What is intensity in Poisson (?) The 2019 Stack Overflow Developer Survey Results Are In ...

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What is intensity in Poisson (?)



The 2019 Stack Overflow Developer Survey Results Are In
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)an estimation of the expected value of a Poisson processbound on compound poisson processInfinitesimal Generator of Poisson processVariable intensity with a Poisson Process?Expectation of the Ratio of a Poisson ProcessesA Poisson-like process with intensity controlled by a Markov chainChange of measure for Poisson process with deterministic intensityPoisson process with stochastic intensity correlated with a Brownian MotionQuestion about Poisson processes as measuresArrival time in Poisson Processes












1












$begingroup$


I am reading Stoikov's slides (slide 15), and there is a statement like this:




Number of stocks bought $N_t^b$ is Poisson with intensity $lambda^b
(p^b -s)$
.




Does this mean that:



$$mathbb{P}[N_t^b = n] = frac{(lambda^b (p^b -s))^n}{n!} exp^{-(lambda^b (p^b -s))}$$



?










share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    Presumably, yes.
    $endgroup$
    – Math1000
    Mar 22 at 21:46
















1












$begingroup$


I am reading Stoikov's slides (slide 15), and there is a statement like this:




Number of stocks bought $N_t^b$ is Poisson with intensity $lambda^b
(p^b -s)$
.




Does this mean that:



$$mathbb{P}[N_t^b = n] = frac{(lambda^b (p^b -s))^n}{n!} exp^{-(lambda^b (p^b -s))}$$



?










share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    Presumably, yes.
    $endgroup$
    – Math1000
    Mar 22 at 21:46














1












1








1





$begingroup$


I am reading Stoikov's slides (slide 15), and there is a statement like this:




Number of stocks bought $N_t^b$ is Poisson with intensity $lambda^b
(p^b -s)$
.




Does this mean that:



$$mathbb{P}[N_t^b = n] = frac{(lambda^b (p^b -s))^n}{n!} exp^{-(lambda^b (p^b -s))}$$



?










share|cite|improve this question









$endgroup$




I am reading Stoikov's slides (slide 15), and there is a statement like this:




Number of stocks bought $N_t^b$ is Poisson with intensity $lambda^b
(p^b -s)$
.




Does this mean that:



$$mathbb{P}[N_t^b = n] = frac{(lambda^b (p^b -s))^n}{n!} exp^{-(lambda^b (p^b -s))}$$



?







probability






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 22 at 21:44









i squared - Keep it Reali squared - Keep it Real

1,63211128




1,63211128








  • 1




    $begingroup$
    Presumably, yes.
    $endgroup$
    – Math1000
    Mar 22 at 21:46














  • 1




    $begingroup$
    Presumably, yes.
    $endgroup$
    – Math1000
    Mar 22 at 21:46








1




1




$begingroup$
Presumably, yes.
$endgroup$
– Math1000
Mar 22 at 21:46




$begingroup$
Presumably, yes.
$endgroup$
– Math1000
Mar 22 at 21:46










1 Answer
1






active

oldest

votes


















1












$begingroup$

The "intensity" $lambda^b
(p^b -s)$
is just the average number of events in a time interval.



The term "intensity" is used to indicate "how strong" is the Poisson process under investigation, i.e., the higher is the average number of events in time interval, the stronger (i.e. the "more intense") is the process.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Thank you. I was also wondering whether there should be any dependence on time in my equation
    $endgroup$
    – i squared - Keep it Real
    Mar 22 at 22:02












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1 Answer
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active

oldest

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active

oldest

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active

oldest

votes









1












$begingroup$

The "intensity" $lambda^b
(p^b -s)$
is just the average number of events in a time interval.



The term "intensity" is used to indicate "how strong" is the Poisson process under investigation, i.e., the higher is the average number of events in time interval, the stronger (i.e. the "more intense") is the process.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Thank you. I was also wondering whether there should be any dependence on time in my equation
    $endgroup$
    – i squared - Keep it Real
    Mar 22 at 22:02
















1












$begingroup$

The "intensity" $lambda^b
(p^b -s)$
is just the average number of events in a time interval.



The term "intensity" is used to indicate "how strong" is the Poisson process under investigation, i.e., the higher is the average number of events in time interval, the stronger (i.e. the "more intense") is the process.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Thank you. I was also wondering whether there should be any dependence on time in my equation
    $endgroup$
    – i squared - Keep it Real
    Mar 22 at 22:02














1












1








1





$begingroup$

The "intensity" $lambda^b
(p^b -s)$
is just the average number of events in a time interval.



The term "intensity" is used to indicate "how strong" is the Poisson process under investigation, i.e., the higher is the average number of events in time interval, the stronger (i.e. the "more intense") is the process.






share|cite|improve this answer











$endgroup$



The "intensity" $lambda^b
(p^b -s)$
is just the average number of events in a time interval.



The term "intensity" is used to indicate "how strong" is the Poisson process under investigation, i.e., the higher is the average number of events in time interval, the stronger (i.e. the "more intense") is the process.







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Mar 22 at 22:22

























answered Mar 22 at 21:47









the_candymanthe_candyman

9,14032147




9,14032147












  • $begingroup$
    Thank you. I was also wondering whether there should be any dependence on time in my equation
    $endgroup$
    – i squared - Keep it Real
    Mar 22 at 22:02


















  • $begingroup$
    Thank you. I was also wondering whether there should be any dependence on time in my equation
    $endgroup$
    – i squared - Keep it Real
    Mar 22 at 22:02
















$begingroup$
Thank you. I was also wondering whether there should be any dependence on time in my equation
$endgroup$
– i squared - Keep it Real
Mar 22 at 22:02




$begingroup$
Thank you. I was also wondering whether there should be any dependence on time in my equation
$endgroup$
– i squared - Keep it Real
Mar 22 at 22:02


















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