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Proof verification for simplex method problems



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Reconstructing an optimal Simplex tableau from an optimal solutionlinear program-Simplex method-Dual problemSimplex method state after first phaseSimplex method - multiple optimal solutions?solving minimum linear programming with simplex methodWhat optimal basis is when using revised simplex methodWhen using the simplex method , how do we know that the number of basic variables will be exactly equal to n+1?Correctness of the artificial constraint method (dual simplex)Linear Program without simplex methodConditions for a unique optimum of linear optimization problems












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$begingroup$


I was studying simplex method in LPP from "Introduction to Linear Optimization by Bertsimas and Tsitsiklis", and came across this problem:




Consider the simplex method applied to a standard form problem and
assume that the rows of the matrix $A$ are linearly independent . For
each of the statements that follow, give either a proof or a
counterexample. Take $ngeq m$, where $A$ is $m*n$ and $b$ is $m*1$ matrix.



(a) An iteration of the simplex method may move the
feasible solution by a positive distance while leaving the cost
unchanged.



(b) If there is a
nondegenerate optimal basis , then there exists a unique optimal
basis.



(c) If $x$ is an optimal solution, no more than $m$ of its
components can be positive.




I tried this question, and was able to solve some of them. But, I'm not sure if my solutions are correct. It'd be really helpful if someone could tell if I solved these correctly and tell the solutions/hints for the unsolved ones.



My try:



I considered a tableau while solving all of these problems.



a) False. Let $c$ and $bar{c}$ be the initial and final costs. When we update the tableau, we'll apply row transformation to go from $c$ to $bar{c}$. But since $c=bar{c}$, for the cost to remain the same after an iteration, the basic variable that is exiting the basis has to be zero. Let $k$ be the index of the variable entering the basis and $B(l)$ be that of leaving the basis. When we move from $x_{B(l)}$ to $x_k$, whatever we multiply by, $x_{B(l)} (=x_k)$ will remain the same ($0$). So, we are still at the same point.



b) I was unable to understand it clearly. What does "basis" mean? The basis matrix $B$ or the vector of basic variables $x_B$? I've no idea on how to proceed in any of those two way either.



c) This is true since $x$ being an optimal solution is a bfs.



Please note that I don't even need full solutions, even hints will do. Thanks!










share|cite|improve this question











$endgroup$

















    0












    $begingroup$


    I was studying simplex method in LPP from "Introduction to Linear Optimization by Bertsimas and Tsitsiklis", and came across this problem:




    Consider the simplex method applied to a standard form problem and
    assume that the rows of the matrix $A$ are linearly independent . For
    each of the statements that follow, give either a proof or a
    counterexample. Take $ngeq m$, where $A$ is $m*n$ and $b$ is $m*1$ matrix.



    (a) An iteration of the simplex method may move the
    feasible solution by a positive distance while leaving the cost
    unchanged.



    (b) If there is a
    nondegenerate optimal basis , then there exists a unique optimal
    basis.



    (c) If $x$ is an optimal solution, no more than $m$ of its
    components can be positive.




    I tried this question, and was able to solve some of them. But, I'm not sure if my solutions are correct. It'd be really helpful if someone could tell if I solved these correctly and tell the solutions/hints for the unsolved ones.



    My try:



    I considered a tableau while solving all of these problems.



    a) False. Let $c$ and $bar{c}$ be the initial and final costs. When we update the tableau, we'll apply row transformation to go from $c$ to $bar{c}$. But since $c=bar{c}$, for the cost to remain the same after an iteration, the basic variable that is exiting the basis has to be zero. Let $k$ be the index of the variable entering the basis and $B(l)$ be that of leaving the basis. When we move from $x_{B(l)}$ to $x_k$, whatever we multiply by, $x_{B(l)} (=x_k)$ will remain the same ($0$). So, we are still at the same point.



    b) I was unable to understand it clearly. What does "basis" mean? The basis matrix $B$ or the vector of basic variables $x_B$? I've no idea on how to proceed in any of those two way either.



    c) This is true since $x$ being an optimal solution is a bfs.



    Please note that I don't even need full solutions, even hints will do. Thanks!










    share|cite|improve this question











    $endgroup$















      0












      0








      0





      $begingroup$


      I was studying simplex method in LPP from "Introduction to Linear Optimization by Bertsimas and Tsitsiklis", and came across this problem:




      Consider the simplex method applied to a standard form problem and
      assume that the rows of the matrix $A$ are linearly independent . For
      each of the statements that follow, give either a proof or a
      counterexample. Take $ngeq m$, where $A$ is $m*n$ and $b$ is $m*1$ matrix.



      (a) An iteration of the simplex method may move the
      feasible solution by a positive distance while leaving the cost
      unchanged.



      (b) If there is a
      nondegenerate optimal basis , then there exists a unique optimal
      basis.



      (c) If $x$ is an optimal solution, no more than $m$ of its
      components can be positive.




      I tried this question, and was able to solve some of them. But, I'm not sure if my solutions are correct. It'd be really helpful if someone could tell if I solved these correctly and tell the solutions/hints for the unsolved ones.



      My try:



      I considered a tableau while solving all of these problems.



      a) False. Let $c$ and $bar{c}$ be the initial and final costs. When we update the tableau, we'll apply row transformation to go from $c$ to $bar{c}$. But since $c=bar{c}$, for the cost to remain the same after an iteration, the basic variable that is exiting the basis has to be zero. Let $k$ be the index of the variable entering the basis and $B(l)$ be that of leaving the basis. When we move from $x_{B(l)}$ to $x_k$, whatever we multiply by, $x_{B(l)} (=x_k)$ will remain the same ($0$). So, we are still at the same point.



      b) I was unable to understand it clearly. What does "basis" mean? The basis matrix $B$ or the vector of basic variables $x_B$? I've no idea on how to proceed in any of those two way either.



      c) This is true since $x$ being an optimal solution is a bfs.



      Please note that I don't even need full solutions, even hints will do. Thanks!










      share|cite|improve this question











      $endgroup$




      I was studying simplex method in LPP from "Introduction to Linear Optimization by Bertsimas and Tsitsiklis", and came across this problem:




      Consider the simplex method applied to a standard form problem and
      assume that the rows of the matrix $A$ are linearly independent . For
      each of the statements that follow, give either a proof or a
      counterexample. Take $ngeq m$, where $A$ is $m*n$ and $b$ is $m*1$ matrix.



      (a) An iteration of the simplex method may move the
      feasible solution by a positive distance while leaving the cost
      unchanged.



      (b) If there is a
      nondegenerate optimal basis , then there exists a unique optimal
      basis.



      (c) If $x$ is an optimal solution, no more than $m$ of its
      components can be positive.




      I tried this question, and was able to solve some of them. But, I'm not sure if my solutions are correct. It'd be really helpful if someone could tell if I solved these correctly and tell the solutions/hints for the unsolved ones.



      My try:



      I considered a tableau while solving all of these problems.



      a) False. Let $c$ and $bar{c}$ be the initial and final costs. When we update the tableau, we'll apply row transformation to go from $c$ to $bar{c}$. But since $c=bar{c}$, for the cost to remain the same after an iteration, the basic variable that is exiting the basis has to be zero. Let $k$ be the index of the variable entering the basis and $B(l)$ be that of leaving the basis. When we move from $x_{B(l)}$ to $x_k$, whatever we multiply by, $x_{B(l)} (=x_k)$ will remain the same ($0$). So, we are still at the same point.



      b) I was unable to understand it clearly. What does "basis" mean? The basis matrix $B$ or the vector of basic variables $x_B$? I've no idea on how to proceed in any of those two way either.



      c) This is true since $x$ being an optimal solution is a bfs.



      Please note that I don't even need full solutions, even hints will do. Thanks!







      proof-verification optimization linear-programming two-phase-simplex






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Mar 24 at 12:36







      Ankit Kumar

















      asked Mar 23 at 12:41









      Ankit KumarAnkit Kumar

      1,542221




      1,542221






















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