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$M$ be a complete $R$-module and $N$ be a closed submodule of $M.$ Then $M/N$ is complete.


The number of generators of a submodule over a Principal Ideal Ring.Does every free $R$-module have a maximal proper submodule?Finitely generated submodule of a localisationEvery non-Noetherian module has a submodule maximal with respect to being not finitely generated.Completion of a module is equivalent to Cauchy sequence criterionAnnihilator of a submodule of a moduleEvery $R$-module $M$ contains an indecomposable submodule.projective module which is a submodule of a finitely generated free moduleIs $hat{G}$ is complete with respect to the induced topology of $G$?Dual of a complete topological group













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Let $M$ be a complete $R$-module with respect to the filteration ${M_n}.$ Also let $N$ be a closed submodule of $M.$ Then how can I show that $M/N$ is complete with respect to the induced filteration, i.e., ${(M/N)_n=(N+M_n)/N}.$



We should show that $M/N$ is Hausdorff and every Cauchy sequence in $M/N$ converges. Since $N= cap_{n=1}^{infty}(N+M_n)$ clearly $M/N$ is Hausdorff. But How can I show that every Cauchy sequence in $M/N$ is convergent ? I need some help. Thanks.










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    $begingroup$


    Let $M$ be a complete $R$-module with respect to the filteration ${M_n}.$ Also let $N$ be a closed submodule of $M.$ Then how can I show that $M/N$ is complete with respect to the induced filteration, i.e., ${(M/N)_n=(N+M_n)/N}.$



    We should show that $M/N$ is Hausdorff and every Cauchy sequence in $M/N$ converges. Since $N= cap_{n=1}^{infty}(N+M_n)$ clearly $M/N$ is Hausdorff. But How can I show that every Cauchy sequence in $M/N$ is convergent ? I need some help. Thanks.










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      Let $M$ be a complete $R$-module with respect to the filteration ${M_n}.$ Also let $N$ be a closed submodule of $M.$ Then how can I show that $M/N$ is complete with respect to the induced filteration, i.e., ${(M/N)_n=(N+M_n)/N}.$



      We should show that $M/N$ is Hausdorff and every Cauchy sequence in $M/N$ converges. Since $N= cap_{n=1}^{infty}(N+M_n)$ clearly $M/N$ is Hausdorff. But How can I show that every Cauchy sequence in $M/N$ is convergent ? I need some help. Thanks.










      share|cite|improve this question









      $endgroup$




      Let $M$ be a complete $R$-module with respect to the filteration ${M_n}.$ Also let $N$ be a closed submodule of $M.$ Then how can I show that $M/N$ is complete with respect to the induced filteration, i.e., ${(M/N)_n=(N+M_n)/N}.$



      We should show that $M/N$ is Hausdorff and every Cauchy sequence in $M/N$ converges. Since $N= cap_{n=1}^{infty}(N+M_n)$ clearly $M/N$ is Hausdorff. But How can I show that every Cauchy sequence in $M/N$ is convergent ? I need some help. Thanks.







      abstract-algebra commutative-algebra modules topological-groups






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