Prove discontinuity at given point Announcing the arrival of Valued Associate #679: Cesar...
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Prove discontinuity at given point
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Monopolist Profit MaximizationFind values of a, b and c for which $f(x)$ if continuous at $x=0$.Confusion about jump discontinuity and Green's function of a B.V.P.Finding $lim_{x to infty} left(frac{a_{1}^{1/x}+a_{2}^{1/x}+cdotcdotcdot{a_{n}}^{1/x}}{n}right)^{nx}$Evalutate $lim_{xto infty} x^2 int_{0}^{x} e^{t^3 - x^3}dt$Continuity of composite functions with point discontinuitiesidentifying discontinuityLimit answer not matchingFinding the value of variables from a given piecewise continuous function.discontinuity of functionSequence of continuous functions with discontinuous limits
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Given the function $y= lim_{n to infty} frac{1}{1+x^n}$ for $x geq 0$, show that the function is discontinuous at $x=1$?
I tried the question , it comes out to be continuous using left hand limit and right hand limit rule
calculus limits continuity discontinuous-functions
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add a comment |
$begingroup$
Given the function $y= lim_{n to infty} frac{1}{1+x^n}$ for $x geq 0$, show that the function is discontinuous at $x=1$?
I tried the question , it comes out to be continuous using left hand limit and right hand limit rule
calculus limits continuity discontinuous-functions
$endgroup$
1
$begingroup$
If $xin(0,1)$ then $x^nto0$ as $ntoinfty$. Therefore, $frac{1}{1+x^n}tofrac{1}{1+0}=1$. However, if $x=1$ then $frac{1}{1+x^n}=frac{1}{1+1}=frac{1}{2}$. Therefore, the limit function has limit from the left at $x=1$ that is equal to $1$, but the value at the point is $1/2$.
$endgroup$
– user647486
Mar 23 at 12:19
1
$begingroup$
Is this question about one function or a sequence of functions? Is it about continuity or about a limit?
$endgroup$
– Kavi Rama Murthy
Mar 23 at 12:20
add a comment |
$begingroup$
Given the function $y= lim_{n to infty} frac{1}{1+x^n}$ for $x geq 0$, show that the function is discontinuous at $x=1$?
I tried the question , it comes out to be continuous using left hand limit and right hand limit rule
calculus limits continuity discontinuous-functions
$endgroup$
Given the function $y= lim_{n to infty} frac{1}{1+x^n}$ for $x geq 0$, show that the function is discontinuous at $x=1$?
I tried the question , it comes out to be continuous using left hand limit and right hand limit rule
calculus limits continuity discontinuous-functions
calculus limits continuity discontinuous-functions
edited Mar 23 at 12:32
Yanior Weg
2,85611547
2,85611547
asked Mar 23 at 12:14
Sanjam MannSanjam Mann
43
43
1
$begingroup$
If $xin(0,1)$ then $x^nto0$ as $ntoinfty$. Therefore, $frac{1}{1+x^n}tofrac{1}{1+0}=1$. However, if $x=1$ then $frac{1}{1+x^n}=frac{1}{1+1}=frac{1}{2}$. Therefore, the limit function has limit from the left at $x=1$ that is equal to $1$, but the value at the point is $1/2$.
$endgroup$
– user647486
Mar 23 at 12:19
1
$begingroup$
Is this question about one function or a sequence of functions? Is it about continuity or about a limit?
$endgroup$
– Kavi Rama Murthy
Mar 23 at 12:20
add a comment |
1
$begingroup$
If $xin(0,1)$ then $x^nto0$ as $ntoinfty$. Therefore, $frac{1}{1+x^n}tofrac{1}{1+0}=1$. However, if $x=1$ then $frac{1}{1+x^n}=frac{1}{1+1}=frac{1}{2}$. Therefore, the limit function has limit from the left at $x=1$ that is equal to $1$, but the value at the point is $1/2$.
$endgroup$
– user647486
Mar 23 at 12:19
1
$begingroup$
Is this question about one function or a sequence of functions? Is it about continuity or about a limit?
$endgroup$
– Kavi Rama Murthy
Mar 23 at 12:20
1
1
$begingroup$
If $xin(0,1)$ then $x^nto0$ as $ntoinfty$. Therefore, $frac{1}{1+x^n}tofrac{1}{1+0}=1$. However, if $x=1$ then $frac{1}{1+x^n}=frac{1}{1+1}=frac{1}{2}$. Therefore, the limit function has limit from the left at $x=1$ that is equal to $1$, but the value at the point is $1/2$.
$endgroup$
– user647486
Mar 23 at 12:19
$begingroup$
If $xin(0,1)$ then $x^nto0$ as $ntoinfty$. Therefore, $frac{1}{1+x^n}tofrac{1}{1+0}=1$. However, if $x=1$ then $frac{1}{1+x^n}=frac{1}{1+1}=frac{1}{2}$. Therefore, the limit function has limit from the left at $x=1$ that is equal to $1$, but the value at the point is $1/2$.
$endgroup$
– user647486
Mar 23 at 12:19
1
1
$begingroup$
Is this question about one function or a sequence of functions? Is it about continuity or about a limit?
$endgroup$
– Kavi Rama Murthy
Mar 23 at 12:20
$begingroup$
Is this question about one function or a sequence of functions? Is it about continuity or about a limit?
$endgroup$
– Kavi Rama Murthy
Mar 23 at 12:20
add a comment |
0
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$begingroup$
If $xin(0,1)$ then $x^nto0$ as $ntoinfty$. Therefore, $frac{1}{1+x^n}tofrac{1}{1+0}=1$. However, if $x=1$ then $frac{1}{1+x^n}=frac{1}{1+1}=frac{1}{2}$. Therefore, the limit function has limit from the left at $x=1$ that is equal to $1$, but the value at the point is $1/2$.
$endgroup$
– user647486
Mar 23 at 12:19
1
$begingroup$
Is this question about one function or a sequence of functions? Is it about continuity or about a limit?
$endgroup$
– Kavi Rama Murthy
Mar 23 at 12:20