Algebraic transformation — where is my mistake?Find least squares regression lineVariance of Least Squares...
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Algebraic transformation — where is my mistake?
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$begingroup$
I tried to find the estimators of $hat{beta_1}$ and $hat{beta_0}$ via the least-squares method algebraically. Somehow I seem to have messed up.
Can you tell me where?
My Calculations.
transformation least-squares linear-regression
$endgroup$
add a comment |
$begingroup$
I tried to find the estimators of $hat{beta_1}$ and $hat{beta_0}$ via the least-squares method algebraically. Somehow I seem to have messed up.
Can you tell me where?
My Calculations.
transformation least-squares linear-regression
$endgroup$
add a comment |
$begingroup$
I tried to find the estimators of $hat{beta_1}$ and $hat{beta_0}$ via the least-squares method algebraically. Somehow I seem to have messed up.
Can you tell me where?
My Calculations.
transformation least-squares linear-regression
$endgroup$
I tried to find the estimators of $hat{beta_1}$ and $hat{beta_0}$ via the least-squares method algebraically. Somehow I seem to have messed up.
Can you tell me where?
My Calculations.
transformation least-squares linear-regression
transformation least-squares linear-regression
asked Feb 22 at 18:05
Jürgen ErhardtJürgen Erhardt
11
11
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1 Answer
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$begingroup$
Your calculations seem fine, you should only continue rearranging the terms and using the fact that from the basic definition of a mean, we have:
$$ sum x_i = nbar x = sum bar x .$$
$endgroup$
add a comment |
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1 Answer
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1 Answer
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active
oldest
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active
oldest
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active
oldest
votes
$begingroup$
Your calculations seem fine, you should only continue rearranging the terms and using the fact that from the basic definition of a mean, we have:
$$ sum x_i = nbar x = sum bar x .$$
$endgroup$
add a comment |
$begingroup$
Your calculations seem fine, you should only continue rearranging the terms and using the fact that from the basic definition of a mean, we have:
$$ sum x_i = nbar x = sum bar x .$$
$endgroup$
add a comment |
$begingroup$
Your calculations seem fine, you should only continue rearranging the terms and using the fact that from the basic definition of a mean, we have:
$$ sum x_i = nbar x = sum bar x .$$
$endgroup$
Your calculations seem fine, you should only continue rearranging the terms and using the fact that from the basic definition of a mean, we have:
$$ sum x_i = nbar x = sum bar x .$$
answered yesterday
pdbpdb
205
205
add a comment |
add a comment |
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