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Exempt portion of equation line from aligning?
The mysteries of mathpaletteAligning plain `align` and `cases`?Alignment across nested aligned environmentsHow to match left alignment of equations in math mode outside and inside an array?How to modify eqnarray?Alignment of two equations on LaTeXHow center align two equations separated by a lineequation custom horizontal alignment & numbering each rowFlushed-left and flushed-right text in align or alignat environmentHow can I align this equation in the center?breqn not aligning first two lines
I am using an array environment to get aligned portions of a series of equations to center (instead of left-justify), as shown below:
usepackagearray,amsmath
[
beginarray>displaystylec @= >displaystylec @+ >displaystylec @+ >displaystylec
sumlimits_r=0^n+1 binomn+1r & binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
& 1 & sumlimits_r=1^n binomn+1r & 1 \
endarray
]
The array environment (I believe) is necessary here to get each of the columns to center instead of justifying left.
Now my problem is that these two lines are part of a greater series of equations, where the others do not follow this pattern to be aligned. However, I need the equals signs to line up across all lines.
My current approach is follow the array with a normal align
environment, having one equation line mirroring the longest line above but enclosed in phantom
to get the align spacing right. But this leaves a single empty line with an equals in it.
...
beginalign*
&= 2 + sum_r=1^nleft[binomnr + binomnr-1right] \
phantomsumlimits_r=0^n+1 binomn+1r &= phantom binomn+10 + binomn+11 + ldots + binomn+1n + binomn+1n+1
endalign*
How can I get this result, but without the extraneous equals line at the end? Preferable a more elegant one, as this idea relies on several iffy factors such as none of the following equations exceeding the size of the one governing the special alignment.
math-mode horizontal-alignment align arrays
New contributor
add a comment |
I am using an array environment to get aligned portions of a series of equations to center (instead of left-justify), as shown below:
usepackagearray,amsmath
[
beginarray>displaystylec @= >displaystylec @+ >displaystylec @+ >displaystylec
sumlimits_r=0^n+1 binomn+1r & binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
& 1 & sumlimits_r=1^n binomn+1r & 1 \
endarray
]
The array environment (I believe) is necessary here to get each of the columns to center instead of justifying left.
Now my problem is that these two lines are part of a greater series of equations, where the others do not follow this pattern to be aligned. However, I need the equals signs to line up across all lines.
My current approach is follow the array with a normal align
environment, having one equation line mirroring the longest line above but enclosed in phantom
to get the align spacing right. But this leaves a single empty line with an equals in it.
...
beginalign*
&= 2 + sum_r=1^nleft[binomnr + binomnr-1right] \
phantomsumlimits_r=0^n+1 binomn+1r &= phantom binomn+10 + binomn+11 + ldots + binomn+1n + binomn+1n+1
endalign*
How can I get this result, but without the extraneous equals line at the end? Preferable a more elegant one, as this idea relies on several iffy factors such as none of the following equations exceeding the size of the one governing the special alignment.
math-mode horizontal-alignment align arrays
New contributor
add a comment |
I am using an array environment to get aligned portions of a series of equations to center (instead of left-justify), as shown below:
usepackagearray,amsmath
[
beginarray>displaystylec @= >displaystylec @+ >displaystylec @+ >displaystylec
sumlimits_r=0^n+1 binomn+1r & binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
& 1 & sumlimits_r=1^n binomn+1r & 1 \
endarray
]
The array environment (I believe) is necessary here to get each of the columns to center instead of justifying left.
Now my problem is that these two lines are part of a greater series of equations, where the others do not follow this pattern to be aligned. However, I need the equals signs to line up across all lines.
My current approach is follow the array with a normal align
environment, having one equation line mirroring the longest line above but enclosed in phantom
to get the align spacing right. But this leaves a single empty line with an equals in it.
...
beginalign*
&= 2 + sum_r=1^nleft[binomnr + binomnr-1right] \
phantomsumlimits_r=0^n+1 binomn+1r &= phantom binomn+10 + binomn+11 + ldots + binomn+1n + binomn+1n+1
endalign*
How can I get this result, but without the extraneous equals line at the end? Preferable a more elegant one, as this idea relies on several iffy factors such as none of the following equations exceeding the size of the one governing the special alignment.
math-mode horizontal-alignment align arrays
New contributor
I am using an array environment to get aligned portions of a series of equations to center (instead of left-justify), as shown below:
usepackagearray,amsmath
[
beginarray>displaystylec @= >displaystylec @+ >displaystylec @+ >displaystylec
sumlimits_r=0^n+1 binomn+1r & binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
& 1 & sumlimits_r=1^n binomn+1r & 1 \
endarray
]
The array environment (I believe) is necessary here to get each of the columns to center instead of justifying left.
Now my problem is that these two lines are part of a greater series of equations, where the others do not follow this pattern to be aligned. However, I need the equals signs to line up across all lines.
My current approach is follow the array with a normal align
environment, having one equation line mirroring the longest line above but enclosed in phantom
to get the align spacing right. But this leaves a single empty line with an equals in it.
...
beginalign*
&= 2 + sum_r=1^nleft[binomnr + binomnr-1right] \
phantomsumlimits_r=0^n+1 binomn+1r &= phantom binomn+10 + binomn+11 + ldots + binomn+1n + binomn+1n+1
endalign*
How can I get this result, but without the extraneous equals line at the end? Preferable a more elegant one, as this idea relies on several iffy factors such as none of the following equations exceeding the size of the one governing the special alignment.
math-mode horizontal-alignment align arrays
math-mode horizontal-alignment align arrays
New contributor
New contributor
New contributor
asked 48 mins ago
PGmathPGmath
1212
1212
New contributor
New contributor
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
try
documentclassarticle
usepackagearray,amsmath
begindocument
[
beginarray>displaystylec @= >displaystylec @+ >displaystylec @+ >displaystylec
sum_r=0^n+1 binomn+1r
& binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
& 1 & sumlimits_r=1^n binomn+1r & 1 \
& multicolumn3>displaystylel
2 + sum_r=1^nleft[binomnr + binomnr-1right]
endarray
]
enddocument
add a comment |
Use the [t]
option. Then you do not need to use multicolumn
many times if you have many subsequent lines.
documentclassarticle
usepackagearray,amsmath
begindocument
beginalign*
sumlimits_r=0^n+1 binomn+1r
&beginarray[t]@>displaystylec @=@>displaystylec @+ >displaystylec @+ >displaystylec
& binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
& 1 & sumlimits_r=1^n binomn+1r & 1 \
endarray\
&=2 + sum_r=1^nleft[binomnr + binomnr-1right]
endalign*
enddocument
I like this approach better but I see it misses the equals on the 2nd line.
– PGmath
27 mins ago
@PGmath Very good catch! My bad. I updated.
– marmot
24 mins ago
Thanks. Can you explain a little what[t]
does? I've never done much involved stuff with arrays before.
– PGmath
9 mins ago
@PGmath It aligns the array at the top.
– marmot
8 mins ago
add a comment |
eqparbox
allows you to store the lengths of boxes via a <tag>
. Boxes with the same <tag>
are set with the maximum width across all content. Below I use this approach with a newly-defined eqmathbox[<tag>][<align>]
(default for <align>
is to c
entre the content) to add content to three different <tag>
ged boxes:
documentclassarticle
usepackageeqparbox,xparse,amsmath
% https://tex.stackexchange.com/a/34412/5764
makeatletter
NewDocumentCommandeqmathboxo Oc m%
IfValueTF#1
defeqmathbox@##1##2eqmakebox[#1][#2]$##1##2$
defeqmathbox@##1##2eqmakebox$##1##2$
mathpaletteeqmathbox@#3
makeatother
begindocument
beginalign*
sum_r = 0^n + 1 binomn + 1r
&= eqmathbox[LEFT]binomn + 10 + eqmathbox[CENTRE]binomn + 11 + dots + binomn + 1n + eqmathbox[RIGHT]binomn + 1n + 1 \
&= eqmathbox[LEFT]1 + eqmathbox[CENTRE]sum_r = 1^n binomn + 1r + eqmathbox[RIGHT]1 \
&= 2 + sum_r = 1^n biggl[ binomnr + binomnr - 1 biggr]
endalign*
enddocument
Since eqparbox
uses TeX's label
-ref
system, you need to compile twice for every change in the content of the maximum width.
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
try
documentclassarticle
usepackagearray,amsmath
begindocument
[
beginarray>displaystylec @= >displaystylec @+ >displaystylec @+ >displaystylec
sum_r=0^n+1 binomn+1r
& binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
& 1 & sumlimits_r=1^n binomn+1r & 1 \
& multicolumn3>displaystylel
2 + sum_r=1^nleft[binomnr + binomnr-1right]
endarray
]
enddocument
add a comment |
try
documentclassarticle
usepackagearray,amsmath
begindocument
[
beginarray>displaystylec @= >displaystylec @+ >displaystylec @+ >displaystylec
sum_r=0^n+1 binomn+1r
& binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
& 1 & sumlimits_r=1^n binomn+1r & 1 \
& multicolumn3>displaystylel
2 + sum_r=1^nleft[binomnr + binomnr-1right]
endarray
]
enddocument
add a comment |
try
documentclassarticle
usepackagearray,amsmath
begindocument
[
beginarray>displaystylec @= >displaystylec @+ >displaystylec @+ >displaystylec
sum_r=0^n+1 binomn+1r
& binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
& 1 & sumlimits_r=1^n binomn+1r & 1 \
& multicolumn3>displaystylel
2 + sum_r=1^nleft[binomnr + binomnr-1right]
endarray
]
enddocument
try
documentclassarticle
usepackagearray,amsmath
begindocument
[
beginarray>displaystylec @= >displaystylec @+ >displaystylec @+ >displaystylec
sum_r=0^n+1 binomn+1r
& binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
& 1 & sumlimits_r=1^n binomn+1r & 1 \
& multicolumn3>displaystylel
2 + sum_r=1^nleft[binomnr + binomnr-1right]
endarray
]
enddocument
answered 37 mins ago
ZarkoZarko
126k868165
126k868165
add a comment |
add a comment |
Use the [t]
option. Then you do not need to use multicolumn
many times if you have many subsequent lines.
documentclassarticle
usepackagearray,amsmath
begindocument
beginalign*
sumlimits_r=0^n+1 binomn+1r
&beginarray[t]@>displaystylec @=@>displaystylec @+ >displaystylec @+ >displaystylec
& binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
& 1 & sumlimits_r=1^n binomn+1r & 1 \
endarray\
&=2 + sum_r=1^nleft[binomnr + binomnr-1right]
endalign*
enddocument
I like this approach better but I see it misses the equals on the 2nd line.
– PGmath
27 mins ago
@PGmath Very good catch! My bad. I updated.
– marmot
24 mins ago
Thanks. Can you explain a little what[t]
does? I've never done much involved stuff with arrays before.
– PGmath
9 mins ago
@PGmath It aligns the array at the top.
– marmot
8 mins ago
add a comment |
Use the [t]
option. Then you do not need to use multicolumn
many times if you have many subsequent lines.
documentclassarticle
usepackagearray,amsmath
begindocument
beginalign*
sumlimits_r=0^n+1 binomn+1r
&beginarray[t]@>displaystylec @=@>displaystylec @+ >displaystylec @+ >displaystylec
& binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
& 1 & sumlimits_r=1^n binomn+1r & 1 \
endarray\
&=2 + sum_r=1^nleft[binomnr + binomnr-1right]
endalign*
enddocument
I like this approach better but I see it misses the equals on the 2nd line.
– PGmath
27 mins ago
@PGmath Very good catch! My bad. I updated.
– marmot
24 mins ago
Thanks. Can you explain a little what[t]
does? I've never done much involved stuff with arrays before.
– PGmath
9 mins ago
@PGmath It aligns the array at the top.
– marmot
8 mins ago
add a comment |
Use the [t]
option. Then you do not need to use multicolumn
many times if you have many subsequent lines.
documentclassarticle
usepackagearray,amsmath
begindocument
beginalign*
sumlimits_r=0^n+1 binomn+1r
&beginarray[t]@>displaystylec @=@>displaystylec @+ >displaystylec @+ >displaystylec
& binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
& 1 & sumlimits_r=1^n binomn+1r & 1 \
endarray\
&=2 + sum_r=1^nleft[binomnr + binomnr-1right]
endalign*
enddocument
Use the [t]
option. Then you do not need to use multicolumn
many times if you have many subsequent lines.
documentclassarticle
usepackagearray,amsmath
begindocument
beginalign*
sumlimits_r=0^n+1 binomn+1r
&beginarray[t]@>displaystylec @=@>displaystylec @+ >displaystylec @+ >displaystylec
& binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
& 1 & sumlimits_r=1^n binomn+1r & 1 \
endarray\
&=2 + sum_r=1^nleft[binomnr + binomnr-1right]
endalign*
enddocument
edited 24 mins ago
answered 31 mins ago
marmotmarmot
107k5129243
107k5129243
I like this approach better but I see it misses the equals on the 2nd line.
– PGmath
27 mins ago
@PGmath Very good catch! My bad. I updated.
– marmot
24 mins ago
Thanks. Can you explain a little what[t]
does? I've never done much involved stuff with arrays before.
– PGmath
9 mins ago
@PGmath It aligns the array at the top.
– marmot
8 mins ago
add a comment |
I like this approach better but I see it misses the equals on the 2nd line.
– PGmath
27 mins ago
@PGmath Very good catch! My bad. I updated.
– marmot
24 mins ago
Thanks. Can you explain a little what[t]
does? I've never done much involved stuff with arrays before.
– PGmath
9 mins ago
@PGmath It aligns the array at the top.
– marmot
8 mins ago
I like this approach better but I see it misses the equals on the 2nd line.
– PGmath
27 mins ago
I like this approach better but I see it misses the equals on the 2nd line.
– PGmath
27 mins ago
@PGmath Very good catch! My bad. I updated.
– marmot
24 mins ago
@PGmath Very good catch! My bad. I updated.
– marmot
24 mins ago
Thanks. Can you explain a little what
[t]
does? I've never done much involved stuff with arrays before.– PGmath
9 mins ago
Thanks. Can you explain a little what
[t]
does? I've never done much involved stuff with arrays before.– PGmath
9 mins ago
@PGmath It aligns the array at the top.
– marmot
8 mins ago
@PGmath It aligns the array at the top.
– marmot
8 mins ago
add a comment |
eqparbox
allows you to store the lengths of boxes via a <tag>
. Boxes with the same <tag>
are set with the maximum width across all content. Below I use this approach with a newly-defined eqmathbox[<tag>][<align>]
(default for <align>
is to c
entre the content) to add content to three different <tag>
ged boxes:
documentclassarticle
usepackageeqparbox,xparse,amsmath
% https://tex.stackexchange.com/a/34412/5764
makeatletter
NewDocumentCommandeqmathboxo Oc m%
IfValueTF#1
defeqmathbox@##1##2eqmakebox[#1][#2]$##1##2$
defeqmathbox@##1##2eqmakebox$##1##2$
mathpaletteeqmathbox@#3
makeatother
begindocument
beginalign*
sum_r = 0^n + 1 binomn + 1r
&= eqmathbox[LEFT]binomn + 10 + eqmathbox[CENTRE]binomn + 11 + dots + binomn + 1n + eqmathbox[RIGHT]binomn + 1n + 1 \
&= eqmathbox[LEFT]1 + eqmathbox[CENTRE]sum_r = 1^n binomn + 1r + eqmathbox[RIGHT]1 \
&= 2 + sum_r = 1^n biggl[ binomnr + binomnr - 1 biggr]
endalign*
enddocument
Since eqparbox
uses TeX's label
-ref
system, you need to compile twice for every change in the content of the maximum width.
add a comment |
eqparbox
allows you to store the lengths of boxes via a <tag>
. Boxes with the same <tag>
are set with the maximum width across all content. Below I use this approach with a newly-defined eqmathbox[<tag>][<align>]
(default for <align>
is to c
entre the content) to add content to three different <tag>
ged boxes:
documentclassarticle
usepackageeqparbox,xparse,amsmath
% https://tex.stackexchange.com/a/34412/5764
makeatletter
NewDocumentCommandeqmathboxo Oc m%
IfValueTF#1
defeqmathbox@##1##2eqmakebox[#1][#2]$##1##2$
defeqmathbox@##1##2eqmakebox$##1##2$
mathpaletteeqmathbox@#3
makeatother
begindocument
beginalign*
sum_r = 0^n + 1 binomn + 1r
&= eqmathbox[LEFT]binomn + 10 + eqmathbox[CENTRE]binomn + 11 + dots + binomn + 1n + eqmathbox[RIGHT]binomn + 1n + 1 \
&= eqmathbox[LEFT]1 + eqmathbox[CENTRE]sum_r = 1^n binomn + 1r + eqmathbox[RIGHT]1 \
&= 2 + sum_r = 1^n biggl[ binomnr + binomnr - 1 biggr]
endalign*
enddocument
Since eqparbox
uses TeX's label
-ref
system, you need to compile twice for every change in the content of the maximum width.
add a comment |
eqparbox
allows you to store the lengths of boxes via a <tag>
. Boxes with the same <tag>
are set with the maximum width across all content. Below I use this approach with a newly-defined eqmathbox[<tag>][<align>]
(default for <align>
is to c
entre the content) to add content to three different <tag>
ged boxes:
documentclassarticle
usepackageeqparbox,xparse,amsmath
% https://tex.stackexchange.com/a/34412/5764
makeatletter
NewDocumentCommandeqmathboxo Oc m%
IfValueTF#1
defeqmathbox@##1##2eqmakebox[#1][#2]$##1##2$
defeqmathbox@##1##2eqmakebox$##1##2$
mathpaletteeqmathbox@#3
makeatother
begindocument
beginalign*
sum_r = 0^n + 1 binomn + 1r
&= eqmathbox[LEFT]binomn + 10 + eqmathbox[CENTRE]binomn + 11 + dots + binomn + 1n + eqmathbox[RIGHT]binomn + 1n + 1 \
&= eqmathbox[LEFT]1 + eqmathbox[CENTRE]sum_r = 1^n binomn + 1r + eqmathbox[RIGHT]1 \
&= 2 + sum_r = 1^n biggl[ binomnr + binomnr - 1 biggr]
endalign*
enddocument
Since eqparbox
uses TeX's label
-ref
system, you need to compile twice for every change in the content of the maximum width.
eqparbox
allows you to store the lengths of boxes via a <tag>
. Boxes with the same <tag>
are set with the maximum width across all content. Below I use this approach with a newly-defined eqmathbox[<tag>][<align>]
(default for <align>
is to c
entre the content) to add content to three different <tag>
ged boxes:
documentclassarticle
usepackageeqparbox,xparse,amsmath
% https://tex.stackexchange.com/a/34412/5764
makeatletter
NewDocumentCommandeqmathboxo Oc m%
IfValueTF#1
defeqmathbox@##1##2eqmakebox[#1][#2]$##1##2$
defeqmathbox@##1##2eqmakebox$##1##2$
mathpaletteeqmathbox@#3
makeatother
begindocument
beginalign*
sum_r = 0^n + 1 binomn + 1r
&= eqmathbox[LEFT]binomn + 10 + eqmathbox[CENTRE]binomn + 11 + dots + binomn + 1n + eqmathbox[RIGHT]binomn + 1n + 1 \
&= eqmathbox[LEFT]1 + eqmathbox[CENTRE]sum_r = 1^n binomn + 1r + eqmathbox[RIGHT]1 \
&= 2 + sum_r = 1^n biggl[ binomnr + binomnr - 1 biggr]
endalign*
enddocument
Since eqparbox
uses TeX's label
-ref
system, you need to compile twice for every change in the content of the maximum width.
edited 12 mins ago
answered 24 mins ago
WernerWerner
446k699871692
446k699871692
add a comment |
add a comment |
PGmath is a new contributor. Be nice, and check out our Code of Conduct.
PGmath is a new contributor. Be nice, and check out our Code of Conduct.
PGmath is a new contributor. Be nice, and check out our Code of Conduct.
PGmath is a new contributor. Be nice, and check out our Code of Conduct.
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