Meaning of partial differential in limits of integration? Announcing the arrival of Valued...
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Meaning of partial differential in limits of integration?
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I have seen some maths problems where there is a partial differential in the limits of integration, for example: $int_{partial z} $
What exactly does it represent/mean? When is it used?
calculus integration definite-integrals
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add a comment |
$begingroup$
I have seen some maths problems where there is a partial differential in the limits of integration, for example: $int_{partial z} $
What exactly does it represent/mean? When is it used?
calculus integration definite-integrals
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1
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It might be the boundary of some domain.
$endgroup$
– Gibbs
Mar 26 at 10:14
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ohh...ok... i get it... Q is a region that denotes an "area", whereas $partial{Q}$ is the "circumference" around this 2-dimensional area. The "boundary" of the "area". Right or wrong?
$endgroup$
– DiscreteMath
Mar 28 at 15:26
add a comment |
$begingroup$
I have seen some maths problems where there is a partial differential in the limits of integration, for example: $int_{partial z} $
What exactly does it represent/mean? When is it used?
calculus integration definite-integrals
$endgroup$
I have seen some maths problems where there is a partial differential in the limits of integration, for example: $int_{partial z} $
What exactly does it represent/mean? When is it used?
calculus integration definite-integrals
calculus integration definite-integrals
asked Mar 26 at 10:13
Simplex1Simplex1
745
745
1
$begingroup$
It might be the boundary of some domain.
$endgroup$
– Gibbs
Mar 26 at 10:14
$begingroup$
ohh...ok... i get it... Q is a region that denotes an "area", whereas $partial{Q}$ is the "circumference" around this 2-dimensional area. The "boundary" of the "area". Right or wrong?
$endgroup$
– DiscreteMath
Mar 28 at 15:26
add a comment |
1
$begingroup$
It might be the boundary of some domain.
$endgroup$
– Gibbs
Mar 26 at 10:14
$begingroup$
ohh...ok... i get it... Q is a region that denotes an "area", whereas $partial{Q}$ is the "circumference" around this 2-dimensional area. The "boundary" of the "area". Right or wrong?
$endgroup$
– DiscreteMath
Mar 28 at 15:26
1
1
$begingroup$
It might be the boundary of some domain.
$endgroup$
– Gibbs
Mar 26 at 10:14
$begingroup$
It might be the boundary of some domain.
$endgroup$
– Gibbs
Mar 26 at 10:14
$begingroup$
ohh...ok... i get it... Q is a region that denotes an "area", whereas $partial{Q}$ is the "circumference" around this 2-dimensional area. The "boundary" of the "area". Right or wrong?
$endgroup$
– DiscreteMath
Mar 28 at 15:26
$begingroup$
ohh...ok... i get it... Q is a region that denotes an "area", whereas $partial{Q}$ is the "circumference" around this 2-dimensional area. The "boundary" of the "area". Right or wrong?
$endgroup$
– DiscreteMath
Mar 28 at 15:26
add a comment |
2 Answers
2
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$begingroup$
If you provide more context, it may be clearer but it may mean "the boundary of $z$".
This makes sense if $z$ represents some region, e.g. a disc, and then the integral over $partial z$ means you integrate over its boundary, in the case of the example the circle bounding the disc.
$endgroup$
add a comment |
$begingroup$
The symbol $partial$ is often used to denote the boundary of a set. So, for example, if $D$ is some (nice enough) set in $mathbb C$, then $partial D$ is the boundary of $D$, and this means that the integral over $partial D$ is simply a line integral.
$endgroup$
add a comment |
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2 Answers
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2 Answers
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$begingroup$
If you provide more context, it may be clearer but it may mean "the boundary of $z$".
This makes sense if $z$ represents some region, e.g. a disc, and then the integral over $partial z$ means you integrate over its boundary, in the case of the example the circle bounding the disc.
$endgroup$
add a comment |
$begingroup$
If you provide more context, it may be clearer but it may mean "the boundary of $z$".
This makes sense if $z$ represents some region, e.g. a disc, and then the integral over $partial z$ means you integrate over its boundary, in the case of the example the circle bounding the disc.
$endgroup$
add a comment |
$begingroup$
If you provide more context, it may be clearer but it may mean "the boundary of $z$".
This makes sense if $z$ represents some region, e.g. a disc, and then the integral over $partial z$ means you integrate over its boundary, in the case of the example the circle bounding the disc.
$endgroup$
If you provide more context, it may be clearer but it may mean "the boundary of $z$".
This makes sense if $z$ represents some region, e.g. a disc, and then the integral over $partial z$ means you integrate over its boundary, in the case of the example the circle bounding the disc.
answered Mar 26 at 10:14
StackTDStackTD
24.3k2254
24.3k2254
add a comment |
add a comment |
$begingroup$
The symbol $partial$ is often used to denote the boundary of a set. So, for example, if $D$ is some (nice enough) set in $mathbb C$, then $partial D$ is the boundary of $D$, and this means that the integral over $partial D$ is simply a line integral.
$endgroup$
add a comment |
$begingroup$
The symbol $partial$ is often used to denote the boundary of a set. So, for example, if $D$ is some (nice enough) set in $mathbb C$, then $partial D$ is the boundary of $D$, and this means that the integral over $partial D$ is simply a line integral.
$endgroup$
add a comment |
$begingroup$
The symbol $partial$ is often used to denote the boundary of a set. So, for example, if $D$ is some (nice enough) set in $mathbb C$, then $partial D$ is the boundary of $D$, and this means that the integral over $partial D$ is simply a line integral.
$endgroup$
The symbol $partial$ is often used to denote the boundary of a set. So, for example, if $D$ is some (nice enough) set in $mathbb C$, then $partial D$ is the boundary of $D$, and this means that the integral over $partial D$ is simply a line integral.
answered Mar 26 at 10:16
5xum5xum
92.9k395162
92.9k395162
add a comment |
add a comment |
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$begingroup$
It might be the boundary of some domain.
$endgroup$
– Gibbs
Mar 26 at 10:14
$begingroup$
ohh...ok... i get it... Q is a region that denotes an "area", whereas $partial{Q}$ is the "circumference" around this 2-dimensional area. The "boundary" of the "area". Right or wrong?
$endgroup$
– DiscreteMath
Mar 28 at 15:26