Finite descent of a semi-Fredholm operator Announcing the arrival of Valued Associate #679:...
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Finite descent of a semi-Fredholm operator
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern)Question about Fredholm operatorFredholm index of invertible bounded operatorOperator is Fredholm if it is the sum of an Invertible and a Compact operatorDensity of Fredholm operatorsrelation between essential spectrum and spectrum of an operatorUpper semi Fredholm operator is closed mapIf $A$ is invertible and $F$ is Fredholm, when is $A+F$ also Fredholm?Is this a Fredholm operator with index 0?Fredholm operator of index 0Semi-Fredholm quasidiagonal operator has index zero
$begingroup$
Let $T$ be a bounded linear operators on a Banach space $X$.Let $K$ be a compact operator on $X$. $T$ and $K$ be commuting operators. If $T$ is lower semi-Fredholm and descent of $T$ is finite.
I want to prove that descent of $(T+K)$ is finite.
operator-theory
$endgroup$
add a comment |
$begingroup$
Let $T$ be a bounded linear operators on a Banach space $X$.Let $K$ be a compact operator on $X$. $T$ and $K$ be commuting operators. If $T$ is lower semi-Fredholm and descent of $T$ is finite.
I want to prove that descent of $(T+K)$ is finite.
operator-theory
$endgroup$
add a comment |
$begingroup$
Let $T$ be a bounded linear operators on a Banach space $X$.Let $K$ be a compact operator on $X$. $T$ and $K$ be commuting operators. If $T$ is lower semi-Fredholm and descent of $T$ is finite.
I want to prove that descent of $(T+K)$ is finite.
operator-theory
$endgroup$
Let $T$ be a bounded linear operators on a Banach space $X$.Let $K$ be a compact operator on $X$. $T$ and $K$ be commuting operators. If $T$ is lower semi-Fredholm and descent of $T$ is finite.
I want to prove that descent of $(T+K)$ is finite.
operator-theory
operator-theory
asked Jul 16 '17 at 6:59
Manu RohillaManu Rohilla
15419
15419
add a comment |
add a comment |
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