Doubt regarding Compactness argument used in Proof The 2019 Stack Overflow Developer Survey...

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Doubt regarding Compactness argument used in Proof



The 2019 Stack Overflow Developer Survey Results Are In
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Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)How to prove facts regarding sentential logicTheorem 2.5.1 from Herstein's bookQuestion about an argument in Lang's Calculus of VarationsClosed subsets of a compact topological space are compact proof clarification 3Understanding Proof of Sylow theorem from Herstein$S={e^{inx}mid nin mathbb Z}$ where $xnotin pimathbb Q$ is dense in $S^1$Doubts Regarding Evaluation of IntegralHow to show sequnce of function converges uniformly on any set on which function is bounded?Counterexample for Bounded convergence theroem if we relax finite measure conditionDoubt in understading Proof of Matrix lie group and Lie algebra locally homemorphic












2












$begingroup$


In that Book I come across following theorem.enter image description here



Notation enter image description here



Author mentioned that by standard argument of compact we can extract sequnce such that $A_{t_{k-1}^{-1}A_{t_k}}in V$.



I do not understand this standard argument .



I would be really thankful If someone help me out



Any Help will be appreciated










share|cite|improve this question











$endgroup$

















    2












    $begingroup$


    In that Book I come across following theorem.enter image description here



    Notation enter image description here



    Author mentioned that by standard argument of compact we can extract sequnce such that $A_{t_{k-1}^{-1}A_{t_k}}in V$.



    I do not understand this standard argument .



    I would be really thankful If someone help me out



    Any Help will be appreciated










    share|cite|improve this question











    $endgroup$















      2












      2








      2


      2



      $begingroup$


      In that Book I come across following theorem.enter image description here



      Notation enter image description here



      Author mentioned that by standard argument of compact we can extract sequnce such that $A_{t_{k-1}^{-1}A_{t_k}}in V$.



      I do not understand this standard argument .



      I would be really thankful If someone help me out



      Any Help will be appreciated










      share|cite|improve this question











      $endgroup$




      In that Book I come across following theorem.enter image description here



      Notation enter image description here



      Author mentioned that by standard argument of compact we can extract sequnce such that $A_{t_{k-1}^{-1}A_{t_k}}in V$.



      I do not understand this standard argument .



      I would be really thankful If someone help me out



      Any Help will be appreciated







      real-analysis proof-explanation






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Mar 25 at 8:43







      SRJ

















      asked Mar 22 at 13:16









      SRJSRJ

      1,8981620




      1,8981620






















          1 Answer
          1






          active

          oldest

          votes


















          2












          $begingroup$

          Hint: The operation $varphi:Gtimes Gto G, (A,B)mapsto A^{-1}B$ is continuous, hence so is $[0,1]times[0,1]to G, (t, s) mapsto A(t)^{-1}A(s)$.

          Then the preimage of $V$ is open.

          (You can also rely on a metric, if you wish, given by matrix norm.)






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Sir V is already given to be an open neighbourhood of I in G. I still do not understand. Can you please elaborate? Thanks a lot
            $endgroup$
            – SRJ
            Mar 23 at 10:40










          • $begingroup$
            As an open set, $varphi^{-1}(V)$ is a union of open balls, hence the diagonal ${(t,t):tin[0,1]}$ can be covered by finitely many of them. Let $varepsilon$ be the radius of the smallest ball among these, then $A(t)^{-1}A(s)in V$ whenever $|s-t|<varepsilon$.
            $endgroup$
            – Berci
            Mar 23 at 13:47












          • $begingroup$
            Thanks a lot... I required some time to digest argument. But Once I understand ... I became too happy AS it uses very basic idea and bypasses very High End tools....Once again thanks....
            $endgroup$
            – SRJ
            Mar 24 at 5:30












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          1 Answer
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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2












          $begingroup$

          Hint: The operation $varphi:Gtimes Gto G, (A,B)mapsto A^{-1}B$ is continuous, hence so is $[0,1]times[0,1]to G, (t, s) mapsto A(t)^{-1}A(s)$.

          Then the preimage of $V$ is open.

          (You can also rely on a metric, if you wish, given by matrix norm.)






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Sir V is already given to be an open neighbourhood of I in G. I still do not understand. Can you please elaborate? Thanks a lot
            $endgroup$
            – SRJ
            Mar 23 at 10:40










          • $begingroup$
            As an open set, $varphi^{-1}(V)$ is a union of open balls, hence the diagonal ${(t,t):tin[0,1]}$ can be covered by finitely many of them. Let $varepsilon$ be the radius of the smallest ball among these, then $A(t)^{-1}A(s)in V$ whenever $|s-t|<varepsilon$.
            $endgroup$
            – Berci
            Mar 23 at 13:47












          • $begingroup$
            Thanks a lot... I required some time to digest argument. But Once I understand ... I became too happy AS it uses very basic idea and bypasses very High End tools....Once again thanks....
            $endgroup$
            – SRJ
            Mar 24 at 5:30
















          2












          $begingroup$

          Hint: The operation $varphi:Gtimes Gto G, (A,B)mapsto A^{-1}B$ is continuous, hence so is $[0,1]times[0,1]to G, (t, s) mapsto A(t)^{-1}A(s)$.

          Then the preimage of $V$ is open.

          (You can also rely on a metric, if you wish, given by matrix norm.)






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Sir V is already given to be an open neighbourhood of I in G. I still do not understand. Can you please elaborate? Thanks a lot
            $endgroup$
            – SRJ
            Mar 23 at 10:40










          • $begingroup$
            As an open set, $varphi^{-1}(V)$ is a union of open balls, hence the diagonal ${(t,t):tin[0,1]}$ can be covered by finitely many of them. Let $varepsilon$ be the radius of the smallest ball among these, then $A(t)^{-1}A(s)in V$ whenever $|s-t|<varepsilon$.
            $endgroup$
            – Berci
            Mar 23 at 13:47












          • $begingroup$
            Thanks a lot... I required some time to digest argument. But Once I understand ... I became too happy AS it uses very basic idea and bypasses very High End tools....Once again thanks....
            $endgroup$
            – SRJ
            Mar 24 at 5:30














          2












          2








          2





          $begingroup$

          Hint: The operation $varphi:Gtimes Gto G, (A,B)mapsto A^{-1}B$ is continuous, hence so is $[0,1]times[0,1]to G, (t, s) mapsto A(t)^{-1}A(s)$.

          Then the preimage of $V$ is open.

          (You can also rely on a metric, if you wish, given by matrix norm.)






          share|cite|improve this answer









          $endgroup$



          Hint: The operation $varphi:Gtimes Gto G, (A,B)mapsto A^{-1}B$ is continuous, hence so is $[0,1]times[0,1]to G, (t, s) mapsto A(t)^{-1}A(s)$.

          Then the preimage of $V$ is open.

          (You can also rely on a metric, if you wish, given by matrix norm.)







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Mar 22 at 14:32









          BerciBerci

          62k23776




          62k23776












          • $begingroup$
            Sir V is already given to be an open neighbourhood of I in G. I still do not understand. Can you please elaborate? Thanks a lot
            $endgroup$
            – SRJ
            Mar 23 at 10:40










          • $begingroup$
            As an open set, $varphi^{-1}(V)$ is a union of open balls, hence the diagonal ${(t,t):tin[0,1]}$ can be covered by finitely many of them. Let $varepsilon$ be the radius of the smallest ball among these, then $A(t)^{-1}A(s)in V$ whenever $|s-t|<varepsilon$.
            $endgroup$
            – Berci
            Mar 23 at 13:47












          • $begingroup$
            Thanks a lot... I required some time to digest argument. But Once I understand ... I became too happy AS it uses very basic idea and bypasses very High End tools....Once again thanks....
            $endgroup$
            – SRJ
            Mar 24 at 5:30


















          • $begingroup$
            Sir V is already given to be an open neighbourhood of I in G. I still do not understand. Can you please elaborate? Thanks a lot
            $endgroup$
            – SRJ
            Mar 23 at 10:40










          • $begingroup$
            As an open set, $varphi^{-1}(V)$ is a union of open balls, hence the diagonal ${(t,t):tin[0,1]}$ can be covered by finitely many of them. Let $varepsilon$ be the radius of the smallest ball among these, then $A(t)^{-1}A(s)in V$ whenever $|s-t|<varepsilon$.
            $endgroup$
            – Berci
            Mar 23 at 13:47












          • $begingroup$
            Thanks a lot... I required some time to digest argument. But Once I understand ... I became too happy AS it uses very basic idea and bypasses very High End tools....Once again thanks....
            $endgroup$
            – SRJ
            Mar 24 at 5:30
















          $begingroup$
          Sir V is already given to be an open neighbourhood of I in G. I still do not understand. Can you please elaborate? Thanks a lot
          $endgroup$
          – SRJ
          Mar 23 at 10:40




          $begingroup$
          Sir V is already given to be an open neighbourhood of I in G. I still do not understand. Can you please elaborate? Thanks a lot
          $endgroup$
          – SRJ
          Mar 23 at 10:40












          $begingroup$
          As an open set, $varphi^{-1}(V)$ is a union of open balls, hence the diagonal ${(t,t):tin[0,1]}$ can be covered by finitely many of them. Let $varepsilon$ be the radius of the smallest ball among these, then $A(t)^{-1}A(s)in V$ whenever $|s-t|<varepsilon$.
          $endgroup$
          – Berci
          Mar 23 at 13:47






          $begingroup$
          As an open set, $varphi^{-1}(V)$ is a union of open balls, hence the diagonal ${(t,t):tin[0,1]}$ can be covered by finitely many of them. Let $varepsilon$ be the radius of the smallest ball among these, then $A(t)^{-1}A(s)in V$ whenever $|s-t|<varepsilon$.
          $endgroup$
          – Berci
          Mar 23 at 13:47














          $begingroup$
          Thanks a lot... I required some time to digest argument. But Once I understand ... I became too happy AS it uses very basic idea and bypasses very High End tools....Once again thanks....
          $endgroup$
          – SRJ
          Mar 24 at 5:30




          $begingroup$
          Thanks a lot... I required some time to digest argument. But Once I understand ... I became too happy AS it uses very basic idea and bypasses very High End tools....Once again thanks....
          $endgroup$
          – SRJ
          Mar 24 at 5:30


















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