Simplification in Algebric EquationLegal simplification of tangent equation?Integration by...
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Simplification in Algebric Equation
Legal simplification of tangent equation?Integration by simplificationContinuity and simplification of a functionCan you prove the simplification of this sum?Following a simplification of expressionDouble binomial series simplificationSimplification of limits doubt.A confusion in Bernoulli equation solutionLimits and algebraic simplificationSimplification of equation gives different domain and range
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I am confused with simplification in algebraic equation, which formula is used to simplify this equation. Please see last highlighted line.
[View Screenshot1
calculus
asked 2 days ago
BeginnerBeginner
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Beginner is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
$begingroup$
I am confused with simplification in algebraic equation, which formula is used to simplify this equation. Please see last highlighted line.
[View Screenshot1
calculus
asked 2 days ago
BeginnerBeginner
11
New contributor
Beginner is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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1
$begingroup$
$(a+b)+(c-a)=a-a+b+c=b+c$
$endgroup$
– Andrei
2 days ago
$begingroup$
What video course is this screenshot from?
$endgroup$
– Michael Rybkin
2 days ago
$begingroup$
Its Calculus Course by Virtual University you can find it on youtube but its in urdu language.
$endgroup$
– Beginner
2 days ago
add a comment |
$begingroup$
I am confused with simplification in algebraic equation, which formula is used to simplify this equation. Please see last highlighted line.
[View Screenshot1
calculus
asked 2 days ago
BeginnerBeginner
11
New contributor
Beginner is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I am confused with simplification in algebraic equation, which formula is used to simplify this equation. Please see last highlighted line.
[View Screenshot1
calculus
calculus
asked 2 days ago
BeginnerBeginner
11
New contributor
Beginner is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 days ago
BeginnerBeginner
11
New contributor
Beginner is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 days ago
BeginnerBeginner
11
New contributor
Beginner is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 days ago
BeginnerBeginner
11
asked 2 days ago
BeginnerBeginner
11
11
New contributor
Beginner is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Beginner is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Beginner is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
$begingroup$
$(a+b)+(c-a)=a-a+b+c=b+c$
$endgroup$
– Andrei
2 days ago
$begingroup$
What video course is this screenshot from?
$endgroup$
– Michael Rybkin
2 days ago
$begingroup$
Its Calculus Course by Virtual University you can find it on youtube but its in urdu language.
$endgroup$
– Beginner
2 days ago
add a comment |
1
$begingroup$
$(a+b)+(c-a)=a-a+b+c=b+c$
$endgroup$
– Andrei
2 days ago
$begingroup$
What video course is this screenshot from?
$endgroup$
– Michael Rybkin
2 days ago
$begingroup$
Its Calculus Course by Virtual University you can find it on youtube but its in urdu language.
$endgroup$
– Beginner
2 days ago
1
1
$begingroup$
$(a+b)+(c-a)=a-a+b+c=b+c$
$endgroup$
– Andrei
2 days ago
$begingroup$
$(a+b)+(c-a)=a-a+b+c=b+c$
$endgroup$
– Andrei
2 days ago
$begingroup$
What video course is this screenshot from?
$endgroup$
– Michael Rybkin
2 days ago
$begingroup$
What video course is this screenshot from?
$endgroup$
– Michael Rybkin
2 days ago
$begingroup$
Its Calculus Course by Virtual University you can find it on youtube but its in urdu language.
$endgroup$
– Beginner
2 days ago
$begingroup$
Its Calculus Course by Virtual University you can find it on youtube but its in urdu language.
$endgroup$
– Beginner
2 days ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Just open the brackets to add all the terms. The ones will cancel each other out:
$$require{cancel}
(1+sqrt{x-2})+(x-1)=cancel{1}+sqrt{x-2}+x-cancel{1}=sqrt{x-2}+x.
$$
Also, don't forget that you can move things around because addition is commutative:
$$
sqrt{x-2}+x=x+sqrt{x-2}.
$$
answered 2 days ago
Michael RybkinMichael Rybkin
3,744420
$endgroup$
$begingroup$
Thank you, well explained.
$endgroup$
– Beginner
2 days ago
add a comment |
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1 Answer
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1 Answer
1
active
oldest
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votes
$begingroup$
Just open the brackets to add all the terms. The ones will cancel each other out:
$$require{cancel}
(1+sqrt{x-2})+(x-1)=cancel{1}+sqrt{x-2}+x-cancel{1}=sqrt{x-2}+x.
$$
Also, don't forget that you can move things around because addition is commutative:
$$
sqrt{x-2}+x=x+sqrt{x-2}.
$$
answered 2 days ago
Michael RybkinMichael Rybkin
3,744420
$endgroup$
$begingroup$
Thank you, well explained.
$endgroup$
– Beginner
2 days ago
add a comment |
$begingroup$
Just open the brackets to add all the terms. The ones will cancel each other out:
$$require{cancel}
(1+sqrt{x-2})+(x-1)=cancel{1}+sqrt{x-2}+x-cancel{1}=sqrt{x-2}+x.
$$
Also, don't forget that you can move things around because addition is commutative:
$$
sqrt{x-2}+x=x+sqrt{x-2}.
$$
answered 2 days ago
Michael RybkinMichael Rybkin
3,744420
$endgroup$
$begingroup$
Thank you, well explained.
$endgroup$
– Beginner
2 days ago
add a comment |
$begingroup$
Just open the brackets to add all the terms. The ones will cancel each other out:
$$require{cancel}
(1+sqrt{x-2})+(x-1)=cancel{1}+sqrt{x-2}+x-cancel{1}=sqrt{x-2}+x.
$$
Also, don't forget that you can move things around because addition is commutative:
$$
sqrt{x-2}+x=x+sqrt{x-2}.
$$
answered 2 days ago
Michael RybkinMichael Rybkin
3,744420
$endgroup$
Just open the brackets to add all the terms. The ones will cancel each other out:
$$require{cancel}
(1+sqrt{x-2})+(x-1)=cancel{1}+sqrt{x-2}+x-cancel{1}=sqrt{x-2}+x.
$$
Also, don't forget that you can move things around because addition is commutative:
$$
sqrt{x-2}+x=x+sqrt{x-2}.
$$
answered 2 days ago
Michael RybkinMichael Rybkin
3,744420
edited 2 days ago
answered 2 days ago
Michael RybkinMichael Rybkin
3,744420
answered 2 days ago
Michael RybkinMichael Rybkin
3,744420
answered 2 days ago
Michael RybkinMichael Rybkin
3,744420
3,744420
$begingroup$
Thank you, well explained.
$endgroup$
– Beginner
2 days ago
add a comment |
$begingroup$
Thank you, well explained.
$endgroup$
– Beginner
2 days ago
$begingroup$
Thank you, well explained.
$endgroup$
– Beginner
2 days ago
$begingroup$
Thank you, well explained.
$endgroup$
– Beginner
2 days ago
add a comment |
Beginner is a new contributor. Be nice, and check out our Code of Conduct.
Beginner is a new contributor. Be nice, and check out our Code of Conduct.
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1
$begingroup$
$(a+b)+(c-a)=a-a+b+c=b+c$
$endgroup$
– Andrei
2 days ago
$begingroup$
What video course is this screenshot from?
$endgroup$
– Michael Rybkin
2 days ago
$begingroup$
Its Calculus Course by Virtual University you can find it on youtube but its in urdu language.
$endgroup$
– Beginner
2 days ago