Approximation of a sumDeriving Inequalities for Binomial TermsChebyshev-like lower boundMarkov/Chebyshev's...

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Approximation of a sum


Deriving Inequalities for Binomial TermsChebyshev-like lower boundMarkov/Chebyshev's inequality ProblemsNeed help using the triangle inequalityChebyshev's inequality, binomial distributionPlease explain about Chebyshev's inequality?Upper/lower bound on variance of positive random variableConverting Discrete Random Variables to ContinousWhen will $f(i):=binom{2k-1}{i}Big((1-p)^i(1+p)^{2k-1-i}-(1+p)^i(1-p)^{2k-1-i} Big)$ attain maximum?Find the least upper bound of a binomial distribution













-1












$begingroup$


We are given 2 large numbers, s and a.



$$s=sum_{j=0}^{26} binom{119}{j}$$ and $$a=frac{2s}{2^n}$$



Since these 2 numbers are too big to handle we will use instead the Binomial(119,0.5) for random variable X as follows:




  • find E[X] and Var(X)

  • find suitable t (from the sum above) so that $P[|X-E[X]|geqq{t}]$ then use t to calculate this probability with Chebyshev's inequality. Finally, the upper bound from the inequality is a number M very close to a, specifically $aleqq{M}$.










share|cite|improve this question









$endgroup$

















    -1












    $begingroup$


    We are given 2 large numbers, s and a.



    $$s=sum_{j=0}^{26} binom{119}{j}$$ and $$a=frac{2s}{2^n}$$



    Since these 2 numbers are too big to handle we will use instead the Binomial(119,0.5) for random variable X as follows:




    • find E[X] and Var(X)

    • find suitable t (from the sum above) so that $P[|X-E[X]|geqq{t}]$ then use t to calculate this probability with Chebyshev's inequality. Finally, the upper bound from the inequality is a number M very close to a, specifically $aleqq{M}$.










    share|cite|improve this question









    $endgroup$















      -1












      -1








      -1





      $begingroup$


      We are given 2 large numbers, s and a.



      $$s=sum_{j=0}^{26} binom{119}{j}$$ and $$a=frac{2s}{2^n}$$



      Since these 2 numbers are too big to handle we will use instead the Binomial(119,0.5) for random variable X as follows:




      • find E[X] and Var(X)

      • find suitable t (from the sum above) so that $P[|X-E[X]|geqq{t}]$ then use t to calculate this probability with Chebyshev's inequality. Finally, the upper bound from the inequality is a number M very close to a, specifically $aleqq{M}$.










      share|cite|improve this question









      $endgroup$




      We are given 2 large numbers, s and a.



      $$s=sum_{j=0}^{26} binom{119}{j}$$ and $$a=frac{2s}{2^n}$$



      Since these 2 numbers are too big to handle we will use instead the Binomial(119,0.5) for random variable X as follows:




      • find E[X] and Var(X)

      • find suitable t (from the sum above) so that $P[|X-E[X]|geqq{t}]$ then use t to calculate this probability with Chebyshev's inequality. Finally, the upper bound from the inequality is a number M very close to a, specifically $aleqq{M}$.







      inequality summation binomial-distribution






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Mar 14 at 12:29









      EmKalEmKal

      112




      112






















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