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0












$begingroup$


simplify expand $$8 sin^2(3 theta)-4$$



I'm stuck on this question can someone help me and show solution.










share|cite|improve this question











$endgroup$












  • $begingroup$
    Is the edit correct?
    $endgroup$
    – Amzoti
    Dec 2 '13 at 0:54










  • $begingroup$
    Yes, it is correct. Sorry, first time on this site.
    $endgroup$
    – James
    Dec 2 '13 at 0:55








  • 1




    $begingroup$
    "Simplify" is really subjective here. Do you want the argument to be $theta$ instead of $3theta$?
    $endgroup$
    – Doc
    Dec 2 '13 at 0:59










  • $begingroup$
    I think my teacher wants it simplified using compound or double angle identities.
    $endgroup$
    – James
    Dec 2 '13 at 1:02
















0












$begingroup$


simplify expand $$8 sin^2(3 theta)-4$$



I'm stuck on this question can someone help me and show solution.










share|cite|improve this question











$endgroup$












  • $begingroup$
    Is the edit correct?
    $endgroup$
    – Amzoti
    Dec 2 '13 at 0:54










  • $begingroup$
    Yes, it is correct. Sorry, first time on this site.
    $endgroup$
    – James
    Dec 2 '13 at 0:55








  • 1




    $begingroup$
    "Simplify" is really subjective here. Do you want the argument to be $theta$ instead of $3theta$?
    $endgroup$
    – Doc
    Dec 2 '13 at 0:59










  • $begingroup$
    I think my teacher wants it simplified using compound or double angle identities.
    $endgroup$
    – James
    Dec 2 '13 at 1:02














0












0








0





$begingroup$


simplify expand $$8 sin^2(3 theta)-4$$



I'm stuck on this question can someone help me and show solution.










share|cite|improve this question











$endgroup$




simplify expand $$8 sin^2(3 theta)-4$$



I'm stuck on this question can someone help me and show solution.







trigonometry






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Dec 2 '13 at 0:54









Amzoti

51.3k125398




51.3k125398










asked Dec 2 '13 at 0:51









JamesJames

1




1












  • $begingroup$
    Is the edit correct?
    $endgroup$
    – Amzoti
    Dec 2 '13 at 0:54










  • $begingroup$
    Yes, it is correct. Sorry, first time on this site.
    $endgroup$
    – James
    Dec 2 '13 at 0:55








  • 1




    $begingroup$
    "Simplify" is really subjective here. Do you want the argument to be $theta$ instead of $3theta$?
    $endgroup$
    – Doc
    Dec 2 '13 at 0:59










  • $begingroup$
    I think my teacher wants it simplified using compound or double angle identities.
    $endgroup$
    – James
    Dec 2 '13 at 1:02


















  • $begingroup$
    Is the edit correct?
    $endgroup$
    – Amzoti
    Dec 2 '13 at 0:54










  • $begingroup$
    Yes, it is correct. Sorry, first time on this site.
    $endgroup$
    – James
    Dec 2 '13 at 0:55








  • 1




    $begingroup$
    "Simplify" is really subjective here. Do you want the argument to be $theta$ instead of $3theta$?
    $endgroup$
    – Doc
    Dec 2 '13 at 0:59










  • $begingroup$
    I think my teacher wants it simplified using compound or double angle identities.
    $endgroup$
    – James
    Dec 2 '13 at 1:02
















$begingroup$
Is the edit correct?
$endgroup$
– Amzoti
Dec 2 '13 at 0:54




$begingroup$
Is the edit correct?
$endgroup$
– Amzoti
Dec 2 '13 at 0:54












$begingroup$
Yes, it is correct. Sorry, first time on this site.
$endgroup$
– James
Dec 2 '13 at 0:55






$begingroup$
Yes, it is correct. Sorry, first time on this site.
$endgroup$
– James
Dec 2 '13 at 0:55






1




1




$begingroup$
"Simplify" is really subjective here. Do you want the argument to be $theta$ instead of $3theta$?
$endgroup$
– Doc
Dec 2 '13 at 0:59




$begingroup$
"Simplify" is really subjective here. Do you want the argument to be $theta$ instead of $3theta$?
$endgroup$
– Doc
Dec 2 '13 at 0:59












$begingroup$
I think my teacher wants it simplified using compound or double angle identities.
$endgroup$
– James
Dec 2 '13 at 1:02




$begingroup$
I think my teacher wants it simplified using compound or double angle identities.
$endgroup$
– James
Dec 2 '13 at 1:02










1 Answer
1






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oldest

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0












$begingroup$

Using $cos(2x)=cos^2x-sin^2x=1-2sin^2x$, we can see that this expression is
$$8sin^2(3theta)-4=-4cdot(1-2sin^2(3theta))=-4,cos(6theta),.$$






share|cite|improve this answer









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    oldest

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    0












    $begingroup$

    Using $cos(2x)=cos^2x-sin^2x=1-2sin^2x$, we can see that this expression is
    $$8sin^2(3theta)-4=-4cdot(1-2sin^2(3theta))=-4,cos(6theta),.$$






    share|cite|improve this answer









    $endgroup$


















      0












      $begingroup$

      Using $cos(2x)=cos^2x-sin^2x=1-2sin^2x$, we can see that this expression is
      $$8sin^2(3theta)-4=-4cdot(1-2sin^2(3theta))=-4,cos(6theta),.$$






      share|cite|improve this answer









      $endgroup$
















        0












        0








        0





        $begingroup$

        Using $cos(2x)=cos^2x-sin^2x=1-2sin^2x$, we can see that this expression is
        $$8sin^2(3theta)-4=-4cdot(1-2sin^2(3theta))=-4,cos(6theta),.$$






        share|cite|improve this answer









        $endgroup$



        Using $cos(2x)=cos^2x-sin^2x=1-2sin^2x$, we can see that this expression is
        $$8sin^2(3theta)-4=-4cdot(1-2sin^2(3theta))=-4,cos(6theta),.$$







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Dec 2 '13 at 1:12









        BerciBerci

        61.9k23675




        61.9k23675






























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