Why is this set uncountable [closed] Announcing the arrival of Valued Associate #679: Cesar...

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Why is this set uncountable [closed]



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Non-trivial examples of operations.MacNeille completion of a totally ordered set: Dedekind cutsWhat is this question asking?Properties of set $mathrm {orb} (x)$Is the ring and semi-ring definition of algebra and set linked?Proof Check in AlgebraAssociated primes of a non-zero module always exist if corresponding ring is NoetherianSet of all subrings of $mathbb{Q}$ are uncountable.For any sets $X$ & $Y$ can the group of automorphisms for the digraph $G(X,Y)=(Xcup Y,Xtimes Y)$ be express in terms of symmetric groups?Is $Set$ a subcategory of $Grp$?












0












$begingroup$


I have an uncountable family $(Omega_i)_{i in L}$ of non empty sets such that



$$
forall i,jin L, ineq j, Omega_icap Omega_j=emptyset$$



and there exists a non empty set $F$ such that $forall iin L,Fcap Omega_i=emptyset.$



How to prove that $bigcup_{iin L} (Fcup Omega_i)$ is uncountable?



thanks










share|cite|improve this question











$endgroup$



closed as off-topic by YiFan, Cesareo, Lee David Chung Lin, dantopa, John Omielan Mar 25 at 4:44


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – YiFan, Cesareo, Lee David Chung Lin, dantopa, John Omielan

If this question can be reworded to fit the rules in the help center, please edit the question.
















  • $begingroup$
    Note: $cup_{iin L} (Fcup Omega_i) supseteq cup_{iin L} Omega_i$
    $endgroup$
    – JavaMan
    Mar 24 at 19:23






  • 5




    $begingroup$
    What happens if $Omega_i = emptyset$ for all $i in L$?
    $endgroup$
    – Fabio Somenzi
    Mar 24 at 19:26
















0












$begingroup$


I have an uncountable family $(Omega_i)_{i in L}$ of non empty sets such that



$$
forall i,jin L, ineq j, Omega_icap Omega_j=emptyset$$



and there exists a non empty set $F$ such that $forall iin L,Fcap Omega_i=emptyset.$



How to prove that $bigcup_{iin L} (Fcup Omega_i)$ is uncountable?



thanks










share|cite|improve this question











$endgroup$



closed as off-topic by YiFan, Cesareo, Lee David Chung Lin, dantopa, John Omielan Mar 25 at 4:44


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – YiFan, Cesareo, Lee David Chung Lin, dantopa, John Omielan

If this question can be reworded to fit the rules in the help center, please edit the question.
















  • $begingroup$
    Note: $cup_{iin L} (Fcup Omega_i) supseteq cup_{iin L} Omega_i$
    $endgroup$
    – JavaMan
    Mar 24 at 19:23






  • 5




    $begingroup$
    What happens if $Omega_i = emptyset$ for all $i in L$?
    $endgroup$
    – Fabio Somenzi
    Mar 24 at 19:26














0












0








0





$begingroup$


I have an uncountable family $(Omega_i)_{i in L}$ of non empty sets such that



$$
forall i,jin L, ineq j, Omega_icap Omega_j=emptyset$$



and there exists a non empty set $F$ such that $forall iin L,Fcap Omega_i=emptyset.$



How to prove that $bigcup_{iin L} (Fcup Omega_i)$ is uncountable?



thanks










share|cite|improve this question











$endgroup$




I have an uncountable family $(Omega_i)_{i in L}$ of non empty sets such that



$$
forall i,jin L, ineq j, Omega_icap Omega_j=emptyset$$



and there exists a non empty set $F$ such that $forall iin L,Fcap Omega_i=emptyset.$



How to prove that $bigcup_{iin L} (Fcup Omega_i)$ is uncountable?



thanks







abstract-algebra






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share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Mar 25 at 22:03









Poline Sandra

1208




1208










asked Mar 24 at 19:17









VrouvrouVrouvrou

1,9251822




1,9251822




closed as off-topic by YiFan, Cesareo, Lee David Chung Lin, dantopa, John Omielan Mar 25 at 4:44


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – YiFan, Cesareo, Lee David Chung Lin, dantopa, John Omielan

If this question can be reworded to fit the rules in the help center, please edit the question.







closed as off-topic by YiFan, Cesareo, Lee David Chung Lin, dantopa, John Omielan Mar 25 at 4:44


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – YiFan, Cesareo, Lee David Chung Lin, dantopa, John Omielan

If this question can be reworded to fit the rules in the help center, please edit the question.












  • $begingroup$
    Note: $cup_{iin L} (Fcup Omega_i) supseteq cup_{iin L} Omega_i$
    $endgroup$
    – JavaMan
    Mar 24 at 19:23






  • 5




    $begingroup$
    What happens if $Omega_i = emptyset$ for all $i in L$?
    $endgroup$
    – Fabio Somenzi
    Mar 24 at 19:26


















  • $begingroup$
    Note: $cup_{iin L} (Fcup Omega_i) supseteq cup_{iin L} Omega_i$
    $endgroup$
    – JavaMan
    Mar 24 at 19:23






  • 5




    $begingroup$
    What happens if $Omega_i = emptyset$ for all $i in L$?
    $endgroup$
    – Fabio Somenzi
    Mar 24 at 19:26
















$begingroup$
Note: $cup_{iin L} (Fcup Omega_i) supseteq cup_{iin L} Omega_i$
$endgroup$
– JavaMan
Mar 24 at 19:23




$begingroup$
Note: $cup_{iin L} (Fcup Omega_i) supseteq cup_{iin L} Omega_i$
$endgroup$
– JavaMan
Mar 24 at 19:23




5




5




$begingroup$
What happens if $Omega_i = emptyset$ for all $i in L$?
$endgroup$
– Fabio Somenzi
Mar 24 at 19:26




$begingroup$
What happens if $Omega_i = emptyset$ for all $i in L$?
$endgroup$
– Fabio Somenzi
Mar 24 at 19:26










1 Answer
1






active

oldest

votes


















1












$begingroup$

$$bigcup_{iin L} (Fcup Omega _i)=Fcupbigcup_{iin L}Omega _i,$$
of course it's uncountable ! Even if $F=emptyset$ (difficult to be smaller), your union is going to be $bigcup_{iin L}Omega _i$, and thus uncountable.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    the sets are all non empty
    $endgroup$
    – Vrouvrou
    Mar 24 at 20:29










  • $begingroup$
    @Vrouvrou: Then my answer should help :)
    $endgroup$
    – user657324
    Mar 24 at 20:37












  • $begingroup$
    @Vrouvrou It is best to include all relevant details in your question.
    $endgroup$
    – Santana Afton
    Mar 24 at 23:15


















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1












$begingroup$

$$bigcup_{iin L} (Fcup Omega _i)=Fcupbigcup_{iin L}Omega _i,$$
of course it's uncountable ! Even if $F=emptyset$ (difficult to be smaller), your union is going to be $bigcup_{iin L}Omega _i$, and thus uncountable.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    the sets are all non empty
    $endgroup$
    – Vrouvrou
    Mar 24 at 20:29










  • $begingroup$
    @Vrouvrou: Then my answer should help :)
    $endgroup$
    – user657324
    Mar 24 at 20:37












  • $begingroup$
    @Vrouvrou It is best to include all relevant details in your question.
    $endgroup$
    – Santana Afton
    Mar 24 at 23:15
















1












$begingroup$

$$bigcup_{iin L} (Fcup Omega _i)=Fcupbigcup_{iin L}Omega _i,$$
of course it's uncountable ! Even if $F=emptyset$ (difficult to be smaller), your union is going to be $bigcup_{iin L}Omega _i$, and thus uncountable.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    the sets are all non empty
    $endgroup$
    – Vrouvrou
    Mar 24 at 20:29










  • $begingroup$
    @Vrouvrou: Then my answer should help :)
    $endgroup$
    – user657324
    Mar 24 at 20:37












  • $begingroup$
    @Vrouvrou It is best to include all relevant details in your question.
    $endgroup$
    – Santana Afton
    Mar 24 at 23:15














1












1








1





$begingroup$

$$bigcup_{iin L} (Fcup Omega _i)=Fcupbigcup_{iin L}Omega _i,$$
of course it's uncountable ! Even if $F=emptyset$ (difficult to be smaller), your union is going to be $bigcup_{iin L}Omega _i$, and thus uncountable.






share|cite|improve this answer











$endgroup$



$$bigcup_{iin L} (Fcup Omega _i)=Fcupbigcup_{iin L}Omega _i,$$
of course it's uncountable ! Even if $F=emptyset$ (difficult to be smaller), your union is going to be $bigcup_{iin L}Omega _i$, and thus uncountable.







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Mar 25 at 3:58

























answered Mar 24 at 19:21









user657324user657324

63310




63310












  • $begingroup$
    the sets are all non empty
    $endgroup$
    – Vrouvrou
    Mar 24 at 20:29










  • $begingroup$
    @Vrouvrou: Then my answer should help :)
    $endgroup$
    – user657324
    Mar 24 at 20:37












  • $begingroup$
    @Vrouvrou It is best to include all relevant details in your question.
    $endgroup$
    – Santana Afton
    Mar 24 at 23:15


















  • $begingroup$
    the sets are all non empty
    $endgroup$
    – Vrouvrou
    Mar 24 at 20:29










  • $begingroup$
    @Vrouvrou: Then my answer should help :)
    $endgroup$
    – user657324
    Mar 24 at 20:37












  • $begingroup$
    @Vrouvrou It is best to include all relevant details in your question.
    $endgroup$
    – Santana Afton
    Mar 24 at 23:15
















$begingroup$
the sets are all non empty
$endgroup$
– Vrouvrou
Mar 24 at 20:29




$begingroup$
the sets are all non empty
$endgroup$
– Vrouvrou
Mar 24 at 20:29












$begingroup$
@Vrouvrou: Then my answer should help :)
$endgroup$
– user657324
Mar 24 at 20:37






$begingroup$
@Vrouvrou: Then my answer should help :)
$endgroup$
– user657324
Mar 24 at 20:37














$begingroup$
@Vrouvrou It is best to include all relevant details in your question.
$endgroup$
– Santana Afton
Mar 24 at 23:15




$begingroup$
@Vrouvrou It is best to include all relevant details in your question.
$endgroup$
– Santana Afton
Mar 24 at 23:15



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