Doubt regarding Compactness argument used in Proof The 2019 Stack Overflow Developer Survey...

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Doubt regarding Compactness argument used in Proof



The 2019 Stack Overflow Developer Survey Results Are In
Announcing the arrival of Valued Associate #679: Cesar Manara
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2












$begingroup$


In that Book I come across following theorem.enter image description here



Notation enter image description here



Author mentioned that by standard argument of compact we can extract sequnce such that $A_{t_{k-1}^{-1}A_{t_k}}in V$.



I do not understand this standard argument .



I would be really thankful If someone help me out



Any Help will be appreciated










share|cite|improve this question











$endgroup$

















    2












    $begingroup$


    In that Book I come across following theorem.enter image description here



    Notation enter image description here



    Author mentioned that by standard argument of compact we can extract sequnce such that $A_{t_{k-1}^{-1}A_{t_k}}in V$.



    I do not understand this standard argument .



    I would be really thankful If someone help me out



    Any Help will be appreciated










    share|cite|improve this question











    $endgroup$















      2












      2








      2


      2



      $begingroup$


      In that Book I come across following theorem.enter image description here



      Notation enter image description here



      Author mentioned that by standard argument of compact we can extract sequnce such that $A_{t_{k-1}^{-1}A_{t_k}}in V$.



      I do not understand this standard argument .



      I would be really thankful If someone help me out



      Any Help will be appreciated










      share|cite|improve this question











      $endgroup$




      In that Book I come across following theorem.enter image description here



      Notation enter image description here



      Author mentioned that by standard argument of compact we can extract sequnce such that $A_{t_{k-1}^{-1}A_{t_k}}in V$.



      I do not understand this standard argument .



      I would be really thankful If someone help me out



      Any Help will be appreciated







      real-analysis proof-explanation






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Mar 25 at 8:43







      SRJ

















      asked Mar 22 at 13:16









      SRJSRJ

      1,8981620




      1,8981620






















          1 Answer
          1






          active

          oldest

          votes


















          2












          $begingroup$

          Hint: The operation $varphi:Gtimes Gto G, (A,B)mapsto A^{-1}B$ is continuous, hence so is $[0,1]times[0,1]to G, (t, s) mapsto A(t)^{-1}A(s)$.

          Then the preimage of $V$ is open.

          (You can also rely on a metric, if you wish, given by matrix norm.)






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Sir V is already given to be an open neighbourhood of I in G. I still do not understand. Can you please elaborate? Thanks a lot
            $endgroup$
            – SRJ
            Mar 23 at 10:40










          • $begingroup$
            As an open set, $varphi^{-1}(V)$ is a union of open balls, hence the diagonal ${(t,t):tin[0,1]}$ can be covered by finitely many of them. Let $varepsilon$ be the radius of the smallest ball among these, then $A(t)^{-1}A(s)in V$ whenever $|s-t|<varepsilon$.
            $endgroup$
            – Berci
            Mar 23 at 13:47












          • $begingroup$
            Thanks a lot... I required some time to digest argument. But Once I understand ... I became too happy AS it uses very basic idea and bypasses very High End tools....Once again thanks....
            $endgroup$
            – SRJ
            Mar 24 at 5:30












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          1 Answer
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          1 Answer
          1






          active

          oldest

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          active

          oldest

          votes






          active

          oldest

          votes









          2












          $begingroup$

          Hint: The operation $varphi:Gtimes Gto G, (A,B)mapsto A^{-1}B$ is continuous, hence so is $[0,1]times[0,1]to G, (t, s) mapsto A(t)^{-1}A(s)$.

          Then the preimage of $V$ is open.

          (You can also rely on a metric, if you wish, given by matrix norm.)






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Sir V is already given to be an open neighbourhood of I in G. I still do not understand. Can you please elaborate? Thanks a lot
            $endgroup$
            – SRJ
            Mar 23 at 10:40










          • $begingroup$
            As an open set, $varphi^{-1}(V)$ is a union of open balls, hence the diagonal ${(t,t):tin[0,1]}$ can be covered by finitely many of them. Let $varepsilon$ be the radius of the smallest ball among these, then $A(t)^{-1}A(s)in V$ whenever $|s-t|<varepsilon$.
            $endgroup$
            – Berci
            Mar 23 at 13:47












          • $begingroup$
            Thanks a lot... I required some time to digest argument. But Once I understand ... I became too happy AS it uses very basic idea and bypasses very High End tools....Once again thanks....
            $endgroup$
            – SRJ
            Mar 24 at 5:30
















          2












          $begingroup$

          Hint: The operation $varphi:Gtimes Gto G, (A,B)mapsto A^{-1}B$ is continuous, hence so is $[0,1]times[0,1]to G, (t, s) mapsto A(t)^{-1}A(s)$.

          Then the preimage of $V$ is open.

          (You can also rely on a metric, if you wish, given by matrix norm.)






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Sir V is already given to be an open neighbourhood of I in G. I still do not understand. Can you please elaborate? Thanks a lot
            $endgroup$
            – SRJ
            Mar 23 at 10:40










          • $begingroup$
            As an open set, $varphi^{-1}(V)$ is a union of open balls, hence the diagonal ${(t,t):tin[0,1]}$ can be covered by finitely many of them. Let $varepsilon$ be the radius of the smallest ball among these, then $A(t)^{-1}A(s)in V$ whenever $|s-t|<varepsilon$.
            $endgroup$
            – Berci
            Mar 23 at 13:47












          • $begingroup$
            Thanks a lot... I required some time to digest argument. But Once I understand ... I became too happy AS it uses very basic idea and bypasses very High End tools....Once again thanks....
            $endgroup$
            – SRJ
            Mar 24 at 5:30














          2












          2








          2





          $begingroup$

          Hint: The operation $varphi:Gtimes Gto G, (A,B)mapsto A^{-1}B$ is continuous, hence so is $[0,1]times[0,1]to G, (t, s) mapsto A(t)^{-1}A(s)$.

          Then the preimage of $V$ is open.

          (You can also rely on a metric, if you wish, given by matrix norm.)






          share|cite|improve this answer









          $endgroup$



          Hint: The operation $varphi:Gtimes Gto G, (A,B)mapsto A^{-1}B$ is continuous, hence so is $[0,1]times[0,1]to G, (t, s) mapsto A(t)^{-1}A(s)$.

          Then the preimage of $V$ is open.

          (You can also rely on a metric, if you wish, given by matrix norm.)







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Mar 22 at 14:32









          BerciBerci

          62k23776




          62k23776












          • $begingroup$
            Sir V is already given to be an open neighbourhood of I in G. I still do not understand. Can you please elaborate? Thanks a lot
            $endgroup$
            – SRJ
            Mar 23 at 10:40










          • $begingroup$
            As an open set, $varphi^{-1}(V)$ is a union of open balls, hence the diagonal ${(t,t):tin[0,1]}$ can be covered by finitely many of them. Let $varepsilon$ be the radius of the smallest ball among these, then $A(t)^{-1}A(s)in V$ whenever $|s-t|<varepsilon$.
            $endgroup$
            – Berci
            Mar 23 at 13:47












          • $begingroup$
            Thanks a lot... I required some time to digest argument. But Once I understand ... I became too happy AS it uses very basic idea and bypasses very High End tools....Once again thanks....
            $endgroup$
            – SRJ
            Mar 24 at 5:30


















          • $begingroup$
            Sir V is already given to be an open neighbourhood of I in G. I still do not understand. Can you please elaborate? Thanks a lot
            $endgroup$
            – SRJ
            Mar 23 at 10:40










          • $begingroup$
            As an open set, $varphi^{-1}(V)$ is a union of open balls, hence the diagonal ${(t,t):tin[0,1]}$ can be covered by finitely many of them. Let $varepsilon$ be the radius of the smallest ball among these, then $A(t)^{-1}A(s)in V$ whenever $|s-t|<varepsilon$.
            $endgroup$
            – Berci
            Mar 23 at 13:47












          • $begingroup$
            Thanks a lot... I required some time to digest argument. But Once I understand ... I became too happy AS it uses very basic idea and bypasses very High End tools....Once again thanks....
            $endgroup$
            – SRJ
            Mar 24 at 5:30
















          $begingroup$
          Sir V is already given to be an open neighbourhood of I in G. I still do not understand. Can you please elaborate? Thanks a lot
          $endgroup$
          – SRJ
          Mar 23 at 10:40




          $begingroup$
          Sir V is already given to be an open neighbourhood of I in G. I still do not understand. Can you please elaborate? Thanks a lot
          $endgroup$
          – SRJ
          Mar 23 at 10:40












          $begingroup$
          As an open set, $varphi^{-1}(V)$ is a union of open balls, hence the diagonal ${(t,t):tin[0,1]}$ can be covered by finitely many of them. Let $varepsilon$ be the radius of the smallest ball among these, then $A(t)^{-1}A(s)in V$ whenever $|s-t|<varepsilon$.
          $endgroup$
          – Berci
          Mar 23 at 13:47






          $begingroup$
          As an open set, $varphi^{-1}(V)$ is a union of open balls, hence the diagonal ${(t,t):tin[0,1]}$ can be covered by finitely many of them. Let $varepsilon$ be the radius of the smallest ball among these, then $A(t)^{-1}A(s)in V$ whenever $|s-t|<varepsilon$.
          $endgroup$
          – Berci
          Mar 23 at 13:47














          $begingroup$
          Thanks a lot... I required some time to digest argument. But Once I understand ... I became too happy AS it uses very basic idea and bypasses very High End tools....Once again thanks....
          $endgroup$
          – SRJ
          Mar 24 at 5:30




          $begingroup$
          Thanks a lot... I required some time to digest argument. But Once I understand ... I became too happy AS it uses very basic idea and bypasses very High End tools....Once again thanks....
          $endgroup$
          – SRJ
          Mar 24 at 5:30


















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