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If I have the $Q$ matrix, can I somehow find the $P$ matrix?


How can I calculate the expected number of changes of state of a discrete-time Markov chain?If $P$ is an invertible transition probability matrix, does $P^{-1}[i,j]$ have any interesting meaning?Can a stationary distribution be zero vectorSteady state of a $4 times 4$ transition matrixHow to solve for steady state matrix symbolically?Determine periodicity from transition matrix?Condition for a stochastic matrix to be a second order transition probability matrix of a DTMC.Reduce the mixing time by switching a regular state to an absorbing state in a Markov chainMarkov transition matrix: $lim limits_{nto infty} P^n$ and $lim limits_{nto infty} frac1n sum_{k=1}^n P^k$Limit of a Markov Chain?













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I have this $Q$ matrix $$left[begin{array}{rrrr} -6& 1& 2& 3\ 4& -15& 5& 6\ 7& 8& -24& 9\ 10& 11& 12& -33 end{array}right]$$



I was just wonering if there is any way to change the $Q$ matrix to transition $P$ matrix?










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    0












    $begingroup$


    I have this $Q$ matrix $$left[begin{array}{rrrr} -6& 1& 2& 3\ 4& -15& 5& 6\ 7& 8& -24& 9\ 10& 11& 12& -33 end{array}right]$$



    I was just wonering if there is any way to change the $Q$ matrix to transition $P$ matrix?










    share|cite|improve this question











    $endgroup$















      0












      0








      0





      $begingroup$


      I have this $Q$ matrix $$left[begin{array}{rrrr} -6& 1& 2& 3\ 4& -15& 5& 6\ 7& 8& -24& 9\ 10& 11& 12& -33 end{array}right]$$



      I was just wonering if there is any way to change the $Q$ matrix to transition $P$ matrix?










      share|cite|improve this question











      $endgroup$




      I have this $Q$ matrix $$left[begin{array}{rrrr} -6& 1& 2& 3\ 4& -15& 5& 6\ 7& 8& -24& 9\ 10& 11& 12& -33 end{array}right]$$



      I was just wonering if there is any way to change the $Q$ matrix to transition $P$ matrix?







      probability stochastic-processes markov-chains






      share|cite|improve this question















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      edited Mar 11 at 13:31









      Rócherz

      2,9762821




      2,9762821










      asked Mar 11 at 11:43









      Abc123Abc123

      174




      174






















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          $begingroup$

          My guess is that by $Q$ matrix you mean the generator of a continuous-time Markov chain
          where the transition matrix for time $t$ is the matrix exponential $T(t) = exp(t Q)$ and you want $P = T(1) = exp(Q)$, the transition matrix for a discrete-time Markov chain such that $P^k = T(k)$ for positive integers $k$. There are lots of ways to compute it. See in particular Moler and val Loan, "Nineteen Dubious Ways to Compute the Exponential of a Matrix, Twenty-Five Years Later".






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            $begingroup$

            My guess is that by $Q$ matrix you mean the generator of a continuous-time Markov chain
            where the transition matrix for time $t$ is the matrix exponential $T(t) = exp(t Q)$ and you want $P = T(1) = exp(Q)$, the transition matrix for a discrete-time Markov chain such that $P^k = T(k)$ for positive integers $k$. There are lots of ways to compute it. See in particular Moler and val Loan, "Nineteen Dubious Ways to Compute the Exponential of a Matrix, Twenty-Five Years Later".






            share|cite|improve this answer









            $endgroup$


















              1












              $begingroup$

              My guess is that by $Q$ matrix you mean the generator of a continuous-time Markov chain
              where the transition matrix for time $t$ is the matrix exponential $T(t) = exp(t Q)$ and you want $P = T(1) = exp(Q)$, the transition matrix for a discrete-time Markov chain such that $P^k = T(k)$ for positive integers $k$. There are lots of ways to compute it. See in particular Moler and val Loan, "Nineteen Dubious Ways to Compute the Exponential of a Matrix, Twenty-Five Years Later".






              share|cite|improve this answer









              $endgroup$
















                1












                1








                1





                $begingroup$

                My guess is that by $Q$ matrix you mean the generator of a continuous-time Markov chain
                where the transition matrix for time $t$ is the matrix exponential $T(t) = exp(t Q)$ and you want $P = T(1) = exp(Q)$, the transition matrix for a discrete-time Markov chain such that $P^k = T(k)$ for positive integers $k$. There are lots of ways to compute it. See in particular Moler and val Loan, "Nineteen Dubious Ways to Compute the Exponential of a Matrix, Twenty-Five Years Later".






                share|cite|improve this answer









                $endgroup$



                My guess is that by $Q$ matrix you mean the generator of a continuous-time Markov chain
                where the transition matrix for time $t$ is the matrix exponential $T(t) = exp(t Q)$ and you want $P = T(1) = exp(Q)$, the transition matrix for a discrete-time Markov chain such that $P^k = T(k)$ for positive integers $k$. There are lots of ways to compute it. See in particular Moler and val Loan, "Nineteen Dubious Ways to Compute the Exponential of a Matrix, Twenty-Five Years Later".







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Mar 11 at 12:16









                Robert IsraelRobert Israel

                327k23216470




                327k23216470






























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