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Negative Resistance


How does current flow through a voltage source?Does electric potential influence the direction of current?Reversed Current in Passive Loads?how does negative differential resistance in a PCT work?How to test if a, in circuit, complementary darling transistor is still functioning properly?How can a grounded gate MOSFET conduct current?Visualizing Electrical PotentialDoes voltage limit current?How can an electron have 0 electric potential after exiting a resistor but have current?Why (physically) does a current divider circuit show that both resistors have an effect on individual current?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








8












$begingroup$


I am a bit confused about the physical meaning of negative resistance.



Mathematically, a component which has negative resistance shows a decreasing voltage across its terminal when the current inside it grows, and vice versa. But how is this physically possible?



Somewhere I have read that an example of component with negative resistance is a voltage source. But I do not understand this statement, since a voltage source is a component which at most shows a (positive) internal resistance.










share|improve this question











$endgroup$











  • $begingroup$
    Maybe if you see a circuit with two resistors in series (voltage divider), having in the middle 2.5V, a component with negative resistance can be said to 'add voltage' instead of removing voltage... but I leave a real answer to the experts here ;-)
    $endgroup$
    – Michel Keijzers
    7 hours ago






  • 1




    $begingroup$
    Minus R will provide power, not dissipate power.
    $endgroup$
    – analogsystemsrf
    7 hours ago










  • $begingroup$
    Meh, there's no such thing as negative resistance. It's an artifice of improperly (IMO) applying Ohm's Law to something non-linear (not resistor-like). If we flip it into conductance, you are saying something has a negative conductance, i.e. its conductance goes below 0 (below total insulator - in other words current flow induces a reverse voltage). Such a device is not a good fit for Ohm's Law.
    $endgroup$
    – Harper
    1 hour ago

















8












$begingroup$


I am a bit confused about the physical meaning of negative resistance.



Mathematically, a component which has negative resistance shows a decreasing voltage across its terminal when the current inside it grows, and vice versa. But how is this physically possible?



Somewhere I have read that an example of component with negative resistance is a voltage source. But I do not understand this statement, since a voltage source is a component which at most shows a (positive) internal resistance.










share|improve this question











$endgroup$











  • $begingroup$
    Maybe if you see a circuit with two resistors in series (voltage divider), having in the middle 2.5V, a component with negative resistance can be said to 'add voltage' instead of removing voltage... but I leave a real answer to the experts here ;-)
    $endgroup$
    – Michel Keijzers
    7 hours ago






  • 1




    $begingroup$
    Minus R will provide power, not dissipate power.
    $endgroup$
    – analogsystemsrf
    7 hours ago










  • $begingroup$
    Meh, there's no such thing as negative resistance. It's an artifice of improperly (IMO) applying Ohm's Law to something non-linear (not resistor-like). If we flip it into conductance, you are saying something has a negative conductance, i.e. its conductance goes below 0 (below total insulator - in other words current flow induces a reverse voltage). Such a device is not a good fit for Ohm's Law.
    $endgroup$
    – Harper
    1 hour ago













8












8








8


1



$begingroup$


I am a bit confused about the physical meaning of negative resistance.



Mathematically, a component which has negative resistance shows a decreasing voltage across its terminal when the current inside it grows, and vice versa. But how is this physically possible?



Somewhere I have read that an example of component with negative resistance is a voltage source. But I do not understand this statement, since a voltage source is a component which at most shows a (positive) internal resistance.










share|improve this question











$endgroup$




I am a bit confused about the physical meaning of negative resistance.



Mathematically, a component which has negative resistance shows a decreasing voltage across its terminal when the current inside it grows, and vice versa. But how is this physically possible?



Somewhere I have read that an example of component with negative resistance is a voltage source. But I do not understand this statement, since a voltage source is a component which at most shows a (positive) internal resistance.







voltage current resistors resistance voltage-source






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 7 hours ago









Marcus Müller

35.5k363101




35.5k363101










asked 8 hours ago









Kinka-ByoKinka-Byo

1013




1013











  • $begingroup$
    Maybe if you see a circuit with two resistors in series (voltage divider), having in the middle 2.5V, a component with negative resistance can be said to 'add voltage' instead of removing voltage... but I leave a real answer to the experts here ;-)
    $endgroup$
    – Michel Keijzers
    7 hours ago






  • 1




    $begingroup$
    Minus R will provide power, not dissipate power.
    $endgroup$
    – analogsystemsrf
    7 hours ago










  • $begingroup$
    Meh, there's no such thing as negative resistance. It's an artifice of improperly (IMO) applying Ohm's Law to something non-linear (not resistor-like). If we flip it into conductance, you are saying something has a negative conductance, i.e. its conductance goes below 0 (below total insulator - in other words current flow induces a reverse voltage). Such a device is not a good fit for Ohm's Law.
    $endgroup$
    – Harper
    1 hour ago
















  • $begingroup$
    Maybe if you see a circuit with two resistors in series (voltage divider), having in the middle 2.5V, a component with negative resistance can be said to 'add voltage' instead of removing voltage... but I leave a real answer to the experts here ;-)
    $endgroup$
    – Michel Keijzers
    7 hours ago






  • 1




    $begingroup$
    Minus R will provide power, not dissipate power.
    $endgroup$
    – analogsystemsrf
    7 hours ago










  • $begingroup$
    Meh, there's no such thing as negative resistance. It's an artifice of improperly (IMO) applying Ohm's Law to something non-linear (not resistor-like). If we flip it into conductance, you are saying something has a negative conductance, i.e. its conductance goes below 0 (below total insulator - in other words current flow induces a reverse voltage). Such a device is not a good fit for Ohm's Law.
    $endgroup$
    – Harper
    1 hour ago















$begingroup$
Maybe if you see a circuit with two resistors in series (voltage divider), having in the middle 2.5V, a component with negative resistance can be said to 'add voltage' instead of removing voltage... but I leave a real answer to the experts here ;-)
$endgroup$
– Michel Keijzers
7 hours ago




$begingroup$
Maybe if you see a circuit with two resistors in series (voltage divider), having in the middle 2.5V, a component with negative resistance can be said to 'add voltage' instead of removing voltage... but I leave a real answer to the experts here ;-)
$endgroup$
– Michel Keijzers
7 hours ago




1




1




$begingroup$
Minus R will provide power, not dissipate power.
$endgroup$
– analogsystemsrf
7 hours ago




$begingroup$
Minus R will provide power, not dissipate power.
$endgroup$
– analogsystemsrf
7 hours ago












$begingroup$
Meh, there's no such thing as negative resistance. It's an artifice of improperly (IMO) applying Ohm's Law to something non-linear (not resistor-like). If we flip it into conductance, you are saying something has a negative conductance, i.e. its conductance goes below 0 (below total insulator - in other words current flow induces a reverse voltage). Such a device is not a good fit for Ohm's Law.
$endgroup$
– Harper
1 hour ago




$begingroup$
Meh, there's no such thing as negative resistance. It's an artifice of improperly (IMO) applying Ohm's Law to something non-linear (not resistor-like). If we flip it into conductance, you are saying something has a negative conductance, i.e. its conductance goes below 0 (below total insulator - in other words current flow induces a reverse voltage). Such a device is not a good fit for Ohm's Law.
$endgroup$
– Harper
1 hour ago










10 Answers
10






active

oldest

votes


















10












$begingroup$

There are a number of mechanisms that result in a region where locally increasing voltage results in locally decreasing current. For example, an Esaki (tunnel) diode.



enter image description here



A common example would be a switching power supply with a steady load. Assuming the efficiency is more-or-less constant, increasing the input voltage results in less current being drawn. It is always consuming energy though.



A stand-alone component that exhibits negative resistance (rather than negative differential resistance) is not possible without some kind of energy source within the component, otherwise it would violate conservation of energy ($P = E^2/R$) and negative P would indicate it is acting as a power source.




If you want to play with a negative resistance effect, one way (assuming you don't mind one end being grounded) is to use a negative impedance converter:





schematic





simulate this circuit – Schematic created using CircuitLab



The above circuit acts like a -10K resistor with one end grounded (within its linear range), and works down to about zero volts. Any power it produces comes from the op-amp supplies.






share|improve this answer











$endgroup$








  • 1




    $begingroup$
    That is really a fine choice of an example device you picked.
    $endgroup$
    – The Photon
    7 hours ago










  • $begingroup$
    @ThePhoton LOL, great minds and all that.
    $endgroup$
    – Spehro Pefhany
    7 hours ago







  • 2




    $begingroup$
    @J... No, it really is negative differential resistance. You put a stiff voltage across it and keep it from oscillating the current will follow that curve. See, for example, DC Characterization of Tunnel Diodes Under Stable Non-Oscillatory Circuit Conditions by Wang et al.
    $endgroup$
    – Spehro Pefhany
    5 hours ago



















3












$begingroup$

In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance.



For a differential neg. resistance (rdiff) the current CHANGES are negativ, for a static neg. resistance the CURRENT itself has a negative sign.



My following answer concerns only the static negative resistor:



Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).






share|improve this answer











$endgroup$




















    2












    $begingroup$

    Anything that drops in voltage with a rise in current has a negative resistance.



    Power sources have this property. The passive components with incremental negative resistance include; any gas discharge bulb or arc, Avalanche effect diodes, Tunnel Diodes, SCR's during trigger phase.



    https://en.wikipedia.org/wiki/Negative_resistance






    share|improve this answer









    $endgroup$




















      2












      $begingroup$


      But how is this physically possible?




      Some components, like Esaki diodes and glow tubes, have an I-V curve that is entirely in the I and III quadrants, but has a negative slope region over a limited range. In this region, a small-signal model of the device will have negative resistance.



      enter image description here



      (image source)



      In the Esaki diode, this behavior is caused by tunneling current that is possible at low bias but not at higher bias voltage.



      It's also possible to make an op-amp circuit with negative input resistance over a limited range. There the I-V curve can even pass through the II and IV quadrants since power can be supplied from the op-amp's power terminals.




      Somewhere I have read that an example of component with negative resistance is a voltage source.




      Looking at the input side of a regulated switching supply with a fixed load, it will often appear as a negative resistance.



      This is because it is a constant power load. If the input voltage drops, the regulator circuit will increase the current drawn in order to continue supplying the load with the desired output voltage.






      share|improve this answer









      $endgroup$




















        2












        $begingroup$

        Shown here is a "Typ-A" NIC block. The grounded resistor (impedance) R3 is converted into a negative resistor (impedance) with a conversion factor (-R1/R2). This typ is short-circuit.stable. (An open-circuit stable NIC results for interchanged opamp inputs).





        schematic





        simulate this circuit – Schematic created using CircuitLab



        Comments: The shown NIC is stable as long as the source resistance of the voltage source (not shown in the figure) is smaller than R1. These NIC blocks are use for undamping filters, oscillators and other systems with unwanted positive (parasitic) resistances. Mathematically, they can be treated as "normal" resistors in series and parallel combinations - however, with a negative sign, of course.



        A very popular application is the "NIC integrator" (or "Deboo integrator"), where an NIC block is connected to the common node of a simple R-C lowpass. In this case, the NIC can compensate the pos. resistor R - thus resembling a current source which loads the intergating capacitor.






        share|improve this answer











        $endgroup$












        • $begingroup$
          Why did you answer twice?
          $endgroup$
          – pipe
          6 hours ago










        • $begingroup$
          It was by accident.....I have tried to include the figure (later) - and suddenly there were two answers...
          $endgroup$
          – LvW
          5 hours ago


















        1












        $begingroup$


        Somewhere I have read that an example of component with negative
        resistance is a voltage source. But I do not understand this
        statement, since a voltage source is a component which at most shows a
        (positive) internal resistance.




        Perhaps a voltage source is mentioned, because we all know that an ideal voltage source should have zero internal resistance: a good one will have a small positive resistance, to which is added any wire resistance going to the load.



        For an electronically regulated supply, it is possible to force output resistance past zero into negative resistance region. This is done by routing some of the load current so that regulating voltage node is adjusted in such a direction that output voltage is forced up. An example of the common LM317 regulator having negative output resistance is shown below - beware, some loads produce wild results:





        schematic





        simulate this circuit – Schematic created using CircuitLab
        Using the built-in circuit simulator, $ R_load $ was swept from 5 ohms up to 15 ohms:



        • at 5 ohms, voltage drop across Rload is 4.322V


        • at 15 ohms, voltage drop across Rload is 3.993V


        The result of that 1-ohm resistor, (and the direction of Rload's current going through it) forces this voltage supply to have negative resistance: at heavier loads, voltage across the load resistor goes up.






        share|improve this answer









        $endgroup$




















          0












          $begingroup$

          A perfect negative resistor is impossible, but a device can have negative resistance characteristics over a limited range.



          The resistance of a non-linear device varies and at a given voltage the equivalent resistance is equal to the slope of the line. If the slope is negative in a range, that range has negative resistance.



          enter image description here






          share|improve this answer









          $endgroup$












          • $begingroup$
            Mattmann944...I think it is important to add that your example concerns a DIFFERENTIAL (dynamic) negative resistance only!! Each working point on your "neg. Resistance" curve resembles a POSITIVE static resistance. More than that, a "perfect" negative resistor is possible, indeed (however, as perfect as each electronic part can be....). No ohmic resistor is "perfect".
            $endgroup$
            – LvW
            4 hours ago










          • $begingroup$
            Yes, your answer is technically more correct than mine. The OP doesn't appear to be a college student, so I tried to keep it simple. I have only seen negative resistance used in the differential sense. Most of the Wikipedia article is devoted to differential. I did say slope, which implies differential.
            $endgroup$
            – Mattman944
            1 hour ago


















          0












          $begingroup$

          DC-DC Converter inputs are a good example of a negative resistance.
          As voltage goes down, current increases to provide the same power output.
          Also a negative resistance can be created by an op amp circuit.






          share|improve this answer









          $endgroup$




















            0












            $begingroup$

            Concerning the sentence :




            Somewhere I have read that an example of component with negative
            resistance is a voltage source.




            I guess that the "voltage source with a negative resistance" is a
            crucial missundertanding.



            The error is probably the following :



            If one takes a normal classical voltage source that delivers U =
            U0 - R I and one sets U0 to 0 Volts,
            then one obtains U = -R I, hence one thinks that the resistor is
            negative.



            In fact the resistance is positive.



            The minus sign comes from the conventions used to describe the sign
            of the current and voltage. These conventions are different for sources and resistors (or any passive component)



            Mostly, and above all in everyday life, this convention is the "Active sign
            convention" for sources and "passive sign convention" for resistors ( Wiki link )



            A lot of people are not aware that they don' t use the same
            convention when they write u =
            U0 - RI for a source and U = R I for a resistor






            share|improve this answer











            $endgroup$




















              0












              $begingroup$

              In a simple way, resistance is the ratio between voltage and current, if you plot the voltage versus the current present in a certain component, the resistance will appear as the slope between these variables. In a physic way, a positive resistance means that if the voltage of a component rises, the current that flows by also rises, otherwise, a negative resistance means that when the voltage of a component rises, the current declines.






              share|improve this answer









              $endgroup$













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                10 Answers
                10






                active

                oldest

                votes








                10 Answers
                10






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes









                10












                $begingroup$

                There are a number of mechanisms that result in a region where locally increasing voltage results in locally decreasing current. For example, an Esaki (tunnel) diode.



                enter image description here



                A common example would be a switching power supply with a steady load. Assuming the efficiency is more-or-less constant, increasing the input voltage results in less current being drawn. It is always consuming energy though.



                A stand-alone component that exhibits negative resistance (rather than negative differential resistance) is not possible without some kind of energy source within the component, otherwise it would violate conservation of energy ($P = E^2/R$) and negative P would indicate it is acting as a power source.




                If you want to play with a negative resistance effect, one way (assuming you don't mind one end being grounded) is to use a negative impedance converter:





                schematic





                simulate this circuit – Schematic created using CircuitLab



                The above circuit acts like a -10K resistor with one end grounded (within its linear range), and works down to about zero volts. Any power it produces comes from the op-amp supplies.






                share|improve this answer











                $endgroup$








                • 1




                  $begingroup$
                  That is really a fine choice of an example device you picked.
                  $endgroup$
                  – The Photon
                  7 hours ago










                • $begingroup$
                  @ThePhoton LOL, great minds and all that.
                  $endgroup$
                  – Spehro Pefhany
                  7 hours ago







                • 2




                  $begingroup$
                  @J... No, it really is negative differential resistance. You put a stiff voltage across it and keep it from oscillating the current will follow that curve. See, for example, DC Characterization of Tunnel Diodes Under Stable Non-Oscillatory Circuit Conditions by Wang et al.
                  $endgroup$
                  – Spehro Pefhany
                  5 hours ago
















                10












                $begingroup$

                There are a number of mechanisms that result in a region where locally increasing voltage results in locally decreasing current. For example, an Esaki (tunnel) diode.



                enter image description here



                A common example would be a switching power supply with a steady load. Assuming the efficiency is more-or-less constant, increasing the input voltage results in less current being drawn. It is always consuming energy though.



                A stand-alone component that exhibits negative resistance (rather than negative differential resistance) is not possible without some kind of energy source within the component, otherwise it would violate conservation of energy ($P = E^2/R$) and negative P would indicate it is acting as a power source.




                If you want to play with a negative resistance effect, one way (assuming you don't mind one end being grounded) is to use a negative impedance converter:





                schematic





                simulate this circuit – Schematic created using CircuitLab



                The above circuit acts like a -10K resistor with one end grounded (within its linear range), and works down to about zero volts. Any power it produces comes from the op-amp supplies.






                share|improve this answer











                $endgroup$








                • 1




                  $begingroup$
                  That is really a fine choice of an example device you picked.
                  $endgroup$
                  – The Photon
                  7 hours ago










                • $begingroup$
                  @ThePhoton LOL, great minds and all that.
                  $endgroup$
                  – Spehro Pefhany
                  7 hours ago







                • 2




                  $begingroup$
                  @J... No, it really is negative differential resistance. You put a stiff voltage across it and keep it from oscillating the current will follow that curve. See, for example, DC Characterization of Tunnel Diodes Under Stable Non-Oscillatory Circuit Conditions by Wang et al.
                  $endgroup$
                  – Spehro Pefhany
                  5 hours ago














                10












                10








                10





                $begingroup$

                There are a number of mechanisms that result in a region where locally increasing voltage results in locally decreasing current. For example, an Esaki (tunnel) diode.



                enter image description here



                A common example would be a switching power supply with a steady load. Assuming the efficiency is more-or-less constant, increasing the input voltage results in less current being drawn. It is always consuming energy though.



                A stand-alone component that exhibits negative resistance (rather than negative differential resistance) is not possible without some kind of energy source within the component, otherwise it would violate conservation of energy ($P = E^2/R$) and negative P would indicate it is acting as a power source.




                If you want to play with a negative resistance effect, one way (assuming you don't mind one end being grounded) is to use a negative impedance converter:





                schematic





                simulate this circuit – Schematic created using CircuitLab



                The above circuit acts like a -10K resistor with one end grounded (within its linear range), and works down to about zero volts. Any power it produces comes from the op-amp supplies.






                share|improve this answer











                $endgroup$



                There are a number of mechanisms that result in a region where locally increasing voltage results in locally decreasing current. For example, an Esaki (tunnel) diode.



                enter image description here



                A common example would be a switching power supply with a steady load. Assuming the efficiency is more-or-less constant, increasing the input voltage results in less current being drawn. It is always consuming energy though.



                A stand-alone component that exhibits negative resistance (rather than negative differential resistance) is not possible without some kind of energy source within the component, otherwise it would violate conservation of energy ($P = E^2/R$) and negative P would indicate it is acting as a power source.




                If you want to play with a negative resistance effect, one way (assuming you don't mind one end being grounded) is to use a negative impedance converter:





                schematic





                simulate this circuit – Schematic created using CircuitLab



                The above circuit acts like a -10K resistor with one end grounded (within its linear range), and works down to about zero volts. Any power it produces comes from the op-amp supplies.







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 7 hours ago

























                answered 7 hours ago









                Spehro PefhanySpehro Pefhany

                215k5164439




                215k5164439







                • 1




                  $begingroup$
                  That is really a fine choice of an example device you picked.
                  $endgroup$
                  – The Photon
                  7 hours ago










                • $begingroup$
                  @ThePhoton LOL, great minds and all that.
                  $endgroup$
                  – Spehro Pefhany
                  7 hours ago







                • 2




                  $begingroup$
                  @J... No, it really is negative differential resistance. You put a stiff voltage across it and keep it from oscillating the current will follow that curve. See, for example, DC Characterization of Tunnel Diodes Under Stable Non-Oscillatory Circuit Conditions by Wang et al.
                  $endgroup$
                  – Spehro Pefhany
                  5 hours ago













                • 1




                  $begingroup$
                  That is really a fine choice of an example device you picked.
                  $endgroup$
                  – The Photon
                  7 hours ago










                • $begingroup$
                  @ThePhoton LOL, great minds and all that.
                  $endgroup$
                  – Spehro Pefhany
                  7 hours ago







                • 2




                  $begingroup$
                  @J... No, it really is negative differential resistance. You put a stiff voltage across it and keep it from oscillating the current will follow that curve. See, for example, DC Characterization of Tunnel Diodes Under Stable Non-Oscillatory Circuit Conditions by Wang et al.
                  $endgroup$
                  – Spehro Pefhany
                  5 hours ago








                1




                1




                $begingroup$
                That is really a fine choice of an example device you picked.
                $endgroup$
                – The Photon
                7 hours ago




                $begingroup$
                That is really a fine choice of an example device you picked.
                $endgroup$
                – The Photon
                7 hours ago












                $begingroup$
                @ThePhoton LOL, great minds and all that.
                $endgroup$
                – Spehro Pefhany
                7 hours ago





                $begingroup$
                @ThePhoton LOL, great minds and all that.
                $endgroup$
                – Spehro Pefhany
                7 hours ago





                2




                2




                $begingroup$
                @J... No, it really is negative differential resistance. You put a stiff voltage across it and keep it from oscillating the current will follow that curve. See, for example, DC Characterization of Tunnel Diodes Under Stable Non-Oscillatory Circuit Conditions by Wang et al.
                $endgroup$
                – Spehro Pefhany
                5 hours ago





                $begingroup$
                @J... No, it really is negative differential resistance. You put a stiff voltage across it and keep it from oscillating the current will follow that curve. See, for example, DC Characterization of Tunnel Diodes Under Stable Non-Oscillatory Circuit Conditions by Wang et al.
                $endgroup$
                – Spehro Pefhany
                5 hours ago














                3












                $begingroup$

                In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance.



                For a differential neg. resistance (rdiff) the current CHANGES are negativ, for a static neg. resistance the CURRENT itself has a negative sign.



                My following answer concerns only the static negative resistor:



                Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



                Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).






                share|improve this answer











                $endgroup$

















                  3












                  $begingroup$

                  In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance.



                  For a differential neg. resistance (rdiff) the current CHANGES are negativ, for a static neg. resistance the CURRENT itself has a negative sign.



                  My following answer concerns only the static negative resistor:



                  Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



                  Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).






                  share|improve this answer











                  $endgroup$















                    3












                    3








                    3





                    $begingroup$

                    In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance.



                    For a differential neg. resistance (rdiff) the current CHANGES are negativ, for a static neg. resistance the CURRENT itself has a negative sign.



                    My following answer concerns only the static negative resistor:



                    Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



                    Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).






                    share|improve this answer











                    $endgroup$



                    In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance.



                    For a differential neg. resistance (rdiff) the current CHANGES are negativ, for a static neg. resistance the CURRENT itself has a negative sign.



                    My following answer concerns only the static negative resistor:



                    Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



                    Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).







                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited 5 hours ago

























                    answered 7 hours ago









                    LvWLvW

                    15k21330




                    15k21330





















                        2












                        $begingroup$

                        Anything that drops in voltage with a rise in current has a negative resistance.



                        Power sources have this property. The passive components with incremental negative resistance include; any gas discharge bulb or arc, Avalanche effect diodes, Tunnel Diodes, SCR's during trigger phase.



                        https://en.wikipedia.org/wiki/Negative_resistance






                        share|improve this answer









                        $endgroup$

















                          2












                          $begingroup$

                          Anything that drops in voltage with a rise in current has a negative resistance.



                          Power sources have this property. The passive components with incremental negative resistance include; any gas discharge bulb or arc, Avalanche effect diodes, Tunnel Diodes, SCR's during trigger phase.



                          https://en.wikipedia.org/wiki/Negative_resistance






                          share|improve this answer









                          $endgroup$















                            2












                            2








                            2





                            $begingroup$

                            Anything that drops in voltage with a rise in current has a negative resistance.



                            Power sources have this property. The passive components with incremental negative resistance include; any gas discharge bulb or arc, Avalanche effect diodes, Tunnel Diodes, SCR's during trigger phase.



                            https://en.wikipedia.org/wiki/Negative_resistance






                            share|improve this answer









                            $endgroup$



                            Anything that drops in voltage with a rise in current has a negative resistance.



                            Power sources have this property. The passive components with incremental negative resistance include; any gas discharge bulb or arc, Avalanche effect diodes, Tunnel Diodes, SCR's during trigger phase.



                            https://en.wikipedia.org/wiki/Negative_resistance







                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered 7 hours ago









                            Sunnyskyguy EE75Sunnyskyguy EE75

                            72.2k227103




                            72.2k227103





















                                2












                                $begingroup$


                                But how is this physically possible?




                                Some components, like Esaki diodes and glow tubes, have an I-V curve that is entirely in the I and III quadrants, but has a negative slope region over a limited range. In this region, a small-signal model of the device will have negative resistance.



                                enter image description here



                                (image source)



                                In the Esaki diode, this behavior is caused by tunneling current that is possible at low bias but not at higher bias voltage.



                                It's also possible to make an op-amp circuit with negative input resistance over a limited range. There the I-V curve can even pass through the II and IV quadrants since power can be supplied from the op-amp's power terminals.




                                Somewhere I have read that an example of component with negative resistance is a voltage source.




                                Looking at the input side of a regulated switching supply with a fixed load, it will often appear as a negative resistance.



                                This is because it is a constant power load. If the input voltage drops, the regulator circuit will increase the current drawn in order to continue supplying the load with the desired output voltage.






                                share|improve this answer









                                $endgroup$

















                                  2












                                  $begingroup$


                                  But how is this physically possible?




                                  Some components, like Esaki diodes and glow tubes, have an I-V curve that is entirely in the I and III quadrants, but has a negative slope region over a limited range. In this region, a small-signal model of the device will have negative resistance.



                                  enter image description here



                                  (image source)



                                  In the Esaki diode, this behavior is caused by tunneling current that is possible at low bias but not at higher bias voltage.



                                  It's also possible to make an op-amp circuit with negative input resistance over a limited range. There the I-V curve can even pass through the II and IV quadrants since power can be supplied from the op-amp's power terminals.




                                  Somewhere I have read that an example of component with negative resistance is a voltage source.




                                  Looking at the input side of a regulated switching supply with a fixed load, it will often appear as a negative resistance.



                                  This is because it is a constant power load. If the input voltage drops, the regulator circuit will increase the current drawn in order to continue supplying the load with the desired output voltage.






                                  share|improve this answer









                                  $endgroup$















                                    2












                                    2








                                    2





                                    $begingroup$


                                    But how is this physically possible?




                                    Some components, like Esaki diodes and glow tubes, have an I-V curve that is entirely in the I and III quadrants, but has a negative slope region over a limited range. In this region, a small-signal model of the device will have negative resistance.



                                    enter image description here



                                    (image source)



                                    In the Esaki diode, this behavior is caused by tunneling current that is possible at low bias but not at higher bias voltage.



                                    It's also possible to make an op-amp circuit with negative input resistance over a limited range. There the I-V curve can even pass through the II and IV quadrants since power can be supplied from the op-amp's power terminals.




                                    Somewhere I have read that an example of component with negative resistance is a voltage source.




                                    Looking at the input side of a regulated switching supply with a fixed load, it will often appear as a negative resistance.



                                    This is because it is a constant power load. If the input voltage drops, the regulator circuit will increase the current drawn in order to continue supplying the load with the desired output voltage.






                                    share|improve this answer









                                    $endgroup$




                                    But how is this physically possible?




                                    Some components, like Esaki diodes and glow tubes, have an I-V curve that is entirely in the I and III quadrants, but has a negative slope region over a limited range. In this region, a small-signal model of the device will have negative resistance.



                                    enter image description here



                                    (image source)



                                    In the Esaki diode, this behavior is caused by tunneling current that is possible at low bias but not at higher bias voltage.



                                    It's also possible to make an op-amp circuit with negative input resistance over a limited range. There the I-V curve can even pass through the II and IV quadrants since power can be supplied from the op-amp's power terminals.




                                    Somewhere I have read that an example of component with negative resistance is a voltage source.




                                    Looking at the input side of a regulated switching supply with a fixed load, it will often appear as a negative resistance.



                                    This is because it is a constant power load. If the input voltage drops, the regulator circuit will increase the current drawn in order to continue supplying the load with the desired output voltage.







                                    share|improve this answer












                                    share|improve this answer



                                    share|improve this answer










                                    answered 7 hours ago









                                    The PhotonThe Photon

                                    87.9k399205




                                    87.9k399205





















                                        2












                                        $begingroup$

                                        Shown here is a "Typ-A" NIC block. The grounded resistor (impedance) R3 is converted into a negative resistor (impedance) with a conversion factor (-R1/R2). This typ is short-circuit.stable. (An open-circuit stable NIC results for interchanged opamp inputs).





                                        schematic





                                        simulate this circuit – Schematic created using CircuitLab



                                        Comments: The shown NIC is stable as long as the source resistance of the voltage source (not shown in the figure) is smaller than R1. These NIC blocks are use for undamping filters, oscillators and other systems with unwanted positive (parasitic) resistances. Mathematically, they can be treated as "normal" resistors in series and parallel combinations - however, with a negative sign, of course.



                                        A very popular application is the "NIC integrator" (or "Deboo integrator"), where an NIC block is connected to the common node of a simple R-C lowpass. In this case, the NIC can compensate the pos. resistor R - thus resembling a current source which loads the intergating capacitor.






                                        share|improve this answer











                                        $endgroup$












                                        • $begingroup$
                                          Why did you answer twice?
                                          $endgroup$
                                          – pipe
                                          6 hours ago










                                        • $begingroup$
                                          It was by accident.....I have tried to include the figure (later) - and suddenly there were two answers...
                                          $endgroup$
                                          – LvW
                                          5 hours ago















                                        2












                                        $begingroup$

                                        Shown here is a "Typ-A" NIC block. The grounded resistor (impedance) R3 is converted into a negative resistor (impedance) with a conversion factor (-R1/R2). This typ is short-circuit.stable. (An open-circuit stable NIC results for interchanged opamp inputs).





                                        schematic





                                        simulate this circuit – Schematic created using CircuitLab



                                        Comments: The shown NIC is stable as long as the source resistance of the voltage source (not shown in the figure) is smaller than R1. These NIC blocks are use for undamping filters, oscillators and other systems with unwanted positive (parasitic) resistances. Mathematically, they can be treated as "normal" resistors in series and parallel combinations - however, with a negative sign, of course.



                                        A very popular application is the "NIC integrator" (or "Deboo integrator"), where an NIC block is connected to the common node of a simple R-C lowpass. In this case, the NIC can compensate the pos. resistor R - thus resembling a current source which loads the intergating capacitor.






                                        share|improve this answer











                                        $endgroup$












                                        • $begingroup$
                                          Why did you answer twice?
                                          $endgroup$
                                          – pipe
                                          6 hours ago










                                        • $begingroup$
                                          It was by accident.....I have tried to include the figure (later) - and suddenly there were two answers...
                                          $endgroup$
                                          – LvW
                                          5 hours ago













                                        2












                                        2








                                        2





                                        $begingroup$

                                        Shown here is a "Typ-A" NIC block. The grounded resistor (impedance) R3 is converted into a negative resistor (impedance) with a conversion factor (-R1/R2). This typ is short-circuit.stable. (An open-circuit stable NIC results for interchanged opamp inputs).





                                        schematic





                                        simulate this circuit – Schematic created using CircuitLab



                                        Comments: The shown NIC is stable as long as the source resistance of the voltage source (not shown in the figure) is smaller than R1. These NIC blocks are use for undamping filters, oscillators and other systems with unwanted positive (parasitic) resistances. Mathematically, they can be treated as "normal" resistors in series and parallel combinations - however, with a negative sign, of course.



                                        A very popular application is the "NIC integrator" (or "Deboo integrator"), where an NIC block is connected to the common node of a simple R-C lowpass. In this case, the NIC can compensate the pos. resistor R - thus resembling a current source which loads the intergating capacitor.






                                        share|improve this answer











                                        $endgroup$



                                        Shown here is a "Typ-A" NIC block. The grounded resistor (impedance) R3 is converted into a negative resistor (impedance) with a conversion factor (-R1/R2). This typ is short-circuit.stable. (An open-circuit stable NIC results for interchanged opamp inputs).





                                        schematic





                                        simulate this circuit – Schematic created using CircuitLab



                                        Comments: The shown NIC is stable as long as the source resistance of the voltage source (not shown in the figure) is smaller than R1. These NIC blocks are use for undamping filters, oscillators and other systems with unwanted positive (parasitic) resistances. Mathematically, they can be treated as "normal" resistors in series and parallel combinations - however, with a negative sign, of course.



                                        A very popular application is the "NIC integrator" (or "Deboo integrator"), where an NIC block is connected to the common node of a simple R-C lowpass. In this case, the NIC can compensate the pos. resistor R - thus resembling a current source which loads the intergating capacitor.







                                        share|improve this answer














                                        share|improve this answer



                                        share|improve this answer








                                        edited 5 hours ago

























                                        answered 7 hours ago









                                        LvWLvW

                                        15k21330




                                        15k21330











                                        • $begingroup$
                                          Why did you answer twice?
                                          $endgroup$
                                          – pipe
                                          6 hours ago










                                        • $begingroup$
                                          It was by accident.....I have tried to include the figure (later) - and suddenly there were two answers...
                                          $endgroup$
                                          – LvW
                                          5 hours ago
















                                        • $begingroup$
                                          Why did you answer twice?
                                          $endgroup$
                                          – pipe
                                          6 hours ago










                                        • $begingroup$
                                          It was by accident.....I have tried to include the figure (later) - and suddenly there were two answers...
                                          $endgroup$
                                          – LvW
                                          5 hours ago















                                        $begingroup$
                                        Why did you answer twice?
                                        $endgroup$
                                        – pipe
                                        6 hours ago




                                        $begingroup$
                                        Why did you answer twice?
                                        $endgroup$
                                        – pipe
                                        6 hours ago












                                        $begingroup$
                                        It was by accident.....I have tried to include the figure (later) - and suddenly there were two answers...
                                        $endgroup$
                                        – LvW
                                        5 hours ago




                                        $begingroup$
                                        It was by accident.....I have tried to include the figure (later) - and suddenly there were two answers...
                                        $endgroup$
                                        – LvW
                                        5 hours ago











                                        1












                                        $begingroup$


                                        Somewhere I have read that an example of component with negative
                                        resistance is a voltage source. But I do not understand this
                                        statement, since a voltage source is a component which at most shows a
                                        (positive) internal resistance.




                                        Perhaps a voltage source is mentioned, because we all know that an ideal voltage source should have zero internal resistance: a good one will have a small positive resistance, to which is added any wire resistance going to the load.



                                        For an electronically regulated supply, it is possible to force output resistance past zero into negative resistance region. This is done by routing some of the load current so that regulating voltage node is adjusted in such a direction that output voltage is forced up. An example of the common LM317 regulator having negative output resistance is shown below - beware, some loads produce wild results:





                                        schematic





                                        simulate this circuit – Schematic created using CircuitLab
                                        Using the built-in circuit simulator, $ R_load $ was swept from 5 ohms up to 15 ohms:



                                        • at 5 ohms, voltage drop across Rload is 4.322V


                                        • at 15 ohms, voltage drop across Rload is 3.993V


                                        The result of that 1-ohm resistor, (and the direction of Rload's current going through it) forces this voltage supply to have negative resistance: at heavier loads, voltage across the load resistor goes up.






                                        share|improve this answer









                                        $endgroup$

















                                          1












                                          $begingroup$


                                          Somewhere I have read that an example of component with negative
                                          resistance is a voltage source. But I do not understand this
                                          statement, since a voltage source is a component which at most shows a
                                          (positive) internal resistance.




                                          Perhaps a voltage source is mentioned, because we all know that an ideal voltage source should have zero internal resistance: a good one will have a small positive resistance, to which is added any wire resistance going to the load.



                                          For an electronically regulated supply, it is possible to force output resistance past zero into negative resistance region. This is done by routing some of the load current so that regulating voltage node is adjusted in such a direction that output voltage is forced up. An example of the common LM317 regulator having negative output resistance is shown below - beware, some loads produce wild results:





                                          schematic





                                          simulate this circuit – Schematic created using CircuitLab
                                          Using the built-in circuit simulator, $ R_load $ was swept from 5 ohms up to 15 ohms:



                                          • at 5 ohms, voltage drop across Rload is 4.322V


                                          • at 15 ohms, voltage drop across Rload is 3.993V


                                          The result of that 1-ohm resistor, (and the direction of Rload's current going through it) forces this voltage supply to have negative resistance: at heavier loads, voltage across the load resistor goes up.






                                          share|improve this answer









                                          $endgroup$















                                            1












                                            1








                                            1





                                            $begingroup$


                                            Somewhere I have read that an example of component with negative
                                            resistance is a voltage source. But I do not understand this
                                            statement, since a voltage source is a component which at most shows a
                                            (positive) internal resistance.




                                            Perhaps a voltage source is mentioned, because we all know that an ideal voltage source should have zero internal resistance: a good one will have a small positive resistance, to which is added any wire resistance going to the load.



                                            For an electronically regulated supply, it is possible to force output resistance past zero into negative resistance region. This is done by routing some of the load current so that regulating voltage node is adjusted in such a direction that output voltage is forced up. An example of the common LM317 regulator having negative output resistance is shown below - beware, some loads produce wild results:





                                            schematic





                                            simulate this circuit – Schematic created using CircuitLab
                                            Using the built-in circuit simulator, $ R_load $ was swept from 5 ohms up to 15 ohms:



                                            • at 5 ohms, voltage drop across Rload is 4.322V


                                            • at 15 ohms, voltage drop across Rload is 3.993V


                                            The result of that 1-ohm resistor, (and the direction of Rload's current going through it) forces this voltage supply to have negative resistance: at heavier loads, voltage across the load resistor goes up.






                                            share|improve this answer









                                            $endgroup$




                                            Somewhere I have read that an example of component with negative
                                            resistance is a voltage source. But I do not understand this
                                            statement, since a voltage source is a component which at most shows a
                                            (positive) internal resistance.




                                            Perhaps a voltage source is mentioned, because we all know that an ideal voltage source should have zero internal resistance: a good one will have a small positive resistance, to which is added any wire resistance going to the load.



                                            For an electronically regulated supply, it is possible to force output resistance past zero into negative resistance region. This is done by routing some of the load current so that regulating voltage node is adjusted in such a direction that output voltage is forced up. An example of the common LM317 regulator having negative output resistance is shown below - beware, some loads produce wild results:





                                            schematic





                                            simulate this circuit – Schematic created using CircuitLab
                                            Using the built-in circuit simulator, $ R_load $ was swept from 5 ohms up to 15 ohms:



                                            • at 5 ohms, voltage drop across Rload is 4.322V


                                            • at 15 ohms, voltage drop across Rload is 3.993V


                                            The result of that 1-ohm resistor, (and the direction of Rload's current going through it) forces this voltage supply to have negative resistance: at heavier loads, voltage across the load resistor goes up.







                                            share|improve this answer












                                            share|improve this answer



                                            share|improve this answer










                                            answered 7 hours ago









                                            glen_geekglen_geek

                                            9,78611016




                                            9,78611016





















                                                0












                                                $begingroup$

                                                A perfect negative resistor is impossible, but a device can have negative resistance characteristics over a limited range.



                                                The resistance of a non-linear device varies and at a given voltage the equivalent resistance is equal to the slope of the line. If the slope is negative in a range, that range has negative resistance.



                                                enter image description here






                                                share|improve this answer









                                                $endgroup$












                                                • $begingroup$
                                                  Mattmann944...I think it is important to add that your example concerns a DIFFERENTIAL (dynamic) negative resistance only!! Each working point on your "neg. Resistance" curve resembles a POSITIVE static resistance. More than that, a "perfect" negative resistor is possible, indeed (however, as perfect as each electronic part can be....). No ohmic resistor is "perfect".
                                                  $endgroup$
                                                  – LvW
                                                  4 hours ago










                                                • $begingroup$
                                                  Yes, your answer is technically more correct than mine. The OP doesn't appear to be a college student, so I tried to keep it simple. I have only seen negative resistance used in the differential sense. Most of the Wikipedia article is devoted to differential. I did say slope, which implies differential.
                                                  $endgroup$
                                                  – Mattman944
                                                  1 hour ago















                                                0












                                                $begingroup$

                                                A perfect negative resistor is impossible, but a device can have negative resistance characteristics over a limited range.



                                                The resistance of a non-linear device varies and at a given voltage the equivalent resistance is equal to the slope of the line. If the slope is negative in a range, that range has negative resistance.



                                                enter image description here






                                                share|improve this answer









                                                $endgroup$












                                                • $begingroup$
                                                  Mattmann944...I think it is important to add that your example concerns a DIFFERENTIAL (dynamic) negative resistance only!! Each working point on your "neg. Resistance" curve resembles a POSITIVE static resistance. More than that, a "perfect" negative resistor is possible, indeed (however, as perfect as each electronic part can be....). No ohmic resistor is "perfect".
                                                  $endgroup$
                                                  – LvW
                                                  4 hours ago










                                                • $begingroup$
                                                  Yes, your answer is technically more correct than mine. The OP doesn't appear to be a college student, so I tried to keep it simple. I have only seen negative resistance used in the differential sense. Most of the Wikipedia article is devoted to differential. I did say slope, which implies differential.
                                                  $endgroup$
                                                  – Mattman944
                                                  1 hour ago













                                                0












                                                0








                                                0





                                                $begingroup$

                                                A perfect negative resistor is impossible, but a device can have negative resistance characteristics over a limited range.



                                                The resistance of a non-linear device varies and at a given voltage the equivalent resistance is equal to the slope of the line. If the slope is negative in a range, that range has negative resistance.



                                                enter image description here






                                                share|improve this answer









                                                $endgroup$



                                                A perfect negative resistor is impossible, but a device can have negative resistance characteristics over a limited range.



                                                The resistance of a non-linear device varies and at a given voltage the equivalent resistance is equal to the slope of the line. If the slope is negative in a range, that range has negative resistance.



                                                enter image description here







                                                share|improve this answer












                                                share|improve this answer



                                                share|improve this answer










                                                answered 7 hours ago









                                                Mattman944Mattman944

                                                3016




                                                3016











                                                • $begingroup$
                                                  Mattmann944...I think it is important to add that your example concerns a DIFFERENTIAL (dynamic) negative resistance only!! Each working point on your "neg. Resistance" curve resembles a POSITIVE static resistance. More than that, a "perfect" negative resistor is possible, indeed (however, as perfect as each electronic part can be....). No ohmic resistor is "perfect".
                                                  $endgroup$
                                                  – LvW
                                                  4 hours ago










                                                • $begingroup$
                                                  Yes, your answer is technically more correct than mine. The OP doesn't appear to be a college student, so I tried to keep it simple. I have only seen negative resistance used in the differential sense. Most of the Wikipedia article is devoted to differential. I did say slope, which implies differential.
                                                  $endgroup$
                                                  – Mattman944
                                                  1 hour ago
















                                                • $begingroup$
                                                  Mattmann944...I think it is important to add that your example concerns a DIFFERENTIAL (dynamic) negative resistance only!! Each working point on your "neg. Resistance" curve resembles a POSITIVE static resistance. More than that, a "perfect" negative resistor is possible, indeed (however, as perfect as each electronic part can be....). No ohmic resistor is "perfect".
                                                  $endgroup$
                                                  – LvW
                                                  4 hours ago










                                                • $begingroup$
                                                  Yes, your answer is technically more correct than mine. The OP doesn't appear to be a college student, so I tried to keep it simple. I have only seen negative resistance used in the differential sense. Most of the Wikipedia article is devoted to differential. I did say slope, which implies differential.
                                                  $endgroup$
                                                  – Mattman944
                                                  1 hour ago















                                                $begingroup$
                                                Mattmann944...I think it is important to add that your example concerns a DIFFERENTIAL (dynamic) negative resistance only!! Each working point on your "neg. Resistance" curve resembles a POSITIVE static resistance. More than that, a "perfect" negative resistor is possible, indeed (however, as perfect as each electronic part can be....). No ohmic resistor is "perfect".
                                                $endgroup$
                                                – LvW
                                                4 hours ago




                                                $begingroup$
                                                Mattmann944...I think it is important to add that your example concerns a DIFFERENTIAL (dynamic) negative resistance only!! Each working point on your "neg. Resistance" curve resembles a POSITIVE static resistance. More than that, a "perfect" negative resistor is possible, indeed (however, as perfect as each electronic part can be....). No ohmic resistor is "perfect".
                                                $endgroup$
                                                – LvW
                                                4 hours ago












                                                $begingroup$
                                                Yes, your answer is technically more correct than mine. The OP doesn't appear to be a college student, so I tried to keep it simple. I have only seen negative resistance used in the differential sense. Most of the Wikipedia article is devoted to differential. I did say slope, which implies differential.
                                                $endgroup$
                                                – Mattman944
                                                1 hour ago




                                                $begingroup$
                                                Yes, your answer is technically more correct than mine. The OP doesn't appear to be a college student, so I tried to keep it simple. I have only seen negative resistance used in the differential sense. Most of the Wikipedia article is devoted to differential. I did say slope, which implies differential.
                                                $endgroup$
                                                – Mattman944
                                                1 hour ago











                                                0












                                                $begingroup$

                                                DC-DC Converter inputs are a good example of a negative resistance.
                                                As voltage goes down, current increases to provide the same power output.
                                                Also a negative resistance can be created by an op amp circuit.






                                                share|improve this answer









                                                $endgroup$

















                                                  0












                                                  $begingroup$

                                                  DC-DC Converter inputs are a good example of a negative resistance.
                                                  As voltage goes down, current increases to provide the same power output.
                                                  Also a negative resistance can be created by an op amp circuit.






                                                  share|improve this answer









                                                  $endgroup$















                                                    0












                                                    0








                                                    0





                                                    $begingroup$

                                                    DC-DC Converter inputs are a good example of a negative resistance.
                                                    As voltage goes down, current increases to provide the same power output.
                                                    Also a negative resistance can be created by an op amp circuit.






                                                    share|improve this answer









                                                    $endgroup$



                                                    DC-DC Converter inputs are a good example of a negative resistance.
                                                    As voltage goes down, current increases to provide the same power output.
                                                    Also a negative resistance can be created by an op amp circuit.







                                                    share|improve this answer












                                                    share|improve this answer



                                                    share|improve this answer










                                                    answered 6 hours ago









                                                    EE_socalEE_socal

                                                    1,10016




                                                    1,10016





















                                                        0












                                                        $begingroup$

                                                        Concerning the sentence :




                                                        Somewhere I have read that an example of component with negative
                                                        resistance is a voltage source.




                                                        I guess that the "voltage source with a negative resistance" is a
                                                        crucial missundertanding.



                                                        The error is probably the following :



                                                        If one takes a normal classical voltage source that delivers U =
                                                        U0 - R I and one sets U0 to 0 Volts,
                                                        then one obtains U = -R I, hence one thinks that the resistor is
                                                        negative.



                                                        In fact the resistance is positive.



                                                        The minus sign comes from the conventions used to describe the sign
                                                        of the current and voltage. These conventions are different for sources and resistors (or any passive component)



                                                        Mostly, and above all in everyday life, this convention is the "Active sign
                                                        convention" for sources and "passive sign convention" for resistors ( Wiki link )



                                                        A lot of people are not aware that they don' t use the same
                                                        convention when they write u =
                                                        U0 - RI for a source and U = R I for a resistor






                                                        share|improve this answer











                                                        $endgroup$

















                                                          0












                                                          $begingroup$

                                                          Concerning the sentence :




                                                          Somewhere I have read that an example of component with negative
                                                          resistance is a voltage source.




                                                          I guess that the "voltage source with a negative resistance" is a
                                                          crucial missundertanding.



                                                          The error is probably the following :



                                                          If one takes a normal classical voltage source that delivers U =
                                                          U0 - R I and one sets U0 to 0 Volts,
                                                          then one obtains U = -R I, hence one thinks that the resistor is
                                                          negative.



                                                          In fact the resistance is positive.



                                                          The minus sign comes from the conventions used to describe the sign
                                                          of the current and voltage. These conventions are different for sources and resistors (or any passive component)



                                                          Mostly, and above all in everyday life, this convention is the "Active sign
                                                          convention" for sources and "passive sign convention" for resistors ( Wiki link )



                                                          A lot of people are not aware that they don' t use the same
                                                          convention when they write u =
                                                          U0 - RI for a source and U = R I for a resistor






                                                          share|improve this answer











                                                          $endgroup$















                                                            0












                                                            0








                                                            0





                                                            $begingroup$

                                                            Concerning the sentence :




                                                            Somewhere I have read that an example of component with negative
                                                            resistance is a voltage source.




                                                            I guess that the "voltage source with a negative resistance" is a
                                                            crucial missundertanding.



                                                            The error is probably the following :



                                                            If one takes a normal classical voltage source that delivers U =
                                                            U0 - R I and one sets U0 to 0 Volts,
                                                            then one obtains U = -R I, hence one thinks that the resistor is
                                                            negative.



                                                            In fact the resistance is positive.



                                                            The minus sign comes from the conventions used to describe the sign
                                                            of the current and voltage. These conventions are different for sources and resistors (or any passive component)



                                                            Mostly, and above all in everyday life, this convention is the "Active sign
                                                            convention" for sources and "passive sign convention" for resistors ( Wiki link )



                                                            A lot of people are not aware that they don' t use the same
                                                            convention when they write u =
                                                            U0 - RI for a source and U = R I for a resistor






                                                            share|improve this answer











                                                            $endgroup$



                                                            Concerning the sentence :




                                                            Somewhere I have read that an example of component with negative
                                                            resistance is a voltage source.




                                                            I guess that the "voltage source with a negative resistance" is a
                                                            crucial missundertanding.



                                                            The error is probably the following :



                                                            If one takes a normal classical voltage source that delivers U =
                                                            U0 - R I and one sets U0 to 0 Volts,
                                                            then one obtains U = -R I, hence one thinks that the resistor is
                                                            negative.



                                                            In fact the resistance is positive.



                                                            The minus sign comes from the conventions used to describe the sign
                                                            of the current and voltage. These conventions are different for sources and resistors (or any passive component)



                                                            Mostly, and above all in everyday life, this convention is the "Active sign
                                                            convention" for sources and "passive sign convention" for resistors ( Wiki link )



                                                            A lot of people are not aware that they don' t use the same
                                                            convention when they write u =
                                                            U0 - RI for a source and U = R I for a resistor







                                                            share|improve this answer














                                                            share|improve this answer



                                                            share|improve this answer








                                                            edited 4 hours ago

























                                                            answered 5 hours ago









                                                            andre314andre314

                                                            546511




                                                            546511





















                                                                0












                                                                $begingroup$

                                                                In a simple way, resistance is the ratio between voltage and current, if you plot the voltage versus the current present in a certain component, the resistance will appear as the slope between these variables. In a physic way, a positive resistance means that if the voltage of a component rises, the current that flows by also rises, otherwise, a negative resistance means that when the voltage of a component rises, the current declines.






                                                                share|improve this answer









                                                                $endgroup$

















                                                                  0












                                                                  $begingroup$

                                                                  In a simple way, resistance is the ratio between voltage and current, if you plot the voltage versus the current present in a certain component, the resistance will appear as the slope between these variables. In a physic way, a positive resistance means that if the voltage of a component rises, the current that flows by also rises, otherwise, a negative resistance means that when the voltage of a component rises, the current declines.






                                                                  share|improve this answer









                                                                  $endgroup$















                                                                    0












                                                                    0








                                                                    0





                                                                    $begingroup$

                                                                    In a simple way, resistance is the ratio between voltage and current, if you plot the voltage versus the current present in a certain component, the resistance will appear as the slope between these variables. In a physic way, a positive resistance means that if the voltage of a component rises, the current that flows by also rises, otherwise, a negative resistance means that when the voltage of a component rises, the current declines.






                                                                    share|improve this answer









                                                                    $endgroup$



                                                                    In a simple way, resistance is the ratio between voltage and current, if you plot the voltage versus the current present in a certain component, the resistance will appear as the slope between these variables. In a physic way, a positive resistance means that if the voltage of a component rises, the current that flows by also rises, otherwise, a negative resistance means that when the voltage of a component rises, the current declines.







                                                                    share|improve this answer












                                                                    share|improve this answer



                                                                    share|improve this answer










                                                                    answered 2 hours ago









                                                                    NightmerkerNightmerker

                                                                    1437




                                                                    1437



























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