Doubt regarding Compactness argument used in Proof The 2019 Stack Overflow Developer Survey...
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Doubt regarding Compactness argument used in Proof
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In that Book I come across following theorem.
Notation
Author mentioned that by standard argument of compact we can extract sequnce such that $A_{t_{k-1}^{-1}A_{t_k}}in V$.
I do not understand this standard argument .
I would be really thankful If someone help me out
Any Help will be appreciated
real-analysis proof-explanation
$endgroup$
add a comment |
$begingroup$
In that Book I come across following theorem.
Notation
Author mentioned that by standard argument of compact we can extract sequnce such that $A_{t_{k-1}^{-1}A_{t_k}}in V$.
I do not understand this standard argument .
I would be really thankful If someone help me out
Any Help will be appreciated
real-analysis proof-explanation
$endgroup$
add a comment |
$begingroup$
In that Book I come across following theorem.
Notation
Author mentioned that by standard argument of compact we can extract sequnce such that $A_{t_{k-1}^{-1}A_{t_k}}in V$.
I do not understand this standard argument .
I would be really thankful If someone help me out
Any Help will be appreciated
real-analysis proof-explanation
$endgroup$
In that Book I come across following theorem.
Notation
Author mentioned that by standard argument of compact we can extract sequnce such that $A_{t_{k-1}^{-1}A_{t_k}}in V$.
I do not understand this standard argument .
I would be really thankful If someone help me out
Any Help will be appreciated
real-analysis proof-explanation
real-analysis proof-explanation
edited Mar 25 at 8:43
SRJ
asked Mar 22 at 13:16
SRJSRJ
1,8981620
1,8981620
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Hint: The operation $varphi:Gtimes Gto G, (A,B)mapsto A^{-1}B$ is continuous, hence so is $[0,1]times[0,1]to G, (t, s) mapsto A(t)^{-1}A(s)$.
Then the preimage of $V$ is open.
(You can also rely on a metric, if you wish, given by matrix norm.)
$endgroup$
$begingroup$
Sir V is already given to be an open neighbourhood of I in G. I still do not understand. Can you please elaborate? Thanks a lot
$endgroup$
– SRJ
Mar 23 at 10:40
$begingroup$
As an open set, $varphi^{-1}(V)$ is a union of open balls, hence the diagonal ${(t,t):tin[0,1]}$ can be covered by finitely many of them. Let $varepsilon$ be the radius of the smallest ball among these, then $A(t)^{-1}A(s)in V$ whenever $|s-t|<varepsilon$.
$endgroup$
– Berci
Mar 23 at 13:47
$begingroup$
Thanks a lot... I required some time to digest argument. But Once I understand ... I became too happy AS it uses very basic idea and bypasses very High End tools....Once again thanks....
$endgroup$
– SRJ
Mar 24 at 5:30
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
$begingroup$
Hint: The operation $varphi:Gtimes Gto G, (A,B)mapsto A^{-1}B$ is continuous, hence so is $[0,1]times[0,1]to G, (t, s) mapsto A(t)^{-1}A(s)$.
Then the preimage of $V$ is open.
(You can also rely on a metric, if you wish, given by matrix norm.)
$endgroup$
$begingroup$
Sir V is already given to be an open neighbourhood of I in G. I still do not understand. Can you please elaborate? Thanks a lot
$endgroup$
– SRJ
Mar 23 at 10:40
$begingroup$
As an open set, $varphi^{-1}(V)$ is a union of open balls, hence the diagonal ${(t,t):tin[0,1]}$ can be covered by finitely many of them. Let $varepsilon$ be the radius of the smallest ball among these, then $A(t)^{-1}A(s)in V$ whenever $|s-t|<varepsilon$.
$endgroup$
– Berci
Mar 23 at 13:47
$begingroup$
Thanks a lot... I required some time to digest argument. But Once I understand ... I became too happy AS it uses very basic idea and bypasses very High End tools....Once again thanks....
$endgroup$
– SRJ
Mar 24 at 5:30
add a comment |
$begingroup$
Hint: The operation $varphi:Gtimes Gto G, (A,B)mapsto A^{-1}B$ is continuous, hence so is $[0,1]times[0,1]to G, (t, s) mapsto A(t)^{-1}A(s)$.
Then the preimage of $V$ is open.
(You can also rely on a metric, if you wish, given by matrix norm.)
$endgroup$
$begingroup$
Sir V is already given to be an open neighbourhood of I in G. I still do not understand. Can you please elaborate? Thanks a lot
$endgroup$
– SRJ
Mar 23 at 10:40
$begingroup$
As an open set, $varphi^{-1}(V)$ is a union of open balls, hence the diagonal ${(t,t):tin[0,1]}$ can be covered by finitely many of them. Let $varepsilon$ be the radius of the smallest ball among these, then $A(t)^{-1}A(s)in V$ whenever $|s-t|<varepsilon$.
$endgroup$
– Berci
Mar 23 at 13:47
$begingroup$
Thanks a lot... I required some time to digest argument. But Once I understand ... I became too happy AS it uses very basic idea and bypasses very High End tools....Once again thanks....
$endgroup$
– SRJ
Mar 24 at 5:30
add a comment |
$begingroup$
Hint: The operation $varphi:Gtimes Gto G, (A,B)mapsto A^{-1}B$ is continuous, hence so is $[0,1]times[0,1]to G, (t, s) mapsto A(t)^{-1}A(s)$.
Then the preimage of $V$ is open.
(You can also rely on a metric, if you wish, given by matrix norm.)
$endgroup$
Hint: The operation $varphi:Gtimes Gto G, (A,B)mapsto A^{-1}B$ is continuous, hence so is $[0,1]times[0,1]to G, (t, s) mapsto A(t)^{-1}A(s)$.
Then the preimage of $V$ is open.
(You can also rely on a metric, if you wish, given by matrix norm.)
answered Mar 22 at 14:32
BerciBerci
62k23776
62k23776
$begingroup$
Sir V is already given to be an open neighbourhood of I in G. I still do not understand. Can you please elaborate? Thanks a lot
$endgroup$
– SRJ
Mar 23 at 10:40
$begingroup$
As an open set, $varphi^{-1}(V)$ is a union of open balls, hence the diagonal ${(t,t):tin[0,1]}$ can be covered by finitely many of them. Let $varepsilon$ be the radius of the smallest ball among these, then $A(t)^{-1}A(s)in V$ whenever $|s-t|<varepsilon$.
$endgroup$
– Berci
Mar 23 at 13:47
$begingroup$
Thanks a lot... I required some time to digest argument. But Once I understand ... I became too happy AS it uses very basic idea and bypasses very High End tools....Once again thanks....
$endgroup$
– SRJ
Mar 24 at 5:30
add a comment |
$begingroup$
Sir V is already given to be an open neighbourhood of I in G. I still do not understand. Can you please elaborate? Thanks a lot
$endgroup$
– SRJ
Mar 23 at 10:40
$begingroup$
As an open set, $varphi^{-1}(V)$ is a union of open balls, hence the diagonal ${(t,t):tin[0,1]}$ can be covered by finitely many of them. Let $varepsilon$ be the radius of the smallest ball among these, then $A(t)^{-1}A(s)in V$ whenever $|s-t|<varepsilon$.
$endgroup$
– Berci
Mar 23 at 13:47
$begingroup$
Thanks a lot... I required some time to digest argument. But Once I understand ... I became too happy AS it uses very basic idea and bypasses very High End tools....Once again thanks....
$endgroup$
– SRJ
Mar 24 at 5:30
$begingroup$
Sir V is already given to be an open neighbourhood of I in G. I still do not understand. Can you please elaborate? Thanks a lot
$endgroup$
– SRJ
Mar 23 at 10:40
$begingroup$
Sir V is already given to be an open neighbourhood of I in G. I still do not understand. Can you please elaborate? Thanks a lot
$endgroup$
– SRJ
Mar 23 at 10:40
$begingroup$
As an open set, $varphi^{-1}(V)$ is a union of open balls, hence the diagonal ${(t,t):tin[0,1]}$ can be covered by finitely many of them. Let $varepsilon$ be the radius of the smallest ball among these, then $A(t)^{-1}A(s)in V$ whenever $|s-t|<varepsilon$.
$endgroup$
– Berci
Mar 23 at 13:47
$begingroup$
As an open set, $varphi^{-1}(V)$ is a union of open balls, hence the diagonal ${(t,t):tin[0,1]}$ can be covered by finitely many of them. Let $varepsilon$ be the radius of the smallest ball among these, then $A(t)^{-1}A(s)in V$ whenever $|s-t|<varepsilon$.
$endgroup$
– Berci
Mar 23 at 13:47
$begingroup$
Thanks a lot... I required some time to digest argument. But Once I understand ... I became too happy AS it uses very basic idea and bypasses very High End tools....Once again thanks....
$endgroup$
– SRJ
Mar 24 at 5:30
$begingroup$
Thanks a lot... I required some time to digest argument. But Once I understand ... I became too happy AS it uses very basic idea and bypasses very High End tools....Once again thanks....
$endgroup$
– SRJ
Mar 24 at 5:30
add a comment |
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