Why is this set uncountable [closed] Announcing the arrival of Valued Associate #679: Cesar...
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Why is this set uncountable [closed]
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Non-trivial examples of operations.MacNeille completion of a totally ordered set: Dedekind cutsWhat is this question asking?Properties of set $mathrm {orb} (x)$Is the ring and semi-ring definition of algebra and set linked?Proof Check in AlgebraAssociated primes of a non-zero module always exist if corresponding ring is NoetherianSet of all subrings of $mathbb{Q}$ are uncountable.For any sets $X$ & $Y$ can the group of automorphisms for the digraph $G(X,Y)=(Xcup Y,Xtimes Y)$ be express in terms of symmetric groups?Is $Set$ a subcategory of $Grp$?
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I have an uncountable family $(Omega_i)_{i in L}$ of non empty sets such that
$$
forall i,jin L, ineq j, Omega_icap Omega_j=emptyset$$
and there exists a non empty set $F$ such that $forall iin L,Fcap Omega_i=emptyset.$
How to prove that $bigcup_{iin L} (Fcup Omega_i)$ is uncountable?
thanks
abstract-algebra
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closed as off-topic by YiFan, Cesareo, Lee David Chung Lin, dantopa, John Omielan Mar 25 at 4:44
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – YiFan, Cesareo, Lee David Chung Lin, dantopa, John Omielan
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
$begingroup$
I have an uncountable family $(Omega_i)_{i in L}$ of non empty sets such that
$$
forall i,jin L, ineq j, Omega_icap Omega_j=emptyset$$
and there exists a non empty set $F$ such that $forall iin L,Fcap Omega_i=emptyset.$
How to prove that $bigcup_{iin L} (Fcup Omega_i)$ is uncountable?
thanks
abstract-algebra
$endgroup$
closed as off-topic by YiFan, Cesareo, Lee David Chung Lin, dantopa, John Omielan Mar 25 at 4:44
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – YiFan, Cesareo, Lee David Chung Lin, dantopa, John Omielan
If this question can be reworded to fit the rules in the help center, please edit the question.
$begingroup$
Note: $cup_{iin L} (Fcup Omega_i) supseteq cup_{iin L} Omega_i$
$endgroup$
– JavaMan
Mar 24 at 19:23
5
$begingroup$
What happens if $Omega_i = emptyset$ for all $i in L$?
$endgroup$
– Fabio Somenzi
Mar 24 at 19:26
add a comment |
$begingroup$
I have an uncountable family $(Omega_i)_{i in L}$ of non empty sets such that
$$
forall i,jin L, ineq j, Omega_icap Omega_j=emptyset$$
and there exists a non empty set $F$ such that $forall iin L,Fcap Omega_i=emptyset.$
How to prove that $bigcup_{iin L} (Fcup Omega_i)$ is uncountable?
thanks
abstract-algebra
$endgroup$
I have an uncountable family $(Omega_i)_{i in L}$ of non empty sets such that
$$
forall i,jin L, ineq j, Omega_icap Omega_j=emptyset$$
and there exists a non empty set $F$ such that $forall iin L,Fcap Omega_i=emptyset.$
How to prove that $bigcup_{iin L} (Fcup Omega_i)$ is uncountable?
thanks
abstract-algebra
abstract-algebra
edited Mar 25 at 22:03
Poline Sandra
1208
1208
asked Mar 24 at 19:17
VrouvrouVrouvrou
1,9251822
1,9251822
closed as off-topic by YiFan, Cesareo, Lee David Chung Lin, dantopa, John Omielan Mar 25 at 4:44
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – YiFan, Cesareo, Lee David Chung Lin, dantopa, John Omielan
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by YiFan, Cesareo, Lee David Chung Lin, dantopa, John Omielan Mar 25 at 4:44
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – YiFan, Cesareo, Lee David Chung Lin, dantopa, John Omielan
If this question can be reworded to fit the rules in the help center, please edit the question.
$begingroup$
Note: $cup_{iin L} (Fcup Omega_i) supseteq cup_{iin L} Omega_i$
$endgroup$
– JavaMan
Mar 24 at 19:23
5
$begingroup$
What happens if $Omega_i = emptyset$ for all $i in L$?
$endgroup$
– Fabio Somenzi
Mar 24 at 19:26
add a comment |
$begingroup$
Note: $cup_{iin L} (Fcup Omega_i) supseteq cup_{iin L} Omega_i$
$endgroup$
– JavaMan
Mar 24 at 19:23
5
$begingroup$
What happens if $Omega_i = emptyset$ for all $i in L$?
$endgroup$
– Fabio Somenzi
Mar 24 at 19:26
$begingroup$
Note: $cup_{iin L} (Fcup Omega_i) supseteq cup_{iin L} Omega_i$
$endgroup$
– JavaMan
Mar 24 at 19:23
$begingroup$
Note: $cup_{iin L} (Fcup Omega_i) supseteq cup_{iin L} Omega_i$
$endgroup$
– JavaMan
Mar 24 at 19:23
5
5
$begingroup$
What happens if $Omega_i = emptyset$ for all $i in L$?
$endgroup$
– Fabio Somenzi
Mar 24 at 19:26
$begingroup$
What happens if $Omega_i = emptyset$ for all $i in L$?
$endgroup$
– Fabio Somenzi
Mar 24 at 19:26
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
$$bigcup_{iin L} (Fcup Omega _i)=Fcupbigcup_{iin L}Omega _i,$$
of course it's uncountable ! Even if $F=emptyset$ (difficult to be smaller), your union is going to be $bigcup_{iin L}Omega _i$, and thus uncountable.
$endgroup$
$begingroup$
the sets are all non empty
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– Vrouvrou
Mar 24 at 20:29
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@Vrouvrou: Then my answer should help :)
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– user657324
Mar 24 at 20:37
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@Vrouvrou It is best to include all relevant details in your question.
$endgroup$
– Santana Afton
Mar 24 at 23:15
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
$$bigcup_{iin L} (Fcup Omega _i)=Fcupbigcup_{iin L}Omega _i,$$
of course it's uncountable ! Even if $F=emptyset$ (difficult to be smaller), your union is going to be $bigcup_{iin L}Omega _i$, and thus uncountable.
$endgroup$
$begingroup$
the sets are all non empty
$endgroup$
– Vrouvrou
Mar 24 at 20:29
$begingroup$
@Vrouvrou: Then my answer should help :)
$endgroup$
– user657324
Mar 24 at 20:37
$begingroup$
@Vrouvrou It is best to include all relevant details in your question.
$endgroup$
– Santana Afton
Mar 24 at 23:15
add a comment |
$begingroup$
$$bigcup_{iin L} (Fcup Omega _i)=Fcupbigcup_{iin L}Omega _i,$$
of course it's uncountable ! Even if $F=emptyset$ (difficult to be smaller), your union is going to be $bigcup_{iin L}Omega _i$, and thus uncountable.
$endgroup$
$begingroup$
the sets are all non empty
$endgroup$
– Vrouvrou
Mar 24 at 20:29
$begingroup$
@Vrouvrou: Then my answer should help :)
$endgroup$
– user657324
Mar 24 at 20:37
$begingroup$
@Vrouvrou It is best to include all relevant details in your question.
$endgroup$
– Santana Afton
Mar 24 at 23:15
add a comment |
$begingroup$
$$bigcup_{iin L} (Fcup Omega _i)=Fcupbigcup_{iin L}Omega _i,$$
of course it's uncountable ! Even if $F=emptyset$ (difficult to be smaller), your union is going to be $bigcup_{iin L}Omega _i$, and thus uncountable.
$endgroup$
$$bigcup_{iin L} (Fcup Omega _i)=Fcupbigcup_{iin L}Omega _i,$$
of course it's uncountable ! Even if $F=emptyset$ (difficult to be smaller), your union is going to be $bigcup_{iin L}Omega _i$, and thus uncountable.
edited Mar 25 at 3:58
answered Mar 24 at 19:21
user657324user657324
63310
63310
$begingroup$
the sets are all non empty
$endgroup$
– Vrouvrou
Mar 24 at 20:29
$begingroup$
@Vrouvrou: Then my answer should help :)
$endgroup$
– user657324
Mar 24 at 20:37
$begingroup$
@Vrouvrou It is best to include all relevant details in your question.
$endgroup$
– Santana Afton
Mar 24 at 23:15
add a comment |
$begingroup$
the sets are all non empty
$endgroup$
– Vrouvrou
Mar 24 at 20:29
$begingroup$
@Vrouvrou: Then my answer should help :)
$endgroup$
– user657324
Mar 24 at 20:37
$begingroup$
@Vrouvrou It is best to include all relevant details in your question.
$endgroup$
– Santana Afton
Mar 24 at 23:15
$begingroup$
the sets are all non empty
$endgroup$
– Vrouvrou
Mar 24 at 20:29
$begingroup$
the sets are all non empty
$endgroup$
– Vrouvrou
Mar 24 at 20:29
$begingroup$
@Vrouvrou: Then my answer should help :)
$endgroup$
– user657324
Mar 24 at 20:37
$begingroup$
@Vrouvrou: Then my answer should help :)
$endgroup$
– user657324
Mar 24 at 20:37
$begingroup$
@Vrouvrou It is best to include all relevant details in your question.
$endgroup$
– Santana Afton
Mar 24 at 23:15
$begingroup$
@Vrouvrou It is best to include all relevant details in your question.
$endgroup$
– Santana Afton
Mar 24 at 23:15
add a comment |
$begingroup$
Note: $cup_{iin L} (Fcup Omega_i) supseteq cup_{iin L} Omega_i$
$endgroup$
– JavaMan
Mar 24 at 19:23
5
$begingroup$
What happens if $Omega_i = emptyset$ for all $i in L$?
$endgroup$
– Fabio Somenzi
Mar 24 at 19:26