ring method of finding volume of solid revolution The 2019 Stack Overflow Developer Survey...
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ring method of finding volume of solid revolution
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Announcing the arrival of Valued Associate #679: Cesar ManaraFind the volume of the solid obtained by rotating the region about the x-axisIntegral volume questionsVolume of solid of revolution with Disk and Tube method for bounded regionArea of solid revolution using integration.Finding the volume of revolution using the method of shellsFinding volume of solid using integration.Find the volume of the solidVolume of Solid of Revolution (Disk/Washer)Volume of the revolution solidVolume of a solid revolution
$begingroup$
Find the volume of the solid figure generated by rotating the area of region bounded by $y=4x-1$ and the x-axis on $[0,3]$ about y_axis?
I tried solving this using ring methode this way
But the answer in my book is 21pi/16
Is my solution wrong?
Btw I solved the question using cone volume formula which came out to be 36pi as well
integration
$endgroup$
add a comment |
$begingroup$
Find the volume of the solid figure generated by rotating the area of region bounded by $y=4x-1$ and the x-axis on $[0,3]$ about y_axis?
I tried solving this using ring methode this way
But the answer in my book is 21pi/16
Is my solution wrong?
Btw I solved the question using cone volume formula which came out to be 36pi as well
integration
$endgroup$
add a comment |
$begingroup$
Find the volume of the solid figure generated by rotating the area of region bounded by $y=4x-1$ and the x-axis on $[0,3]$ about y_axis?
I tried solving this using ring methode this way
But the answer in my book is 21pi/16
Is my solution wrong?
Btw I solved the question using cone volume formula which came out to be 36pi as well
integration
$endgroup$
Find the volume of the solid figure generated by rotating the area of region bounded by $y=4x-1$ and the x-axis on $[0,3]$ about y_axis?
I tried solving this using ring methode this way
But the answer in my book is 21pi/16
Is my solution wrong?
Btw I solved the question using cone volume formula which came out to be 36pi as well
integration
integration
asked Mar 22 at 13:26
Marva JamiMarva Jami
604
604
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add a comment |
1 Answer
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$begingroup$
The formulation of the exercise is not very clear. What is the region bounded by the line and the $x$-axis on [0,3]? If the area of $a)$ in the following image is meant, then yes, $36pi$ is correct, (for rotation around $y$-axis).
I would have interpreted the description to refer to an area such as $b)$. The rotation volume of b) has a volume of $left(63-frac{1}{24}right) pi$, which is also not the suggested solution. I was not able to find an area in this picture with that volume.
$endgroup$
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
The formulation of the exercise is not very clear. What is the region bounded by the line and the $x$-axis on [0,3]? If the area of $a)$ in the following image is meant, then yes, $36pi$ is correct, (for rotation around $y$-axis).
I would have interpreted the description to refer to an area such as $b)$. The rotation volume of b) has a volume of $left(63-frac{1}{24}right) pi$, which is also not the suggested solution. I was not able to find an area in this picture with that volume.
$endgroup$
add a comment |
$begingroup$
The formulation of the exercise is not very clear. What is the region bounded by the line and the $x$-axis on [0,3]? If the area of $a)$ in the following image is meant, then yes, $36pi$ is correct, (for rotation around $y$-axis).
I would have interpreted the description to refer to an area such as $b)$. The rotation volume of b) has a volume of $left(63-frac{1}{24}right) pi$, which is also not the suggested solution. I was not able to find an area in this picture with that volume.
$endgroup$
add a comment |
$begingroup$
The formulation of the exercise is not very clear. What is the region bounded by the line and the $x$-axis on [0,3]? If the area of $a)$ in the following image is meant, then yes, $36pi$ is correct, (for rotation around $y$-axis).
I would have interpreted the description to refer to an area such as $b)$. The rotation volume of b) has a volume of $left(63-frac{1}{24}right) pi$, which is also not the suggested solution. I was not able to find an area in this picture with that volume.
$endgroup$
The formulation of the exercise is not very clear. What is the region bounded by the line and the $x$-axis on [0,3]? If the area of $a)$ in the following image is meant, then yes, $36pi$ is correct, (for rotation around $y$-axis).
I would have interpreted the description to refer to an area such as $b)$. The rotation volume of b) has a volume of $left(63-frac{1}{24}right) pi$, which is also not the suggested solution. I was not able to find an area in this picture with that volume.
answered Mar 22 at 14:39
StrichcoderStrichcoder
5047
5047
add a comment |
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