Java parenthesis replacement with empty string2019 Community Moderator ElectionReference - What does this...
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Java parenthesis replacement with empty string
2019 Community Moderator ElectionReference - What does this regex mean?What is the difference between String and string in C#?Is Java “pass-by-reference” or “pass-by-value”?How do I read / convert an InputStream into a String in Java?Case insensitive 'Contains(string)'How to replace all occurrences of a string in JavaScriptHow to check whether a string contains a substring in JavaScript?Does Python have a string 'contains' substring method?How to split a string in JavaHow do I convert a String to an int in Java?Why is char[] preferred over String for passwords?
Why doesn't the first line replace "(" with an empty string , while the second one does?
public static void main(String []args){
String a="This(rab)(bar)";
a=a.replace("\(",""); //First
String b=a.replaceFirst("\(","");//Second
System.out.println(a + " "+b);
}
java string replace
asked Mar 10 at 9:12
Erik NouroyanErik Nouroyan
342
New contributor
Erik Nouroyan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
Why doesn't the first line replace "(" with an empty string , while the second one does?
public static void main(String []args){
String a="This(rab)(bar)";
a=a.replace("\(",""); //First
String b=a.replaceFirst("\(","");//Second
System.out.println(a + " "+b);
}
java string replace
asked Mar 10 at 9:12
Erik NouroyanErik Nouroyan
342
New contributor
Erik Nouroyan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
Why doesn't the first line replace "(" with an empty string , while the second one does?
public static void main(String []args){
String a="This(rab)(bar)";
a=a.replace("\(",""); //First
String b=a.replaceFirst("\(","");//Second
System.out.println(a + " "+b);
}
java string replace
asked Mar 10 at 9:12
Erik NouroyanErik Nouroyan
342
New contributor
Erik Nouroyan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Why doesn't the first line replace "(" with an empty string , while the second one does?
public static void main(String []args){
String a="This(rab)(bar)";
a=a.replace("\(",""); //First
String b=a.replaceFirst("\(","");//Second
System.out.println(a + " "+b);
}
java string replace
java string replace
asked Mar 10 at 9:12
Erik NouroyanErik Nouroyan
342
New contributor
Erik Nouroyan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Mar 10 at 9:12
Erik NouroyanErik Nouroyan
342
New contributor
Erik Nouroyan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Mar 10 at 9:12
Erik NouroyanErik Nouroyan
342
New contributor
Erik Nouroyan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Mar 10 at 9:12
Erik NouroyanErik Nouroyan
342
asked Mar 10 at 9:12
Erik NouroyanErik Nouroyan
342
342
New contributor
Erik Nouroyan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Erik Nouroyan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Erik Nouroyan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
There is a difference between replace and replaceFirst. If your IDE shows you the method signatures, you'll see:
See how replace accepts a plain old target whereas replaceFirst accepts a regex?
"\(" is a regex that means "a single open parenthesis". replace doesn't treat the strings you pass in as regexes. It will simply try to find a backslash followed by an open parenthesis, which does not exist in your string.
If you want to use replace, just use "(".
answered Mar 10 at 9:16
SweeperSweeper
70k1074142
So isn't this "(" a regex? It's a string isn't it?
– Erik Nouroyan
Mar 10 at 9:23
@ErikNouroyan(is not a valid regex. It doesn’t mean “match an open parenthesis”.(is valid regex that means “Match an open parenthesis”. In java string literals, the backslash gets escapes to become ``.
– Sweeper
Mar 10 at 9:28
why does replaceFirst take "\( " as a single paranthesis insted of backslash and single paranthesis?
– Erik Nouroyan
Mar 10 at 9:30
Because(is a regex that means “one opening parenthesis” andreplaceFirstaccepts a regex.(on its own has special meaning in regex - start of a capturing group, so you need to escape it with `` to mean “one open parenthesis”. @ErikNouroyan
– Sweeper
Mar 10 at 9:33
1
stackoverflow.com/a/22944075/5133585 might help. @ErikNouroyan
– Sweeper
Mar 10 at 9:37
|
show 2 more comments
For replace to work you should write:
a=a.replace("(",""); //First
or use replaceAll if you want to pass a regex:
a=a.replaceAll("\(",""); //First
replace accepts a sequence of characters to replace:
public String replace(CharSequence target, CharSequence replacement)
Therefore, in your case it attempts to replace the 3 characters "(", not just the single character "(".
answered Mar 10 at 9:16
EranEran
288k37471561
In that case why doesn't this work? a=a.replace("(",""); //First
– Erik Nouroyan
Mar 10 at 9:17
@ErikNouroyanreplacedoes not expect a regex as the first argument. Therefore it tried to replace the actual sub-string "\(", which is not present ina.
– Eran
Mar 10 at 9:18
add a comment |
The problem is that it is running in replace with several characters and, therefore, what it will look for is and (, so that this does not happen the quotation marks should only contain the character to replace :
a = a.replace("(", ""); // First
Next I leave a sniper with the original proposal and the fixed one :
public class Main {
private static final Main initRun = new Main();
public static void main(String[] args) {
String a = "This(rab)(bar)";
System.out.println("Original");
initRun.runOriginal(a);
System.out.println("Fixed");
initRun.runFixed(a);
// Output
// Original
// This(rab)(bar)
// Thisrab)(bar)
// Fixed
// Thisrab)bar)
// Thisrab)bar)
}
/**
* Execute the original proposal
*
* @param a String for replace
*/
void runOriginal(String a) {
a = a.replace("\(", ""); // First
String b = a.replaceFirst("\(", "");// Second
System.out.println(a + "n" + b);
}
/**
* Execute the fixed proposal
*
* @param a String for replace
*/
void runFixed(String a) {
a = a.replace("(", ""); // First
String b = a.replaceFirst("\(", "");// Second
System.out.println(a + "n" + b);
}
}
answered Mar 10 at 9:52
Nicolás Alarcón RapelaNicolás Alarcón Rapela
1,164624
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
There is a difference between replace and replaceFirst. If your IDE shows you the method signatures, you'll see:
See how replace accepts a plain old target whereas replaceFirst accepts a regex?
"\(" is a regex that means "a single open parenthesis". replace doesn't treat the strings you pass in as regexes. It will simply try to find a backslash followed by an open parenthesis, which does not exist in your string.
If you want to use replace, just use "(".
answered Mar 10 at 9:16
SweeperSweeper
70k1074142
So isn't this "(" a regex? It's a string isn't it?
– Erik Nouroyan
Mar 10 at 9:23
@ErikNouroyan(is not a valid regex. It doesn’t mean “match an open parenthesis”.(is valid regex that means “Match an open parenthesis”. In java string literals, the backslash gets escapes to become ``.
– Sweeper
Mar 10 at 9:28
why does replaceFirst take "\( " as a single paranthesis insted of backslash and single paranthesis?
– Erik Nouroyan
Mar 10 at 9:30
Because(is a regex that means “one opening parenthesis” andreplaceFirstaccepts a regex.(on its own has special meaning in regex - start of a capturing group, so you need to escape it with `` to mean “one open parenthesis”. @ErikNouroyan
– Sweeper
Mar 10 at 9:33
1
stackoverflow.com/a/22944075/5133585 might help. @ErikNouroyan
– Sweeper
Mar 10 at 9:37
|
show 2 more comments
There is a difference between replace and replaceFirst. If your IDE shows you the method signatures, you'll see:
See how replace accepts a plain old target whereas replaceFirst accepts a regex?
"\(" is a regex that means "a single open parenthesis". replace doesn't treat the strings you pass in as regexes. It will simply try to find a backslash followed by an open parenthesis, which does not exist in your string.
If you want to use replace, just use "(".
answered Mar 10 at 9:16
SweeperSweeper
70k1074142
So isn't this "(" a regex? It's a string isn't it?
– Erik Nouroyan
Mar 10 at 9:23
@ErikNouroyan(is not a valid regex. It doesn’t mean “match an open parenthesis”.(is valid regex that means “Match an open parenthesis”. In java string literals, the backslash gets escapes to become ``.
– Sweeper
Mar 10 at 9:28
why does replaceFirst take "\( " as a single paranthesis insted of backslash and single paranthesis?
– Erik Nouroyan
Mar 10 at 9:30
Because(is a regex that means “one opening parenthesis” andreplaceFirstaccepts a regex.(on its own has special meaning in regex - start of a capturing group, so you need to escape it with `` to mean “one open parenthesis”. @ErikNouroyan
– Sweeper
Mar 10 at 9:33
1
stackoverflow.com/a/22944075/5133585 might help. @ErikNouroyan
– Sweeper
Mar 10 at 9:37
|
show 2 more comments
There is a difference between replace and replaceFirst. If your IDE shows you the method signatures, you'll see:
See how replace accepts a plain old target whereas replaceFirst accepts a regex?
"\(" is a regex that means "a single open parenthesis". replace doesn't treat the strings you pass in as regexes. It will simply try to find a backslash followed by an open parenthesis, which does not exist in your string.
If you want to use replace, just use "(".
answered Mar 10 at 9:16
SweeperSweeper
70k1074142
There is a difference between replace and replaceFirst. If your IDE shows you the method signatures, you'll see:
See how replace accepts a plain old target whereas replaceFirst accepts a regex?
"\(" is a regex that means "a single open parenthesis". replace doesn't treat the strings you pass in as regexes. It will simply try to find a backslash followed by an open parenthesis, which does not exist in your string.
If you want to use replace, just use "(".
answered Mar 10 at 9:16
SweeperSweeper
70k1074142
answered Mar 10 at 9:16
SweeperSweeper
70k1074142
answered Mar 10 at 9:16
SweeperSweeper
70k1074142
answered Mar 10 at 9:16
SweeperSweeper
70k1074142
70k1074142
So isn't this "(" a regex? It's a string isn't it?
– Erik Nouroyan
Mar 10 at 9:23
@ErikNouroyan(is not a valid regex. It doesn’t mean “match an open parenthesis”.(is valid regex that means “Match an open parenthesis”. In java string literals, the backslash gets escapes to become ``.
– Sweeper
Mar 10 at 9:28
why does replaceFirst take "\( " as a single paranthesis insted of backslash and single paranthesis?
– Erik Nouroyan
Mar 10 at 9:30
Because(is a regex that means “one opening parenthesis” andreplaceFirstaccepts a regex.(on its own has special meaning in regex - start of a capturing group, so you need to escape it with `` to mean “one open parenthesis”. @ErikNouroyan
– Sweeper
Mar 10 at 9:33
1
stackoverflow.com/a/22944075/5133585 might help. @ErikNouroyan
– Sweeper
Mar 10 at 9:37
|
show 2 more comments
So isn't this "(" a regex? It's a string isn't it?
– Erik Nouroyan
Mar 10 at 9:23
@ErikNouroyan(is not a valid regex. It doesn’t mean “match an open parenthesis”.(is valid regex that means “Match an open parenthesis”. In java string literals, the backslash gets escapes to become ``.
– Sweeper
Mar 10 at 9:28
why does replaceFirst take "\( " as a single paranthesis insted of backslash and single paranthesis?
– Erik Nouroyan
Mar 10 at 9:30
Because(is a regex that means “one opening parenthesis” andreplaceFirstaccepts a regex.(on its own has special meaning in regex - start of a capturing group, so you need to escape it with `` to mean “one open parenthesis”. @ErikNouroyan
– Sweeper
Mar 10 at 9:33
1
stackoverflow.com/a/22944075/5133585 might help. @ErikNouroyan
– Sweeper
Mar 10 at 9:37
So isn't this "(" a regex? It's a string isn't it?
– Erik Nouroyan
Mar 10 at 9:23
So isn't this "(" a regex? It's a string isn't it?
– Erik Nouroyan
Mar 10 at 9:23
@ErikNouroyan
( is not a valid regex. It doesn’t mean “match an open parenthesis”. ( is valid regex that means “Match an open parenthesis”. In java string literals, the backslash gets escapes to become ``.– Sweeper
Mar 10 at 9:28
@ErikNouroyan
( is not a valid regex. It doesn’t mean “match an open parenthesis”. ( is valid regex that means “Match an open parenthesis”. In java string literals, the backslash gets escapes to become ``.– Sweeper
Mar 10 at 9:28
why does replaceFirst take "\( " as a single paranthesis insted of backslash and single paranthesis?
– Erik Nouroyan
Mar 10 at 9:30
why does replaceFirst take "\( " as a single paranthesis insted of backslash and single paranthesis?
– Erik Nouroyan
Mar 10 at 9:30
Because
( is a regex that means “one opening parenthesis” and replaceFirst accepts a regex. ( on its own has special meaning in regex - start of a capturing group, so you need to escape it with `` to mean “one open parenthesis”. @ErikNouroyan– Sweeper
Mar 10 at 9:33
Because
( is a regex that means “one opening parenthesis” and replaceFirst accepts a regex. ( on its own has special meaning in regex - start of a capturing group, so you need to escape it with `` to mean “one open parenthesis”. @ErikNouroyan– Sweeper
Mar 10 at 9:33
1
1
stackoverflow.com/a/22944075/5133585 might help. @ErikNouroyan
– Sweeper
Mar 10 at 9:37
stackoverflow.com/a/22944075/5133585 might help. @ErikNouroyan
– Sweeper
Mar 10 at 9:37
|
show 2 more comments
For replace to work you should write:
a=a.replace("(",""); //First
or use replaceAll if you want to pass a regex:
a=a.replaceAll("\(",""); //First
replace accepts a sequence of characters to replace:
public String replace(CharSequence target, CharSequence replacement)
Therefore, in your case it attempts to replace the 3 characters "(", not just the single character "(".
answered Mar 10 at 9:16
EranEran
288k37471561
In that case why doesn't this work? a=a.replace("(",""); //First
– Erik Nouroyan
Mar 10 at 9:17
@ErikNouroyanreplacedoes not expect a regex as the first argument. Therefore it tried to replace the actual sub-string "\(", which is not present ina.
– Eran
Mar 10 at 9:18
add a comment |
For replace to work you should write:
a=a.replace("(",""); //First
or use replaceAll if you want to pass a regex:
a=a.replaceAll("\(",""); //First
replace accepts a sequence of characters to replace:
public String replace(CharSequence target, CharSequence replacement)
Therefore, in your case it attempts to replace the 3 characters "(", not just the single character "(".
answered Mar 10 at 9:16
EranEran
288k37471561
In that case why doesn't this work? a=a.replace("(",""); //First
– Erik Nouroyan
Mar 10 at 9:17
@ErikNouroyanreplacedoes not expect a regex as the first argument. Therefore it tried to replace the actual sub-string "\(", which is not present ina.
– Eran
Mar 10 at 9:18
add a comment |
For replace to work you should write:
a=a.replace("(",""); //First
or use replaceAll if you want to pass a regex:
a=a.replaceAll("\(",""); //First
replace accepts a sequence of characters to replace:
public String replace(CharSequence target, CharSequence replacement)
Therefore, in your case it attempts to replace the 3 characters "(", not just the single character "(".
answered Mar 10 at 9:16
EranEran
288k37471561
For replace to work you should write:
a=a.replace("(",""); //First
or use replaceAll if you want to pass a regex:
a=a.replaceAll("\(",""); //First
replace accepts a sequence of characters to replace:
public String replace(CharSequence target, CharSequence replacement)
Therefore, in your case it attempts to replace the 3 characters "(", not just the single character "(".
answered Mar 10 at 9:16
EranEran
288k37471561
edited Mar 10 at 9:17
answered Mar 10 at 9:16
EranEran
288k37471561
answered Mar 10 at 9:16
EranEran
288k37471561
answered Mar 10 at 9:16
EranEran
288k37471561
288k37471561
In that case why doesn't this work? a=a.replace("(",""); //First
– Erik Nouroyan
Mar 10 at 9:17
@ErikNouroyanreplacedoes not expect a regex as the first argument. Therefore it tried to replace the actual sub-string "\(", which is not present ina.
– Eran
Mar 10 at 9:18
add a comment |
In that case why doesn't this work? a=a.replace("(",""); //First
– Erik Nouroyan
Mar 10 at 9:17
@ErikNouroyanreplacedoes not expect a regex as the first argument. Therefore it tried to replace the actual sub-string "\(", which is not present ina.
– Eran
Mar 10 at 9:18
In that case why doesn't this work? a=a.replace("(",""); //First
– Erik Nouroyan
Mar 10 at 9:17
In that case why doesn't this work? a=a.replace("(",""); //First
– Erik Nouroyan
Mar 10 at 9:17
@ErikNouroyan
replace does not expect a regex as the first argument. Therefore it tried to replace the actual sub-string "\(", which is not present in a.– Eran
Mar 10 at 9:18
@ErikNouroyan
replace does not expect a regex as the first argument. Therefore it tried to replace the actual sub-string "\(", which is not present in a.– Eran
Mar 10 at 9:18
add a comment |
The problem is that it is running in replace with several characters and, therefore, what it will look for is and (, so that this does not happen the quotation marks should only contain the character to replace :
a = a.replace("(", ""); // First
Next I leave a sniper with the original proposal and the fixed one :
public class Main {
private static final Main initRun = new Main();
public static void main(String[] args) {
String a = "This(rab)(bar)";
System.out.println("Original");
initRun.runOriginal(a);
System.out.println("Fixed");
initRun.runFixed(a);
// Output
// Original
// This(rab)(bar)
// Thisrab)(bar)
// Fixed
// Thisrab)bar)
// Thisrab)bar)
}
/**
* Execute the original proposal
*
* @param a String for replace
*/
void runOriginal(String a) {
a = a.replace("\(", ""); // First
String b = a.replaceFirst("\(", "");// Second
System.out.println(a + "n" + b);
}
/**
* Execute the fixed proposal
*
* @param a String for replace
*/
void runFixed(String a) {
a = a.replace("(", ""); // First
String b = a.replaceFirst("\(", "");// Second
System.out.println(a + "n" + b);
}
}
answered Mar 10 at 9:52
Nicolás Alarcón RapelaNicolás Alarcón Rapela
1,164624
add a comment |
The problem is that it is running in replace with several characters and, therefore, what it will look for is and (, so that this does not happen the quotation marks should only contain the character to replace :
a = a.replace("(", ""); // First
Next I leave a sniper with the original proposal and the fixed one :
public class Main {
private static final Main initRun = new Main();
public static void main(String[] args) {
String a = "This(rab)(bar)";
System.out.println("Original");
initRun.runOriginal(a);
System.out.println("Fixed");
initRun.runFixed(a);
// Output
// Original
// This(rab)(bar)
// Thisrab)(bar)
// Fixed
// Thisrab)bar)
// Thisrab)bar)
}
/**
* Execute the original proposal
*
* @param a String for replace
*/
void runOriginal(String a) {
a = a.replace("\(", ""); // First
String b = a.replaceFirst("\(", "");// Second
System.out.println(a + "n" + b);
}
/**
* Execute the fixed proposal
*
* @param a String for replace
*/
void runFixed(String a) {
a = a.replace("(", ""); // First
String b = a.replaceFirst("\(", "");// Second
System.out.println(a + "n" + b);
}
}
answered Mar 10 at 9:52
Nicolás Alarcón RapelaNicolás Alarcón Rapela
1,164624
add a comment |
The problem is that it is running in replace with several characters and, therefore, what it will look for is and (, so that this does not happen the quotation marks should only contain the character to replace :
a = a.replace("(", ""); // First
Next I leave a sniper with the original proposal and the fixed one :
public class Main {
private static final Main initRun = new Main();
public static void main(String[] args) {
String a = "This(rab)(bar)";
System.out.println("Original");
initRun.runOriginal(a);
System.out.println("Fixed");
initRun.runFixed(a);
// Output
// Original
// This(rab)(bar)
// Thisrab)(bar)
// Fixed
// Thisrab)bar)
// Thisrab)bar)
}
/**
* Execute the original proposal
*
* @param a String for replace
*/
void runOriginal(String a) {
a = a.replace("\(", ""); // First
String b = a.replaceFirst("\(", "");// Second
System.out.println(a + "n" + b);
}
/**
* Execute the fixed proposal
*
* @param a String for replace
*/
void runFixed(String a) {
a = a.replace("(", ""); // First
String b = a.replaceFirst("\(", "");// Second
System.out.println(a + "n" + b);
}
}
answered Mar 10 at 9:52
Nicolás Alarcón RapelaNicolás Alarcón Rapela
1,164624
The problem is that it is running in replace with several characters and, therefore, what it will look for is and (, so that this does not happen the quotation marks should only contain the character to replace :
a = a.replace("(", ""); // First
Next I leave a sniper with the original proposal and the fixed one :
public class Main {
private static final Main initRun = new Main();
public static void main(String[] args) {
String a = "This(rab)(bar)";
System.out.println("Original");
initRun.runOriginal(a);
System.out.println("Fixed");
initRun.runFixed(a);
// Output
// Original
// This(rab)(bar)
// Thisrab)(bar)
// Fixed
// Thisrab)bar)
// Thisrab)bar)
}
/**
* Execute the original proposal
*
* @param a String for replace
*/
void runOriginal(String a) {
a = a.replace("\(", ""); // First
String b = a.replaceFirst("\(", "");// Second
System.out.println(a + "n" + b);
}
/**
* Execute the fixed proposal
*
* @param a String for replace
*/
void runFixed(String a) {
a = a.replace("(", ""); // First
String b = a.replaceFirst("\(", "");// Second
System.out.println(a + "n" + b);
}
}
answered Mar 10 at 9:52
Nicolás Alarcón RapelaNicolás Alarcón Rapela
1,164624
answered Mar 10 at 9:52
Nicolás Alarcón RapelaNicolás Alarcón Rapela
1,164624
answered Mar 10 at 9:52
Nicolás Alarcón RapelaNicolás Alarcón Rapela
1,164624
answered Mar 10 at 9:52
Nicolás Alarcón RapelaNicolás Alarcón Rapela
1,164624
1,164624
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Erik Nouroyan is a new contributor. Be nice, and check out our Code of Conduct.
Erik Nouroyan is a new contributor. Be nice, and check out our Code of Conduct.
Erik Nouroyan is a new contributor. Be nice, and check out our Code of Conduct.
Erik Nouroyan is a new contributor. Be nice, and check out our Code of Conduct.
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