Constructing an $epsilon$-net of $l_2$ unit ballcan I bound the following probability?Bounding the estimation...
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Constructing an $epsilon$-net of $l_2$ unit ball
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I am interested in probabilistic or explicit ways to construct an $epsilon$-net of the $l_2$ unit ball in $mathbb{R}^{d}$.
I know that, for every $epsilon > 0$, there exists an $epsilon$-net $mathcal{N}_{epsilon}$ for the unit sphere in $d$ dimensions such that
$$
Mtriangleqleft|mathcal{N}_{epsilon}right|
le left( 1+frac{2}{epsilon}right)^{d}.
$$
(Lemma 5.2 in https://arxiv.org/abs/1011.3027)
To my understanding, the aforementioned bound holds for an $epsilon$-net of the entire ball, not only the sphere.
In the case of the sphere, we can construct an $epsilon$-net with high probability,
by drawing a sufficient number ($O(Mlog{M})$) of independent random vectors according to a Gaussian distribution $N(mathbf{0}, mathbf{I})$, and normalizing the length to $1$.
I believe that one way to get an $epsilon$-net for the ball,
would be to repeat the above procedure $O(1/epsilon)$ times, for all spheres of radii $epsilon, 2epsilon,3epsilon, dots, 1$.
The union of the $epsilon$-nets, should be able to cover the ball.
However, it would require $tilde{O}left((1+2/{epsilon})^{d+1}right)$ points (ignoring the logarithmic factor).
- Is there a simple way to construct an $epsilon$-net for the unit ball directly, $textit{i.e.}$, without constructing nets for multiple spheres?
- Is there way to achieve the bound on $left|mathcal{N}_{epsilon}right|$ (possibly up to logarithmic factors)?
I would appreciate any pointers to either probabilistic or explicit methods.
probability
$endgroup$
add a comment |
$begingroup$
I am interested in probabilistic or explicit ways to construct an $epsilon$-net of the $l_2$ unit ball in $mathbb{R}^{d}$.
I know that, for every $epsilon > 0$, there exists an $epsilon$-net $mathcal{N}_{epsilon}$ for the unit sphere in $d$ dimensions such that
$$
Mtriangleqleft|mathcal{N}_{epsilon}right|
le left( 1+frac{2}{epsilon}right)^{d}.
$$
(Lemma 5.2 in https://arxiv.org/abs/1011.3027)
To my understanding, the aforementioned bound holds for an $epsilon$-net of the entire ball, not only the sphere.
In the case of the sphere, we can construct an $epsilon$-net with high probability,
by drawing a sufficient number ($O(Mlog{M})$) of independent random vectors according to a Gaussian distribution $N(mathbf{0}, mathbf{I})$, and normalizing the length to $1$.
I believe that one way to get an $epsilon$-net for the ball,
would be to repeat the above procedure $O(1/epsilon)$ times, for all spheres of radii $epsilon, 2epsilon,3epsilon, dots, 1$.
The union of the $epsilon$-nets, should be able to cover the ball.
However, it would require $tilde{O}left((1+2/{epsilon})^{d+1}right)$ points (ignoring the logarithmic factor).
- Is there a simple way to construct an $epsilon$-net for the unit ball directly, $textit{i.e.}$, without constructing nets for multiple spheres?
- Is there way to achieve the bound on $left|mathcal{N}_{epsilon}right|$ (possibly up to logarithmic factors)?
I would appreciate any pointers to either probabilistic or explicit methods.
probability
$endgroup$
add a comment |
$begingroup$
I am interested in probabilistic or explicit ways to construct an $epsilon$-net of the $l_2$ unit ball in $mathbb{R}^{d}$.
I know that, for every $epsilon > 0$, there exists an $epsilon$-net $mathcal{N}_{epsilon}$ for the unit sphere in $d$ dimensions such that
$$
Mtriangleqleft|mathcal{N}_{epsilon}right|
le left( 1+frac{2}{epsilon}right)^{d}.
$$
(Lemma 5.2 in https://arxiv.org/abs/1011.3027)
To my understanding, the aforementioned bound holds for an $epsilon$-net of the entire ball, not only the sphere.
In the case of the sphere, we can construct an $epsilon$-net with high probability,
by drawing a sufficient number ($O(Mlog{M})$) of independent random vectors according to a Gaussian distribution $N(mathbf{0}, mathbf{I})$, and normalizing the length to $1$.
I believe that one way to get an $epsilon$-net for the ball,
would be to repeat the above procedure $O(1/epsilon)$ times, for all spheres of radii $epsilon, 2epsilon,3epsilon, dots, 1$.
The union of the $epsilon$-nets, should be able to cover the ball.
However, it would require $tilde{O}left((1+2/{epsilon})^{d+1}right)$ points (ignoring the logarithmic factor).
- Is there a simple way to construct an $epsilon$-net for the unit ball directly, $textit{i.e.}$, without constructing nets for multiple spheres?
- Is there way to achieve the bound on $left|mathcal{N}_{epsilon}right|$ (possibly up to logarithmic factors)?
I would appreciate any pointers to either probabilistic or explicit methods.
probability
$endgroup$
I am interested in probabilistic or explicit ways to construct an $epsilon$-net of the $l_2$ unit ball in $mathbb{R}^{d}$.
I know that, for every $epsilon > 0$, there exists an $epsilon$-net $mathcal{N}_{epsilon}$ for the unit sphere in $d$ dimensions such that
$$
Mtriangleqleft|mathcal{N}_{epsilon}right|
le left( 1+frac{2}{epsilon}right)^{d}.
$$
(Lemma 5.2 in https://arxiv.org/abs/1011.3027)
To my understanding, the aforementioned bound holds for an $epsilon$-net of the entire ball, not only the sphere.
In the case of the sphere, we can construct an $epsilon$-net with high probability,
by drawing a sufficient number ($O(Mlog{M})$) of independent random vectors according to a Gaussian distribution $N(mathbf{0}, mathbf{I})$, and normalizing the length to $1$.
I believe that one way to get an $epsilon$-net for the ball,
would be to repeat the above procedure $O(1/epsilon)$ times, for all spheres of radii $epsilon, 2epsilon,3epsilon, dots, 1$.
The union of the $epsilon$-nets, should be able to cover the ball.
However, it would require $tilde{O}left((1+2/{epsilon})^{d+1}right)$ points (ignoring the logarithmic factor).
- Is there a simple way to construct an $epsilon$-net for the unit ball directly, $textit{i.e.}$, without constructing nets for multiple spheres?
- Is there way to achieve the bound on $left|mathcal{N}_{epsilon}right|$ (possibly up to logarithmic factors)?
I would appreciate any pointers to either probabilistic or explicit methods.
probability
probability
edited Mar 18 at 20:35
Clement C.
51k34093
51k34093
asked Nov 9 '14 at 20:57
megasmegas
1,801614
1,801614
add a comment |
add a comment |
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