Is it possible to have a Hausdorff dimension less than the topological dimension?Topological manifolds...

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Is it possible to have a Hausdorff dimension less than the topological dimension?


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"Normal" geometric shapes have Hausdorff dimensions equal to their topological dimensions. Mandelbrot defined fractals as shapes that have a Hausdorff dimension greater than their topological dimension. Is there a class of shapes that have a Hausdorff dimension less than their topological dimension, or is this impossible? If there is such a shape, what are common examples of them? If this is impossible, why?










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  • $begingroup$
    No, covering dimension is always $le$ Hausdorff dimension (Sznirelman's theorem).
    $endgroup$
    – Moishe Kohan
    Mar 10 at 3:30
















0












$begingroup$


"Normal" geometric shapes have Hausdorff dimensions equal to their topological dimensions. Mandelbrot defined fractals as shapes that have a Hausdorff dimension greater than their topological dimension. Is there a class of shapes that have a Hausdorff dimension less than their topological dimension, or is this impossible? If there is such a shape, what are common examples of them? If this is impossible, why?










share|cite|improve this question











$endgroup$












  • $begingroup$
    No, covering dimension is always $le$ Hausdorff dimension (Sznirelman's theorem).
    $endgroup$
    – Moishe Kohan
    Mar 10 at 3:30














0












0








0


1



$begingroup$


"Normal" geometric shapes have Hausdorff dimensions equal to their topological dimensions. Mandelbrot defined fractals as shapes that have a Hausdorff dimension greater than their topological dimension. Is there a class of shapes that have a Hausdorff dimension less than their topological dimension, or is this impossible? If there is such a shape, what are common examples of them? If this is impossible, why?










share|cite|improve this question











$endgroup$




"Normal" geometric shapes have Hausdorff dimensions equal to their topological dimensions. Mandelbrot defined fractals as shapes that have a Hausdorff dimension greater than their topological dimension. Is there a class of shapes that have a Hausdorff dimension less than their topological dimension, or is this impossible? If there is such a shape, what are common examples of them? If this is impossible, why?







dimension-theory hausdorff-measure






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share|cite|improve this question













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share|cite|improve this question








edited Mar 10 at 3:23









J. W. Tanner

3,2201320




3,2201320










asked Mar 10 at 3:15









tox123tox123

562721




562721












  • $begingroup$
    No, covering dimension is always $le$ Hausdorff dimension (Sznirelman's theorem).
    $endgroup$
    – Moishe Kohan
    Mar 10 at 3:30


















  • $begingroup$
    No, covering dimension is always $le$ Hausdorff dimension (Sznirelman's theorem).
    $endgroup$
    – Moishe Kohan
    Mar 10 at 3:30
















$begingroup$
No, covering dimension is always $le$ Hausdorff dimension (Sznirelman's theorem).
$endgroup$
– Moishe Kohan
Mar 10 at 3:30




$begingroup$
No, covering dimension is always $le$ Hausdorff dimension (Sznirelman's theorem).
$endgroup$
– Moishe Kohan
Mar 10 at 3:30










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