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I found some code in a script given to me by another person as a resource for lockdown/hardening of Ubuntu 16.04 for a project I am doing.
I have no idea what it does and do no want to run it if I can't identify the change it would make, is anyone aware of what it does or changes? Only code without a brief explanation comment, and it happens to be the only thing I do not know. Also, second function is identifiable by function but I don't understand the purpose or specifics.
function bacon.config.ubuntu.chage()
CHAGE_SCRIPT='/etc/cron.daily/userchage'
if [ ! -e $CHAGE_SCRIPT ]; then
printf "#%c/bin/bash nfor i in $(awk -F: 'if(($3 >= 1000)&&($3 <65534)) print $1' /etc/passwd); do nchage -m 0 -M 60 -W 10 $i ndone n" ! > $CHAGE_SCRIPT
chmod +x $CHAGE_SCRIPT
fi
function bacon.config.ubuntu.log.rotate()
echo "bacon.config.ubuntu.log.rotate: [INFO] Installing logrotate..."
sudo apt-get install logrotate 1>/dev/null
echo "bacon.config.ubuntu.log.rotate: [INFO] Configuring logrotate..."
sed 's/rotate 4/rotate 60/' /etc/logrotate.conf > /etc/logrotate.conf.new
mv /etc/logrotate.conf.new /etc/logrotate.conf
sed 's/rotate 1/rotate 60/' /etc/logrotate.conf > /etc/logrotate.conf.new
mv /etc/logrotate.conf.new /etc/log.rotate.conf
sed 's/rotate 7/rotate 1825/' /etc/logrotate.d/rsyslog > /etc/logrotate.d/rsyslog.new
mv /etc/logrotate.d/rsyslog.new /etc/logrotate.d/rsyslog
Any help identifying these would be amazing.
bash scripts
New contributor
add a comment |
I found some code in a script given to me by another person as a resource for lockdown/hardening of Ubuntu 16.04 for a project I am doing.
I have no idea what it does and do no want to run it if I can't identify the change it would make, is anyone aware of what it does or changes? Only code without a brief explanation comment, and it happens to be the only thing I do not know. Also, second function is identifiable by function but I don't understand the purpose or specifics.
function bacon.config.ubuntu.chage()
CHAGE_SCRIPT='/etc/cron.daily/userchage'
if [ ! -e $CHAGE_SCRIPT ]; then
printf "#%c/bin/bash nfor i in $(awk -F: 'if(($3 >= 1000)&&($3 <65534)) print $1' /etc/passwd); do nchage -m 0 -M 60 -W 10 $i ndone n" ! > $CHAGE_SCRIPT
chmod +x $CHAGE_SCRIPT
fi
function bacon.config.ubuntu.log.rotate()
echo "bacon.config.ubuntu.log.rotate: [INFO] Installing logrotate..."
sudo apt-get install logrotate 1>/dev/null
echo "bacon.config.ubuntu.log.rotate: [INFO] Configuring logrotate..."
sed 's/rotate 4/rotate 60/' /etc/logrotate.conf > /etc/logrotate.conf.new
mv /etc/logrotate.conf.new /etc/logrotate.conf
sed 's/rotate 1/rotate 60/' /etc/logrotate.conf > /etc/logrotate.conf.new
mv /etc/logrotate.conf.new /etc/log.rotate.conf
sed 's/rotate 7/rotate 1825/' /etc/logrotate.d/rsyslog > /etc/logrotate.d/rsyslog.new
mv /etc/logrotate.d/rsyslog.new /etc/logrotate.d/rsyslog
Any help identifying these would be amazing.
bash scripts
New contributor
2
I would ask the person who gave me the code what it does.
– WinEunuuchs2Unix
11 hours ago
1
@WinEunuuchs2Unix Normally I would as well, but they are away from the office for a while due to personal circumstances. Trust me, I know how much easier that would be. :)
– Brendan77222
11 hours ago
2
Well done on not running a script as root when you don't know what it does.
– Wildcard
3 hours ago
add a comment |
I found some code in a script given to me by another person as a resource for lockdown/hardening of Ubuntu 16.04 for a project I am doing.
I have no idea what it does and do no want to run it if I can't identify the change it would make, is anyone aware of what it does or changes? Only code without a brief explanation comment, and it happens to be the only thing I do not know. Also, second function is identifiable by function but I don't understand the purpose or specifics.
function bacon.config.ubuntu.chage()
CHAGE_SCRIPT='/etc/cron.daily/userchage'
if [ ! -e $CHAGE_SCRIPT ]; then
printf "#%c/bin/bash nfor i in $(awk -F: 'if(($3 >= 1000)&&($3 <65534)) print $1' /etc/passwd); do nchage -m 0 -M 60 -W 10 $i ndone n" ! > $CHAGE_SCRIPT
chmod +x $CHAGE_SCRIPT
fi
function bacon.config.ubuntu.log.rotate()
echo "bacon.config.ubuntu.log.rotate: [INFO] Installing logrotate..."
sudo apt-get install logrotate 1>/dev/null
echo "bacon.config.ubuntu.log.rotate: [INFO] Configuring logrotate..."
sed 's/rotate 4/rotate 60/' /etc/logrotate.conf > /etc/logrotate.conf.new
mv /etc/logrotate.conf.new /etc/logrotate.conf
sed 's/rotate 1/rotate 60/' /etc/logrotate.conf > /etc/logrotate.conf.new
mv /etc/logrotate.conf.new /etc/log.rotate.conf
sed 's/rotate 7/rotate 1825/' /etc/logrotate.d/rsyslog > /etc/logrotate.d/rsyslog.new
mv /etc/logrotate.d/rsyslog.new /etc/logrotate.d/rsyslog
Any help identifying these would be amazing.
bash scripts
New contributor
I found some code in a script given to me by another person as a resource for lockdown/hardening of Ubuntu 16.04 for a project I am doing.
I have no idea what it does and do no want to run it if I can't identify the change it would make, is anyone aware of what it does or changes? Only code without a brief explanation comment, and it happens to be the only thing I do not know. Also, second function is identifiable by function but I don't understand the purpose or specifics.
function bacon.config.ubuntu.chage()
CHAGE_SCRIPT='/etc/cron.daily/userchage'
if [ ! -e $CHAGE_SCRIPT ]; then
printf "#%c/bin/bash nfor i in $(awk -F: 'if(($3 >= 1000)&&($3 <65534)) print $1' /etc/passwd); do nchage -m 0 -M 60 -W 10 $i ndone n" ! > $CHAGE_SCRIPT
chmod +x $CHAGE_SCRIPT
fi
function bacon.config.ubuntu.log.rotate()
echo "bacon.config.ubuntu.log.rotate: [INFO] Installing logrotate..."
sudo apt-get install logrotate 1>/dev/null
echo "bacon.config.ubuntu.log.rotate: [INFO] Configuring logrotate..."
sed 's/rotate 4/rotate 60/' /etc/logrotate.conf > /etc/logrotate.conf.new
mv /etc/logrotate.conf.new /etc/logrotate.conf
sed 's/rotate 1/rotate 60/' /etc/logrotate.conf > /etc/logrotate.conf.new
mv /etc/logrotate.conf.new /etc/log.rotate.conf
sed 's/rotate 7/rotate 1825/' /etc/logrotate.d/rsyslog > /etc/logrotate.d/rsyslog.new
mv /etc/logrotate.d/rsyslog.new /etc/logrotate.d/rsyslog
Any help identifying these would be amazing.
bash scripts
bash scripts
New contributor
New contributor
edited 10 hours ago
serv-inc
1,7211521
1,7211521
New contributor
asked 11 hours ago
Brendan77222Brendan77222
315
315
New contributor
New contributor
2
I would ask the person who gave me the code what it does.
– WinEunuuchs2Unix
11 hours ago
1
@WinEunuuchs2Unix Normally I would as well, but they are away from the office for a while due to personal circumstances. Trust me, I know how much easier that would be. :)
– Brendan77222
11 hours ago
2
Well done on not running a script as root when you don't know what it does.
– Wildcard
3 hours ago
add a comment |
2
I would ask the person who gave me the code what it does.
– WinEunuuchs2Unix
11 hours ago
1
@WinEunuuchs2Unix Normally I would as well, but they are away from the office for a while due to personal circumstances. Trust me, I know how much easier that would be. :)
– Brendan77222
11 hours ago
2
Well done on not running a script as root when you don't know what it does.
– Wildcard
3 hours ago
2
2
I would ask the person who gave me the code what it does.
– WinEunuuchs2Unix
11 hours ago
I would ask the person who gave me the code what it does.
– WinEunuuchs2Unix
11 hours ago
1
1
@WinEunuuchs2Unix Normally I would as well, but they are away from the office for a while due to personal circumstances. Trust me, I know how much easier that would be. :)
– Brendan77222
11 hours ago
@WinEunuuchs2Unix Normally I would as well, but they are away from the office for a while due to personal circumstances. Trust me, I know how much easier that would be. :)
– Brendan77222
11 hours ago
2
2
Well done on not running a script as root when you don't know what it does.
– Wildcard
3 hours ago
Well done on not running a script as root when you don't know what it does.
– Wildcard
3 hours ago
add a comment |
3 Answers
3
active
oldest
votes
The first function checks whether file $CHAGE_SCRIPT
exists, and if not attempts to create it with a printf
statement. You can see what this statement does by running it in a terminal:
$ printf "#%c/bin/bash nfor i in $(awk -F: 'if(($3 >= 1000)&&($3 <65534)) print $1' /etc/passwd); do nchage -m 0 -M 60 -W 10 $i ndone n" !
#!/bin/bash
for i in $(awk -F: 'if(( >= 1000)&&( <65534)) print $1' /etc/passwd); do
chage -m 0 -M 60 -W 10 $i
done
You will notice that instances of $3
evaluate empty because (unlike $1
) they are not protected from expansion by the shell. The use of %c
to insert the !
in #!/bin/bash
suggests the original author doesn't really understand how bash's history expansion works.
IMHO it would be simpler and clearer to use a here-document:
function bacon.config.ubuntu.chage()
CHAGE_SCRIPT='/etc/cron.daily/userchage'
if [ ! -e "$CHAGE_SCRIPT" ]; then
cat << 'EOF' > "$CHAGE_SCRIPT"
#!/bin/bash
for i in $(awk -F: 'if(($3 >= 1000)&&($3 <65534)) print $1' /etc/passwd); do
chage -m 0 -M 60 -W 10 $i
done
EOF
chmod +x "$CHAGE_SCRIPT"
fi
The operation of the second function should be pretty obvious - it could be simplified by combining all the sed
commands so that the file is only written / moved once.
If the $3 evaluates empty, is there a reason to include it? If I wanted something to complete the same task, without useless portions included how much would I need to change it?
– Brendan77222
10 hours ago
1
@Brendan77222 I'm assuming the empty evaluation of$3
was unintentional - since it would result in a syntax error from awk
– steeldriver
9 hours ago
would leaving it in or taking it out be something I need to be concerned with? Should I want it to function as intended at least.
– Brendan77222
6 hours ago
add a comment |
The script contains two function definitions. The first function, bacon.config.ubuntu.chage
, creates a script at /etc/cron.daily/userchage
(comments added by me):
#!/bin/bash
# loop through users with uid >= 1000 and uid < 65534 theoretically, but $3 isn't escaped -> doesn't work
for i in $(awk -F: 'if(( >= 1000)&&( <65534)) print $1' /etc/passwd);do
# set password to expire after 60 days, warning after 50 days
chage -m 0 -M 60 -W 10 $i
done
The second function installs logrotate and creates a config file for it.
New contributor
Awesome those comments help a lot. is there a reason for inserting a script at /etc/chron.daily/userchage rather than just executing the for loop you put here? I am unfamiliar with userchage file's function
– Brendan77222
10 hours ago
1
Yes, any scripts in /etc/cron.daily/ will be executed once per day.
– FliegendeWurst
10 hours ago
Awesome, thank you for the confirmation on what I suspected. Awesome help.
– Brendan77222
10 hours ago
add a comment |
The chage
program changes the password expiry for all users. That is, it only lets them keep their current password for at most 60 days. It is run daily. The minimum duration of 0
is questionable as of https://security.stackexchange.com/questions/78758/what-is-the-purpose-of-the-password-minimum-age-setting. Maybe ask on https://security.stackexchange.com if this is really recommended.
Why logrotate
should improve security is a bit above me.
1
Oh, we definitely want a minimum password age of 24 hours. I assume that is the -m flag? I can read the man page as well, just was confused on why it used a check for a script. But I now feel from your comment it does that to ensure this is checked daily rather than a one time thing.
– Brendan77222
10 hours ago
1
Exactly. And-m
seems correct. If you can read the man pages, you can seeman cron
for thecron.daily
folder.
– serv-inc
7 hours ago
add a comment |
Your Answer
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
The first function checks whether file $CHAGE_SCRIPT
exists, and if not attempts to create it with a printf
statement. You can see what this statement does by running it in a terminal:
$ printf "#%c/bin/bash nfor i in $(awk -F: 'if(($3 >= 1000)&&($3 <65534)) print $1' /etc/passwd); do nchage -m 0 -M 60 -W 10 $i ndone n" !
#!/bin/bash
for i in $(awk -F: 'if(( >= 1000)&&( <65534)) print $1' /etc/passwd); do
chage -m 0 -M 60 -W 10 $i
done
You will notice that instances of $3
evaluate empty because (unlike $1
) they are not protected from expansion by the shell. The use of %c
to insert the !
in #!/bin/bash
suggests the original author doesn't really understand how bash's history expansion works.
IMHO it would be simpler and clearer to use a here-document:
function bacon.config.ubuntu.chage()
CHAGE_SCRIPT='/etc/cron.daily/userchage'
if [ ! -e "$CHAGE_SCRIPT" ]; then
cat << 'EOF' > "$CHAGE_SCRIPT"
#!/bin/bash
for i in $(awk -F: 'if(($3 >= 1000)&&($3 <65534)) print $1' /etc/passwd); do
chage -m 0 -M 60 -W 10 $i
done
EOF
chmod +x "$CHAGE_SCRIPT"
fi
The operation of the second function should be pretty obvious - it could be simplified by combining all the sed
commands so that the file is only written / moved once.
If the $3 evaluates empty, is there a reason to include it? If I wanted something to complete the same task, without useless portions included how much would I need to change it?
– Brendan77222
10 hours ago
1
@Brendan77222 I'm assuming the empty evaluation of$3
was unintentional - since it would result in a syntax error from awk
– steeldriver
9 hours ago
would leaving it in or taking it out be something I need to be concerned with? Should I want it to function as intended at least.
– Brendan77222
6 hours ago
add a comment |
The first function checks whether file $CHAGE_SCRIPT
exists, and if not attempts to create it with a printf
statement. You can see what this statement does by running it in a terminal:
$ printf "#%c/bin/bash nfor i in $(awk -F: 'if(($3 >= 1000)&&($3 <65534)) print $1' /etc/passwd); do nchage -m 0 -M 60 -W 10 $i ndone n" !
#!/bin/bash
for i in $(awk -F: 'if(( >= 1000)&&( <65534)) print $1' /etc/passwd); do
chage -m 0 -M 60 -W 10 $i
done
You will notice that instances of $3
evaluate empty because (unlike $1
) they are not protected from expansion by the shell. The use of %c
to insert the !
in #!/bin/bash
suggests the original author doesn't really understand how bash's history expansion works.
IMHO it would be simpler and clearer to use a here-document:
function bacon.config.ubuntu.chage()
CHAGE_SCRIPT='/etc/cron.daily/userchage'
if [ ! -e "$CHAGE_SCRIPT" ]; then
cat << 'EOF' > "$CHAGE_SCRIPT"
#!/bin/bash
for i in $(awk -F: 'if(($3 >= 1000)&&($3 <65534)) print $1' /etc/passwd); do
chage -m 0 -M 60 -W 10 $i
done
EOF
chmod +x "$CHAGE_SCRIPT"
fi
The operation of the second function should be pretty obvious - it could be simplified by combining all the sed
commands so that the file is only written / moved once.
If the $3 evaluates empty, is there a reason to include it? If I wanted something to complete the same task, without useless portions included how much would I need to change it?
– Brendan77222
10 hours ago
1
@Brendan77222 I'm assuming the empty evaluation of$3
was unintentional - since it would result in a syntax error from awk
– steeldriver
9 hours ago
would leaving it in or taking it out be something I need to be concerned with? Should I want it to function as intended at least.
– Brendan77222
6 hours ago
add a comment |
The first function checks whether file $CHAGE_SCRIPT
exists, and if not attempts to create it with a printf
statement. You can see what this statement does by running it in a terminal:
$ printf "#%c/bin/bash nfor i in $(awk -F: 'if(($3 >= 1000)&&($3 <65534)) print $1' /etc/passwd); do nchage -m 0 -M 60 -W 10 $i ndone n" !
#!/bin/bash
for i in $(awk -F: 'if(( >= 1000)&&( <65534)) print $1' /etc/passwd); do
chage -m 0 -M 60 -W 10 $i
done
You will notice that instances of $3
evaluate empty because (unlike $1
) they are not protected from expansion by the shell. The use of %c
to insert the !
in #!/bin/bash
suggests the original author doesn't really understand how bash's history expansion works.
IMHO it would be simpler and clearer to use a here-document:
function bacon.config.ubuntu.chage()
CHAGE_SCRIPT='/etc/cron.daily/userchage'
if [ ! -e "$CHAGE_SCRIPT" ]; then
cat << 'EOF' > "$CHAGE_SCRIPT"
#!/bin/bash
for i in $(awk -F: 'if(($3 >= 1000)&&($3 <65534)) print $1' /etc/passwd); do
chage -m 0 -M 60 -W 10 $i
done
EOF
chmod +x "$CHAGE_SCRIPT"
fi
The operation of the second function should be pretty obvious - it could be simplified by combining all the sed
commands so that the file is only written / moved once.
The first function checks whether file $CHAGE_SCRIPT
exists, and if not attempts to create it with a printf
statement. You can see what this statement does by running it in a terminal:
$ printf "#%c/bin/bash nfor i in $(awk -F: 'if(($3 >= 1000)&&($3 <65534)) print $1' /etc/passwd); do nchage -m 0 -M 60 -W 10 $i ndone n" !
#!/bin/bash
for i in $(awk -F: 'if(( >= 1000)&&( <65534)) print $1' /etc/passwd); do
chage -m 0 -M 60 -W 10 $i
done
You will notice that instances of $3
evaluate empty because (unlike $1
) they are not protected from expansion by the shell. The use of %c
to insert the !
in #!/bin/bash
suggests the original author doesn't really understand how bash's history expansion works.
IMHO it would be simpler and clearer to use a here-document:
function bacon.config.ubuntu.chage()
CHAGE_SCRIPT='/etc/cron.daily/userchage'
if [ ! -e "$CHAGE_SCRIPT" ]; then
cat << 'EOF' > "$CHAGE_SCRIPT"
#!/bin/bash
for i in $(awk -F: 'if(($3 >= 1000)&&($3 <65534)) print $1' /etc/passwd); do
chage -m 0 -M 60 -W 10 $i
done
EOF
chmod +x "$CHAGE_SCRIPT"
fi
The operation of the second function should be pretty obvious - it could be simplified by combining all the sed
commands so that the file is only written / moved once.
answered 11 hours ago
steeldriversteeldriver
71.3k11115187
71.3k11115187
If the $3 evaluates empty, is there a reason to include it? If I wanted something to complete the same task, without useless portions included how much would I need to change it?
– Brendan77222
10 hours ago
1
@Brendan77222 I'm assuming the empty evaluation of$3
was unintentional - since it would result in a syntax error from awk
– steeldriver
9 hours ago
would leaving it in or taking it out be something I need to be concerned with? Should I want it to function as intended at least.
– Brendan77222
6 hours ago
add a comment |
If the $3 evaluates empty, is there a reason to include it? If I wanted something to complete the same task, without useless portions included how much would I need to change it?
– Brendan77222
10 hours ago
1
@Brendan77222 I'm assuming the empty evaluation of$3
was unintentional - since it would result in a syntax error from awk
– steeldriver
9 hours ago
would leaving it in or taking it out be something I need to be concerned with? Should I want it to function as intended at least.
– Brendan77222
6 hours ago
If the $3 evaluates empty, is there a reason to include it? If I wanted something to complete the same task, without useless portions included how much would I need to change it?
– Brendan77222
10 hours ago
If the $3 evaluates empty, is there a reason to include it? If I wanted something to complete the same task, without useless portions included how much would I need to change it?
– Brendan77222
10 hours ago
1
1
@Brendan77222 I'm assuming the empty evaluation of
$3
was unintentional - since it would result in a syntax error from awk– steeldriver
9 hours ago
@Brendan77222 I'm assuming the empty evaluation of
$3
was unintentional - since it would result in a syntax error from awk– steeldriver
9 hours ago
would leaving it in or taking it out be something I need to be concerned with? Should I want it to function as intended at least.
– Brendan77222
6 hours ago
would leaving it in or taking it out be something I need to be concerned with? Should I want it to function as intended at least.
– Brendan77222
6 hours ago
add a comment |
The script contains two function definitions. The first function, bacon.config.ubuntu.chage
, creates a script at /etc/cron.daily/userchage
(comments added by me):
#!/bin/bash
# loop through users with uid >= 1000 and uid < 65534 theoretically, but $3 isn't escaped -> doesn't work
for i in $(awk -F: 'if(( >= 1000)&&( <65534)) print $1' /etc/passwd);do
# set password to expire after 60 days, warning after 50 days
chage -m 0 -M 60 -W 10 $i
done
The second function installs logrotate and creates a config file for it.
New contributor
Awesome those comments help a lot. is there a reason for inserting a script at /etc/chron.daily/userchage rather than just executing the for loop you put here? I am unfamiliar with userchage file's function
– Brendan77222
10 hours ago
1
Yes, any scripts in /etc/cron.daily/ will be executed once per day.
– FliegendeWurst
10 hours ago
Awesome, thank you for the confirmation on what I suspected. Awesome help.
– Brendan77222
10 hours ago
add a comment |
The script contains two function definitions. The first function, bacon.config.ubuntu.chage
, creates a script at /etc/cron.daily/userchage
(comments added by me):
#!/bin/bash
# loop through users with uid >= 1000 and uid < 65534 theoretically, but $3 isn't escaped -> doesn't work
for i in $(awk -F: 'if(( >= 1000)&&( <65534)) print $1' /etc/passwd);do
# set password to expire after 60 days, warning after 50 days
chage -m 0 -M 60 -W 10 $i
done
The second function installs logrotate and creates a config file for it.
New contributor
Awesome those comments help a lot. is there a reason for inserting a script at /etc/chron.daily/userchage rather than just executing the for loop you put here? I am unfamiliar with userchage file's function
– Brendan77222
10 hours ago
1
Yes, any scripts in /etc/cron.daily/ will be executed once per day.
– FliegendeWurst
10 hours ago
Awesome, thank you for the confirmation on what I suspected. Awesome help.
– Brendan77222
10 hours ago
add a comment |
The script contains two function definitions. The first function, bacon.config.ubuntu.chage
, creates a script at /etc/cron.daily/userchage
(comments added by me):
#!/bin/bash
# loop through users with uid >= 1000 and uid < 65534 theoretically, but $3 isn't escaped -> doesn't work
for i in $(awk -F: 'if(( >= 1000)&&( <65534)) print $1' /etc/passwd);do
# set password to expire after 60 days, warning after 50 days
chage -m 0 -M 60 -W 10 $i
done
The second function installs logrotate and creates a config file for it.
New contributor
The script contains two function definitions. The first function, bacon.config.ubuntu.chage
, creates a script at /etc/cron.daily/userchage
(comments added by me):
#!/bin/bash
# loop through users with uid >= 1000 and uid < 65534 theoretically, but $3 isn't escaped -> doesn't work
for i in $(awk -F: 'if(( >= 1000)&&( <65534)) print $1' /etc/passwd);do
# set password to expire after 60 days, warning after 50 days
chage -m 0 -M 60 -W 10 $i
done
The second function installs logrotate and creates a config file for it.
New contributor
edited 10 hours ago
New contributor
answered 11 hours ago
FliegendeWurstFliegendeWurst
11310
11310
New contributor
New contributor
Awesome those comments help a lot. is there a reason for inserting a script at /etc/chron.daily/userchage rather than just executing the for loop you put here? I am unfamiliar with userchage file's function
– Brendan77222
10 hours ago
1
Yes, any scripts in /etc/cron.daily/ will be executed once per day.
– FliegendeWurst
10 hours ago
Awesome, thank you for the confirmation on what I suspected. Awesome help.
– Brendan77222
10 hours ago
add a comment |
Awesome those comments help a lot. is there a reason for inserting a script at /etc/chron.daily/userchage rather than just executing the for loop you put here? I am unfamiliar with userchage file's function
– Brendan77222
10 hours ago
1
Yes, any scripts in /etc/cron.daily/ will be executed once per day.
– FliegendeWurst
10 hours ago
Awesome, thank you for the confirmation on what I suspected. Awesome help.
– Brendan77222
10 hours ago
Awesome those comments help a lot. is there a reason for inserting a script at /etc/chron.daily/userchage rather than just executing the for loop you put here? I am unfamiliar with userchage file's function
– Brendan77222
10 hours ago
Awesome those comments help a lot. is there a reason for inserting a script at /etc/chron.daily/userchage rather than just executing the for loop you put here? I am unfamiliar with userchage file's function
– Brendan77222
10 hours ago
1
1
Yes, any scripts in /etc/cron.daily/ will be executed once per day.
– FliegendeWurst
10 hours ago
Yes, any scripts in /etc/cron.daily/ will be executed once per day.
– FliegendeWurst
10 hours ago
Awesome, thank you for the confirmation on what I suspected. Awesome help.
– Brendan77222
10 hours ago
Awesome, thank you for the confirmation on what I suspected. Awesome help.
– Brendan77222
10 hours ago
add a comment |
The chage
program changes the password expiry for all users. That is, it only lets them keep their current password for at most 60 days. It is run daily. The minimum duration of 0
is questionable as of https://security.stackexchange.com/questions/78758/what-is-the-purpose-of-the-password-minimum-age-setting. Maybe ask on https://security.stackexchange.com if this is really recommended.
Why logrotate
should improve security is a bit above me.
1
Oh, we definitely want a minimum password age of 24 hours. I assume that is the -m flag? I can read the man page as well, just was confused on why it used a check for a script. But I now feel from your comment it does that to ensure this is checked daily rather than a one time thing.
– Brendan77222
10 hours ago
1
Exactly. And-m
seems correct. If you can read the man pages, you can seeman cron
for thecron.daily
folder.
– serv-inc
7 hours ago
add a comment |
The chage
program changes the password expiry for all users. That is, it only lets them keep their current password for at most 60 days. It is run daily. The minimum duration of 0
is questionable as of https://security.stackexchange.com/questions/78758/what-is-the-purpose-of-the-password-minimum-age-setting. Maybe ask on https://security.stackexchange.com if this is really recommended.
Why logrotate
should improve security is a bit above me.
1
Oh, we definitely want a minimum password age of 24 hours. I assume that is the -m flag? I can read the man page as well, just was confused on why it used a check for a script. But I now feel from your comment it does that to ensure this is checked daily rather than a one time thing.
– Brendan77222
10 hours ago
1
Exactly. And-m
seems correct. If you can read the man pages, you can seeman cron
for thecron.daily
folder.
– serv-inc
7 hours ago
add a comment |
The chage
program changes the password expiry for all users. That is, it only lets them keep their current password for at most 60 days. It is run daily. The minimum duration of 0
is questionable as of https://security.stackexchange.com/questions/78758/what-is-the-purpose-of-the-password-minimum-age-setting. Maybe ask on https://security.stackexchange.com if this is really recommended.
Why logrotate
should improve security is a bit above me.
The chage
program changes the password expiry for all users. That is, it only lets them keep their current password for at most 60 days. It is run daily. The minimum duration of 0
is questionable as of https://security.stackexchange.com/questions/78758/what-is-the-purpose-of-the-password-minimum-age-setting. Maybe ask on https://security.stackexchange.com if this is really recommended.
Why logrotate
should improve security is a bit above me.
answered 10 hours ago
serv-incserv-inc
1,7211521
1,7211521
1
Oh, we definitely want a minimum password age of 24 hours. I assume that is the -m flag? I can read the man page as well, just was confused on why it used a check for a script. But I now feel from your comment it does that to ensure this is checked daily rather than a one time thing.
– Brendan77222
10 hours ago
1
Exactly. And-m
seems correct. If you can read the man pages, you can seeman cron
for thecron.daily
folder.
– serv-inc
7 hours ago
add a comment |
1
Oh, we definitely want a minimum password age of 24 hours. I assume that is the -m flag? I can read the man page as well, just was confused on why it used a check for a script. But I now feel from your comment it does that to ensure this is checked daily rather than a one time thing.
– Brendan77222
10 hours ago
1
Exactly. And-m
seems correct. If you can read the man pages, you can seeman cron
for thecron.daily
folder.
– serv-inc
7 hours ago
1
1
Oh, we definitely want a minimum password age of 24 hours. I assume that is the -m flag? I can read the man page as well, just was confused on why it used a check for a script. But I now feel from your comment it does that to ensure this is checked daily rather than a one time thing.
– Brendan77222
10 hours ago
Oh, we definitely want a minimum password age of 24 hours. I assume that is the -m flag? I can read the man page as well, just was confused on why it used a check for a script. But I now feel from your comment it does that to ensure this is checked daily rather than a one time thing.
– Brendan77222
10 hours ago
1
1
Exactly. And
-m
seems correct. If you can read the man pages, you can see man cron
for the cron.daily
folder.– serv-inc
7 hours ago
Exactly. And
-m
seems correct. If you can read the man pages, you can see man cron
for the cron.daily
folder.– serv-inc
7 hours ago
add a comment |
Brendan77222 is a new contributor. Be nice, and check out our Code of Conduct.
Brendan77222 is a new contributor. Be nice, and check out our Code of Conduct.
Brendan77222 is a new contributor. Be nice, and check out our Code of Conduct.
Brendan77222 is a new contributor. Be nice, and check out our Code of Conduct.
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2
I would ask the person who gave me the code what it does.
– WinEunuuchs2Unix
11 hours ago
1
@WinEunuuchs2Unix Normally I would as well, but they are away from the office for a while due to personal circumstances. Trust me, I know how much easier that would be. :)
– Brendan77222
11 hours ago
2
Well done on not running a script as root when you don't know what it does.
– Wildcard
3 hours ago