Integral relate to Hahn polynomial Announcing the arrival of Valued Associate #679: Cesar...

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Integral relate to Hahn polynomial



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)log sin and log cos integral, maybe relate to fourier seriesImproper integral of $int_0^infty frac{e^{-ax} - e^{-bx}}{x} dx$Closed form of $int_{0}^{infty} frac{tanh(x),tanh(2x)}{x^2};dx$Help! How to solve this integral?Differentiate under integral sign-Leibniz Rulepoor mellin transform?Using The Riemann Zeta Functional Equationmellin Transform $sum _{k=1}^{infty } k^2 text{sech}(k x)=frac{pi ^3}{8 x^3}$Integral calculation by using Mellin TransformImproper integral related to Gamma function












0












$begingroup$


I try to calculate te following integral
$$int_{-infty }^{infty } frac{e^{x z} left(text{sech}^2right(pi x) ) Gamma left(n+frac{i x}{2}+frac{1}{2}right)}{2 Gamma left(frac{i x}{2}+frac{1}{2}right)} , dx $$
I try to use Nassalla-Raman integral
enter image description here
and Mellin convolution but I get no result.



Thanks in advance










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    What are the conditions on $z$ and $n$? For nice $z$ and $n$, substituting $x = -2 i t$ and reducing all factors to $Gamma(a_k pm t)$ gives the definition of the Meijer G-function.
    $endgroup$
    – Maxim
    Mar 25 at 22:41










  • $begingroup$
    Thanks @Maxim , good idea ,This type of orthogonal polynomials those of hanh and those of wilsom used to accelerate representations of functions, use many degrees of freedom and are not very fast like the classic ones making them few useful, but only theoretical and diicult to calculate
    $endgroup$
    – capea perez
    Mar 26 at 17:49


















0












$begingroup$


I try to calculate te following integral
$$int_{-infty }^{infty } frac{e^{x z} left(text{sech}^2right(pi x) ) Gamma left(n+frac{i x}{2}+frac{1}{2}right)}{2 Gamma left(frac{i x}{2}+frac{1}{2}right)} , dx $$
I try to use Nassalla-Raman integral
enter image description here
and Mellin convolution but I get no result.



Thanks in advance










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    What are the conditions on $z$ and $n$? For nice $z$ and $n$, substituting $x = -2 i t$ and reducing all factors to $Gamma(a_k pm t)$ gives the definition of the Meijer G-function.
    $endgroup$
    – Maxim
    Mar 25 at 22:41










  • $begingroup$
    Thanks @Maxim , good idea ,This type of orthogonal polynomials those of hanh and those of wilsom used to accelerate representations of functions, use many degrees of freedom and are not very fast like the classic ones making them few useful, but only theoretical and diicult to calculate
    $endgroup$
    – capea perez
    Mar 26 at 17:49
















0












0








0





$begingroup$


I try to calculate te following integral
$$int_{-infty }^{infty } frac{e^{x z} left(text{sech}^2right(pi x) ) Gamma left(n+frac{i x}{2}+frac{1}{2}right)}{2 Gamma left(frac{i x}{2}+frac{1}{2}right)} , dx $$
I try to use Nassalla-Raman integral
enter image description here
and Mellin convolution but I get no result.



Thanks in advance










share|cite|improve this question











$endgroup$




I try to calculate te following integral
$$int_{-infty }^{infty } frac{e^{x z} left(text{sech}^2right(pi x) ) Gamma left(n+frac{i x}{2}+frac{1}{2}right)}{2 Gamma left(frac{i x}{2}+frac{1}{2}right)} , dx $$
I try to use Nassalla-Raman integral
enter image description here
and Mellin convolution but I get no result.



Thanks in advance







calculus






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Mar 25 at 18:25









Bernard

124k742117




124k742117










asked Mar 25 at 17:28









capea perezcapea perez

335




335








  • 1




    $begingroup$
    What are the conditions on $z$ and $n$? For nice $z$ and $n$, substituting $x = -2 i t$ and reducing all factors to $Gamma(a_k pm t)$ gives the definition of the Meijer G-function.
    $endgroup$
    – Maxim
    Mar 25 at 22:41










  • $begingroup$
    Thanks @Maxim , good idea ,This type of orthogonal polynomials those of hanh and those of wilsom used to accelerate representations of functions, use many degrees of freedom and are not very fast like the classic ones making them few useful, but only theoretical and diicult to calculate
    $endgroup$
    – capea perez
    Mar 26 at 17:49
















  • 1




    $begingroup$
    What are the conditions on $z$ and $n$? For nice $z$ and $n$, substituting $x = -2 i t$ and reducing all factors to $Gamma(a_k pm t)$ gives the definition of the Meijer G-function.
    $endgroup$
    – Maxim
    Mar 25 at 22:41










  • $begingroup$
    Thanks @Maxim , good idea ,This type of orthogonal polynomials those of hanh and those of wilsom used to accelerate representations of functions, use many degrees of freedom and are not very fast like the classic ones making them few useful, but only theoretical and diicult to calculate
    $endgroup$
    – capea perez
    Mar 26 at 17:49










1




1




$begingroup$
What are the conditions on $z$ and $n$? For nice $z$ and $n$, substituting $x = -2 i t$ and reducing all factors to $Gamma(a_k pm t)$ gives the definition of the Meijer G-function.
$endgroup$
– Maxim
Mar 25 at 22:41




$begingroup$
What are the conditions on $z$ and $n$? For nice $z$ and $n$, substituting $x = -2 i t$ and reducing all factors to $Gamma(a_k pm t)$ gives the definition of the Meijer G-function.
$endgroup$
– Maxim
Mar 25 at 22:41












$begingroup$
Thanks @Maxim , good idea ,This type of orthogonal polynomials those of hanh and those of wilsom used to accelerate representations of functions, use many degrees of freedom and are not very fast like the classic ones making them few useful, but only theoretical and diicult to calculate
$endgroup$
– capea perez
Mar 26 at 17:49






$begingroup$
Thanks @Maxim , good idea ,This type of orthogonal polynomials those of hanh and those of wilsom used to accelerate representations of functions, use many degrees of freedom and are not very fast like the classic ones making them few useful, but only theoretical and diicult to calculate
$endgroup$
– capea perez
Mar 26 at 17:49












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