Dtjytyk

Why datecode is SO IMPORTANT to chip manufacturers?

A proverb that is used to imply that you have unexpectedly faced a big problem

Simple Http Server

Caught masturbating at work

Was Kant an Intuitionist about mathematical objects?

Why is the change of basis formula counter-intuitive? [See details]

AppleTVs create a chatty alternate WiFi network

What does Turing mean by this statement?

Relating to the President and obstruction, were Mueller's conclusions preordained?

Project Euler #1 in C++

One-one communication

Is there public access to the Meteor Crater in Arizona?

My mentor says to set image to Fine instead of RAW — how is this different from JPG?

How can a team of shapeshifters communicate?

Tannaka duality for semisimple groups

How to ask rejected full-time candidates to apply to teach individual courses?

What is the difference between a "ranged attack" and a "ranged weapon attack"?

What is the origin of 落第?

As a dual citizen, my US passport will expire one day after traveling to the US. Will this work?

Co-worker has annoying ringtone

What does 丫 mean? 丫是什么意思？

Moving a wrapfig vertically to encroach partially on a subsection title

Sally's older brother

How many time has Arya actually used Needle?

Is this a correct example and application for differentiation calculus?

-1

$begingroup$

Let’s suppose you are driving from your home to your friend’s place. Assume that there is a speed limit of 50Km/hr. Assume, it takes 1 hr to reach at your friend’s place. So, if you are driving at constant 50km/hr, you will reach after 1 hr.

Suppose, you were driving at 45Km/hr while you were passing through the traffic cameras and you were travelling at 55Km/hr at some point.

Application of Differentiation
the differentiation gives you at what interval what was your speed.
Basically, it tells your instantaneous velocity i.e. the speed at a particular time. So, that’s the power of differentiation. For e.g. somebody found that the relation between your position with respect to time. Perhaps, with gps map, they found the relationship position vs. time for your entire journey.

Distance covered = p^2 t + pt + p
where p is position and t is time.

So, do a differentiation now with respect to time to find out your speed at a particular time interval.

d(Distance)/dt i.e. velocity = 2pt + p + 0

So, let’s say at 0.5 hrs, your speed was -

let’s say you know the position also , it is 2.
Now, your speed was - 2*2*0.5 + 2 = 4km/hr.

Since your position was 4km/hr, you don’t have to be given a fine.

Is this a correct application?
Can a distance covered can be in terms of position and time?
Also, differentiating will give us velocity isn't it correct?

calculus

share|cite|improve this question

asked Mar 26 at 0:19

Prawn HongsPrawn Hongs

1

$endgroup$

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  You're missing a lot of physics concepts in there. I suppose it might be better to ask on the physics section instead. Nevertheless, note that your equation of movement on a straight line should be: $x(t) = x_0 + v_0 t + a t^2/2$ only when the acceleration $a$ is constant (note that the equation is different from what you wrote). If $a$ changes with time you would need to compute integrals to get the velocity $v(t)$ as a function of time and the position $x(t)$ as a function of time.
  $endgroup$
  – Ertxiem
  Mar 26 at 0:40
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Many questions and mixing "uniform motion" with "motion with constant acceleration" with "motion without constant acceleration"(?). How is the behavior of the car when passing through the traffic cameras in terms of acceleration? See en.wikiversity.org/wiki/Motion_-_Kinematics and physics.info/kinematics-calculus
  $endgroup$
  – cgiovanardi
  Mar 26 at 23:56
  

  
  
  
  

add a comment | 

-1

$begingroup$

Let’s suppose you are driving from your home to your friend’s place. Assume that there is a speed limit of 50Km/hr. Assume, it takes 1 hr to reach at your friend’s place. So, if you are driving at constant 50km/hr, you will reach after 1 hr.

Suppose, you were driving at 45Km/hr while you were passing through the traffic cameras and you were travelling at 55Km/hr at some point.

Application of Differentiation
the differentiation gives you at what interval what was your speed.
Basically, it tells your instantaneous velocity i.e. the speed at a particular time. So, that’s the power of differentiation. For e.g. somebody found that the relation between your position with respect to time. Perhaps, with gps map, they found the relationship position vs. time for your entire journey.

Distance covered = p^2 t + pt + p
where p is position and t is time.

So, do a differentiation now with respect to time to find out your speed at a particular time interval.

d(Distance)/dt i.e. velocity = 2pt + p + 0

So, let’s say at 0.5 hrs, your speed was -

let’s say you know the position also , it is 2.
Now, your speed was - 2*2*0.5 + 2 = 4km/hr.

Since your position was 4km/hr, you don’t have to be given a fine.

Is this a correct application?
Can a distance covered can be in terms of position and time?
Also, differentiating will give us velocity isn't it correct?

calculus

share|cite|improve this question

asked Mar 26 at 0:19

Prawn HongsPrawn Hongs

1

$endgroup$

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  You're missing a lot of physics concepts in there. I suppose it might be better to ask on the physics section instead. Nevertheless, note that your equation of movement on a straight line should be: $x(t) = x_0 + v_0 t + a t^2/2$ only when the acceleration $a$ is constant (note that the equation is different from what you wrote). If $a$ changes with time you would need to compute integrals to get the velocity $v(t)$ as a function of time and the position $x(t)$ as a function of time.
  $endgroup$
  – Ertxiem
  Mar 26 at 0:40
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Many questions and mixing "uniform motion" with "motion with constant acceleration" with "motion without constant acceleration"(?). How is the behavior of the car when passing through the traffic cameras in terms of acceleration? See en.wikiversity.org/wiki/Motion_-_Kinematics and physics.info/kinematics-calculus
  $endgroup$
  – cgiovanardi
  Mar 26 at 23:56
  

  
  
  
  

add a comment | 

$begingroup$

Let’s suppose you are driving from your home to your friend’s place. Assume that there is a speed limit of 50Km/hr. Assume, it takes 1 hr to reach at your friend’s place. So, if you are driving at constant 50km/hr, you will reach after 1 hr.

Suppose, you were driving at 45Km/hr while you were passing through the traffic cameras and you were travelling at 55Km/hr at some point.

Application of Differentiation
the differentiation gives you at what interval what was your speed.
Basically, it tells your instantaneous velocity i.e. the speed at a particular time. So, that’s the power of differentiation. For e.g. somebody found that the relation between your position with respect to time. Perhaps, with gps map, they found the relationship position vs. time for your entire journey.

Distance covered = p^2 t + pt + p
where p is position and t is time.

So, do a differentiation now with respect to time to find out your speed at a particular time interval.

d(Distance)/dt i.e. velocity = 2pt + p + 0

So, let’s say at 0.5 hrs, your speed was -

let’s say you know the position also , it is 2.
Now, your speed was - 2*2*0.5 + 2 = 4km/hr.

Since your position was 4km/hr, you don’t have to be given a fine.

Is this a correct application?
Can a distance covered can be in terms of position and time?
Also, differentiating will give us velocity isn't it correct?

calculus

share|cite|improve this question

asked Mar 26 at 0:19

Prawn HongsPrawn Hongs

1

$endgroup$

share|cite|improve this question

asked Mar 26 at 0:19

Prawn HongsPrawn Hongs

1

share|cite|improve this question

asked Mar 26 at 0:19

Prawn HongsPrawn Hongs

1

asked Mar 26 at 0:19

Prawn HongsPrawn Hongs

1

asked Mar 26 at 0:19

Prawn HongsPrawn Hongs

1