What is intensity in Poisson (?) The 2019 Stack Overflow Developer Survey Results Are In ...
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What is intensity in Poisson (?)
The 2019 Stack Overflow Developer Survey Results Are In
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Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)an estimation of the expected value of a Poisson processbound on compound poisson processInfinitesimal Generator of Poisson processVariable intensity with a Poisson Process?Expectation of the Ratio of a Poisson ProcessesA Poisson-like process with intensity controlled by a Markov chainChange of measure for Poisson process with deterministic intensityPoisson process with stochastic intensity correlated with a Brownian MotionQuestion about Poisson processes as measuresArrival time in Poisson Processes
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I am reading Stoikov's slides (slide 15), and there is a statement like this:
Number of stocks bought $N_t^b$ is Poisson with intensity $lambda^b
(p^b -s)$.
Does this mean that:
$$mathbb{P}[N_t^b = n] = frac{(lambda^b (p^b -s))^n}{n!} exp^{-(lambda^b (p^b -s))}$$
?
probability
$endgroup$
add a comment |
$begingroup$
I am reading Stoikov's slides (slide 15), and there is a statement like this:
Number of stocks bought $N_t^b$ is Poisson with intensity $lambda^b
(p^b -s)$.
Does this mean that:
$$mathbb{P}[N_t^b = n] = frac{(lambda^b (p^b -s))^n}{n!} exp^{-(lambda^b (p^b -s))}$$
?
probability
$endgroup$
1
$begingroup$
Presumably, yes.
$endgroup$
– Math1000
Mar 22 at 21:46
add a comment |
$begingroup$
I am reading Stoikov's slides (slide 15), and there is a statement like this:
Number of stocks bought $N_t^b$ is Poisson with intensity $lambda^b
(p^b -s)$.
Does this mean that:
$$mathbb{P}[N_t^b = n] = frac{(lambda^b (p^b -s))^n}{n!} exp^{-(lambda^b (p^b -s))}$$
?
probability
$endgroup$
I am reading Stoikov's slides (slide 15), and there is a statement like this:
Number of stocks bought $N_t^b$ is Poisson with intensity $lambda^b
(p^b -s)$.
Does this mean that:
$$mathbb{P}[N_t^b = n] = frac{(lambda^b (p^b -s))^n}{n!} exp^{-(lambda^b (p^b -s))}$$
?
probability
probability
asked Mar 22 at 21:44
i squared - Keep it Reali squared - Keep it Real
1,63211128
1,63211128
1
$begingroup$
Presumably, yes.
$endgroup$
– Math1000
Mar 22 at 21:46
add a comment |
1
$begingroup$
Presumably, yes.
$endgroup$
– Math1000
Mar 22 at 21:46
1
1
$begingroup$
Presumably, yes.
$endgroup$
– Math1000
Mar 22 at 21:46
$begingroup$
Presumably, yes.
$endgroup$
– Math1000
Mar 22 at 21:46
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
The "intensity" $lambda^b
(p^b -s)$ is just the average number of events in a time interval.
The term "intensity" is used to indicate "how strong" is the Poisson process under investigation, i.e., the higher is the average number of events in time interval, the stronger (i.e. the "more intense") is the process.
$endgroup$
$begingroup$
Thank you. I was also wondering whether there should be any dependence on time in my equation
$endgroup$
– i squared - Keep it Real
Mar 22 at 22:02
add a comment |
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1 Answer
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1 Answer
1
active
oldest
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active
oldest
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active
oldest
votes
$begingroup$
The "intensity" $lambda^b
(p^b -s)$ is just the average number of events in a time interval.
The term "intensity" is used to indicate "how strong" is the Poisson process under investigation, i.e., the higher is the average number of events in time interval, the stronger (i.e. the "more intense") is the process.
$endgroup$
$begingroup$
Thank you. I was also wondering whether there should be any dependence on time in my equation
$endgroup$
– i squared - Keep it Real
Mar 22 at 22:02
add a comment |
$begingroup$
The "intensity" $lambda^b
(p^b -s)$ is just the average number of events in a time interval.
The term "intensity" is used to indicate "how strong" is the Poisson process under investigation, i.e., the higher is the average number of events in time interval, the stronger (i.e. the "more intense") is the process.
$endgroup$
$begingroup$
Thank you. I was also wondering whether there should be any dependence on time in my equation
$endgroup$
– i squared - Keep it Real
Mar 22 at 22:02
add a comment |
$begingroup$
The "intensity" $lambda^b
(p^b -s)$ is just the average number of events in a time interval.
The term "intensity" is used to indicate "how strong" is the Poisson process under investigation, i.e., the higher is the average number of events in time interval, the stronger (i.e. the "more intense") is the process.
$endgroup$
The "intensity" $lambda^b
(p^b -s)$ is just the average number of events in a time interval.
The term "intensity" is used to indicate "how strong" is the Poisson process under investigation, i.e., the higher is the average number of events in time interval, the stronger (i.e. the "more intense") is the process.
edited Mar 22 at 22:22
answered Mar 22 at 21:47
the_candymanthe_candyman
9,14032147
9,14032147
$begingroup$
Thank you. I was also wondering whether there should be any dependence on time in my equation
$endgroup$
– i squared - Keep it Real
Mar 22 at 22:02
add a comment |
$begingroup$
Thank you. I was also wondering whether there should be any dependence on time in my equation
$endgroup$
– i squared - Keep it Real
Mar 22 at 22:02
$begingroup$
Thank you. I was also wondering whether there should be any dependence on time in my equation
$endgroup$
– i squared - Keep it Real
Mar 22 at 22:02
$begingroup$
Thank you. I was also wondering whether there should be any dependence on time in my equation
$endgroup$
– i squared - Keep it Real
Mar 22 at 22:02
add a comment |
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$begingroup$
Presumably, yes.
$endgroup$
– Math1000
Mar 22 at 21:46