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development of a function and set of convergence



The 2019 Stack Overflow Developer Survey Results Are In
Unicorn Meta Zoo #1: Why another podcast?
Announcing the arrival of Valued Associate #679: Cesar ManaraAbsolute and conditional convergence of seriesConvergence of series with modified denominatorProof of convergence of Dirichlet's Eta FunctionFunction continuous at irrationals and discontinuous at rationalsUniform convergence: $sum frac{x^2}{(1 + x^2)^n}$Using the nested set property to prove uniform convergenceStudy the pointwise, normal and then uniform convergence of the following series of functions.Having a doubt in my answer regarding uniform convergence of functional series.Radius and Set of Convergence for the following SeriesConvergence of series of remainders












0












$begingroup$


I want to find the development of the function $ e^{x^2}$
and the set of convergence.



Considering that:
$e^x= sum_{k=0}^n frac {x^k}{k!} + R_n(x,0)$



and substituting $x$ with $x^2$ I can write
$e^{x^2}= sum_{k=0}^n frac {x^{2k}}{k!} + R_n(x,0)$



Now I have to prove that $ R_n(x,0)$ tends to $0$ to say that



$e^{x^2}= sum_{k=0}^infty frac {x^{2k}}{k!}$



and for which $x$ it happens.



please help me










share|cite|improve this question









$endgroup$












  • $begingroup$
    It is $R_n(x^2, 0)$ after the substitution ...
    $endgroup$
    – Martin R
    Mar 22 at 12:26












  • $begingroup$
    ok , and if I had $R(x,x_0)$, does it become $R(x^2, {x_0}^2)$?
    $endgroup$
    – Anne
    Mar 22 at 12:29


















0












$begingroup$


I want to find the development of the function $ e^{x^2}$
and the set of convergence.



Considering that:
$e^x= sum_{k=0}^n frac {x^k}{k!} + R_n(x,0)$



and substituting $x$ with $x^2$ I can write
$e^{x^2}= sum_{k=0}^n frac {x^{2k}}{k!} + R_n(x,0)$



Now I have to prove that $ R_n(x,0)$ tends to $0$ to say that



$e^{x^2}= sum_{k=0}^infty frac {x^{2k}}{k!}$



and for which $x$ it happens.



please help me










share|cite|improve this question









$endgroup$












  • $begingroup$
    It is $R_n(x^2, 0)$ after the substitution ...
    $endgroup$
    – Martin R
    Mar 22 at 12:26












  • $begingroup$
    ok , and if I had $R(x,x_0)$, does it become $R(x^2, {x_0}^2)$?
    $endgroup$
    – Anne
    Mar 22 at 12:29
















0












0








0





$begingroup$


I want to find the development of the function $ e^{x^2}$
and the set of convergence.



Considering that:
$e^x= sum_{k=0}^n frac {x^k}{k!} + R_n(x,0)$



and substituting $x$ with $x^2$ I can write
$e^{x^2}= sum_{k=0}^n frac {x^{2k}}{k!} + R_n(x,0)$



Now I have to prove that $ R_n(x,0)$ tends to $0$ to say that



$e^{x^2}= sum_{k=0}^infty frac {x^{2k}}{k!}$



and for which $x$ it happens.



please help me










share|cite|improve this question









$endgroup$




I want to find the development of the function $ e^{x^2}$
and the set of convergence.



Considering that:
$e^x= sum_{k=0}^n frac {x^k}{k!} + R_n(x,0)$



and substituting $x$ with $x^2$ I can write
$e^{x^2}= sum_{k=0}^n frac {x^{2k}}{k!} + R_n(x,0)$



Now I have to prove that $ R_n(x,0)$ tends to $0$ to say that



$e^{x^2}= sum_{k=0}^infty frac {x^{2k}}{k!}$



and for which $x$ it happens.



please help me







sequences-and-series analysis taylor-expansion






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 22 at 12:21









AnneAnne

797419




797419












  • $begingroup$
    It is $R_n(x^2, 0)$ after the substitution ...
    $endgroup$
    – Martin R
    Mar 22 at 12:26












  • $begingroup$
    ok , and if I had $R(x,x_0)$, does it become $R(x^2, {x_0}^2)$?
    $endgroup$
    – Anne
    Mar 22 at 12:29




















  • $begingroup$
    It is $R_n(x^2, 0)$ after the substitution ...
    $endgroup$
    – Martin R
    Mar 22 at 12:26












  • $begingroup$
    ok , and if I had $R(x,x_0)$, does it become $R(x^2, {x_0}^2)$?
    $endgroup$
    – Anne
    Mar 22 at 12:29


















$begingroup$
It is $R_n(x^2, 0)$ after the substitution ...
$endgroup$
– Martin R
Mar 22 at 12:26






$begingroup$
It is $R_n(x^2, 0)$ after the substitution ...
$endgroup$
– Martin R
Mar 22 at 12:26














$begingroup$
ok , and if I had $R(x,x_0)$, does it become $R(x^2, {x_0}^2)$?
$endgroup$
– Anne
Mar 22 at 12:29






$begingroup$
ok , and if I had $R(x,x_0)$, does it become $R(x^2, {x_0}^2)$?
$endgroup$
– Anne
Mar 22 at 12:29












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