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Basis functions and weak ODE solution


proving Orthonormal basisSolving differential equation by weak formulation and minimizing a functionalWeak topologies and weak convergence - Looking for feedbacksSimple coupled ODEOperator Convergence in Hilbert spaceEigenvalue of every eigenvector is an eigenvalue of element of o.n eigenvector basisBasis of $H_0^1$ of solutions to the time-independent Schrödinger equationFinding Orthonormal Basis from Orthogonal BasisWhich is the partial solution of the ode 4th orderGeneral solutions to differential equations and loss of information about eigenvalues













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$begingroup$


Given some linear differential operator $L$, I'm trying to solve the eigenvalue problem $L(u) = lambda u$. Given basis functions, call them $phi_i$, I use a variational procedure and the Ritz method to approximate $lambda$ via the associated weak formulation
$$langle L(phi_i),phi_jrangle = lambda langle phi_i,phi_jrangle.$$



As you can see, this expression is now a matrix equation, solutions to which are straightforward. For my particular problem, the basis functions are $$phi_j = cosleft( frac{pi j}{2}(x+1) right) coshleft( frac{pi j}{2}(y+h) right).$$



However, this solution, when inputted into the weak formulation equation, does not output correct eigenvalues. However, $phi_j$ can be split into even and odd components:
$$ phi_j^o = sin left( pi(j-1/2)x right)coshleft( pi(p-1/2)(y+h) right)\
phi_j^e = cos left( pi j x right)coshleft( pi j(y+h) right)
$$



Now to obtain eigenvalues I solve two separate equations, one for even eigenvalues and one for odd:
$$langle L(phi_i^e),phi_j^erangle = lambda langle phi_i^e,phi_j^erangle\
langle L(phi_i^o),phi_j^orangle = lambda langle phi_i^o,phi_j^orangle.$$



This latter approach gives correct solutions: why? Any insight or direction is greatly appreciated.










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Josh McCraney is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$

















    0












    $begingroup$


    Given some linear differential operator $L$, I'm trying to solve the eigenvalue problem $L(u) = lambda u$. Given basis functions, call them $phi_i$, I use a variational procedure and the Ritz method to approximate $lambda$ via the associated weak formulation
    $$langle L(phi_i),phi_jrangle = lambda langle phi_i,phi_jrangle.$$



    As you can see, this expression is now a matrix equation, solutions to which are straightforward. For my particular problem, the basis functions are $$phi_j = cosleft( frac{pi j}{2}(x+1) right) coshleft( frac{pi j}{2}(y+h) right).$$



    However, this solution, when inputted into the weak formulation equation, does not output correct eigenvalues. However, $phi_j$ can be split into even and odd components:
    $$ phi_j^o = sin left( pi(j-1/2)x right)coshleft( pi(p-1/2)(y+h) right)\
    phi_j^e = cos left( pi j x right)coshleft( pi j(y+h) right)
    $$



    Now to obtain eigenvalues I solve two separate equations, one for even eigenvalues and one for odd:
    $$langle L(phi_i^e),phi_j^erangle = lambda langle phi_i^e,phi_j^erangle\
    langle L(phi_i^o),phi_j^orangle = lambda langle phi_i^o,phi_j^orangle.$$



    This latter approach gives correct solutions: why? Any insight or direction is greatly appreciated.










    share|cite|improve this question







    New contributor




    Josh McCraney is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$















      0












      0








      0





      $begingroup$


      Given some linear differential operator $L$, I'm trying to solve the eigenvalue problem $L(u) = lambda u$. Given basis functions, call them $phi_i$, I use a variational procedure and the Ritz method to approximate $lambda$ via the associated weak formulation
      $$langle L(phi_i),phi_jrangle = lambda langle phi_i,phi_jrangle.$$



      As you can see, this expression is now a matrix equation, solutions to which are straightforward. For my particular problem, the basis functions are $$phi_j = cosleft( frac{pi j}{2}(x+1) right) coshleft( frac{pi j}{2}(y+h) right).$$



      However, this solution, when inputted into the weak formulation equation, does not output correct eigenvalues. However, $phi_j$ can be split into even and odd components:
      $$ phi_j^o = sin left( pi(j-1/2)x right)coshleft( pi(p-1/2)(y+h) right)\
      phi_j^e = cos left( pi j x right)coshleft( pi j(y+h) right)
      $$



      Now to obtain eigenvalues I solve two separate equations, one for even eigenvalues and one for odd:
      $$langle L(phi_i^e),phi_j^erangle = lambda langle phi_i^e,phi_j^erangle\
      langle L(phi_i^o),phi_j^orangle = lambda langle phi_i^o,phi_j^orangle.$$



      This latter approach gives correct solutions: why? Any insight or direction is greatly appreciated.










      share|cite|improve this question







      New contributor




      Josh McCraney is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      Given some linear differential operator $L$, I'm trying to solve the eigenvalue problem $L(u) = lambda u$. Given basis functions, call them $phi_i$, I use a variational procedure and the Ritz method to approximate $lambda$ via the associated weak formulation
      $$langle L(phi_i),phi_jrangle = lambda langle phi_i,phi_jrangle.$$



      As you can see, this expression is now a matrix equation, solutions to which are straightforward. For my particular problem, the basis functions are $$phi_j = cosleft( frac{pi j}{2}(x+1) right) coshleft( frac{pi j}{2}(y+h) right).$$



      However, this solution, when inputted into the weak formulation equation, does not output correct eigenvalues. However, $phi_j$ can be split into even and odd components:
      $$ phi_j^o = sin left( pi(j-1/2)x right)coshleft( pi(p-1/2)(y+h) right)\
      phi_j^e = cos left( pi j x right)coshleft( pi j(y+h) right)
      $$



      Now to obtain eigenvalues I solve two separate equations, one for even eigenvalues and one for odd:
      $$langle L(phi_i^e),phi_j^erangle = lambda langle phi_i^e,phi_j^erangle\
      langle L(phi_i^o),phi_j^orangle = lambda langle phi_i^o,phi_j^orangle.$$



      This latter approach gives correct solutions: why? Any insight or direction is greatly appreciated.







      functional-analysis ordinary-differential-equations change-of-basis






      share|cite|improve this question







      New contributor




      Josh McCraney is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|cite|improve this question







      New contributor




      Josh McCraney is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|cite|improve this question




      share|cite|improve this question






      New contributor




      Josh McCraney is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









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      Josh McCraney is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






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