Automorphism group of a finite group [closed] Announcing the arrival of Valued Associate #679:...

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Automorphism group of a finite group [closed]



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Automorphism group of alternating group.Automorphism TowerAutomorphism group of the general affine group of the affine line over a finite field?Groups which can not occur as automorphism group of a groupCan the Cayley Graph of a group have an automorphism that cyclically permutes all nodes?Automorphism Groups of Finite FieldsOuter automorphism groups of finite groupsA group $G$ whose automorphism group contains a subgroup isomorphic to $G$Can groups of automorphism over non-isomorphic groups be isomorphic?Solvability of the (outer) automorphism group of a central product












5












$begingroup$


For which finite groups $G$ is $operatorname{Aut}(G)$ isomorphic to a (non necessarily strict) subgroup of $G$?










share|cite|improve this question









$endgroup$



closed as off-topic by Shaun, Cesareo, clathratus, Lee David Chung Lin, Eevee Trainer Mar 27 at 4:21


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Shaun, Cesareo, clathratus, Lee David Chung Lin, Eevee Trainer

If this question can be reworded to fit the rules in the help center, please edit the question.
















  • $begingroup$
    Do you known any interesting examples?
    $endgroup$
    – lhf
    Mar 24 at 23:05






  • 1




    $begingroup$
    $Aut(C_{2})$ is trivial, $Aut(S_{3})cong S_{3}$.
    $endgroup$
    – Sylvain Julien
    Mar 25 at 6:02
















5












$begingroup$


For which finite groups $G$ is $operatorname{Aut}(G)$ isomorphic to a (non necessarily strict) subgroup of $G$?










share|cite|improve this question









$endgroup$



closed as off-topic by Shaun, Cesareo, clathratus, Lee David Chung Lin, Eevee Trainer Mar 27 at 4:21


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Shaun, Cesareo, clathratus, Lee David Chung Lin, Eevee Trainer

If this question can be reworded to fit the rules in the help center, please edit the question.
















  • $begingroup$
    Do you known any interesting examples?
    $endgroup$
    – lhf
    Mar 24 at 23:05






  • 1




    $begingroup$
    $Aut(C_{2})$ is trivial, $Aut(S_{3})cong S_{3}$.
    $endgroup$
    – Sylvain Julien
    Mar 25 at 6:02














5












5








5


1



$begingroup$


For which finite groups $G$ is $operatorname{Aut}(G)$ isomorphic to a (non necessarily strict) subgroup of $G$?










share|cite|improve this question









$endgroup$




For which finite groups $G$ is $operatorname{Aut}(G)$ isomorphic to a (non necessarily strict) subgroup of $G$?







finite-groups automorphism-group






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 24 at 20:38









Sylvain JulienSylvain Julien

1,154918




1,154918




closed as off-topic by Shaun, Cesareo, clathratus, Lee David Chung Lin, Eevee Trainer Mar 27 at 4:21


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Shaun, Cesareo, clathratus, Lee David Chung Lin, Eevee Trainer

If this question can be reworded to fit the rules in the help center, please edit the question.







closed as off-topic by Shaun, Cesareo, clathratus, Lee David Chung Lin, Eevee Trainer Mar 27 at 4:21


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Shaun, Cesareo, clathratus, Lee David Chung Lin, Eevee Trainer

If this question can be reworded to fit the rules in the help center, please edit the question.












  • $begingroup$
    Do you known any interesting examples?
    $endgroup$
    – lhf
    Mar 24 at 23:05






  • 1




    $begingroup$
    $Aut(C_{2})$ is trivial, $Aut(S_{3})cong S_{3}$.
    $endgroup$
    – Sylvain Julien
    Mar 25 at 6:02


















  • $begingroup$
    Do you known any interesting examples?
    $endgroup$
    – lhf
    Mar 24 at 23:05






  • 1




    $begingroup$
    $Aut(C_{2})$ is trivial, $Aut(S_{3})cong S_{3}$.
    $endgroup$
    – Sylvain Julien
    Mar 25 at 6:02
















$begingroup$
Do you known any interesting examples?
$endgroup$
– lhf
Mar 24 at 23:05




$begingroup$
Do you known any interesting examples?
$endgroup$
– lhf
Mar 24 at 23:05




1




1




$begingroup$
$Aut(C_{2})$ is trivial, $Aut(S_{3})cong S_{3}$.
$endgroup$
– Sylvain Julien
Mar 25 at 6:02




$begingroup$
$Aut(C_{2})$ is trivial, $Aut(S_{3})cong S_{3}$.
$endgroup$
– Sylvain Julien
Mar 25 at 6:02










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