How to invert this type of infinite series? The 2019 Stack Overflow Developer Survey Results...
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How to invert this type of infinite series?
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Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)invert a power series?Can every power series be representated as a taylor series?how to find out radius of convergence of the following series?How to derive a Taylor series from the ones we know ($cos x$, $sin x$, …)Taylor/Maclaurin series type questionPowers of Taylor seriesGive a function $f(x)$ sucht that the given power series is the Taylor series of $f(x)$.Multivariable Taylor series convergenceLimit of infinite sum (Taylor series)Can you convert a taylor series into a power series while avoiding singularities/discontinuities that result from a=0?
$begingroup$
If have a function $f$ given by a series
$$
f(z) = sum_{n,m = 0}^infty u_{n,m} z^{n + m t}
$$
for some $tinmathbb{R}^+$.
Is there an straightforward way (something similar to the inversion formula for Taylor series) to derive a similar series for $f^{-1}(z)$?
power-series taylor-expansion inverse inverse-function
$endgroup$
|
show 2 more comments
$begingroup$
If have a function $f$ given by a series
$$
f(z) = sum_{n,m = 0}^infty u_{n,m} z^{n + m t}
$$
for some $tinmathbb{R}^+$.
Is there an straightforward way (something similar to the inversion formula for Taylor series) to derive a similar series for $f^{-1}(z)$?
power-series taylor-expansion inverse inverse-function
$endgroup$
$begingroup$
Lagrange inversion? en.wikipedia.org/wiki/Lagrange_inversion_theorem
$endgroup$
– Lord Shark the Unknown
Mar 22 at 22:08
$begingroup$
I'm not sure how that would work in this case, since it's not exactly a Taylor series
$endgroup$
– Dark Malthorp
Mar 22 at 22:10
$begingroup$
What is the inversion formula for Taylor series ?
$endgroup$
– Yves Daoust
Mar 22 at 22:11
$begingroup$
With $w:=z^t$, you in fact have a bivariate series $f(z,w)=sum u_{n,m}z^nw^m$.
$endgroup$
– Yves Daoust
Mar 22 at 22:14
$begingroup$
OK. Does that help me invert it?
$endgroup$
– Dark Malthorp
Mar 23 at 1:04
|
show 2 more comments
$begingroup$
If have a function $f$ given by a series
$$
f(z) = sum_{n,m = 0}^infty u_{n,m} z^{n + m t}
$$
for some $tinmathbb{R}^+$.
Is there an straightforward way (something similar to the inversion formula for Taylor series) to derive a similar series for $f^{-1}(z)$?
power-series taylor-expansion inverse inverse-function
$endgroup$
If have a function $f$ given by a series
$$
f(z) = sum_{n,m = 0}^infty u_{n,m} z^{n + m t}
$$
for some $tinmathbb{R}^+$.
Is there an straightforward way (something similar to the inversion formula for Taylor series) to derive a similar series for $f^{-1}(z)$?
power-series taylor-expansion inverse inverse-function
power-series taylor-expansion inverse inverse-function
asked Mar 22 at 22:05
Dark MalthorpDark Malthorp
938314
938314
$begingroup$
Lagrange inversion? en.wikipedia.org/wiki/Lagrange_inversion_theorem
$endgroup$
– Lord Shark the Unknown
Mar 22 at 22:08
$begingroup$
I'm not sure how that would work in this case, since it's not exactly a Taylor series
$endgroup$
– Dark Malthorp
Mar 22 at 22:10
$begingroup$
What is the inversion formula for Taylor series ?
$endgroup$
– Yves Daoust
Mar 22 at 22:11
$begingroup$
With $w:=z^t$, you in fact have a bivariate series $f(z,w)=sum u_{n,m}z^nw^m$.
$endgroup$
– Yves Daoust
Mar 22 at 22:14
$begingroup$
OK. Does that help me invert it?
$endgroup$
– Dark Malthorp
Mar 23 at 1:04
|
show 2 more comments
$begingroup$
Lagrange inversion? en.wikipedia.org/wiki/Lagrange_inversion_theorem
$endgroup$
– Lord Shark the Unknown
Mar 22 at 22:08
$begingroup$
I'm not sure how that would work in this case, since it's not exactly a Taylor series
$endgroup$
– Dark Malthorp
Mar 22 at 22:10
$begingroup$
What is the inversion formula for Taylor series ?
$endgroup$
– Yves Daoust
Mar 22 at 22:11
$begingroup$
With $w:=z^t$, you in fact have a bivariate series $f(z,w)=sum u_{n,m}z^nw^m$.
$endgroup$
– Yves Daoust
Mar 22 at 22:14
$begingroup$
OK. Does that help me invert it?
$endgroup$
– Dark Malthorp
Mar 23 at 1:04
$begingroup$
Lagrange inversion? en.wikipedia.org/wiki/Lagrange_inversion_theorem
$endgroup$
– Lord Shark the Unknown
Mar 22 at 22:08
$begingroup$
Lagrange inversion? en.wikipedia.org/wiki/Lagrange_inversion_theorem
$endgroup$
– Lord Shark the Unknown
Mar 22 at 22:08
$begingroup$
I'm not sure how that would work in this case, since it's not exactly a Taylor series
$endgroup$
– Dark Malthorp
Mar 22 at 22:10
$begingroup$
I'm not sure how that would work in this case, since it's not exactly a Taylor series
$endgroup$
– Dark Malthorp
Mar 22 at 22:10
$begingroup$
What is the inversion formula for Taylor series ?
$endgroup$
– Yves Daoust
Mar 22 at 22:11
$begingroup$
What is the inversion formula for Taylor series ?
$endgroup$
– Yves Daoust
Mar 22 at 22:11
$begingroup$
With $w:=z^t$, you in fact have a bivariate series $f(z,w)=sum u_{n,m}z^nw^m$.
$endgroup$
– Yves Daoust
Mar 22 at 22:14
$begingroup$
With $w:=z^t$, you in fact have a bivariate series $f(z,w)=sum u_{n,m}z^nw^m$.
$endgroup$
– Yves Daoust
Mar 22 at 22:14
$begingroup$
OK. Does that help me invert it?
$endgroup$
– Dark Malthorp
Mar 23 at 1:04
$begingroup$
OK. Does that help me invert it?
$endgroup$
– Dark Malthorp
Mar 23 at 1:04
|
show 2 more comments
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$begingroup$
Lagrange inversion? en.wikipedia.org/wiki/Lagrange_inversion_theorem
$endgroup$
– Lord Shark the Unknown
Mar 22 at 22:08
$begingroup$
I'm not sure how that would work in this case, since it's not exactly a Taylor series
$endgroup$
– Dark Malthorp
Mar 22 at 22:10
$begingroup$
What is the inversion formula for Taylor series ?
$endgroup$
– Yves Daoust
Mar 22 at 22:11
$begingroup$
With $w:=z^t$, you in fact have a bivariate series $f(z,w)=sum u_{n,m}z^nw^m$.
$endgroup$
– Yves Daoust
Mar 22 at 22:14
$begingroup$
OK. Does that help me invert it?
$endgroup$
– Dark Malthorp
Mar 23 at 1:04