Application of winding number and the roots of complex polynomial from a non simple closed cuvreroots of...

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Application of winding number and the roots of complex polynomial from a non simple closed cuvre


roots of $f(z)=z^4+8z^3+3z^2+8z+3=0$ in the right half planeLemma in deriving the winding number?Homotopy invariance of winding number in complex analysis.Defining the winding number for a general curveWinding number of a simple closed curve in a plane.Is there a closed loop in the complex plane such that for any given integer $x$, I can find a point inside the loop that has winding number $x$?closed path, winding number, Jordan contourWinding number in physics and mathematicsconnection between winding number and topological degreeWhen is the winding number undefined













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$begingroup$


There is a formula for the simple closed curve $gamma(t)$ and complex polynomial $p(z)$. The winding number of $p(gamma)$ around (0,0) is the sum of roots counting multiplicity of $p(z)$ within the closed curve $gamma(t)$. This is just a direct result from the argument principle.



Now I want to ask what if the closed curve $gamma(t)$ is NOT simple anymore which means it may have self-intersections. What will the winding number $w(p(gamma),(0,0))$ be? I think it should be still related to the roots of $p(z)$










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    1












    $begingroup$


    There is a formula for the simple closed curve $gamma(t)$ and complex polynomial $p(z)$. The winding number of $p(gamma)$ around (0,0) is the sum of roots counting multiplicity of $p(z)$ within the closed curve $gamma(t)$. This is just a direct result from the argument principle.



    Now I want to ask what if the closed curve $gamma(t)$ is NOT simple anymore which means it may have self-intersections. What will the winding number $w(p(gamma),(0,0))$ be? I think it should be still related to the roots of $p(z)$










    share|cite|improve this question









    New contributor




    Phoebe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$















      1












      1








      1





      $begingroup$


      There is a formula for the simple closed curve $gamma(t)$ and complex polynomial $p(z)$. The winding number of $p(gamma)$ around (0,0) is the sum of roots counting multiplicity of $p(z)$ within the closed curve $gamma(t)$. This is just a direct result from the argument principle.



      Now I want to ask what if the closed curve $gamma(t)$ is NOT simple anymore which means it may have self-intersections. What will the winding number $w(p(gamma),(0,0))$ be? I think it should be still related to the roots of $p(z)$










      share|cite|improve this question









      New contributor




      Phoebe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      There is a formula for the simple closed curve $gamma(t)$ and complex polynomial $p(z)$. The winding number of $p(gamma)$ around (0,0) is the sum of roots counting multiplicity of $p(z)$ within the closed curve $gamma(t)$. This is just a direct result from the argument principle.



      Now I want to ask what if the closed curve $gamma(t)$ is NOT simple anymore which means it may have self-intersections. What will the winding number $w(p(gamma),(0,0))$ be? I think it should be still related to the roots of $p(z)$







      complex-analysis polynomials curves winding-number






      share|cite|improve this question









      New contributor




      Phoebe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|cite|improve this question









      New contributor




      Phoebe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|cite|improve this question




      share|cite|improve this question








      edited yesterday









      Martin R

      29.7k33558




      29.7k33558






      New contributor




      Phoebe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked yesterday









      Phoebe Phoebe

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      61




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      New contributor





      Phoebe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






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      Check out our Code of Conduct.






















          1 Answer
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          active

          oldest

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          0












          $begingroup$

          The winding number of $p circ gamma $ with respect to $0$ is
          $$
          I(p circ gamma,0) = frac{1}{2pi i}int_{p circ gamma} frac{dw}{w}
          = frac{1}{2pi i}int_gamma frac{p'(z)}{p(z)} , dz
          $$

          and that can be computed with the Residue theorem. If $a_1, ldots, a_m$ are the distinct roots of $p$ with multiplicities $k_1, ldots ,k_m$, then
          $$
          frac{1}{2pi i}int_gamma frac{p'(z)}{p(z)} , dz
          = sum_{j=1}^m I(gamma, a_j) operatorname{Res}(frac{p'}{p}, a_j)
          , .
          $$

          It is relatively easy to compute that the residue of $p'/p$ at a $k$-fold zero of $p$ is $k$, so that
          $$
          I(p circ gamma,0)= sum_{j=1}^m I(gamma, a_j) k_j , .
          $$

          This is the general formula.



          For a simple positively oriented closed curve $gamma$ the winding numbers $I(gamma, a_j)$ are either zero or one, and the sum reduces to
          $$
          I(p circ gamma,0) = sum_{a_j text{ inside } gamma} k_j
          $$






          share|cite|improve this answer











          $endgroup$













          • $begingroup$
            The formula for a simple closed curve is missing a sign depending on the orientation of $gamma$.
            $endgroup$
            – Paul Frost
            yesterday










          • $begingroup$
            @PaulFrost: You are right, thanks.
            $endgroup$
            – Martin R
            yesterday











          Your Answer





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          1 Answer
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          1 Answer
          1






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          active

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          0












          $begingroup$

          The winding number of $p circ gamma $ with respect to $0$ is
          $$
          I(p circ gamma,0) = frac{1}{2pi i}int_{p circ gamma} frac{dw}{w}
          = frac{1}{2pi i}int_gamma frac{p'(z)}{p(z)} , dz
          $$

          and that can be computed with the Residue theorem. If $a_1, ldots, a_m$ are the distinct roots of $p$ with multiplicities $k_1, ldots ,k_m$, then
          $$
          frac{1}{2pi i}int_gamma frac{p'(z)}{p(z)} , dz
          = sum_{j=1}^m I(gamma, a_j) operatorname{Res}(frac{p'}{p}, a_j)
          , .
          $$

          It is relatively easy to compute that the residue of $p'/p$ at a $k$-fold zero of $p$ is $k$, so that
          $$
          I(p circ gamma,0)= sum_{j=1}^m I(gamma, a_j) k_j , .
          $$

          This is the general formula.



          For a simple positively oriented closed curve $gamma$ the winding numbers $I(gamma, a_j)$ are either zero or one, and the sum reduces to
          $$
          I(p circ gamma,0) = sum_{a_j text{ inside } gamma} k_j
          $$






          share|cite|improve this answer











          $endgroup$













          • $begingroup$
            The formula for a simple closed curve is missing a sign depending on the orientation of $gamma$.
            $endgroup$
            – Paul Frost
            yesterday










          • $begingroup$
            @PaulFrost: You are right, thanks.
            $endgroup$
            – Martin R
            yesterday
















          0












          $begingroup$

          The winding number of $p circ gamma $ with respect to $0$ is
          $$
          I(p circ gamma,0) = frac{1}{2pi i}int_{p circ gamma} frac{dw}{w}
          = frac{1}{2pi i}int_gamma frac{p'(z)}{p(z)} , dz
          $$

          and that can be computed with the Residue theorem. If $a_1, ldots, a_m$ are the distinct roots of $p$ with multiplicities $k_1, ldots ,k_m$, then
          $$
          frac{1}{2pi i}int_gamma frac{p'(z)}{p(z)} , dz
          = sum_{j=1}^m I(gamma, a_j) operatorname{Res}(frac{p'}{p}, a_j)
          , .
          $$

          It is relatively easy to compute that the residue of $p'/p$ at a $k$-fold zero of $p$ is $k$, so that
          $$
          I(p circ gamma,0)= sum_{j=1}^m I(gamma, a_j) k_j , .
          $$

          This is the general formula.



          For a simple positively oriented closed curve $gamma$ the winding numbers $I(gamma, a_j)$ are either zero or one, and the sum reduces to
          $$
          I(p circ gamma,0) = sum_{a_j text{ inside } gamma} k_j
          $$






          share|cite|improve this answer











          $endgroup$













          • $begingroup$
            The formula for a simple closed curve is missing a sign depending on the orientation of $gamma$.
            $endgroup$
            – Paul Frost
            yesterday










          • $begingroup$
            @PaulFrost: You are right, thanks.
            $endgroup$
            – Martin R
            yesterday














          0












          0








          0





          $begingroup$

          The winding number of $p circ gamma $ with respect to $0$ is
          $$
          I(p circ gamma,0) = frac{1}{2pi i}int_{p circ gamma} frac{dw}{w}
          = frac{1}{2pi i}int_gamma frac{p'(z)}{p(z)} , dz
          $$

          and that can be computed with the Residue theorem. If $a_1, ldots, a_m$ are the distinct roots of $p$ with multiplicities $k_1, ldots ,k_m$, then
          $$
          frac{1}{2pi i}int_gamma frac{p'(z)}{p(z)} , dz
          = sum_{j=1}^m I(gamma, a_j) operatorname{Res}(frac{p'}{p}, a_j)
          , .
          $$

          It is relatively easy to compute that the residue of $p'/p$ at a $k$-fold zero of $p$ is $k$, so that
          $$
          I(p circ gamma,0)= sum_{j=1}^m I(gamma, a_j) k_j , .
          $$

          This is the general formula.



          For a simple positively oriented closed curve $gamma$ the winding numbers $I(gamma, a_j)$ are either zero or one, and the sum reduces to
          $$
          I(p circ gamma,0) = sum_{a_j text{ inside } gamma} k_j
          $$






          share|cite|improve this answer











          $endgroup$



          The winding number of $p circ gamma $ with respect to $0$ is
          $$
          I(p circ gamma,0) = frac{1}{2pi i}int_{p circ gamma} frac{dw}{w}
          = frac{1}{2pi i}int_gamma frac{p'(z)}{p(z)} , dz
          $$

          and that can be computed with the Residue theorem. If $a_1, ldots, a_m$ are the distinct roots of $p$ with multiplicities $k_1, ldots ,k_m$, then
          $$
          frac{1}{2pi i}int_gamma frac{p'(z)}{p(z)} , dz
          = sum_{j=1}^m I(gamma, a_j) operatorname{Res}(frac{p'}{p}, a_j)
          , .
          $$

          It is relatively easy to compute that the residue of $p'/p$ at a $k$-fold zero of $p$ is $k$, so that
          $$
          I(p circ gamma,0)= sum_{j=1}^m I(gamma, a_j) k_j , .
          $$

          This is the general formula.



          For a simple positively oriented closed curve $gamma$ the winding numbers $I(gamma, a_j)$ are either zero or one, and the sum reduces to
          $$
          I(p circ gamma,0) = sum_{a_j text{ inside } gamma} k_j
          $$







          share|cite|improve this answer














          share|cite|improve this answer



          share|cite|improve this answer








          edited yesterday

























          answered yesterday









          Martin RMartin R

          29.7k33558




          29.7k33558












          • $begingroup$
            The formula for a simple closed curve is missing a sign depending on the orientation of $gamma$.
            $endgroup$
            – Paul Frost
            yesterday










          • $begingroup$
            @PaulFrost: You are right, thanks.
            $endgroup$
            – Martin R
            yesterday


















          • $begingroup$
            The formula for a simple closed curve is missing a sign depending on the orientation of $gamma$.
            $endgroup$
            – Paul Frost
            yesterday










          • $begingroup$
            @PaulFrost: You are right, thanks.
            $endgroup$
            – Martin R
            yesterday
















          $begingroup$
          The formula for a simple closed curve is missing a sign depending on the orientation of $gamma$.
          $endgroup$
          – Paul Frost
          yesterday




          $begingroup$
          The formula for a simple closed curve is missing a sign depending on the orientation of $gamma$.
          $endgroup$
          – Paul Frost
          yesterday












          $begingroup$
          @PaulFrost: You are right, thanks.
          $endgroup$
          – Martin R
          yesterday




          $begingroup$
          @PaulFrost: You are right, thanks.
          $endgroup$
          – Martin R
          yesterday










          Phoebe is a new contributor. Be nice, and check out our Code of Conduct.










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