SAT for a formula using Tableaux Propositional Logic (precedence of operators)Need help with solving...
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SAT for a formula using Tableaux Propositional Logic (precedence of operators)
Need help with solving proposition logic formula, should be a tautologyPropositional logic and distributive lawHelp with natural deduction (Propositional logic)Motivation for signed tableaux rules for propositional intuitionistic logiclogic: derive a formula using lawsclause “elimination” using assumptions in a propositional formulaHow to prove this propositional logic equation?Initialization in the tableaux method for first order logicPropositional logic proof checkGiven is a set of clauses. Find a logic formula in CNF such that..
$begingroup$
My doubt is in check if the following formula $phi$ is SAT or not using the Tableaux Method. Let me write formula:
$phi = neg left ( p vee q supset left ( left ( neg p wedge q right ) vee p vee neg q right ) right )$
How start rules of tableaux method in this case?
logic propositional-calculus formal-languages satisfiability
$endgroup$
add a comment |
$begingroup$
My doubt is in check if the following formula $phi$ is SAT or not using the Tableaux Method. Let me write formula:
$phi = neg left ( p vee q supset left ( left ( neg p wedge q right ) vee p vee neg q right ) right )$
How start rules of tableaux method in this case?
logic propositional-calculus formal-languages satisfiability
$endgroup$
add a comment |
$begingroup$
My doubt is in check if the following formula $phi$ is SAT or not using the Tableaux Method. Let me write formula:
$phi = neg left ( p vee q supset left ( left ( neg p wedge q right ) vee p vee neg q right ) right )$
How start rules of tableaux method in this case?
logic propositional-calculus formal-languages satisfiability
$endgroup$
My doubt is in check if the following formula $phi$ is SAT or not using the Tableaux Method. Let me write formula:
$phi = neg left ( p vee q supset left ( left ( neg p wedge q right ) vee p vee neg q right ) right )$
How start rules of tableaux method in this case?
logic propositional-calculus formal-languages satisfiability
logic propositional-calculus formal-languages satisfiability
edited Mar 12 at 21:02
mayday24
asked Mar 12 at 15:35
mayday24mayday24
83
83
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2 Answers
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$begingroup$
You have to apply the rule corresponding to the principal connective of the negated formula.
Assuming the usual convention for omitting parentheses, we have that conjunction and disjunction symbols apply to as little as possible.
Thus, the formula will be read as :
$¬[(p∨q) to ((¬p∧q)∨p∨¬q)]$.
In this case, the formula is the negation of a conditional; thus, you have to start using the rule :
$lnot (alpha to beta)$.
$endgroup$
add a comment |
$begingroup$
Thank you! I apply the rest of Tableaux Method if can be useful for someone.
$p vee q$ $[mu_1]$from rule of AND. I apply tableaux method for this point later..
$ neg ( (neg p wedge q) vee p vee neg q)$ from rule of AND, associative property
$ neg (neg p wedge q) wedge neg(p vee neg q)$ de Morgan property
$neg (neg p wedge q) $ rule of AND
$neg(p vee neg q)$ rule of OR
$p vee neg q $ $[mu_2]$
$neg p wedge q $
$neg p$
$q$
..apply first OR $[mu_1]$
$beta_1$ branch: $p$ clash! Branch closed.
$beta_2$ branch: $q$
..apply second OR $[mu_2]$
$beta_{2_1}$ branch: $p$ clash! Branch closed.
$beta_{2_2}$ branch: $neg q$ clash! Branch closed.
We can say that $phi$ is UNSAT.
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You have to apply the rule corresponding to the principal connective of the negated formula.
Assuming the usual convention for omitting parentheses, we have that conjunction and disjunction symbols apply to as little as possible.
Thus, the formula will be read as :
$¬[(p∨q) to ((¬p∧q)∨p∨¬q)]$.
In this case, the formula is the negation of a conditional; thus, you have to start using the rule :
$lnot (alpha to beta)$.
$endgroup$
add a comment |
$begingroup$
You have to apply the rule corresponding to the principal connective of the negated formula.
Assuming the usual convention for omitting parentheses, we have that conjunction and disjunction symbols apply to as little as possible.
Thus, the formula will be read as :
$¬[(p∨q) to ((¬p∧q)∨p∨¬q)]$.
In this case, the formula is the negation of a conditional; thus, you have to start using the rule :
$lnot (alpha to beta)$.
$endgroup$
add a comment |
$begingroup$
You have to apply the rule corresponding to the principal connective of the negated formula.
Assuming the usual convention for omitting parentheses, we have that conjunction and disjunction symbols apply to as little as possible.
Thus, the formula will be read as :
$¬[(p∨q) to ((¬p∧q)∨p∨¬q)]$.
In this case, the formula is the negation of a conditional; thus, you have to start using the rule :
$lnot (alpha to beta)$.
$endgroup$
You have to apply the rule corresponding to the principal connective of the negated formula.
Assuming the usual convention for omitting parentheses, we have that conjunction and disjunction symbols apply to as little as possible.
Thus, the formula will be read as :
$¬[(p∨q) to ((¬p∧q)∨p∨¬q)]$.
In this case, the formula is the negation of a conditional; thus, you have to start using the rule :
$lnot (alpha to beta)$.
edited Mar 12 at 15:45
answered Mar 12 at 15:39
Mauro ALLEGRANZAMauro ALLEGRANZA
67.2k449115
67.2k449115
add a comment |
add a comment |
$begingroup$
Thank you! I apply the rest of Tableaux Method if can be useful for someone.
$p vee q$ $[mu_1]$from rule of AND. I apply tableaux method for this point later..
$ neg ( (neg p wedge q) vee p vee neg q)$ from rule of AND, associative property
$ neg (neg p wedge q) wedge neg(p vee neg q)$ de Morgan property
$neg (neg p wedge q) $ rule of AND
$neg(p vee neg q)$ rule of OR
$p vee neg q $ $[mu_2]$
$neg p wedge q $
$neg p$
$q$
..apply first OR $[mu_1]$
$beta_1$ branch: $p$ clash! Branch closed.
$beta_2$ branch: $q$
..apply second OR $[mu_2]$
$beta_{2_1}$ branch: $p$ clash! Branch closed.
$beta_{2_2}$ branch: $neg q$ clash! Branch closed.
We can say that $phi$ is UNSAT.
$endgroup$
add a comment |
$begingroup$
Thank you! I apply the rest of Tableaux Method if can be useful for someone.
$p vee q$ $[mu_1]$from rule of AND. I apply tableaux method for this point later..
$ neg ( (neg p wedge q) vee p vee neg q)$ from rule of AND, associative property
$ neg (neg p wedge q) wedge neg(p vee neg q)$ de Morgan property
$neg (neg p wedge q) $ rule of AND
$neg(p vee neg q)$ rule of OR
$p vee neg q $ $[mu_2]$
$neg p wedge q $
$neg p$
$q$
..apply first OR $[mu_1]$
$beta_1$ branch: $p$ clash! Branch closed.
$beta_2$ branch: $q$
..apply second OR $[mu_2]$
$beta_{2_1}$ branch: $p$ clash! Branch closed.
$beta_{2_2}$ branch: $neg q$ clash! Branch closed.
We can say that $phi$ is UNSAT.
$endgroup$
add a comment |
$begingroup$
Thank you! I apply the rest of Tableaux Method if can be useful for someone.
$p vee q$ $[mu_1]$from rule of AND. I apply tableaux method for this point later..
$ neg ( (neg p wedge q) vee p vee neg q)$ from rule of AND, associative property
$ neg (neg p wedge q) wedge neg(p vee neg q)$ de Morgan property
$neg (neg p wedge q) $ rule of AND
$neg(p vee neg q)$ rule of OR
$p vee neg q $ $[mu_2]$
$neg p wedge q $
$neg p$
$q$
..apply first OR $[mu_1]$
$beta_1$ branch: $p$ clash! Branch closed.
$beta_2$ branch: $q$
..apply second OR $[mu_2]$
$beta_{2_1}$ branch: $p$ clash! Branch closed.
$beta_{2_2}$ branch: $neg q$ clash! Branch closed.
We can say that $phi$ is UNSAT.
$endgroup$
Thank you! I apply the rest of Tableaux Method if can be useful for someone.
$p vee q$ $[mu_1]$from rule of AND. I apply tableaux method for this point later..
$ neg ( (neg p wedge q) vee p vee neg q)$ from rule of AND, associative property
$ neg (neg p wedge q) wedge neg(p vee neg q)$ de Morgan property
$neg (neg p wedge q) $ rule of AND
$neg(p vee neg q)$ rule of OR
$p vee neg q $ $[mu_2]$
$neg p wedge q $
$neg p$
$q$
..apply first OR $[mu_1]$
$beta_1$ branch: $p$ clash! Branch closed.
$beta_2$ branch: $q$
..apply second OR $[mu_2]$
$beta_{2_1}$ branch: $p$ clash! Branch closed.
$beta_{2_2}$ branch: $neg q$ clash! Branch closed.
We can say that $phi$ is UNSAT.
edited Mar 12 at 16:20
answered Mar 12 at 16:15
mayday24mayday24
83
83
add a comment |
add a comment |
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