special value of generalized hypergeometric function 1F2(2;1,5/2;x^2) The 2019 Stack Overflow...
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special value of generalized hypergeometric function 1F2(2;1,5/2;x^2)
The 2019 Stack Overflow Developer Survey Results Are InEvaluating limit involving hypergeometric function $limlimits_{zto 1^-}{}_2F_1(-a,-b,-(a+b),z)$Integral with hypergeometric functionSimplification of hypergeometric function with specific argumentsEvaluating a certain integral which generalizes the ${_3F_2}$ hypergeometric functionSimplification of Hypergeometric Function with special argumentsGeneralised Hypergeometric Function and Integral: Elementary QuestionFrom integral to hypergeometric seriesHypergeometric function integrationIntegral involving hypergeometric functions - $int_{0}^{infty} e^{(ax)} U(c,d,b_1x)U(c,d,b_2x) dx$Rewriting Appell's Hypergeometric Function $F_1$ in terms of Gauss' Hypergeometric Function $_2F_1$
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In an attempt to solve an integral, I had some trouble with evaluating the following hypergeometric function. Though Mathematica can solve it, I still wonder how can I evaluate this. Any useful information would be grateful.
enter image description here
hypergeometric-function
asked Mar 21 at 5:26
user649562user649562
1
$endgroup$
add a comment |
$begingroup$
In an attempt to solve an integral, I had some trouble with evaluating the following hypergeometric function. Though Mathematica can solve it, I still wonder how can I evaluate this. Any useful information would be grateful.
enter image description here
hypergeometric-function
asked Mar 21 at 5:26
user649562user649562
1
$endgroup$
$begingroup$
$$ _2F_1(2;1,frac52;x^2)= frac{3sin^{-1}(x)}{2x^3sqrt{1-x^2}}-frac{3}{2x^2}$$
$endgroup$
– JJacquelin
Mar 21 at 5:56
$begingroup$
@JJacquelin. Long time no speak ! Cheers
$endgroup$
– Claude Leibovici
Mar 21 at 7:06
$begingroup$
@Claude Leibovici. Glad to meet you again !
$endgroup$
– JJacquelin
Mar 21 at 7:29
add a comment |
$begingroup$
In an attempt to solve an integral, I had some trouble with evaluating the following hypergeometric function. Though Mathematica can solve it, I still wonder how can I evaluate this. Any useful information would be grateful.
enter image description here
hypergeometric-function
asked Mar 21 at 5:26
user649562user649562
1
$endgroup$
In an attempt to solve an integral, I had some trouble with evaluating the following hypergeometric function. Though Mathematica can solve it, I still wonder how can I evaluate this. Any useful information would be grateful.
enter image description here
hypergeometric-function
hypergeometric-function
asked Mar 21 at 5:26
user649562user649562
1
asked Mar 21 at 5:26
user649562user649562
1
asked Mar 21 at 5:26
user649562user649562
1
asked Mar 21 at 5:26
user649562user649562
1
asked Mar 21 at 5:26
user649562user649562
1
1
$begingroup$
$$ _2F_1(2;1,frac52;x^2)= frac{3sin^{-1}(x)}{2x^3sqrt{1-x^2}}-frac{3}{2x^2}$$
$endgroup$
– JJacquelin
Mar 21 at 5:56
$begingroup$
@JJacquelin. Long time no speak ! Cheers
$endgroup$
– Claude Leibovici
Mar 21 at 7:06
$begingroup$
@Claude Leibovici. Glad to meet you again !
$endgroup$
– JJacquelin
Mar 21 at 7:29
add a comment |
$begingroup$
$$ _2F_1(2;1,frac52;x^2)= frac{3sin^{-1}(x)}{2x^3sqrt{1-x^2}}-frac{3}{2x^2}$$
$endgroup$
– JJacquelin
Mar 21 at 5:56
$begingroup$
@JJacquelin. Long time no speak ! Cheers
$endgroup$
– Claude Leibovici
Mar 21 at 7:06
$begingroup$
@Claude Leibovici. Glad to meet you again !
$endgroup$
– JJacquelin
Mar 21 at 7:29
$begingroup$
$$ _2F_1(2;1,frac52;x^2)= frac{3sin^{-1}(x)}{2x^3sqrt{1-x^2}}-frac{3}{2x^2}$$
$endgroup$
– JJacquelin
Mar 21 at 5:56
$begingroup$
$$ _2F_1(2;1,frac52;x^2)= frac{3sin^{-1}(x)}{2x^3sqrt{1-x^2}}-frac{3}{2x^2}$$
$endgroup$
– JJacquelin
Mar 21 at 5:56
$begingroup$
@JJacquelin. Long time no speak ! Cheers
$endgroup$
– Claude Leibovici
Mar 21 at 7:06
$begingroup$
@JJacquelin. Long time no speak ! Cheers
$endgroup$
– Claude Leibovici
Mar 21 at 7:06
$begingroup$
@Claude Leibovici. Glad to meet you again !
$endgroup$
– JJacquelin
Mar 21 at 7:29
$begingroup$
@Claude Leibovici. Glad to meet you again !
$endgroup$
– JJacquelin
Mar 21 at 7:29
add a comment |
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$begingroup$
$$ _2F_1(2;1,frac52;x^2)= frac{3sin^{-1}(x)}{2x^3sqrt{1-x^2}}-frac{3}{2x^2}$$
$endgroup$
– JJacquelin
Mar 21 at 5:56
$begingroup$
@JJacquelin. Long time no speak ! Cheers
$endgroup$
– Claude Leibovici
Mar 21 at 7:06
$begingroup$
@Claude Leibovici. Glad to meet you again !
$endgroup$
– JJacquelin
Mar 21 at 7:29