Algebra: Linear Equations & Graphs. A doubt with Slope - intercept form & Point - slope form.Finding...
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Algebra: Linear Equations & Graphs. A doubt with Slope - intercept form & Point - slope form.
Finding the coordinates of the point where each line crosses the $y$-axisProblem with graphing linear equationsCorrect standard form for the equation of a line?“Write an equation of line J, that passes through P, and is parallel to given line L”Show an equation of a line passing through $P$ and parallel to the line given by $ax+by+c=0$.Finding the equation of the tangent (in slope-intercept form) at a particular point?mysterious in slope-intercept form of the equation of the lineAn odd point in a cubic equationIf $(5,8)$ is a point on the graph of $f(x)$, find $2f(x)-9$For which values of $p$ is the line $y_p(x)$ tangent to $f(x)$
$begingroup$
Slope - intercept form : y = mx + b
Point - slope form :
m (x - a) = y - b
mx - ma = y - b
y = mx - ma + b
As ma & b are constants, b - ma = c
y = mx + c
It seems like the two forms are the same. Then why name them different ?
Thanks in advance!
algebra-precalculus
asked Mar 10 at 14:28
Deepak S.MDeepak S.M
33
$endgroup$
add a comment |
$begingroup$
Slope - intercept form : y = mx + b
Point - slope form :
m (x - a) = y - b
mx - ma = y - b
y = mx - ma + b
As ma & b are constants, b - ma = c
y = mx + c
It seems like the two forms are the same. Then why name them different ?
Thanks in advance!
algebra-precalculus
asked Mar 10 at 14:28
Deepak S.MDeepak S.M
33
$endgroup$
$begingroup$
They’re written in different forms but equivalent
$endgroup$
– J. W. Tanner
Mar 10 at 14:33
$begingroup$
I see, Is there any use to writing them in different forms ?
$endgroup$
– Deepak S.M
Mar 10 at 14:40
$begingroup$
With one form you can see the intercept right away; with another you can see a point on the line right away
$endgroup$
– J. W. Tanner
Mar 10 at 14:41
$begingroup$
Oh.. Thanks! :)
$endgroup$
– Deepak S.M
Mar 10 at 14:54
add a comment |
$begingroup$
Slope - intercept form : y = mx + b
Point - slope form :
m (x - a) = y - b
mx - ma = y - b
y = mx - ma + b
As ma & b are constants, b - ma = c
y = mx + c
It seems like the two forms are the same. Then why name them different ?
Thanks in advance!
algebra-precalculus
asked Mar 10 at 14:28
Deepak S.MDeepak S.M
33
$endgroup$
Slope - intercept form : y = mx + b
Point - slope form :
m (x - a) = y - b
mx - ma = y - b
y = mx - ma + b
As ma & b are constants, b - ma = c
y = mx + c
It seems like the two forms are the same. Then why name them different ?
Thanks in advance!
algebra-precalculus
algebra-precalculus
asked Mar 10 at 14:28
Deepak S.MDeepak S.M
33
asked Mar 10 at 14:28
Deepak S.MDeepak S.M
33
asked Mar 10 at 14:28
Deepak S.MDeepak S.M
33
asked Mar 10 at 14:28
Deepak S.MDeepak S.M
33
asked Mar 10 at 14:28
Deepak S.MDeepak S.M
33
33
$begingroup$
They’re written in different forms but equivalent
$endgroup$
– J. W. Tanner
Mar 10 at 14:33
$begingroup$
I see, Is there any use to writing them in different forms ?
$endgroup$
– Deepak S.M
Mar 10 at 14:40
$begingroup$
With one form you can see the intercept right away; with another you can see a point on the line right away
$endgroup$
– J. W. Tanner
Mar 10 at 14:41
$begingroup$
Oh.. Thanks! :)
$endgroup$
– Deepak S.M
Mar 10 at 14:54
add a comment |
$begingroup$
They’re written in different forms but equivalent
$endgroup$
– J. W. Tanner
Mar 10 at 14:33
$begingroup$
I see, Is there any use to writing them in different forms ?
$endgroup$
– Deepak S.M
Mar 10 at 14:40
$begingroup$
With one form you can see the intercept right away; with another you can see a point on the line right away
$endgroup$
– J. W. Tanner
Mar 10 at 14:41
$begingroup$
Oh.. Thanks! :)
$endgroup$
– Deepak S.M
Mar 10 at 14:54
$begingroup$
They’re written in different forms but equivalent
$endgroup$
– J. W. Tanner
Mar 10 at 14:33
$begingroup$
They’re written in different forms but equivalent
$endgroup$
– J. W. Tanner
Mar 10 at 14:33
$begingroup$
I see, Is there any use to writing them in different forms ?
$endgroup$
– Deepak S.M
Mar 10 at 14:40
$begingroup$
I see, Is there any use to writing them in different forms ?
$endgroup$
– Deepak S.M
Mar 10 at 14:40
$begingroup$
With one form you can see the intercept right away; with another you can see a point on the line right away
$endgroup$
– J. W. Tanner
Mar 10 at 14:41
$begingroup$
With one form you can see the intercept right away; with another you can see a point on the line right away
$endgroup$
– J. W. Tanner
Mar 10 at 14:41
$begingroup$
Oh.. Thanks! :)
$endgroup$
– Deepak S.M
Mar 10 at 14:54
$begingroup$
Oh.. Thanks! :)
$endgroup$
– Deepak S.M
Mar 10 at 14:54
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
There are several forms for a linear equation, including $ax+by=0$, $y=mx+b$, $y-y_1=m(x-x_1)$, and $frac x {x_0} + frac y {y_0} = 1,$ and the two-point form. They are all equivalent. Particular forms are useful for seeing particular parameters.
answered Mar 10 at 14:58
J. W. TannerJ. W. Tanner
3,2401320
$endgroup$
$begingroup$
Thank you so much for further explanation! :)
$endgroup$
– Deepak S.M
Mar 10 at 15:04
add a comment |
Your Answer
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1 Answer
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active
oldest
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1 Answer
1
active
oldest
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oldest
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active
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$begingroup$
There are several forms for a linear equation, including $ax+by=0$, $y=mx+b$, $y-y_1=m(x-x_1)$, and $frac x {x_0} + frac y {y_0} = 1,$ and the two-point form. They are all equivalent. Particular forms are useful for seeing particular parameters.
answered Mar 10 at 14:58
J. W. TannerJ. W. Tanner
3,2401320
$endgroup$
$begingroup$
Thank you so much for further explanation! :)
$endgroup$
– Deepak S.M
Mar 10 at 15:04
add a comment |
$begingroup$
There are several forms for a linear equation, including $ax+by=0$, $y=mx+b$, $y-y_1=m(x-x_1)$, and $frac x {x_0} + frac y {y_0} = 1,$ and the two-point form. They are all equivalent. Particular forms are useful for seeing particular parameters.
answered Mar 10 at 14:58
J. W. TannerJ. W. Tanner
3,2401320
$endgroup$
$begingroup$
Thank you so much for further explanation! :)
$endgroup$
– Deepak S.M
Mar 10 at 15:04
add a comment |
$begingroup$
There are several forms for a linear equation, including $ax+by=0$, $y=mx+b$, $y-y_1=m(x-x_1)$, and $frac x {x_0} + frac y {y_0} = 1,$ and the two-point form. They are all equivalent. Particular forms are useful for seeing particular parameters.
answered Mar 10 at 14:58
J. W. TannerJ. W. Tanner
3,2401320
$endgroup$
There are several forms for a linear equation, including $ax+by=0$, $y=mx+b$, $y-y_1=m(x-x_1)$, and $frac x {x_0} + frac y {y_0} = 1,$ and the two-point form. They are all equivalent. Particular forms are useful for seeing particular parameters.
answered Mar 10 at 14:58
J. W. TannerJ. W. Tanner
3,2401320
answered Mar 10 at 14:58
J. W. TannerJ. W. Tanner
3,2401320
answered Mar 10 at 14:58
J. W. TannerJ. W. Tanner
3,2401320
answered Mar 10 at 14:58
J. W. TannerJ. W. Tanner
3,2401320
3,2401320
$begingroup$
Thank you so much for further explanation! :)
$endgroup$
– Deepak S.M
Mar 10 at 15:04
add a comment |
$begingroup$
Thank you so much for further explanation! :)
$endgroup$
– Deepak S.M
Mar 10 at 15:04
$begingroup$
Thank you so much for further explanation! :)
$endgroup$
– Deepak S.M
Mar 10 at 15:04
$begingroup$
Thank you so much for further explanation! :)
$endgroup$
– Deepak S.M
Mar 10 at 15:04
add a comment |
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$begingroup$
They’re written in different forms but equivalent
$endgroup$
– J. W. Tanner
Mar 10 at 14:33
$begingroup$
I see, Is there any use to writing them in different forms ?
$endgroup$
– Deepak S.M
Mar 10 at 14:40
$begingroup$
With one form you can see the intercept right away; with another you can see a point on the line right away
$endgroup$
– J. W. Tanner
Mar 10 at 14:41
$begingroup$
Oh.. Thanks! :)
$endgroup$
– Deepak S.M
Mar 10 at 14:54