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Counter-example to “Every RV has a CDF.”


Form of $sigma(X_n)$ and $sigma(X_n)$-measurabilityIs a predictable process adapted?Convergence in probability to a non-measurable limitUnderstanding this Dynkin system $pi-lambda$ proof that a CDF completely determines a distribution?Measurability of randomly chosen coordinateHelp validating counter-example (basic probability - generated $sigma$-algebra)Making sense of measure-theoretic definition of random variableWhy is the canonical product $sigma$-algebra the right $sigma$-algebra on the product space?IID discrete but not a.s. equalHitting time in general not measurable













2












$begingroup$


I’ve seen the statement that all RVs have CDFs and vice versa in many textbooks.
The way they show is by simply constructing $F_X(x) = P(X in (infty, x))$.



But that assumes $forall xinmathbb R: (infty, x) in mathcal F$, which isn’t necessarily true for all $sigma$-algebras on $mathbb R$. Thus, haven’t we found a counter-example?



To be explicit, the definition of RVs I’m using is: measurable functions from the sample space of a probability space $(Omega, mathcal F, P)$ to any measurable space $(A, mathcal A)$.










share|cite|improve this question











$endgroup$












  • $begingroup$
    There are many similarly-titled questions, but imo this is not a duplicate. I’m asking about a specific counter-example. I could try to edit the title to make it sound more distinct if needed.
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:01






  • 1




    $begingroup$
    The term 'random variable' has a fixed universally accepted meaning and what you are trying to do is to change its meaning.
    $endgroup$
    – Kavi Rama Murthy
    Mar 13 at 8:06










  • $begingroup$
    @KaviRamaMurthy I think you’re definitely right in that we’re working with different definitions of RVs. I edited the question to state mine. Could you state yours? I know you mentioned it’s a universally accepted meaning, but somehow I seem to have missed it in the references I consulted.
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:10
















2












$begingroup$


I’ve seen the statement that all RVs have CDFs and vice versa in many textbooks.
The way they show is by simply constructing $F_X(x) = P(X in (infty, x))$.



But that assumes $forall xinmathbb R: (infty, x) in mathcal F$, which isn’t necessarily true for all $sigma$-algebras on $mathbb R$. Thus, haven’t we found a counter-example?



To be explicit, the definition of RVs I’m using is: measurable functions from the sample space of a probability space $(Omega, mathcal F, P)$ to any measurable space $(A, mathcal A)$.










share|cite|improve this question











$endgroup$












  • $begingroup$
    There are many similarly-titled questions, but imo this is not a duplicate. I’m asking about a specific counter-example. I could try to edit the title to make it sound more distinct if needed.
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:01






  • 1




    $begingroup$
    The term 'random variable' has a fixed universally accepted meaning and what you are trying to do is to change its meaning.
    $endgroup$
    – Kavi Rama Murthy
    Mar 13 at 8:06










  • $begingroup$
    @KaviRamaMurthy I think you’re definitely right in that we’re working with different definitions of RVs. I edited the question to state mine. Could you state yours? I know you mentioned it’s a universally accepted meaning, but somehow I seem to have missed it in the references I consulted.
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:10














2












2








2





$begingroup$


I’ve seen the statement that all RVs have CDFs and vice versa in many textbooks.
The way they show is by simply constructing $F_X(x) = P(X in (infty, x))$.



But that assumes $forall xinmathbb R: (infty, x) in mathcal F$, which isn’t necessarily true for all $sigma$-algebras on $mathbb R$. Thus, haven’t we found a counter-example?



To be explicit, the definition of RVs I’m using is: measurable functions from the sample space of a probability space $(Omega, mathcal F, P)$ to any measurable space $(A, mathcal A)$.










share|cite|improve this question











$endgroup$




I’ve seen the statement that all RVs have CDFs and vice versa in many textbooks.
The way they show is by simply constructing $F_X(x) = P(X in (infty, x))$.



But that assumes $forall xinmathbb R: (infty, x) in mathcal F$, which isn’t necessarily true for all $sigma$-algebras on $mathbb R$. Thus, haven’t we found a counter-example?



To be explicit, the definition of RVs I’m using is: measurable functions from the sample space of a probability space $(Omega, mathcal F, P)$ to any measurable space $(A, mathcal A)$.







probability-theory






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Mar 13 at 8:17







Yatharth Agarwal

















asked Mar 13 at 8:00









Yatharth AgarwalYatharth Agarwal

542418




542418












  • $begingroup$
    There are many similarly-titled questions, but imo this is not a duplicate. I’m asking about a specific counter-example. I could try to edit the title to make it sound more distinct if needed.
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:01






  • 1




    $begingroup$
    The term 'random variable' has a fixed universally accepted meaning and what you are trying to do is to change its meaning.
    $endgroup$
    – Kavi Rama Murthy
    Mar 13 at 8:06










  • $begingroup$
    @KaviRamaMurthy I think you’re definitely right in that we’re working with different definitions of RVs. I edited the question to state mine. Could you state yours? I know you mentioned it’s a universally accepted meaning, but somehow I seem to have missed it in the references I consulted.
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:10


















  • $begingroup$
    There are many similarly-titled questions, but imo this is not a duplicate. I’m asking about a specific counter-example. I could try to edit the title to make it sound more distinct if needed.
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:01






  • 1




    $begingroup$
    The term 'random variable' has a fixed universally accepted meaning and what you are trying to do is to change its meaning.
    $endgroup$
    – Kavi Rama Murthy
    Mar 13 at 8:06










  • $begingroup$
    @KaviRamaMurthy I think you’re definitely right in that we’re working with different definitions of RVs. I edited the question to state mine. Could you state yours? I know you mentioned it’s a universally accepted meaning, but somehow I seem to have missed it in the references I consulted.
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:10
















$begingroup$
There are many similarly-titled questions, but imo this is not a duplicate. I’m asking about a specific counter-example. I could try to edit the title to make it sound more distinct if needed.
$endgroup$
– Yatharth Agarwal
Mar 13 at 8:01




$begingroup$
There are many similarly-titled questions, but imo this is not a duplicate. I’m asking about a specific counter-example. I could try to edit the title to make it sound more distinct if needed.
$endgroup$
– Yatharth Agarwal
Mar 13 at 8:01




1




1




$begingroup$
The term 'random variable' has a fixed universally accepted meaning and what you are trying to do is to change its meaning.
$endgroup$
– Kavi Rama Murthy
Mar 13 at 8:06




$begingroup$
The term 'random variable' has a fixed universally accepted meaning and what you are trying to do is to change its meaning.
$endgroup$
– Kavi Rama Murthy
Mar 13 at 8:06












$begingroup$
@KaviRamaMurthy I think you’re definitely right in that we’re working with different definitions of RVs. I edited the question to state mine. Could you state yours? I know you mentioned it’s a universally accepted meaning, but somehow I seem to have missed it in the references I consulted.
$endgroup$
– Yatharth Agarwal
Mar 13 at 8:10




$begingroup$
@KaviRamaMurthy I think you’re definitely right in that we’re working with different definitions of RVs. I edited the question to state mine. Could you state yours? I know you mentioned it’s a universally accepted meaning, but somehow I seem to have missed it in the references I consulted.
$endgroup$
– Yatharth Agarwal
Mar 13 at 8:10










1 Answer
1






active

oldest

votes


















1












$begingroup$

What you have defined is often called a random element of $A$. In contrast, random variables are usually defined as measurable functions from a probability space to $(mathbb R, mathcal B(mathbb R))$. With this restriction, the definition $F_X(x)=P(Xleq x)$ is always valid.



If a random variable is defined as measurable map from a measure space into a measurable space the we can associate with it what is called the induced measure: $nu (A)=P(X^{-1}(A))$ for $A in mathcal A$. Sometimes this is also called the distribution of $X$. It so happens that in the case $A=mathbb R$ with Borel sigma algebra there is a one-to-one correspondence between induced measures and the functions $F_X$.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Hmm… the definitions I’ve seen only required $X$ map to a measurable space $(A, mathcal A)$, not necessarily $A = mathbb R$ and not necessarily $mathcal A = mathcal B (mathbb R)$.
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:07












  • $begingroup$
    Could you provide a reference? I’d love to dig deeper.
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:11










  • $begingroup$
    In that case you are asking about existence of what? Can you give a precise definition of the term 'random variable' and the term 'distribution function'?
    $endgroup$
    – Kavi Rama Murthy
    Mar 13 at 8:12






  • 1




    $begingroup$
    @YatharthAgarwal What you have defined is often called a random element of $A$. In any case please see if my revised answer is clear.
    $endgroup$
    – Kavi Rama Murthy
    Mar 13 at 8:18










  • $begingroup$
    Ahhh random elements vs random variables. The text I was using didn’t distinguish. This makes sense—thank you!
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:19











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1 Answer
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1 Answer
1






active

oldest

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active

oldest

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active

oldest

votes









1












$begingroup$

What you have defined is often called a random element of $A$. In contrast, random variables are usually defined as measurable functions from a probability space to $(mathbb R, mathcal B(mathbb R))$. With this restriction, the definition $F_X(x)=P(Xleq x)$ is always valid.



If a random variable is defined as measurable map from a measure space into a measurable space the we can associate with it what is called the induced measure: $nu (A)=P(X^{-1}(A))$ for $A in mathcal A$. Sometimes this is also called the distribution of $X$. It so happens that in the case $A=mathbb R$ with Borel sigma algebra there is a one-to-one correspondence between induced measures and the functions $F_X$.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Hmm… the definitions I’ve seen only required $X$ map to a measurable space $(A, mathcal A)$, not necessarily $A = mathbb R$ and not necessarily $mathcal A = mathcal B (mathbb R)$.
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:07












  • $begingroup$
    Could you provide a reference? I’d love to dig deeper.
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:11










  • $begingroup$
    In that case you are asking about existence of what? Can you give a precise definition of the term 'random variable' and the term 'distribution function'?
    $endgroup$
    – Kavi Rama Murthy
    Mar 13 at 8:12






  • 1




    $begingroup$
    @YatharthAgarwal What you have defined is often called a random element of $A$. In any case please see if my revised answer is clear.
    $endgroup$
    – Kavi Rama Murthy
    Mar 13 at 8:18










  • $begingroup$
    Ahhh random elements vs random variables. The text I was using didn’t distinguish. This makes sense—thank you!
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:19
















1












$begingroup$

What you have defined is often called a random element of $A$. In contrast, random variables are usually defined as measurable functions from a probability space to $(mathbb R, mathcal B(mathbb R))$. With this restriction, the definition $F_X(x)=P(Xleq x)$ is always valid.



If a random variable is defined as measurable map from a measure space into a measurable space the we can associate with it what is called the induced measure: $nu (A)=P(X^{-1}(A))$ for $A in mathcal A$. Sometimes this is also called the distribution of $X$. It so happens that in the case $A=mathbb R$ with Borel sigma algebra there is a one-to-one correspondence between induced measures and the functions $F_X$.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Hmm… the definitions I’ve seen only required $X$ map to a measurable space $(A, mathcal A)$, not necessarily $A = mathbb R$ and not necessarily $mathcal A = mathcal B (mathbb R)$.
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:07












  • $begingroup$
    Could you provide a reference? I’d love to dig deeper.
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:11










  • $begingroup$
    In that case you are asking about existence of what? Can you give a precise definition of the term 'random variable' and the term 'distribution function'?
    $endgroup$
    – Kavi Rama Murthy
    Mar 13 at 8:12






  • 1




    $begingroup$
    @YatharthAgarwal What you have defined is often called a random element of $A$. In any case please see if my revised answer is clear.
    $endgroup$
    – Kavi Rama Murthy
    Mar 13 at 8:18










  • $begingroup$
    Ahhh random elements vs random variables. The text I was using didn’t distinguish. This makes sense—thank you!
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:19














1












1








1





$begingroup$

What you have defined is often called a random element of $A$. In contrast, random variables are usually defined as measurable functions from a probability space to $(mathbb R, mathcal B(mathbb R))$. With this restriction, the definition $F_X(x)=P(Xleq x)$ is always valid.



If a random variable is defined as measurable map from a measure space into a measurable space the we can associate with it what is called the induced measure: $nu (A)=P(X^{-1}(A))$ for $A in mathcal A$. Sometimes this is also called the distribution of $X$. It so happens that in the case $A=mathbb R$ with Borel sigma algebra there is a one-to-one correspondence between induced measures and the functions $F_X$.






share|cite|improve this answer











$endgroup$



What you have defined is often called a random element of $A$. In contrast, random variables are usually defined as measurable functions from a probability space to $(mathbb R, mathcal B(mathbb R))$. With this restriction, the definition $F_X(x)=P(Xleq x)$ is always valid.



If a random variable is defined as measurable map from a measure space into a measurable space the we can associate with it what is called the induced measure: $nu (A)=P(X^{-1}(A))$ for $A in mathcal A$. Sometimes this is also called the distribution of $X$. It so happens that in the case $A=mathbb R$ with Borel sigma algebra there is a one-to-one correspondence between induced measures and the functions $F_X$.







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Mar 13 at 8:22









Yatharth Agarwal

542418




542418










answered Mar 13 at 8:04









Kavi Rama MurthyKavi Rama Murthy

68.9k53169




68.9k53169












  • $begingroup$
    Hmm… the definitions I’ve seen only required $X$ map to a measurable space $(A, mathcal A)$, not necessarily $A = mathbb R$ and not necessarily $mathcal A = mathcal B (mathbb R)$.
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:07












  • $begingroup$
    Could you provide a reference? I’d love to dig deeper.
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:11










  • $begingroup$
    In that case you are asking about existence of what? Can you give a precise definition of the term 'random variable' and the term 'distribution function'?
    $endgroup$
    – Kavi Rama Murthy
    Mar 13 at 8:12






  • 1




    $begingroup$
    @YatharthAgarwal What you have defined is often called a random element of $A$. In any case please see if my revised answer is clear.
    $endgroup$
    – Kavi Rama Murthy
    Mar 13 at 8:18










  • $begingroup$
    Ahhh random elements vs random variables. The text I was using didn’t distinguish. This makes sense—thank you!
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:19


















  • $begingroup$
    Hmm… the definitions I’ve seen only required $X$ map to a measurable space $(A, mathcal A)$, not necessarily $A = mathbb R$ and not necessarily $mathcal A = mathcal B (mathbb R)$.
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:07












  • $begingroup$
    Could you provide a reference? I’d love to dig deeper.
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:11










  • $begingroup$
    In that case you are asking about existence of what? Can you give a precise definition of the term 'random variable' and the term 'distribution function'?
    $endgroup$
    – Kavi Rama Murthy
    Mar 13 at 8:12






  • 1




    $begingroup$
    @YatharthAgarwal What you have defined is often called a random element of $A$. In any case please see if my revised answer is clear.
    $endgroup$
    – Kavi Rama Murthy
    Mar 13 at 8:18










  • $begingroup$
    Ahhh random elements vs random variables. The text I was using didn’t distinguish. This makes sense—thank you!
    $endgroup$
    – Yatharth Agarwal
    Mar 13 at 8:19
















$begingroup$
Hmm… the definitions I’ve seen only required $X$ map to a measurable space $(A, mathcal A)$, not necessarily $A = mathbb R$ and not necessarily $mathcal A = mathcal B (mathbb R)$.
$endgroup$
– Yatharth Agarwal
Mar 13 at 8:07






$begingroup$
Hmm… the definitions I’ve seen only required $X$ map to a measurable space $(A, mathcal A)$, not necessarily $A = mathbb R$ and not necessarily $mathcal A = mathcal B (mathbb R)$.
$endgroup$
– Yatharth Agarwal
Mar 13 at 8:07














$begingroup$
Could you provide a reference? I’d love to dig deeper.
$endgroup$
– Yatharth Agarwal
Mar 13 at 8:11




$begingroup$
Could you provide a reference? I’d love to dig deeper.
$endgroup$
– Yatharth Agarwal
Mar 13 at 8:11












$begingroup$
In that case you are asking about existence of what? Can you give a precise definition of the term 'random variable' and the term 'distribution function'?
$endgroup$
– Kavi Rama Murthy
Mar 13 at 8:12




$begingroup$
In that case you are asking about existence of what? Can you give a precise definition of the term 'random variable' and the term 'distribution function'?
$endgroup$
– Kavi Rama Murthy
Mar 13 at 8:12




1




1




$begingroup$
@YatharthAgarwal What you have defined is often called a random element of $A$. In any case please see if my revised answer is clear.
$endgroup$
– Kavi Rama Murthy
Mar 13 at 8:18




$begingroup$
@YatharthAgarwal What you have defined is often called a random element of $A$. In any case please see if my revised answer is clear.
$endgroup$
– Kavi Rama Murthy
Mar 13 at 8:18












$begingroup$
Ahhh random elements vs random variables. The text I was using didn’t distinguish. This makes sense—thank you!
$endgroup$
– Yatharth Agarwal
Mar 13 at 8:19




$begingroup$
Ahhh random elements vs random variables. The text I was using didn’t distinguish. This makes sense—thank you!
$endgroup$
– Yatharth Agarwal
Mar 13 at 8:19


















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