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Exempt portion of equation line from aligning?


The mysteries of mathpaletteAligning plain `align` and `cases`?Alignment across nested aligned environmentsHow to match left alignment of equations in math mode outside and inside an array?How to modify eqnarray?Alignment of two equations on LaTeXHow center align two equations separated by a lineequation custom horizontal alignment & numbering each rowFlushed-left and flushed-right text in align or alignat environmentHow can I align this equation in the center?breqn not aligning first two lines













4















I am using an array environment to get aligned portions of a series of equations to center (instead of left-justify), as shown below:



usepackagearray,amsmath
[
beginarray>displaystylec @= >displaystylec @+ >displaystylec @+ >displaystylec
sumlimits_r=0^n+1 binomn+1r & binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
& 1 & sumlimits_r=1^n binomn+1r & 1 \
endarray
]


eqn1



The array environment (I believe) is necessary here to get each of the columns to center instead of justifying left.



Now my problem is that these two lines are part of a greater series of equations, where the others do not follow this pattern to be aligned. However, I need the equals signs to line up across all lines.



My current approach is follow the array with a normal align environment, having one equation line mirroring the longest line above but enclosed in phantom to get the align spacing right. But this leaves a single empty line with an equals in it.



...

beginalign*
&= 2 + sum_r=1^nleft[binomnr + binomnr-1right] \
phantomsumlimits_r=0^n+1 binomn+1r &= phantom binomn+10 + binomn+11 + ldots + binomn+1n + binomn+1n+1
endalign*


eqn2



How can I get this result, but without the extraneous equals line at the end? Preferable a more elegant one, as this idea relies on several iffy factors such as none of the following equations exceeding the size of the one governing the special alignment.










share|improve this question







New contributor




PGmath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
























    4















    I am using an array environment to get aligned portions of a series of equations to center (instead of left-justify), as shown below:



    usepackagearray,amsmath
    [
    beginarray>displaystylec @= >displaystylec @+ >displaystylec @+ >displaystylec
    sumlimits_r=0^n+1 binomn+1r & binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
    & 1 & sumlimits_r=1^n binomn+1r & 1 \
    endarray
    ]


    eqn1



    The array environment (I believe) is necessary here to get each of the columns to center instead of justifying left.



    Now my problem is that these two lines are part of a greater series of equations, where the others do not follow this pattern to be aligned. However, I need the equals signs to line up across all lines.



    My current approach is follow the array with a normal align environment, having one equation line mirroring the longest line above but enclosed in phantom to get the align spacing right. But this leaves a single empty line with an equals in it.



    ...

    beginalign*
    &= 2 + sum_r=1^nleft[binomnr + binomnr-1right] \
    phantomsumlimits_r=0^n+1 binomn+1r &= phantom binomn+10 + binomn+11 + ldots + binomn+1n + binomn+1n+1
    endalign*


    eqn2



    How can I get this result, but without the extraneous equals line at the end? Preferable a more elegant one, as this idea relies on several iffy factors such as none of the following equations exceeding the size of the one governing the special alignment.










    share|improve this question







    New contributor




    PGmath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






















      4












      4








      4








      I am using an array environment to get aligned portions of a series of equations to center (instead of left-justify), as shown below:



      usepackagearray,amsmath
      [
      beginarray>displaystylec @= >displaystylec @+ >displaystylec @+ >displaystylec
      sumlimits_r=0^n+1 binomn+1r & binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
      & 1 & sumlimits_r=1^n binomn+1r & 1 \
      endarray
      ]


      eqn1



      The array environment (I believe) is necessary here to get each of the columns to center instead of justifying left.



      Now my problem is that these two lines are part of a greater series of equations, where the others do not follow this pattern to be aligned. However, I need the equals signs to line up across all lines.



      My current approach is follow the array with a normal align environment, having one equation line mirroring the longest line above but enclosed in phantom to get the align spacing right. But this leaves a single empty line with an equals in it.



      ...

      beginalign*
      &= 2 + sum_r=1^nleft[binomnr + binomnr-1right] \
      phantomsumlimits_r=0^n+1 binomn+1r &= phantom binomn+10 + binomn+11 + ldots + binomn+1n + binomn+1n+1
      endalign*


      eqn2



      How can I get this result, but without the extraneous equals line at the end? Preferable a more elegant one, as this idea relies on several iffy factors such as none of the following equations exceeding the size of the one governing the special alignment.










      share|improve this question







      New contributor




      PGmath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      I am using an array environment to get aligned portions of a series of equations to center (instead of left-justify), as shown below:



      usepackagearray,amsmath
      [
      beginarray>displaystylec @= >displaystylec @+ >displaystylec @+ >displaystylec
      sumlimits_r=0^n+1 binomn+1r & binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
      & 1 & sumlimits_r=1^n binomn+1r & 1 \
      endarray
      ]


      eqn1



      The array environment (I believe) is necessary here to get each of the columns to center instead of justifying left.



      Now my problem is that these two lines are part of a greater series of equations, where the others do not follow this pattern to be aligned. However, I need the equals signs to line up across all lines.



      My current approach is follow the array with a normal align environment, having one equation line mirroring the longest line above but enclosed in phantom to get the align spacing right. But this leaves a single empty line with an equals in it.



      ...

      beginalign*
      &= 2 + sum_r=1^nleft[binomnr + binomnr-1right] \
      phantomsumlimits_r=0^n+1 binomn+1r &= phantom binomn+10 + binomn+11 + ldots + binomn+1n + binomn+1n+1
      endalign*


      eqn2



      How can I get this result, but without the extraneous equals line at the end? Preferable a more elegant one, as this idea relies on several iffy factors such as none of the following equations exceeding the size of the one governing the special alignment.







      math-mode horizontal-alignment align arrays






      share|improve this question







      New contributor




      PGmath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question







      New contributor




      PGmath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question






      New contributor




      PGmath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 48 mins ago









      PGmathPGmath

      1212




      1212




      New contributor




      PGmath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      PGmath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      PGmath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.




















          3 Answers
          3






          active

          oldest

          votes


















          2














          try



          documentclassarticle
          usepackagearray,amsmath
          begindocument
          [
          beginarray>displaystylec @= >displaystylec @+ >displaystylec @+ >displaystylec
          sum_r=0^n+1 binomn+1r
          & binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
          & 1 & sumlimits_r=1^n binomn+1r & 1 \
          & multicolumn3>displaystylel
          2 + sum_r=1^nleft[binomnr + binomnr-1right]

          endarray
          ]
          enddocument


          enter image description here






          share|improve this answer






























            2














            Use the [t] option. Then you do not need to use multicolumn many times if you have many subsequent lines.



            documentclassarticle
            usepackagearray,amsmath
            begindocument
            beginalign*
            sumlimits_r=0^n+1 binomn+1r
            &beginarray[t]@>displaystylec @=@>displaystylec @+ >displaystylec @+ >displaystylec
            & binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
            & 1 & sumlimits_r=1^n binomn+1r & 1 \
            endarray\
            &=2 + sum_r=1^nleft[binomnr + binomnr-1right]
            endalign*
            enddocument


            enter image description here






            share|improve this answer

























            • I like this approach better but I see it misses the equals on the 2nd line.

              – PGmath
              27 mins ago












            • @PGmath Very good catch! My bad. I updated.

              – marmot
              24 mins ago











            • Thanks. Can you explain a little what [t] does? I've never done much involved stuff with arrays before.

              – PGmath
              9 mins ago











            • @PGmath It aligns the array at the top.

              – marmot
              8 mins ago


















            2














            eqparbox allows you to store the lengths of boxes via a <tag>. Boxes with the same <tag> are set with the maximum width across all content. Below I use this approach with a newly-defined eqmathbox[<tag>][<align>] (default for <align> is to centre the content) to add content to three different <tag>ged boxes:



            enter image description here



            documentclassarticle

            usepackageeqparbox,xparse,amsmath

            % https://tex.stackexchange.com/a/34412/5764
            makeatletter
            NewDocumentCommandeqmathboxo Oc m%
            IfValueTF#1
            defeqmathbox@##1##2eqmakebox[#1][#2]$##1##2$
            defeqmathbox@##1##2eqmakebox$##1##2$
            mathpaletteeqmathbox@#3

            makeatother

            begindocument

            beginalign*
            sum_r = 0^n + 1 binomn + 1r
            &= eqmathbox[LEFT]binomn + 10 + eqmathbox[CENTRE]binomn + 11 + dots + binomn + 1n + eqmathbox[RIGHT]binomn + 1n + 1 \
            &= eqmathbox[LEFT]1 + eqmathbox[CENTRE]sum_r = 1^n binomn + 1r + eqmathbox[RIGHT]1 \
            &= 2 + sum_r = 1^n biggl[ binomnr + binomnr - 1 biggr]
            endalign*

            enddocument


            Since eqparbox uses TeX's label-ref system, you need to compile twice for every change in the content of the maximum width.






            share|improve this answer
























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              3 Answers
              3






              active

              oldest

              votes








              3 Answers
              3






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              2














              try



              documentclassarticle
              usepackagearray,amsmath
              begindocument
              [
              beginarray>displaystylec @= >displaystylec @+ >displaystylec @+ >displaystylec
              sum_r=0^n+1 binomn+1r
              & binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
              & 1 & sumlimits_r=1^n binomn+1r & 1 \
              & multicolumn3>displaystylel
              2 + sum_r=1^nleft[binomnr + binomnr-1right]

              endarray
              ]
              enddocument


              enter image description here






              share|improve this answer



























                2














                try



                documentclassarticle
                usepackagearray,amsmath
                begindocument
                [
                beginarray>displaystylec @= >displaystylec @+ >displaystylec @+ >displaystylec
                sum_r=0^n+1 binomn+1r
                & binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
                & 1 & sumlimits_r=1^n binomn+1r & 1 \
                & multicolumn3>displaystylel
                2 + sum_r=1^nleft[binomnr + binomnr-1right]

                endarray
                ]
                enddocument


                enter image description here






                share|improve this answer

























                  2












                  2








                  2







                  try



                  documentclassarticle
                  usepackagearray,amsmath
                  begindocument
                  [
                  beginarray>displaystylec @= >displaystylec @+ >displaystylec @+ >displaystylec
                  sum_r=0^n+1 binomn+1r
                  & binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
                  & 1 & sumlimits_r=1^n binomn+1r & 1 \
                  & multicolumn3>displaystylel
                  2 + sum_r=1^nleft[binomnr + binomnr-1right]

                  endarray
                  ]
                  enddocument


                  enter image description here






                  share|improve this answer













                  try



                  documentclassarticle
                  usepackagearray,amsmath
                  begindocument
                  [
                  beginarray>displaystylec @= >displaystylec @+ >displaystylec @+ >displaystylec
                  sum_r=0^n+1 binomn+1r
                  & binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
                  & 1 & sumlimits_r=1^n binomn+1r & 1 \
                  & multicolumn3>displaystylel
                  2 + sum_r=1^nleft[binomnr + binomnr-1right]

                  endarray
                  ]
                  enddocument


                  enter image description here







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 37 mins ago









                  ZarkoZarko

                  126k868165




                  126k868165





















                      2














                      Use the [t] option. Then you do not need to use multicolumn many times if you have many subsequent lines.



                      documentclassarticle
                      usepackagearray,amsmath
                      begindocument
                      beginalign*
                      sumlimits_r=0^n+1 binomn+1r
                      &beginarray[t]@>displaystylec @=@>displaystylec @+ >displaystylec @+ >displaystylec
                      & binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
                      & 1 & sumlimits_r=1^n binomn+1r & 1 \
                      endarray\
                      &=2 + sum_r=1^nleft[binomnr + binomnr-1right]
                      endalign*
                      enddocument


                      enter image description here






                      share|improve this answer

























                      • I like this approach better but I see it misses the equals on the 2nd line.

                        – PGmath
                        27 mins ago












                      • @PGmath Very good catch! My bad. I updated.

                        – marmot
                        24 mins ago











                      • Thanks. Can you explain a little what [t] does? I've never done much involved stuff with arrays before.

                        – PGmath
                        9 mins ago











                      • @PGmath It aligns the array at the top.

                        – marmot
                        8 mins ago















                      2














                      Use the [t] option. Then you do not need to use multicolumn many times if you have many subsequent lines.



                      documentclassarticle
                      usepackagearray,amsmath
                      begindocument
                      beginalign*
                      sumlimits_r=0^n+1 binomn+1r
                      &beginarray[t]@>displaystylec @=@>displaystylec @+ >displaystylec @+ >displaystylec
                      & binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
                      & 1 & sumlimits_r=1^n binomn+1r & 1 \
                      endarray\
                      &=2 + sum_r=1^nleft[binomnr + binomnr-1right]
                      endalign*
                      enddocument


                      enter image description here






                      share|improve this answer

























                      • I like this approach better but I see it misses the equals on the 2nd line.

                        – PGmath
                        27 mins ago












                      • @PGmath Very good catch! My bad. I updated.

                        – marmot
                        24 mins ago











                      • Thanks. Can you explain a little what [t] does? I've never done much involved stuff with arrays before.

                        – PGmath
                        9 mins ago











                      • @PGmath It aligns the array at the top.

                        – marmot
                        8 mins ago













                      2












                      2








                      2







                      Use the [t] option. Then you do not need to use multicolumn many times if you have many subsequent lines.



                      documentclassarticle
                      usepackagearray,amsmath
                      begindocument
                      beginalign*
                      sumlimits_r=0^n+1 binomn+1r
                      &beginarray[t]@>displaystylec @=@>displaystylec @+ >displaystylec @+ >displaystylec
                      & binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
                      & 1 & sumlimits_r=1^n binomn+1r & 1 \
                      endarray\
                      &=2 + sum_r=1^nleft[binomnr + binomnr-1right]
                      endalign*
                      enddocument


                      enter image description here






                      share|improve this answer















                      Use the [t] option. Then you do not need to use multicolumn many times if you have many subsequent lines.



                      documentclassarticle
                      usepackagearray,amsmath
                      begindocument
                      beginalign*
                      sumlimits_r=0^n+1 binomn+1r
                      &beginarray[t]@>displaystylec @=@>displaystylec @+ >displaystylec @+ >displaystylec
                      & binomn+10 & binomn+11 + ldots + binomn+1n & binomn+1n+1 \
                      & 1 & sumlimits_r=1^n binomn+1r & 1 \
                      endarray\
                      &=2 + sum_r=1^nleft[binomnr + binomnr-1right]
                      endalign*
                      enddocument


                      enter image description here







                      share|improve this answer














                      share|improve this answer



                      share|improve this answer








                      edited 24 mins ago

























                      answered 31 mins ago









                      marmotmarmot

                      107k5129243




                      107k5129243












                      • I like this approach better but I see it misses the equals on the 2nd line.

                        – PGmath
                        27 mins ago












                      • @PGmath Very good catch! My bad. I updated.

                        – marmot
                        24 mins ago











                      • Thanks. Can you explain a little what [t] does? I've never done much involved stuff with arrays before.

                        – PGmath
                        9 mins ago











                      • @PGmath It aligns the array at the top.

                        – marmot
                        8 mins ago

















                      • I like this approach better but I see it misses the equals on the 2nd line.

                        – PGmath
                        27 mins ago












                      • @PGmath Very good catch! My bad. I updated.

                        – marmot
                        24 mins ago











                      • Thanks. Can you explain a little what [t] does? I've never done much involved stuff with arrays before.

                        – PGmath
                        9 mins ago











                      • @PGmath It aligns the array at the top.

                        – marmot
                        8 mins ago
















                      I like this approach better but I see it misses the equals on the 2nd line.

                      – PGmath
                      27 mins ago






                      I like this approach better but I see it misses the equals on the 2nd line.

                      – PGmath
                      27 mins ago














                      @PGmath Very good catch! My bad. I updated.

                      – marmot
                      24 mins ago





                      @PGmath Very good catch! My bad. I updated.

                      – marmot
                      24 mins ago













                      Thanks. Can you explain a little what [t] does? I've never done much involved stuff with arrays before.

                      – PGmath
                      9 mins ago





                      Thanks. Can you explain a little what [t] does? I've never done much involved stuff with arrays before.

                      – PGmath
                      9 mins ago













                      @PGmath It aligns the array at the top.

                      – marmot
                      8 mins ago





                      @PGmath It aligns the array at the top.

                      – marmot
                      8 mins ago











                      2














                      eqparbox allows you to store the lengths of boxes via a <tag>. Boxes with the same <tag> are set with the maximum width across all content. Below I use this approach with a newly-defined eqmathbox[<tag>][<align>] (default for <align> is to centre the content) to add content to three different <tag>ged boxes:



                      enter image description here



                      documentclassarticle

                      usepackageeqparbox,xparse,amsmath

                      % https://tex.stackexchange.com/a/34412/5764
                      makeatletter
                      NewDocumentCommandeqmathboxo Oc m%
                      IfValueTF#1
                      defeqmathbox@##1##2eqmakebox[#1][#2]$##1##2$
                      defeqmathbox@##1##2eqmakebox$##1##2$
                      mathpaletteeqmathbox@#3

                      makeatother

                      begindocument

                      beginalign*
                      sum_r = 0^n + 1 binomn + 1r
                      &= eqmathbox[LEFT]binomn + 10 + eqmathbox[CENTRE]binomn + 11 + dots + binomn + 1n + eqmathbox[RIGHT]binomn + 1n + 1 \
                      &= eqmathbox[LEFT]1 + eqmathbox[CENTRE]sum_r = 1^n binomn + 1r + eqmathbox[RIGHT]1 \
                      &= 2 + sum_r = 1^n biggl[ binomnr + binomnr - 1 biggr]
                      endalign*

                      enddocument


                      Since eqparbox uses TeX's label-ref system, you need to compile twice for every change in the content of the maximum width.






                      share|improve this answer





























                        2














                        eqparbox allows you to store the lengths of boxes via a <tag>. Boxes with the same <tag> are set with the maximum width across all content. Below I use this approach with a newly-defined eqmathbox[<tag>][<align>] (default for <align> is to centre the content) to add content to three different <tag>ged boxes:



                        enter image description here



                        documentclassarticle

                        usepackageeqparbox,xparse,amsmath

                        % https://tex.stackexchange.com/a/34412/5764
                        makeatletter
                        NewDocumentCommandeqmathboxo Oc m%
                        IfValueTF#1
                        defeqmathbox@##1##2eqmakebox[#1][#2]$##1##2$
                        defeqmathbox@##1##2eqmakebox$##1##2$
                        mathpaletteeqmathbox@#3

                        makeatother

                        begindocument

                        beginalign*
                        sum_r = 0^n + 1 binomn + 1r
                        &= eqmathbox[LEFT]binomn + 10 + eqmathbox[CENTRE]binomn + 11 + dots + binomn + 1n + eqmathbox[RIGHT]binomn + 1n + 1 \
                        &= eqmathbox[LEFT]1 + eqmathbox[CENTRE]sum_r = 1^n binomn + 1r + eqmathbox[RIGHT]1 \
                        &= 2 + sum_r = 1^n biggl[ binomnr + binomnr - 1 biggr]
                        endalign*

                        enddocument


                        Since eqparbox uses TeX's label-ref system, you need to compile twice for every change in the content of the maximum width.






                        share|improve this answer



























                          2












                          2








                          2







                          eqparbox allows you to store the lengths of boxes via a <tag>. Boxes with the same <tag> are set with the maximum width across all content. Below I use this approach with a newly-defined eqmathbox[<tag>][<align>] (default for <align> is to centre the content) to add content to three different <tag>ged boxes:



                          enter image description here



                          documentclassarticle

                          usepackageeqparbox,xparse,amsmath

                          % https://tex.stackexchange.com/a/34412/5764
                          makeatletter
                          NewDocumentCommandeqmathboxo Oc m%
                          IfValueTF#1
                          defeqmathbox@##1##2eqmakebox[#1][#2]$##1##2$
                          defeqmathbox@##1##2eqmakebox$##1##2$
                          mathpaletteeqmathbox@#3

                          makeatother

                          begindocument

                          beginalign*
                          sum_r = 0^n + 1 binomn + 1r
                          &= eqmathbox[LEFT]binomn + 10 + eqmathbox[CENTRE]binomn + 11 + dots + binomn + 1n + eqmathbox[RIGHT]binomn + 1n + 1 \
                          &= eqmathbox[LEFT]1 + eqmathbox[CENTRE]sum_r = 1^n binomn + 1r + eqmathbox[RIGHT]1 \
                          &= 2 + sum_r = 1^n biggl[ binomnr + binomnr - 1 biggr]
                          endalign*

                          enddocument


                          Since eqparbox uses TeX's label-ref system, you need to compile twice for every change in the content of the maximum width.






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                          eqparbox allows you to store the lengths of boxes via a <tag>. Boxes with the same <tag> are set with the maximum width across all content. Below I use this approach with a newly-defined eqmathbox[<tag>][<align>] (default for <align> is to centre the content) to add content to three different <tag>ged boxes:



                          enter image description here



                          documentclassarticle

                          usepackageeqparbox,xparse,amsmath

                          % https://tex.stackexchange.com/a/34412/5764
                          makeatletter
                          NewDocumentCommandeqmathboxo Oc m%
                          IfValueTF#1
                          defeqmathbox@##1##2eqmakebox[#1][#2]$##1##2$
                          defeqmathbox@##1##2eqmakebox$##1##2$
                          mathpaletteeqmathbox@#3

                          makeatother

                          begindocument

                          beginalign*
                          sum_r = 0^n + 1 binomn + 1r
                          &= eqmathbox[LEFT]binomn + 10 + eqmathbox[CENTRE]binomn + 11 + dots + binomn + 1n + eqmathbox[RIGHT]binomn + 1n + 1 \
                          &= eqmathbox[LEFT]1 + eqmathbox[CENTRE]sum_r = 1^n binomn + 1r + eqmathbox[RIGHT]1 \
                          &= 2 + sum_r = 1^n biggl[ binomnr + binomnr - 1 biggr]
                          endalign*

                          enddocument


                          Since eqparbox uses TeX's label-ref system, you need to compile twice for every change in the content of the maximum width.







                          share|improve this answer














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                          edited 12 mins ago

























                          answered 24 mins ago









                          WernerWerner

                          446k699871692




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