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A line with a parametric vector equation
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$begingroup$
I am struggling with this question. Any help would be greatly appreciated
matrices vectors
edited Mar 11 at 18:30
KReiser
9,87121435
asked Mar 11 at 10:12
SamSam
305
New contributor
Sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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add a comment |
$begingroup$
I am struggling with this question. Any help would be greatly appreciated
matrices vectors
edited Mar 11 at 18:30
KReiser
9,87121435
asked Mar 11 at 10:12
SamSam
305
New contributor
Sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
Please do not apply the algebraic-geometry tag to elementary problems involving algebra and geometry, as per the tag description.
$endgroup$
– KReiser
Mar 11 at 18:30
add a comment |
$begingroup$
I am struggling with this question. Any help would be greatly appreciated
matrices vectors
edited Mar 11 at 18:30
KReiser
9,87121435
asked Mar 11 at 10:12
SamSam
305
New contributor
Sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I am struggling with this question. Any help would be greatly appreciated
matrices vectors
matrices vectors
edited Mar 11 at 18:30
KReiser
9,87121435
asked Mar 11 at 10:12
SamSam
305
New contributor
Sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Mar 11 at 18:30
KReiser
9,87121435
asked Mar 11 at 10:12
SamSam
305
New contributor
Sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Mar 11 at 18:30
KReiser
9,87121435
edited Mar 11 at 18:30
KReiser
9,87121435
edited Mar 11 at 18:30
KReiser
9,87121435
9,87121435
asked Mar 11 at 10:12
SamSam
305
New contributor
Sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Mar 11 at 10:12
SamSam
305
asked Mar 11 at 10:12
SamSam
305
305
New contributor
Sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$begingroup$
Please do not apply the algebraic-geometry tag to elementary problems involving algebra and geometry, as per the tag description.
$endgroup$
– KReiser
Mar 11 at 18:30
add a comment |
$begingroup$
Please do not apply the algebraic-geometry tag to elementary problems involving algebra and geometry, as per the tag description.
$endgroup$
– KReiser
Mar 11 at 18:30
$begingroup$
Please do not apply the algebraic-geometry tag to elementary problems involving algebra and geometry, as per the tag description.
$endgroup$
– KReiser
Mar 11 at 18:30
$begingroup$
Please do not apply the algebraic-geometry tag to elementary problems involving algebra and geometry, as per the tag description.
$endgroup$
– KReiser
Mar 11 at 18:30
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Do you know how a parametric equation works?
Hint
What does the value of (the parameter) $t$ have to be for the first coordinate to be $-8$?
Once you have this value of $t$, what is the value of the second coordinate?
answered Mar 11 at 10:16
StackTDStackTD
23.8k2154
$endgroup$
$begingroup$
I believe $t$ has to be -2?
$endgroup$
– Sam
Mar 11 at 10:26
1
$begingroup$
Correct, and then you know all the other coordinates as well.
$endgroup$
– StackTD
Mar 11 at 10:27
$begingroup$
Therefore the answer is $19$?
$endgroup$
– Sam
Mar 11 at 10:29
1
$begingroup$
Yes, that's right :-).
$endgroup$
– StackTD
Mar 11 at 10:30
add a comment |
$begingroup$
If $x_1=-8$, then we have $t=-2$.
Can you take it from here ?
answered Mar 11 at 10:16
FredFred
48.3k1849
$endgroup$
$begingroup$
so $x2=9+-2*-5=19$?
$endgroup$
– Sam
Mar 11 at 10:29
$begingroup$
Yes, we have $x_2=19.$
$endgroup$
– Fred
Mar 11 at 10:33
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Do you know how a parametric equation works?
Hint
What does the value of (the parameter) $t$ have to be for the first coordinate to be $-8$?
Once you have this value of $t$, what is the value of the second coordinate?
answered Mar 11 at 10:16
StackTDStackTD
23.8k2154
$endgroup$
$begingroup$
I believe $t$ has to be -2?
$endgroup$
– Sam
Mar 11 at 10:26
1
$begingroup$
Correct, and then you know all the other coordinates as well.
$endgroup$
– StackTD
Mar 11 at 10:27
$begingroup$
Therefore the answer is $19$?
$endgroup$
– Sam
Mar 11 at 10:29
1
$begingroup$
Yes, that's right :-).
$endgroup$
– StackTD
Mar 11 at 10:30
add a comment |
$begingroup$
Do you know how a parametric equation works?
Hint
What does the value of (the parameter) $t$ have to be for the first coordinate to be $-8$?
Once you have this value of $t$, what is the value of the second coordinate?
answered Mar 11 at 10:16
StackTDStackTD
23.8k2154
$endgroup$
$begingroup$
I believe $t$ has to be -2?
$endgroup$
– Sam
Mar 11 at 10:26
1
$begingroup$
Correct, and then you know all the other coordinates as well.
$endgroup$
– StackTD
Mar 11 at 10:27
$begingroup$
Therefore the answer is $19$?
$endgroup$
– Sam
Mar 11 at 10:29
1
$begingroup$
Yes, that's right :-).
$endgroup$
– StackTD
Mar 11 at 10:30
add a comment |
$begingroup$
Do you know how a parametric equation works?
Hint
What does the value of (the parameter) $t$ have to be for the first coordinate to be $-8$?
Once you have this value of $t$, what is the value of the second coordinate?
answered Mar 11 at 10:16
StackTDStackTD
23.8k2154
$endgroup$
Do you know how a parametric equation works?
Hint
What does the value of (the parameter) $t$ have to be for the first coordinate to be $-8$?
Once you have this value of $t$, what is the value of the second coordinate?
answered Mar 11 at 10:16
StackTDStackTD
23.8k2154
answered Mar 11 at 10:16
StackTDStackTD
23.8k2154
answered Mar 11 at 10:16
StackTDStackTD
23.8k2154
answered Mar 11 at 10:16
StackTDStackTD
23.8k2154
23.8k2154
$begingroup$
I believe $t$ has to be -2?
$endgroup$
– Sam
Mar 11 at 10:26
1
$begingroup$
Correct, and then you know all the other coordinates as well.
$endgroup$
– StackTD
Mar 11 at 10:27
$begingroup$
Therefore the answer is $19$?
$endgroup$
– Sam
Mar 11 at 10:29
1
$begingroup$
Yes, that's right :-).
$endgroup$
– StackTD
Mar 11 at 10:30
add a comment |
$begingroup$
I believe $t$ has to be -2?
$endgroup$
– Sam
Mar 11 at 10:26
1
$begingroup$
Correct, and then you know all the other coordinates as well.
$endgroup$
– StackTD
Mar 11 at 10:27
$begingroup$
Therefore the answer is $19$?
$endgroup$
– Sam
Mar 11 at 10:29
1
$begingroup$
Yes, that's right :-).
$endgroup$
– StackTD
Mar 11 at 10:30
$begingroup$
I believe $t$ has to be -2?
$endgroup$
– Sam
Mar 11 at 10:26
$begingroup$
I believe $t$ has to be -2?
$endgroup$
– Sam
Mar 11 at 10:26
1
1
$begingroup$
Correct, and then you know all the other coordinates as well.
$endgroup$
– StackTD
Mar 11 at 10:27
$begingroup$
Correct, and then you know all the other coordinates as well.
$endgroup$
– StackTD
Mar 11 at 10:27
$begingroup$
Therefore the answer is $19$?
$endgroup$
– Sam
Mar 11 at 10:29
$begingroup$
Therefore the answer is $19$?
$endgroup$
– Sam
Mar 11 at 10:29
1
1
$begingroup$
Yes, that's right :-).
$endgroup$
– StackTD
Mar 11 at 10:30
$begingroup$
Yes, that's right :-).
$endgroup$
– StackTD
Mar 11 at 10:30
add a comment |
$begingroup$
If $x_1=-8$, then we have $t=-2$.
Can you take it from here ?
answered Mar 11 at 10:16
FredFred
48.3k1849
$endgroup$
$begingroup$
so $x2=9+-2*-5=19$?
$endgroup$
– Sam
Mar 11 at 10:29
$begingroup$
Yes, we have $x_2=19.$
$endgroup$
– Fred
Mar 11 at 10:33
add a comment |
$begingroup$
If $x_1=-8$, then we have $t=-2$.
Can you take it from here ?
answered Mar 11 at 10:16
FredFred
48.3k1849
$endgroup$
$begingroup$
so $x2=9+-2*-5=19$?
$endgroup$
– Sam
Mar 11 at 10:29
$begingroup$
Yes, we have $x_2=19.$
$endgroup$
– Fred
Mar 11 at 10:33
add a comment |
$begingroup$
If $x_1=-8$, then we have $t=-2$.
Can you take it from here ?
answered Mar 11 at 10:16
FredFred
48.3k1849
$endgroup$
If $x_1=-8$, then we have $t=-2$.
Can you take it from here ?
answered Mar 11 at 10:16
FredFred
48.3k1849
answered Mar 11 at 10:16
FredFred
48.3k1849
answered Mar 11 at 10:16
FredFred
48.3k1849
answered Mar 11 at 10:16
FredFred
48.3k1849
48.3k1849
$begingroup$
so $x2=9+-2*-5=19$?
$endgroup$
– Sam
Mar 11 at 10:29
$begingroup$
Yes, we have $x_2=19.$
$endgroup$
– Fred
Mar 11 at 10:33
add a comment |
$begingroup$
so $x2=9+-2*-5=19$?
$endgroup$
– Sam
Mar 11 at 10:29
$begingroup$
Yes, we have $x_2=19.$
$endgroup$
– Fred
Mar 11 at 10:33
$begingroup$
so $x2=9+-2*-5=19$?
$endgroup$
– Sam
Mar 11 at 10:29
$begingroup$
so $x2=9+-2*-5=19$?
$endgroup$
– Sam
Mar 11 at 10:29
$begingroup$
Yes, we have $x_2=19.$
$endgroup$
– Fred
Mar 11 at 10:33
$begingroup$
Yes, we have $x_2=19.$
$endgroup$
– Fred
Mar 11 at 10:33
add a comment |
Sam is a new contributor. Be nice, and check out our Code of Conduct.
Sam is a new contributor. Be nice, and check out our Code of Conduct.
Sam is a new contributor. Be nice, and check out our Code of Conduct.
Sam is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
Please do not apply the algebraic-geometry tag to elementary problems involving algebra and geometry, as per the tag description.
$endgroup$
– KReiser
Mar 11 at 18:30