)
        $$
        y(f(y+d)-f(y))leq g(y+d)-g(y)leq (y+d)(f(y+d)-f(y)).
        $$

        This is nice because it's similar to the relationship between the derivatives. (Dividing by $d$ and letting it go to $0$ gives the relationship between the derivatives if they exist.) But it doesn't immediately answer questions about what kinds of $f$ are allowed or how to construct the corresponding $g$. (See below for problematic examples.)


      • Lebesgue's theorem for the differentiability of monotone functions seems to imply that $f$ and $g$ are differentiable almost everywhere. (The previous point implies that if $f$ is monotone, $g$ is monotone on $(-infty,0)$ and on $(0,infty)$.) So we can talk about the derivatives of $f$ and $g$ almost everywhere. But we might not be able to obtain (an "allowed") $g$ via integration of $g'(x)=f'(x)x$. For example, if $f$ is the Cantor function for $xin[0,1]$, then
        $$
        int_0^x f'(zeta)zeta dzeta = 0,
        $$

        right (see, e.g., sect. 2 here)? But if $f$ is the Cantor function and $g=0$, then $r_{frac{1}{2}}(frac{1}{2})<r_{frac{1}{2}}(1)$. That is, $r_{frac{1}{2}}$ does not have a maximum at $1/2$. So can $f$ be the Cantor function? That is, if $f$ is the Cantor function, is there a corresponding $g$ (s.t. $r_y$ has a maximum at $y$ for all $y$) and if so what is the corresponding $g$? More generally, can $f$ be a function that we can't find by integrating its derivative and if so, is there a way of finding the corresponding $g$?


      • The above point asks whether $g$ might not be an integral over $g'$. Another question is whether $g'$ (or $f'$) must be integrable at all. Of course, there are continuous functions whose derivatives are not integrable, but the examples I am aware of aren't even monotone (not to mention our other requirements for $f,g$).


      • One standard move that people use to replace derivatives is to use sub-/super-derivatives. But that seems to require the functions in question to be convex/concave. But neither $r_y$, nor $f$ or $g$ must be convex/concave everywhere.











      share|cite|improve this question









      New contributor




      CPO is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      In short, my question – which has come up in a mechanism design setting I'm working on – is the following. Let $f,gcolon mathbb{R} rightarrow mathbb{R}$ be continuous functions and let $f$ be non-decreasing and non-negative. Then for each $yinmathbb{R}$ consider the function
      $$
      r_ycolon mathbb{R} rightarrow mathbb{R}colon x mapsto f(x)cdot y-g(x)
      $$

      over $mathbb{R}$. What do $f,g$ have to look like for $r_y$ to be globally optimal at $x=y$ for all $yin mathbb{R}$?



      Of course, if $f,g$ are somewhat "well-behaved", we can go through the usual motions. For all $y$ it has to be $r_y'(y)=0$, i.e. $g'(y)=f'(y)y$ and via the fundamental theorem of calculus
      $$
      g(x)=C+int_0^x f'(zeta)zeta dzeta.
      $$



      But my calculus/real analysis knowledge is insufficient to understand whether the premises of the problem ensure that $f,g$ are sufficiently well-behaved or to understand what happens if they are not well-behaved.



      Here are some more thoughts of mine. It's been a while since I took advanced calculus, so some of this might be confused.




      • Instead of talking about derivatives, we can talk about the (ratios of) differences. In particular, for all $d>0,yin mathbb{R}$, it must be $r_y(y+d)-r_y(y)leq 0$ and $r_y(y)-r_y(y-d)geq 0$. Rearranging stuff a little, this is equivalent to (for all $d>0,yin mathbb{R}$)
        $$
        y(f(y+d)-f(y))leq g(y+d)-g(y)leq (y+d)(f(y+d)-f(y)).
        $$

        This is nice because it's similar to the relationship between the derivatives. (Dividing by $d$ and letting it go to $0$ gives the relationship between the derivatives if they exist.) But it doesn't immediately answer questions about what kinds of $f$ are allowed or how to construct the corresponding $g$. (See below for problematic examples.)


      • Lebesgue's theorem for the differentiability of monotone functions seems to imply that $f$ and $g$ are differentiable almost everywhere. (The previous point implies that if $f$ is monotone, $g$ is monotone on $(-infty,0)$ and on $(0,infty)$.) So we can talk about the derivatives of $f$ and $g$ almost everywhere. But we might not be able to obtain (an "allowed") $g$ via integration of $g'(x)=f'(x)x$. For example, if $f$ is the Cantor function for $xin[0,1]$, then
        $$
        int_0^x f'(zeta)zeta dzeta = 0,
        $$

        right (see, e.g., sect. 2 here)? But if $f$ is the Cantor function and $g=0$, then $r_{frac{1}{2}}(frac{1}{2})<r_{frac{1}{2}}(1)$. That is, $r_{frac{1}{2}}$ does not have a maximum at $1/2$. So can $f$ be the Cantor function? That is, if $f$ is the Cantor function, is there a corresponding $g$ (s.t. $r_y$ has a maximum at $y$ for all $y$) and if so what is the corresponding $g$? More generally, can $f$ be a function that we can't find by integrating its derivative and if so, is there a way of finding the corresponding $g$?


      • The above point asks whether $g$ might not be an integral over $g'$. Another question is whether $g'$ (or $f'$) must be integrable at all. Of course, there are continuous functions whose derivatives are not integrable, but the examples I am aware of aren't even monotone (not to mention our other requirements for $f,g$).


      • One standard move that people use to replace derivatives is to use sub-/super-derivatives. But that seems to require the functions in question to be convex/concave. But neither $r_y$, nor $f$ or $g$ must be convex/concave everywhere.








      real-analysis calculus integration






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