Convergence of scalar product in a hilbert space The 2019 Stack Overflow Developer Survey...
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Convergence of scalar product in a hilbert space
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Background: From this paper I'm trying to understand why the OPE in conformal field theory has a finite radius of convergence.
The authors make the claim that
the scalar product of two states converges when one of the two states is expanded into an
orthonormal basis.
Here a "state" is a ray in a hilbert space.
1. Does the following argument prove the claim above? (Notation from Rudin chapter 4)
Let $phi, psi in ell^2(A) = H$ with $psi$ expressible in an orthonormal basis of $H$. Without loss of generality, assume $psi$ is normalized and one of the basis vectors of the basis mentioned. Then
$$(phi, psi) = sum_{ain A}phi(a)overline{psi}(a) = phi(0)$$
where by assumption $psi(a) = 1$ for $a = 0$ and vanishes elsewhere. Then since $phi in H$ the inner product converges.
2. Can it be shown that if neither state may be expanded in an orthonormal basis of $H$ then the scalar product may not converge?
Thanks!
functional-analysis hilbert-spaces mathematical-physics conformal-field-theory
$endgroup$
add a comment |
$begingroup$
Background: From this paper I'm trying to understand why the OPE in conformal field theory has a finite radius of convergence.
The authors make the claim that
the scalar product of two states converges when one of the two states is expanded into an
orthonormal basis.
Here a "state" is a ray in a hilbert space.
1. Does the following argument prove the claim above? (Notation from Rudin chapter 4)
Let $phi, psi in ell^2(A) = H$ with $psi$ expressible in an orthonormal basis of $H$. Without loss of generality, assume $psi$ is normalized and one of the basis vectors of the basis mentioned. Then
$$(phi, psi) = sum_{ain A}phi(a)overline{psi}(a) = phi(0)$$
where by assumption $psi(a) = 1$ for $a = 0$ and vanishes elsewhere. Then since $phi in H$ the inner product converges.
2. Can it be shown that if neither state may be expanded in an orthonormal basis of $H$ then the scalar product may not converge?
Thanks!
functional-analysis hilbert-spaces mathematical-physics conformal-field-theory
$endgroup$
1
$begingroup$
You (or the paper) must be working with different definitions than usual. On a Hilbert space the scalar product of any two vectors is well defined, and any vector is expressible with respect to any orthonormal basis. At this point it would be helpful to be explicit about what you are working with.
$endgroup$
– s.harp
Mar 22 at 23:03
add a comment |
$begingroup$
Background: From this paper I'm trying to understand why the OPE in conformal field theory has a finite radius of convergence.
The authors make the claim that
the scalar product of two states converges when one of the two states is expanded into an
orthonormal basis.
Here a "state" is a ray in a hilbert space.
1. Does the following argument prove the claim above? (Notation from Rudin chapter 4)
Let $phi, psi in ell^2(A) = H$ with $psi$ expressible in an orthonormal basis of $H$. Without loss of generality, assume $psi$ is normalized and one of the basis vectors of the basis mentioned. Then
$$(phi, psi) = sum_{ain A}phi(a)overline{psi}(a) = phi(0)$$
where by assumption $psi(a) = 1$ for $a = 0$ and vanishes elsewhere. Then since $phi in H$ the inner product converges.
2. Can it be shown that if neither state may be expanded in an orthonormal basis of $H$ then the scalar product may not converge?
Thanks!
functional-analysis hilbert-spaces mathematical-physics conformal-field-theory
$endgroup$
Background: From this paper I'm trying to understand why the OPE in conformal field theory has a finite radius of convergence.
The authors make the claim that
the scalar product of two states converges when one of the two states is expanded into an
orthonormal basis.
Here a "state" is a ray in a hilbert space.
1. Does the following argument prove the claim above? (Notation from Rudin chapter 4)
Let $phi, psi in ell^2(A) = H$ with $psi$ expressible in an orthonormal basis of $H$. Without loss of generality, assume $psi$ is normalized and one of the basis vectors of the basis mentioned. Then
$$(phi, psi) = sum_{ain A}phi(a)overline{psi}(a) = phi(0)$$
where by assumption $psi(a) = 1$ for $a = 0$ and vanishes elsewhere. Then since $phi in H$ the inner product converges.
2. Can it be shown that if neither state may be expanded in an orthonormal basis of $H$ then the scalar product may not converge?
Thanks!
functional-analysis hilbert-spaces mathematical-physics conformal-field-theory
functional-analysis hilbert-spaces mathematical-physics conformal-field-theory
edited Mar 24 at 0:41
Andrews
1,2962423
1,2962423
asked Mar 22 at 20:19
DiffycueDiffycue
401215
401215
1
$begingroup$
You (or the paper) must be working with different definitions than usual. On a Hilbert space the scalar product of any two vectors is well defined, and any vector is expressible with respect to any orthonormal basis. At this point it would be helpful to be explicit about what you are working with.
$endgroup$
– s.harp
Mar 22 at 23:03
add a comment |
1
$begingroup$
You (or the paper) must be working with different definitions than usual. On a Hilbert space the scalar product of any two vectors is well defined, and any vector is expressible with respect to any orthonormal basis. At this point it would be helpful to be explicit about what you are working with.
$endgroup$
– s.harp
Mar 22 at 23:03
1
1
$begingroup$
You (or the paper) must be working with different definitions than usual. On a Hilbert space the scalar product of any two vectors is well defined, and any vector is expressible with respect to any orthonormal basis. At this point it would be helpful to be explicit about what you are working with.
$endgroup$
– s.harp
Mar 22 at 23:03
$begingroup$
You (or the paper) must be working with different definitions than usual. On a Hilbert space the scalar product of any two vectors is well defined, and any vector is expressible with respect to any orthonormal basis. At this point it would be helpful to be explicit about what you are working with.
$endgroup$
– s.harp
Mar 22 at 23:03
add a comment |
0
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$begingroup$
You (or the paper) must be working with different definitions than usual. On a Hilbert space the scalar product of any two vectors is well defined, and any vector is expressible with respect to any orthonormal basis. At this point it would be helpful to be explicit about what you are working with.
$endgroup$
– s.harp
Mar 22 at 23:03