Could use some help in probability questionProbability Math Question…?Probability - What is the probability...
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Could use some help in probability question
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Two distinct numbers are selected simultaneously and at random from the set {1, 2, 3, 4, 5}. What is the probability that the smaller one divides the larger one? Express your answer as a common fraction.
probability computational-mathematics
asked 2 days ago
grif389grif389
32
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Two distinct numbers are selected simultaneously and at random from the set {1, 2, 3, 4, 5}. What is the probability that the smaller one divides the larger one? Express your answer as a common fraction.
probability computational-mathematics
asked 2 days ago
grif389grif389
32
New contributor
grif389 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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Are these 2 questions related? If not please post 2 seperate questions
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– MoonKnight
2 days ago
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My bad thanks man
$endgroup$
– grif389
2 days ago
$begingroup$
You are more likely to get responses if you share or thoughts and attempts on solving the problem.
$endgroup$
– PierreCarre
2 days ago
add a comment |
$begingroup$
Two distinct numbers are selected simultaneously and at random from the set {1, 2, 3, 4, 5}. What is the probability that the smaller one divides the larger one? Express your answer as a common fraction.
probability computational-mathematics
asked 2 days ago
grif389grif389
32
New contributor
grif389 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Two distinct numbers are selected simultaneously and at random from the set {1, 2, 3, 4, 5}. What is the probability that the smaller one divides the larger one? Express your answer as a common fraction.
probability computational-mathematics
probability computational-mathematics
asked 2 days ago
grif389grif389
32
New contributor
grif389 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 days ago
grif389grif389
32
New contributor
grif389 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 2 days ago
grif389
asked 2 days ago
grif389grif389
32
New contributor
grif389 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked 2 days ago
grif389grif389
32
asked 2 days ago
grif389grif389
32
32
New contributor
grif389 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor
grif389 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
grif389 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$begingroup$
Are these 2 questions related? If not please post 2 seperate questions
$endgroup$
– MoonKnight
2 days ago
$begingroup$
My bad thanks man
$endgroup$
– grif389
2 days ago
$begingroup$
You are more likely to get responses if you share or thoughts and attempts on solving the problem.
$endgroup$
– PierreCarre
2 days ago
add a comment |
$begingroup$
Are these 2 questions related? If not please post 2 seperate questions
$endgroup$
– MoonKnight
2 days ago
$begingroup$
My bad thanks man
$endgroup$
– grif389
2 days ago
$begingroup$
You are more likely to get responses if you share or thoughts and attempts on solving the problem.
$endgroup$
– PierreCarre
2 days ago
$begingroup$
Are these 2 questions related? If not please post 2 seperate questions
$endgroup$
– MoonKnight
2 days ago
$begingroup$
Are these 2 questions related? If not please post 2 seperate questions
$endgroup$
– MoonKnight
2 days ago
$begingroup$
My bad thanks man
$endgroup$
– grif389
2 days ago
$begingroup$
My bad thanks man
$endgroup$
– grif389
2 days ago
$begingroup$
You are more likely to get responses if you share or thoughts and attempts on solving the problem.
$endgroup$
– PierreCarre
2 days ago
$begingroup$
You are more likely to get responses if you share or thoughts and attempts on solving the problem.
$endgroup$
– PierreCarre
2 days ago
add a comment |
1 Answer
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There are $binom{5}{2}=10$ choices of this pair. The ones that qualify are the four of the form $(1,,n)$ and $(2,,4)$, and the answer is $frac12$.
answered 2 days ago
J.G.J.G.
29.4k22846
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$begingroup$
There are $binom{5}{2}=10$ choices of this pair. The ones that qualify are the four of the form $(1,,n)$ and $(2,,4)$, and the answer is $frac12$.
answered 2 days ago
J.G.J.G.
29.4k22846
$endgroup$
add a comment |
$begingroup$
There are $binom{5}{2}=10$ choices of this pair. The ones that qualify are the four of the form $(1,,n)$ and $(2,,4)$, and the answer is $frac12$.
answered 2 days ago
J.G.J.G.
29.4k22846
$endgroup$
add a comment |
$begingroup$
There are $binom{5}{2}=10$ choices of this pair. The ones that qualify are the four of the form $(1,,n)$ and $(2,,4)$, and the answer is $frac12$.
answered 2 days ago
J.G.J.G.
29.4k22846
$endgroup$
There are $binom{5}{2}=10$ choices of this pair. The ones that qualify are the four of the form $(1,,n)$ and $(2,,4)$, and the answer is $frac12$.
answered 2 days ago
J.G.J.G.
29.4k22846
answered 2 days ago
J.G.J.G.
29.4k22846
answered 2 days ago
J.G.J.G.
29.4k22846
answered 2 days ago
J.G.J.G.
29.4k22846
29.4k22846
add a comment |
add a comment |
grif389 is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
Are these 2 questions related? If not please post 2 seperate questions
$endgroup$
– MoonKnight
2 days ago
$begingroup$
My bad thanks man
$endgroup$
– grif389
2 days ago
$begingroup$
You are more likely to get responses if you share or thoughts and attempts on solving the problem.
$endgroup$
– PierreCarre
2 days ago