$fin C^{1}$. If $X, f(X)$ are heavy-tailed, so is $left| f'(X) cdot ...
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$fin C^{1}$. If $X, f(X)$ are heavy-tailed, so is $left| f'(X) cdot f(X)right|$.
$Eleft[prod_{i=1}^nX_iright]=prod_{i=1}^nEleft[X_iright]$ for all independent and real-valued random variablesIs $mathbb{E}exp left( k int_0^T B_t^2 , dt right)<infty$ for small $k>0$?If $X$ and $Y$ are independent random variables and $X$ is absolutely continuous then $X+Y$ is absolutely continuousBernstein-type inequality for heavy-tailed random variablesChange of variables in integration w.r.t Haar measureNormal distribution transformation with $phi(x)=x^2$Calculate $mathbb{E}left[ f(S-y(t+E)) e^{-rE}right]$Is $frac{partial}{partial theta} fleft(X,thetaright)biggr|_{theta_0}$ a random variable?Finding $mathbb{E}left(g left(min(X,c) right)right)$, where $g(X) simexp(1)$ and $c$ : constant.Sum of Random Variables that are not in $L^p(mathbb{R})$
$begingroup$
Let $X$ be a $mathbb{R}$-valued heavy-tailed and continuous random variable with density function $p_X$. Furthermore, let $f:mathbb{R}tomathbb{R}$ be continuously differentiable.
I am trying to show whether the following assertion is true:
If $X$ and $f(X)$ are heavy-tailed, so is
begin{equation}
left|f'(X) cdot f(X)right|.
end{equation}
To prove heavy-tailedness we need to show that for all $t>0$
begin{equation}
mathbb{E}left[expleft(t cdot left|f'(x) cdot f(x)right|right) right]
= int_{mathbb R} expleft(t cdot left|f'(x) cdot f(x)right|right) p_X(x) dx = infty
end{equation}
Any hints?
probability probability-theory statistics probability-distributions
$endgroup$
add a comment |
$begingroup$
Let $X$ be a $mathbb{R}$-valued heavy-tailed and continuous random variable with density function $p_X$. Furthermore, let $f:mathbb{R}tomathbb{R}$ be continuously differentiable.
I am trying to show whether the following assertion is true:
If $X$ and $f(X)$ are heavy-tailed, so is
begin{equation}
left|f'(X) cdot f(X)right|.
end{equation}
To prove heavy-tailedness we need to show that for all $t>0$
begin{equation}
mathbb{E}left[expleft(t cdot left|f'(x) cdot f(x)right|right) right]
= int_{mathbb R} expleft(t cdot left|f'(x) cdot f(x)right|right) p_X(x) dx = infty
end{equation}
Any hints?
probability probability-theory statistics probability-distributions
$endgroup$
$begingroup$
You edited your question and no longer assume $f$ to be Lipschitz - in other words you no longer assume $f'$ to be bounded. Is that really what you wanted?
$endgroup$
– Mars Plastic
Mar 13 at 16:11
add a comment |
$begingroup$
Let $X$ be a $mathbb{R}$-valued heavy-tailed and continuous random variable with density function $p_X$. Furthermore, let $f:mathbb{R}tomathbb{R}$ be continuously differentiable.
I am trying to show whether the following assertion is true:
If $X$ and $f(X)$ are heavy-tailed, so is
begin{equation}
left|f'(X) cdot f(X)right|.
end{equation}
To prove heavy-tailedness we need to show that for all $t>0$
begin{equation}
mathbb{E}left[expleft(t cdot left|f'(x) cdot f(x)right|right) right]
= int_{mathbb R} expleft(t cdot left|f'(x) cdot f(x)right|right) p_X(x) dx = infty
end{equation}
Any hints?
probability probability-theory statistics probability-distributions
$endgroup$
Let $X$ be a $mathbb{R}$-valued heavy-tailed and continuous random variable with density function $p_X$. Furthermore, let $f:mathbb{R}tomathbb{R}$ be continuously differentiable.
I am trying to show whether the following assertion is true:
If $X$ and $f(X)$ are heavy-tailed, so is
begin{equation}
left|f'(X) cdot f(X)right|.
end{equation}
To prove heavy-tailedness we need to show that for all $t>0$
begin{equation}
mathbb{E}left[expleft(t cdot left|f'(x) cdot f(x)right|right) right]
= int_{mathbb R} expleft(t cdot left|f'(x) cdot f(x)right|right) p_X(x) dx = infty
end{equation}
Any hints?
probability probability-theory statistics probability-distributions
probability probability-theory statistics probability-distributions
edited Mar 13 at 16:09
Carl
asked Mar 11 at 12:59
CarlCarl
11311
11311
$begingroup$
You edited your question and no longer assume $f$ to be Lipschitz - in other words you no longer assume $f'$ to be bounded. Is that really what you wanted?
$endgroup$
– Mars Plastic
Mar 13 at 16:11
add a comment |
$begingroup$
You edited your question and no longer assume $f$ to be Lipschitz - in other words you no longer assume $f'$ to be bounded. Is that really what you wanted?
$endgroup$
– Mars Plastic
Mar 13 at 16:11
$begingroup$
You edited your question and no longer assume $f$ to be Lipschitz - in other words you no longer assume $f'$ to be bounded. Is that really what you wanted?
$endgroup$
– Mars Plastic
Mar 13 at 16:11
$begingroup$
You edited your question and no longer assume $f$ to be Lipschitz - in other words you no longer assume $f'$ to be bounded. Is that really what you wanted?
$endgroup$
– Mars Plastic
Mar 13 at 16:11
add a comment |
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$begingroup$
You edited your question and no longer assume $f$ to be Lipschitz - in other words you no longer assume $f'$ to be bounded. Is that really what you wanted?
$endgroup$
– Mars Plastic
Mar 13 at 16:11