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A line with a parametric vector equation


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    Please do not apply the algebraic-geometry tag to elementary problems involving algebra and geometry, as per the tag description.
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    – KReiser
    Mar 11 at 18:30
















-1












$begingroup$


I am struggling with this question. Any help would be greatly appreciated



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Sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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  • $begingroup$
    Please do not apply the algebraic-geometry tag to elementary problems involving algebra and geometry, as per the tag description.
    $endgroup$
    – KReiser
    Mar 11 at 18:30














-1












-1








-1





$begingroup$


I am struggling with this question. Any help would be greatly appreciated



enter image description here










share|cite|improve this question









New contributor




Sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




I am struggling with this question. Any help would be greatly appreciated



enter image description here







matrices vectors






share|cite|improve this question









New contributor




Sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|cite|improve this question









New contributor




Sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this question




share|cite|improve this question








edited Mar 11 at 18:30









KReiser

9,87121435




9,87121435






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asked Mar 11 at 10:12









SamSam

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New contributor





Sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • $begingroup$
    Please do not apply the algebraic-geometry tag to elementary problems involving algebra and geometry, as per the tag description.
    $endgroup$
    – KReiser
    Mar 11 at 18:30


















  • $begingroup$
    Please do not apply the algebraic-geometry tag to elementary problems involving algebra and geometry, as per the tag description.
    $endgroup$
    – KReiser
    Mar 11 at 18:30
















$begingroup$
Please do not apply the algebraic-geometry tag to elementary problems involving algebra and geometry, as per the tag description.
$endgroup$
– KReiser
Mar 11 at 18:30




$begingroup$
Please do not apply the algebraic-geometry tag to elementary problems involving algebra and geometry, as per the tag description.
$endgroup$
– KReiser
Mar 11 at 18:30










2 Answers
2






active

oldest

votes


















1












$begingroup$

Do you know how a parametric equation works?



Hint



What does the value of (the parameter) $t$ have to be for the first coordinate to be $-8$?



Once you have this value of $t$, what is the value of the second coordinate?






share|cite|improve this answer









$endgroup$













  • $begingroup$
    I believe $t$ has to be -2?
    $endgroup$
    – Sam
    Mar 11 at 10:26






  • 1




    $begingroup$
    Correct, and then you know all the other coordinates as well.
    $endgroup$
    – StackTD
    Mar 11 at 10:27










  • $begingroup$
    Therefore the answer is $19$?
    $endgroup$
    – Sam
    Mar 11 at 10:29








  • 1




    $begingroup$
    Yes, that's right :-).
    $endgroup$
    – StackTD
    Mar 11 at 10:30





















1












$begingroup$

If $x_1=-8$, then we have $t=-2$.



Can you take it from here ?






share|cite|improve this answer









$endgroup$













  • $begingroup$
    so $x2=9+-2*-5=19$?
    $endgroup$
    – Sam
    Mar 11 at 10:29












  • $begingroup$
    Yes, we have $x_2=19.$
    $endgroup$
    – Fred
    Mar 11 at 10:33











Your Answer





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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









1












$begingroup$

Do you know how a parametric equation works?



Hint



What does the value of (the parameter) $t$ have to be for the first coordinate to be $-8$?



Once you have this value of $t$, what is the value of the second coordinate?






share|cite|improve this answer









$endgroup$













  • $begingroup$
    I believe $t$ has to be -2?
    $endgroup$
    – Sam
    Mar 11 at 10:26






  • 1




    $begingroup$
    Correct, and then you know all the other coordinates as well.
    $endgroup$
    – StackTD
    Mar 11 at 10:27










  • $begingroup$
    Therefore the answer is $19$?
    $endgroup$
    – Sam
    Mar 11 at 10:29








  • 1




    $begingroup$
    Yes, that's right :-).
    $endgroup$
    – StackTD
    Mar 11 at 10:30


















1












$begingroup$

Do you know how a parametric equation works?



Hint



What does the value of (the parameter) $t$ have to be for the first coordinate to be $-8$?



Once you have this value of $t$, what is the value of the second coordinate?






share|cite|improve this answer









$endgroup$













  • $begingroup$
    I believe $t$ has to be -2?
    $endgroup$
    – Sam
    Mar 11 at 10:26






  • 1




    $begingroup$
    Correct, and then you know all the other coordinates as well.
    $endgroup$
    – StackTD
    Mar 11 at 10:27










  • $begingroup$
    Therefore the answer is $19$?
    $endgroup$
    – Sam
    Mar 11 at 10:29








  • 1




    $begingroup$
    Yes, that's right :-).
    $endgroup$
    – StackTD
    Mar 11 at 10:30
















1












1








1





$begingroup$

Do you know how a parametric equation works?



Hint



What does the value of (the parameter) $t$ have to be for the first coordinate to be $-8$?



Once you have this value of $t$, what is the value of the second coordinate?






share|cite|improve this answer









$endgroup$



Do you know how a parametric equation works?



Hint



What does the value of (the parameter) $t$ have to be for the first coordinate to be $-8$?



Once you have this value of $t$, what is the value of the second coordinate?







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Mar 11 at 10:16









StackTDStackTD

23.8k2154




23.8k2154












  • $begingroup$
    I believe $t$ has to be -2?
    $endgroup$
    – Sam
    Mar 11 at 10:26






  • 1




    $begingroup$
    Correct, and then you know all the other coordinates as well.
    $endgroup$
    – StackTD
    Mar 11 at 10:27










  • $begingroup$
    Therefore the answer is $19$?
    $endgroup$
    – Sam
    Mar 11 at 10:29








  • 1




    $begingroup$
    Yes, that's right :-).
    $endgroup$
    – StackTD
    Mar 11 at 10:30




















  • $begingroup$
    I believe $t$ has to be -2?
    $endgroup$
    – Sam
    Mar 11 at 10:26






  • 1




    $begingroup$
    Correct, and then you know all the other coordinates as well.
    $endgroup$
    – StackTD
    Mar 11 at 10:27










  • $begingroup$
    Therefore the answer is $19$?
    $endgroup$
    – Sam
    Mar 11 at 10:29








  • 1




    $begingroup$
    Yes, that's right :-).
    $endgroup$
    – StackTD
    Mar 11 at 10:30


















$begingroup$
I believe $t$ has to be -2?
$endgroup$
– Sam
Mar 11 at 10:26




$begingroup$
I believe $t$ has to be -2?
$endgroup$
– Sam
Mar 11 at 10:26




1




1




$begingroup$
Correct, and then you know all the other coordinates as well.
$endgroup$
– StackTD
Mar 11 at 10:27




$begingroup$
Correct, and then you know all the other coordinates as well.
$endgroup$
– StackTD
Mar 11 at 10:27












$begingroup$
Therefore the answer is $19$?
$endgroup$
– Sam
Mar 11 at 10:29






$begingroup$
Therefore the answer is $19$?
$endgroup$
– Sam
Mar 11 at 10:29






1




1




$begingroup$
Yes, that's right :-).
$endgroup$
– StackTD
Mar 11 at 10:30






$begingroup$
Yes, that's right :-).
$endgroup$
– StackTD
Mar 11 at 10:30













1












$begingroup$

If $x_1=-8$, then we have $t=-2$.



Can you take it from here ?






share|cite|improve this answer









$endgroup$













  • $begingroup$
    so $x2=9+-2*-5=19$?
    $endgroup$
    – Sam
    Mar 11 at 10:29












  • $begingroup$
    Yes, we have $x_2=19.$
    $endgroup$
    – Fred
    Mar 11 at 10:33
















1












$begingroup$

If $x_1=-8$, then we have $t=-2$.



Can you take it from here ?






share|cite|improve this answer









$endgroup$













  • $begingroup$
    so $x2=9+-2*-5=19$?
    $endgroup$
    – Sam
    Mar 11 at 10:29












  • $begingroup$
    Yes, we have $x_2=19.$
    $endgroup$
    – Fred
    Mar 11 at 10:33














1












1








1





$begingroup$

If $x_1=-8$, then we have $t=-2$.



Can you take it from here ?






share|cite|improve this answer









$endgroup$



If $x_1=-8$, then we have $t=-2$.



Can you take it from here ?







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Mar 11 at 10:16









FredFred

48.3k1849




48.3k1849












  • $begingroup$
    so $x2=9+-2*-5=19$?
    $endgroup$
    – Sam
    Mar 11 at 10:29












  • $begingroup$
    Yes, we have $x_2=19.$
    $endgroup$
    – Fred
    Mar 11 at 10:33


















  • $begingroup$
    so $x2=9+-2*-5=19$?
    $endgroup$
    – Sam
    Mar 11 at 10:29












  • $begingroup$
    Yes, we have $x_2=19.$
    $endgroup$
    – Fred
    Mar 11 at 10:33
















$begingroup$
so $x2=9+-2*-5=19$?
$endgroup$
– Sam
Mar 11 at 10:29






$begingroup$
so $x2=9+-2*-5=19$?
$endgroup$
– Sam
Mar 11 at 10:29














$begingroup$
Yes, we have $x_2=19.$
$endgroup$
– Fred
Mar 11 at 10:33




$begingroup$
Yes, we have $x_2=19.$
$endgroup$
– Fred
Mar 11 at 10:33










Sam is a new contributor. Be nice, and check out our Code of Conduct.










draft saved

draft discarded


















Sam is a new contributor. Be nice, and check out our Code of Conduct.













Sam is a new contributor. Be nice, and check out our Code of Conduct.












Sam is a new contributor. Be nice, and check out our Code of Conduct.
















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