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How to fade a semiplane defined by line?


How can I stop defined points that are not displayed from influencing image size?LaTeX complains that tkzDrawArc is not definedHow to draw a dashed line and length with tkz-euclideColor fade a line in tikzpictureHow may I extend (prolong or produce) a line segment accurately in the following geometrical figure?Drawing rectilinear curves in Tikz, aka an Etch-a-Sketch drawingDraw Perpendicular to a lineHow to fade the color of an angle?Fade draw and fill in TikZHow to use points defined in tkz-euclide in tikz?













2















With the following code:



documentclass[tikz]standalone

usepackagetkz-euclide,tkz-fct,amsmath
usetkzobjall


begindocument
begintikzpicture[anchor=center]
tkzInit[xmin=-1, xmax=3, ymin=-1,ymax=3]
tkzDefPoints.5/2/P_1, 2.5/0/P_2, 1.5/1/M,2/1.5/A

tkzDrawX[noticks, label=(operatornameRe(x) )]
tkzDrawY[noticks, label=(operatornameIm(x) )]

tkzDrawPoints[fill=black, size=1mm](P_1,P_2,M)
tkzMarkRightAngle(A,M,P_1)
tkzFct[domain=-1:3, color=red, thick]x-.5
draw (P_1) -- (P_2);
tkzLabelPoints[above right](P_1,P_2)
tkzLabelPoints[right](M)

tkzText[color=black](1.5,3)z-z_1
endtikzpicture
enddocument


I'm getting:



enter image description here



I wanted to add a fade like this:



enter image description here



but I can't have the fade to be in the right angle.



How can I get this kind of fade, fadding to white?










share|improve this question


























    2















    With the following code:



    documentclass[tikz]standalone

    usepackagetkz-euclide,tkz-fct,amsmath
    usetkzobjall


    begindocument
    begintikzpicture[anchor=center]
    tkzInit[xmin=-1, xmax=3, ymin=-1,ymax=3]
    tkzDefPoints.5/2/P_1, 2.5/0/P_2, 1.5/1/M,2/1.5/A

    tkzDrawX[noticks, label=(operatornameRe(x) )]
    tkzDrawY[noticks, label=(operatornameIm(x) )]

    tkzDrawPoints[fill=black, size=1mm](P_1,P_2,M)
    tkzMarkRightAngle(A,M,P_1)
    tkzFct[domain=-1:3, color=red, thick]x-.5
    draw (P_1) -- (P_2);
    tkzLabelPoints[above right](P_1,P_2)
    tkzLabelPoints[right](M)

    tkzText[color=black](1.5,3)z-z_1
    endtikzpicture
    enddocument


    I'm getting:



    enter image description here



    I wanted to add a fade like this:



    enter image description here



    but I can't have the fade to be in the right angle.



    How can I get this kind of fade, fadding to white?










    share|improve this question
























      2












      2








      2








      With the following code:



      documentclass[tikz]standalone

      usepackagetkz-euclide,tkz-fct,amsmath
      usetkzobjall


      begindocument
      begintikzpicture[anchor=center]
      tkzInit[xmin=-1, xmax=3, ymin=-1,ymax=3]
      tkzDefPoints.5/2/P_1, 2.5/0/P_2, 1.5/1/M,2/1.5/A

      tkzDrawX[noticks, label=(operatornameRe(x) )]
      tkzDrawY[noticks, label=(operatornameIm(x) )]

      tkzDrawPoints[fill=black, size=1mm](P_1,P_2,M)
      tkzMarkRightAngle(A,M,P_1)
      tkzFct[domain=-1:3, color=red, thick]x-.5
      draw (P_1) -- (P_2);
      tkzLabelPoints[above right](P_1,P_2)
      tkzLabelPoints[right](M)

      tkzText[color=black](1.5,3)z-z_1
      endtikzpicture
      enddocument


      I'm getting:



      enter image description here



      I wanted to add a fade like this:



      enter image description here



      but I can't have the fade to be in the right angle.



      How can I get this kind of fade, fadding to white?










      share|improve this question














      With the following code:



      documentclass[tikz]standalone

      usepackagetkz-euclide,tkz-fct,amsmath
      usetkzobjall


      begindocument
      begintikzpicture[anchor=center]
      tkzInit[xmin=-1, xmax=3, ymin=-1,ymax=3]
      tkzDefPoints.5/2/P_1, 2.5/0/P_2, 1.5/1/M,2/1.5/A

      tkzDrawX[noticks, label=(operatornameRe(x) )]
      tkzDrawY[noticks, label=(operatornameIm(x) )]

      tkzDrawPoints[fill=black, size=1mm](P_1,P_2,M)
      tkzMarkRightAngle(A,M,P_1)
      tkzFct[domain=-1:3, color=red, thick]x-.5
      draw (P_1) -- (P_2);
      tkzLabelPoints[above right](P_1,P_2)
      tkzLabelPoints[right](M)

      tkzText[color=black](1.5,3)z-z_1
      endtikzpicture
      enddocument


      I'm getting:



      enter image description here



      I wanted to add a fade like this:



      enter image description here



      but I can't have the fade to be in the right angle.



      How can I get this kind of fade, fadding to white?







      tikz-pgf tkz-euclide






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 5 hours ago









      Concept7Concept7

      866




      866




















          2 Answers
          2






          active

          oldest

          votes


















          3














          You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'



          enter image description here



          documentclass[tikz,border=5mm]standalone
          usepackagetkz-euclide
          usetkzobjall
          begindocument
          begintikzpicture
          coordinate[label=above right:$P_1$] (P1) at (.5,2);
          coordinate[label=above right:$P_2$] (P2) at (2.5,0);
          coordinate[label=right:$M$] (M) at (1.5,1);
          coordinate (A) at (2,1.5);
          pgfmathsetmacroa.5-sqrt(2)
          pgfmathsetmacrob.5+sqrt(12.5)

          shade[top color=white,bottom color=red!50,
          transform canvas=rotate around=45:(.5,0)]
          (a,0) rectangle (b,.5);
          draw[-latex] (-1,0)--(3.5,0) node[below]rmRe$(x)$;
          draw[-latex] (0,-1)--(0,3.5) node[left]rmIm$(x)$;

          draw (P1) -- (P2);
          draw[red,thick] plot[domain=-.5:3] (x,x-.5);
          foreach p in P1,P2,M
          fill (p) circle(1pt);
          node at (1.5,3)z-z_1;
          tkzMarkRightAngle(P1,M,A)
          endtikzpicture
          enddocument





          share|improve this answer






























            1














            This is in principle very simple but tkz-euclide seems to mess up things a bit. One can just use a shading angle, which can, of course, be computed by TikZ.



            documentclass[tikz]standalone
            usetikzlibrarycalc,backgrounds
            usepackageamsmath
            DeclareMathOperatorreRe
            DeclareMathOperatorimIm
            begindocument
            begintikzpicture[anchor=center,declare function=f(x)=x-0.5;
            xmin=-1;xmax=3;]
            draw[-latex] (-1.5,0) -- (3.5,0) node[below left]$re z$;
            draw[-latex] (0,-1.5) -- (0,3.5) node[below left]$im z$;;
            path foreach X/Y/L/P in .5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0
            (X,Y) coordinate[label=P:$L$] (L);
            beginscope[on background layer]
            shade let p1=(xmin,f(xmin)),p2=(xmax,f(xmax)),
            n1=atan2(y2-y1,x2-x1) in
            [left color=white,right color=red,middle color=white,shading angle=n1]
            (p1) -- (p2) -- ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)
            ;
            endscope
            draw[red,thick] plot[variable=x,domain=xmin:xmax] (x,f(x));
            draw (P_1) -- (P_2);
            node[anchor=south,red] at (1.5,3) leq;
            endtikzpicture
            enddocument


            enter image description here






            share|improve this answer
























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              2 Answers
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              2 Answers
              2






              active

              oldest

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              active

              oldest

              votes






              active

              oldest

              votes









              3














              You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'



              enter image description here



              documentclass[tikz,border=5mm]standalone
              usepackagetkz-euclide
              usetkzobjall
              begindocument
              begintikzpicture
              coordinate[label=above right:$P_1$] (P1) at (.5,2);
              coordinate[label=above right:$P_2$] (P2) at (2.5,0);
              coordinate[label=right:$M$] (M) at (1.5,1);
              coordinate (A) at (2,1.5);
              pgfmathsetmacroa.5-sqrt(2)
              pgfmathsetmacrob.5+sqrt(12.5)

              shade[top color=white,bottom color=red!50,
              transform canvas=rotate around=45:(.5,0)]
              (a,0) rectangle (b,.5);
              draw[-latex] (-1,0)--(3.5,0) node[below]rmRe$(x)$;
              draw[-latex] (0,-1)--(0,3.5) node[left]rmIm$(x)$;

              draw (P1) -- (P2);
              draw[red,thick] plot[domain=-.5:3] (x,x-.5);
              foreach p in P1,P2,M
              fill (p) circle(1pt);
              node at (1.5,3)z-z_1;
              tkzMarkRightAngle(P1,M,A)
              endtikzpicture
              enddocument





              share|improve this answer



























                3














                You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'



                enter image description here



                documentclass[tikz,border=5mm]standalone
                usepackagetkz-euclide
                usetkzobjall
                begindocument
                begintikzpicture
                coordinate[label=above right:$P_1$] (P1) at (.5,2);
                coordinate[label=above right:$P_2$] (P2) at (2.5,0);
                coordinate[label=right:$M$] (M) at (1.5,1);
                coordinate (A) at (2,1.5);
                pgfmathsetmacroa.5-sqrt(2)
                pgfmathsetmacrob.5+sqrt(12.5)

                shade[top color=white,bottom color=red!50,
                transform canvas=rotate around=45:(.5,0)]
                (a,0) rectangle (b,.5);
                draw[-latex] (-1,0)--(3.5,0) node[below]rmRe$(x)$;
                draw[-latex] (0,-1)--(0,3.5) node[left]rmIm$(x)$;

                draw (P1) -- (P2);
                draw[red,thick] plot[domain=-.5:3] (x,x-.5);
                foreach p in P1,P2,M
                fill (p) circle(1pt);
                node at (1.5,3)z-z_1;
                tkzMarkRightAngle(P1,M,A)
                endtikzpicture
                enddocument





                share|improve this answer

























                  3












                  3








                  3







                  You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'



                  enter image description here



                  documentclass[tikz,border=5mm]standalone
                  usepackagetkz-euclide
                  usetkzobjall
                  begindocument
                  begintikzpicture
                  coordinate[label=above right:$P_1$] (P1) at (.5,2);
                  coordinate[label=above right:$P_2$] (P2) at (2.5,0);
                  coordinate[label=right:$M$] (M) at (1.5,1);
                  coordinate (A) at (2,1.5);
                  pgfmathsetmacroa.5-sqrt(2)
                  pgfmathsetmacrob.5+sqrt(12.5)

                  shade[top color=white,bottom color=red!50,
                  transform canvas=rotate around=45:(.5,0)]
                  (a,0) rectangle (b,.5);
                  draw[-latex] (-1,0)--(3.5,0) node[below]rmRe$(x)$;
                  draw[-latex] (0,-1)--(0,3.5) node[left]rmIm$(x)$;

                  draw (P1) -- (P2);
                  draw[red,thick] plot[domain=-.5:3] (x,x-.5);
                  foreach p in P1,P2,M
                  fill (p) circle(1pt);
                  node at (1.5,3)z-z_1;
                  tkzMarkRightAngle(P1,M,A)
                  endtikzpicture
                  enddocument





                  share|improve this answer













                  You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'



                  enter image description here



                  documentclass[tikz,border=5mm]standalone
                  usepackagetkz-euclide
                  usetkzobjall
                  begindocument
                  begintikzpicture
                  coordinate[label=above right:$P_1$] (P1) at (.5,2);
                  coordinate[label=above right:$P_2$] (P2) at (2.5,0);
                  coordinate[label=right:$M$] (M) at (1.5,1);
                  coordinate (A) at (2,1.5);
                  pgfmathsetmacroa.5-sqrt(2)
                  pgfmathsetmacrob.5+sqrt(12.5)

                  shade[top color=white,bottom color=red!50,
                  transform canvas=rotate around=45:(.5,0)]
                  (a,0) rectangle (b,.5);
                  draw[-latex] (-1,0)--(3.5,0) node[below]rmRe$(x)$;
                  draw[-latex] (0,-1)--(0,3.5) node[left]rmIm$(x)$;

                  draw (P1) -- (P2);
                  draw[red,thick] plot[domain=-.5:3] (x,x-.5);
                  foreach p in P1,P2,M
                  fill (p) circle(1pt);
                  node at (1.5,3)z-z_1;
                  tkzMarkRightAngle(P1,M,A)
                  endtikzpicture
                  enddocument






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 4 hours ago









                  Black MildBlack Mild

                  687611




                  687611





















                      1














                      This is in principle very simple but tkz-euclide seems to mess up things a bit. One can just use a shading angle, which can, of course, be computed by TikZ.



                      documentclass[tikz]standalone
                      usetikzlibrarycalc,backgrounds
                      usepackageamsmath
                      DeclareMathOperatorreRe
                      DeclareMathOperatorimIm
                      begindocument
                      begintikzpicture[anchor=center,declare function=f(x)=x-0.5;
                      xmin=-1;xmax=3;]
                      draw[-latex] (-1.5,0) -- (3.5,0) node[below left]$re z$;
                      draw[-latex] (0,-1.5) -- (0,3.5) node[below left]$im z$;;
                      path foreach X/Y/L/P in .5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0
                      (X,Y) coordinate[label=P:$L$] (L);
                      beginscope[on background layer]
                      shade let p1=(xmin,f(xmin)),p2=(xmax,f(xmax)),
                      n1=atan2(y2-y1,x2-x1) in
                      [left color=white,right color=red,middle color=white,shading angle=n1]
                      (p1) -- (p2) -- ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)
                      ;
                      endscope
                      draw[red,thick] plot[variable=x,domain=xmin:xmax] (x,f(x));
                      draw (P_1) -- (P_2);
                      node[anchor=south,red] at (1.5,3) leq;
                      endtikzpicture
                      enddocument


                      enter image description here






                      share|improve this answer





























                        1














                        This is in principle very simple but tkz-euclide seems to mess up things a bit. One can just use a shading angle, which can, of course, be computed by TikZ.



                        documentclass[tikz]standalone
                        usetikzlibrarycalc,backgrounds
                        usepackageamsmath
                        DeclareMathOperatorreRe
                        DeclareMathOperatorimIm
                        begindocument
                        begintikzpicture[anchor=center,declare function=f(x)=x-0.5;
                        xmin=-1;xmax=3;]
                        draw[-latex] (-1.5,0) -- (3.5,0) node[below left]$re z$;
                        draw[-latex] (0,-1.5) -- (0,3.5) node[below left]$im z$;;
                        path foreach X/Y/L/P in .5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0
                        (X,Y) coordinate[label=P:$L$] (L);
                        beginscope[on background layer]
                        shade let p1=(xmin,f(xmin)),p2=(xmax,f(xmax)),
                        n1=atan2(y2-y1,x2-x1) in
                        [left color=white,right color=red,middle color=white,shading angle=n1]
                        (p1) -- (p2) -- ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)
                        ;
                        endscope
                        draw[red,thick] plot[variable=x,domain=xmin:xmax] (x,f(x));
                        draw (P_1) -- (P_2);
                        node[anchor=south,red] at (1.5,3) leq;
                        endtikzpicture
                        enddocument


                        enter image description here






                        share|improve this answer



























                          1












                          1








                          1







                          This is in principle very simple but tkz-euclide seems to mess up things a bit. One can just use a shading angle, which can, of course, be computed by TikZ.



                          documentclass[tikz]standalone
                          usetikzlibrarycalc,backgrounds
                          usepackageamsmath
                          DeclareMathOperatorreRe
                          DeclareMathOperatorimIm
                          begindocument
                          begintikzpicture[anchor=center,declare function=f(x)=x-0.5;
                          xmin=-1;xmax=3;]
                          draw[-latex] (-1.5,0) -- (3.5,0) node[below left]$re z$;
                          draw[-latex] (0,-1.5) -- (0,3.5) node[below left]$im z$;;
                          path foreach X/Y/L/P in .5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0
                          (X,Y) coordinate[label=P:$L$] (L);
                          beginscope[on background layer]
                          shade let p1=(xmin,f(xmin)),p2=(xmax,f(xmax)),
                          n1=atan2(y2-y1,x2-x1) in
                          [left color=white,right color=red,middle color=white,shading angle=n1]
                          (p1) -- (p2) -- ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)
                          ;
                          endscope
                          draw[red,thick] plot[variable=x,domain=xmin:xmax] (x,f(x));
                          draw (P_1) -- (P_2);
                          node[anchor=south,red] at (1.5,3) leq;
                          endtikzpicture
                          enddocument


                          enter image description here






                          share|improve this answer















                          This is in principle very simple but tkz-euclide seems to mess up things a bit. One can just use a shading angle, which can, of course, be computed by TikZ.



                          documentclass[tikz]standalone
                          usetikzlibrarycalc,backgrounds
                          usepackageamsmath
                          DeclareMathOperatorreRe
                          DeclareMathOperatorimIm
                          begindocument
                          begintikzpicture[anchor=center,declare function=f(x)=x-0.5;
                          xmin=-1;xmax=3;]
                          draw[-latex] (-1.5,0) -- (3.5,0) node[below left]$re z$;
                          draw[-latex] (0,-1.5) -- (0,3.5) node[below left]$im z$;;
                          path foreach X/Y/L/P in .5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0
                          (X,Y) coordinate[label=P:$L$] (L);
                          beginscope[on background layer]
                          shade let p1=(xmin,f(xmin)),p2=(xmax,f(xmax)),
                          n1=atan2(y2-y1,x2-x1) in
                          [left color=white,right color=red,middle color=white,shading angle=n1]
                          (p1) -- (p2) -- ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)
                          ;
                          endscope
                          draw[red,thick] plot[variable=x,domain=xmin:xmax] (x,f(x));
                          draw (P_1) -- (P_2);
                          node[anchor=south,red] at (1.5,3) leq;
                          endtikzpicture
                          enddocument


                          enter image description here







                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited 3 hours ago

























                          answered 4 hours ago









                          marmotmarmot

                          111k5138257




                          111k5138257



























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                              Integral that is continuous and looks like it converges to a geometric seriesTesting if a geometric series converges by taking limit to infinitySummation of arithmetic-geometric series of higher orderGeometric series with polynomial exponentHow to Recognize a Geometric SeriesShowing an integral equality with series over the integersDiscontinuity of a series of continuous functionsReasons why a Series ConvergesSum of infinite geometric series with two terms in summationUsing geometric series for computing IntegralsLimit of geometric series sum when $r = 1$

                              Joseph Lister