How much above the cost price must he marks his goods above the cost price to make a profit of 17%On Profit...
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How much above the cost price must he marks his goods above the cost price to make a profit of 17%
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$begingroup$
A businessman allows a discount of $10$% on written price. How much above the cost price must he mark his goods to make a profit of $17$% ?
note:
$xtimesfrac{90}{100}=xtimesfrac{117}{100}$
$frac{117}{90}times100=130$
so $30$%
is this right ?
algebra-precalculus
$endgroup$
bumped to the homepage by Community♦ 17 hours ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
add a comment |
$begingroup$
A businessman allows a discount of $10$% on written price. How much above the cost price must he mark his goods to make a profit of $17$% ?
note:
$xtimesfrac{90}{100}=xtimesfrac{117}{100}$
$frac{117}{90}times100=130$
so $30$%
is this right ?
algebra-precalculus
$endgroup$
bumped to the homepage by Community♦ 17 hours ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
add a comment |
$begingroup$
A businessman allows a discount of $10$% on written price. How much above the cost price must he mark his goods to make a profit of $17$% ?
note:
$xtimesfrac{90}{100}=xtimesfrac{117}{100}$
$frac{117}{90}times100=130$
so $30$%
is this right ?
algebra-precalculus
$endgroup$
A businessman allows a discount of $10$% on written price. How much above the cost price must he mark his goods to make a profit of $17$% ?
note:
$xtimesfrac{90}{100}=xtimesfrac{117}{100}$
$frac{117}{90}times100=130$
so $30$%
is this right ?
algebra-precalculus
algebra-precalculus
edited Aug 27 '14 at 9:03
Claude Leibovici
123k1157135
123k1157135
asked Aug 27 '14 at 7:32
jyothikajyothika
45117
45117
bumped to the homepage by Community♦ 17 hours ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
bumped to the homepage by Community♦ 17 hours ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
add a comment |
add a comment |
1 Answer
1
active
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votes
$begingroup$
Your calculation is a bit unclear, but you got the answer right.
If your businessman has a cost price of $P$, then to make a profit of 17% he should get at least $1.17P$ for his product.
Since he can give a discount of 10%, this $1.17P$ is 90% of the written price. Thus, the written price should be $frac{1.17P}{0.9}=1.3P$. This indeed corresponds with a written price that is 30% above the cost price.
$endgroup$
$begingroup$
same as u written @spk 117*100/90=130 so 30%
$endgroup$
– jyothika
Aug 27 '14 at 7:46
$begingroup$
why u persons are down voting?you are egoistic
$endgroup$
– jyothika
Aug 27 '14 at 7:53
$begingroup$
discouraging others.
$endgroup$
– jyothika
Aug 27 '14 at 7:54
$begingroup$
This question appears to be off-topic for this platform.
$endgroup$
– Hirak
Aug 27 '14 at 7:55
$begingroup$
if $x$ is the cost price and $y$ is the written price, then $x+frac{17x}{100}=y-frac{10y}{100}$
$endgroup$
– Vikram
Aug 27 '14 at 8:30
|
show 2 more comments
Your Answer
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1 Answer
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1 Answer
1
active
oldest
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$begingroup$
Your calculation is a bit unclear, but you got the answer right.
If your businessman has a cost price of $P$, then to make a profit of 17% he should get at least $1.17P$ for his product.
Since he can give a discount of 10%, this $1.17P$ is 90% of the written price. Thus, the written price should be $frac{1.17P}{0.9}=1.3P$. This indeed corresponds with a written price that is 30% above the cost price.
$endgroup$
$begingroup$
same as u written @spk 117*100/90=130 so 30%
$endgroup$
– jyothika
Aug 27 '14 at 7:46
$begingroup$
why u persons are down voting?you are egoistic
$endgroup$
– jyothika
Aug 27 '14 at 7:53
$begingroup$
discouraging others.
$endgroup$
– jyothika
Aug 27 '14 at 7:54
$begingroup$
This question appears to be off-topic for this platform.
$endgroup$
– Hirak
Aug 27 '14 at 7:55
$begingroup$
if $x$ is the cost price and $y$ is the written price, then $x+frac{17x}{100}=y-frac{10y}{100}$
$endgroup$
– Vikram
Aug 27 '14 at 8:30
|
show 2 more comments
$begingroup$
Your calculation is a bit unclear, but you got the answer right.
If your businessman has a cost price of $P$, then to make a profit of 17% he should get at least $1.17P$ for his product.
Since he can give a discount of 10%, this $1.17P$ is 90% of the written price. Thus, the written price should be $frac{1.17P}{0.9}=1.3P$. This indeed corresponds with a written price that is 30% above the cost price.
$endgroup$
$begingroup$
same as u written @spk 117*100/90=130 so 30%
$endgroup$
– jyothika
Aug 27 '14 at 7:46
$begingroup$
why u persons are down voting?you are egoistic
$endgroup$
– jyothika
Aug 27 '14 at 7:53
$begingroup$
discouraging others.
$endgroup$
– jyothika
Aug 27 '14 at 7:54
$begingroup$
This question appears to be off-topic for this platform.
$endgroup$
– Hirak
Aug 27 '14 at 7:55
$begingroup$
if $x$ is the cost price and $y$ is the written price, then $x+frac{17x}{100}=y-frac{10y}{100}$
$endgroup$
– Vikram
Aug 27 '14 at 8:30
|
show 2 more comments
$begingroup$
Your calculation is a bit unclear, but you got the answer right.
If your businessman has a cost price of $P$, then to make a profit of 17% he should get at least $1.17P$ for his product.
Since he can give a discount of 10%, this $1.17P$ is 90% of the written price. Thus, the written price should be $frac{1.17P}{0.9}=1.3P$. This indeed corresponds with a written price that is 30% above the cost price.
$endgroup$
Your calculation is a bit unclear, but you got the answer right.
If your businessman has a cost price of $P$, then to make a profit of 17% he should get at least $1.17P$ for his product.
Since he can give a discount of 10%, this $1.17P$ is 90% of the written price. Thus, the written price should be $frac{1.17P}{0.9}=1.3P$. This indeed corresponds with a written price that is 30% above the cost price.
answered Aug 27 '14 at 7:44
SPK.zSPK.z
723310
723310
$begingroup$
same as u written @spk 117*100/90=130 so 30%
$endgroup$
– jyothika
Aug 27 '14 at 7:46
$begingroup$
why u persons are down voting?you are egoistic
$endgroup$
– jyothika
Aug 27 '14 at 7:53
$begingroup$
discouraging others.
$endgroup$
– jyothika
Aug 27 '14 at 7:54
$begingroup$
This question appears to be off-topic for this platform.
$endgroup$
– Hirak
Aug 27 '14 at 7:55
$begingroup$
if $x$ is the cost price and $y$ is the written price, then $x+frac{17x}{100}=y-frac{10y}{100}$
$endgroup$
– Vikram
Aug 27 '14 at 8:30
|
show 2 more comments
$begingroup$
same as u written @spk 117*100/90=130 so 30%
$endgroup$
– jyothika
Aug 27 '14 at 7:46
$begingroup$
why u persons are down voting?you are egoistic
$endgroup$
– jyothika
Aug 27 '14 at 7:53
$begingroup$
discouraging others.
$endgroup$
– jyothika
Aug 27 '14 at 7:54
$begingroup$
This question appears to be off-topic for this platform.
$endgroup$
– Hirak
Aug 27 '14 at 7:55
$begingroup$
if $x$ is the cost price and $y$ is the written price, then $x+frac{17x}{100}=y-frac{10y}{100}$
$endgroup$
– Vikram
Aug 27 '14 at 8:30
$begingroup$
same as u written @spk 117*100/90=130 so 30%
$endgroup$
– jyothika
Aug 27 '14 at 7:46
$begingroup$
same as u written @spk 117*100/90=130 so 30%
$endgroup$
– jyothika
Aug 27 '14 at 7:46
$begingroup$
why u persons are down voting?you are egoistic
$endgroup$
– jyothika
Aug 27 '14 at 7:53
$begingroup$
why u persons are down voting?you are egoistic
$endgroup$
– jyothika
Aug 27 '14 at 7:53
$begingroup$
discouraging others.
$endgroup$
– jyothika
Aug 27 '14 at 7:54
$begingroup$
discouraging others.
$endgroup$
– jyothika
Aug 27 '14 at 7:54
$begingroup$
This question appears to be off-topic for this platform.
$endgroup$
– Hirak
Aug 27 '14 at 7:55
$begingroup$
This question appears to be off-topic for this platform.
$endgroup$
– Hirak
Aug 27 '14 at 7:55
$begingroup$
if $x$ is the cost price and $y$ is the written price, then $x+frac{17x}{100}=y-frac{10y}{100}$
$endgroup$
– Vikram
Aug 27 '14 at 8:30
$begingroup$
if $x$ is the cost price and $y$ is the written price, then $x+frac{17x}{100}=y-frac{10y}{100}$
$endgroup$
– Vikram
Aug 27 '14 at 8:30
|
show 2 more comments
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