How to invert this type of infinite series? The 2019 Stack Overflow Developer Survey Results...

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How to invert this type of infinite series?



The 2019 Stack Overflow Developer Survey Results Are In
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)invert a power series?Can every power series be representated as a taylor series?how to find out radius of convergence of the following series?How to derive a Taylor series from the ones we know ($cos x$, $sin x$, …)Taylor/Maclaurin series type questionPowers of Taylor seriesGive a function $f(x)$ sucht that the given power series is the Taylor series of $f(x)$.Multivariable Taylor series convergenceLimit of infinite sum (Taylor series)Can you convert a taylor series into a power series while avoiding singularities/discontinuities that result from a=0?












0












$begingroup$


If have a function $f$ given by a series
$$
f(z) = sum_{n,m = 0}^infty u_{n,m} z^{n + m t}
$$

for some $tinmathbb{R}^+$.



Is there an straightforward way (something similar to the inversion formula for Taylor series) to derive a similar series for $f^{-1}(z)$?










share|cite|improve this question









$endgroup$












  • $begingroup$
    Lagrange inversion? en.wikipedia.org/wiki/Lagrange_inversion_theorem
    $endgroup$
    – Lord Shark the Unknown
    Mar 22 at 22:08










  • $begingroup$
    I'm not sure how that would work in this case, since it's not exactly a Taylor series
    $endgroup$
    – Dark Malthorp
    Mar 22 at 22:10










  • $begingroup$
    What is the inversion formula for Taylor series ?
    $endgroup$
    – Yves Daoust
    Mar 22 at 22:11










  • $begingroup$
    With $w:=z^t$, you in fact have a bivariate series $f(z,w)=sum u_{n,m}z^nw^m$.
    $endgroup$
    – Yves Daoust
    Mar 22 at 22:14












  • $begingroup$
    OK. Does that help me invert it?
    $endgroup$
    – Dark Malthorp
    Mar 23 at 1:04
















0












$begingroup$


If have a function $f$ given by a series
$$
f(z) = sum_{n,m = 0}^infty u_{n,m} z^{n + m t}
$$

for some $tinmathbb{R}^+$.



Is there an straightforward way (something similar to the inversion formula for Taylor series) to derive a similar series for $f^{-1}(z)$?










share|cite|improve this question









$endgroup$












  • $begingroup$
    Lagrange inversion? en.wikipedia.org/wiki/Lagrange_inversion_theorem
    $endgroup$
    – Lord Shark the Unknown
    Mar 22 at 22:08










  • $begingroup$
    I'm not sure how that would work in this case, since it's not exactly a Taylor series
    $endgroup$
    – Dark Malthorp
    Mar 22 at 22:10










  • $begingroup$
    What is the inversion formula for Taylor series ?
    $endgroup$
    – Yves Daoust
    Mar 22 at 22:11










  • $begingroup$
    With $w:=z^t$, you in fact have a bivariate series $f(z,w)=sum u_{n,m}z^nw^m$.
    $endgroup$
    – Yves Daoust
    Mar 22 at 22:14












  • $begingroup$
    OK. Does that help me invert it?
    $endgroup$
    – Dark Malthorp
    Mar 23 at 1:04














0












0








0


1



$begingroup$


If have a function $f$ given by a series
$$
f(z) = sum_{n,m = 0}^infty u_{n,m} z^{n + m t}
$$

for some $tinmathbb{R}^+$.



Is there an straightforward way (something similar to the inversion formula for Taylor series) to derive a similar series for $f^{-1}(z)$?










share|cite|improve this question









$endgroup$




If have a function $f$ given by a series
$$
f(z) = sum_{n,m = 0}^infty u_{n,m} z^{n + m t}
$$

for some $tinmathbb{R}^+$.



Is there an straightforward way (something similar to the inversion formula for Taylor series) to derive a similar series for $f^{-1}(z)$?







power-series taylor-expansion inverse inverse-function






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 22 at 22:05









Dark MalthorpDark Malthorp

938314




938314












  • $begingroup$
    Lagrange inversion? en.wikipedia.org/wiki/Lagrange_inversion_theorem
    $endgroup$
    – Lord Shark the Unknown
    Mar 22 at 22:08










  • $begingroup$
    I'm not sure how that would work in this case, since it's not exactly a Taylor series
    $endgroup$
    – Dark Malthorp
    Mar 22 at 22:10










  • $begingroup$
    What is the inversion formula for Taylor series ?
    $endgroup$
    – Yves Daoust
    Mar 22 at 22:11










  • $begingroup$
    With $w:=z^t$, you in fact have a bivariate series $f(z,w)=sum u_{n,m}z^nw^m$.
    $endgroup$
    – Yves Daoust
    Mar 22 at 22:14












  • $begingroup$
    OK. Does that help me invert it?
    $endgroup$
    – Dark Malthorp
    Mar 23 at 1:04


















  • $begingroup$
    Lagrange inversion? en.wikipedia.org/wiki/Lagrange_inversion_theorem
    $endgroup$
    – Lord Shark the Unknown
    Mar 22 at 22:08










  • $begingroup$
    I'm not sure how that would work in this case, since it's not exactly a Taylor series
    $endgroup$
    – Dark Malthorp
    Mar 22 at 22:10










  • $begingroup$
    What is the inversion formula for Taylor series ?
    $endgroup$
    – Yves Daoust
    Mar 22 at 22:11










  • $begingroup$
    With $w:=z^t$, you in fact have a bivariate series $f(z,w)=sum u_{n,m}z^nw^m$.
    $endgroup$
    – Yves Daoust
    Mar 22 at 22:14












  • $begingroup$
    OK. Does that help me invert it?
    $endgroup$
    – Dark Malthorp
    Mar 23 at 1:04
















$begingroup$
Lagrange inversion? en.wikipedia.org/wiki/Lagrange_inversion_theorem
$endgroup$
– Lord Shark the Unknown
Mar 22 at 22:08




$begingroup$
Lagrange inversion? en.wikipedia.org/wiki/Lagrange_inversion_theorem
$endgroup$
– Lord Shark the Unknown
Mar 22 at 22:08












$begingroup$
I'm not sure how that would work in this case, since it's not exactly a Taylor series
$endgroup$
– Dark Malthorp
Mar 22 at 22:10




$begingroup$
I'm not sure how that would work in this case, since it's not exactly a Taylor series
$endgroup$
– Dark Malthorp
Mar 22 at 22:10












$begingroup$
What is the inversion formula for Taylor series ?
$endgroup$
– Yves Daoust
Mar 22 at 22:11




$begingroup$
What is the inversion formula for Taylor series ?
$endgroup$
– Yves Daoust
Mar 22 at 22:11












$begingroup$
With $w:=z^t$, you in fact have a bivariate series $f(z,w)=sum u_{n,m}z^nw^m$.
$endgroup$
– Yves Daoust
Mar 22 at 22:14






$begingroup$
With $w:=z^t$, you in fact have a bivariate series $f(z,w)=sum u_{n,m}z^nw^m$.
$endgroup$
– Yves Daoust
Mar 22 at 22:14














$begingroup$
OK. Does that help me invert it?
$endgroup$
– Dark Malthorp
Mar 23 at 1:04




$begingroup$
OK. Does that help me invert it?
$endgroup$
– Dark Malthorp
Mar 23 at 1:04










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